\r and \b help a lot in reducing amount of progress updates, but how do I disable those characters in iTerm2 to show all lines instead?
e.g.: if program print
printf("\ra");
printf("\rb");
I will receive
a
b
instead of just
b
Related
I am writing a small text based game to familiarize myself with Kotlin. I am creating two strings that print out the multiple choice options. I have confirmed that all four array elements are captured appropriately, but when the string prints it cuts off the a) and c) options. I have used \t, spaces, etc. and it does the same thing. I have also tried to just use print() and then use a \n at the end
println(menuList[0])
println(menuList[1])
println(menuList[2])
println(menuList[3])
println("a) ${menuList[0]} b) ${menuList[1]}")
println("c) ${menuList[2]} d) ${menuList[3]}")
Output:
erroneous output of multiple choice text
The source text came from a file which was separating each line with \r\n, but the code reading it was splitting it with \n. The result was that each entry ended with \r. When printed out, this caused the first value to be overwritten.
The solution is, when reading the file, to split by \r\n rather than \n.
I can't find new-tab whereas there is new-line so how do you preserver tabs in blocks ?
help new-line
USAGE:
NEW-LINE position value
DESCRIPTION:
Sets or clears the new-line marker within a block or paren.
NEW-LINE is a native! value.
ARGUMENTS:
position [block! paren!] "Position to change marker (modified)".
value "Set TRUE for newline".
REFINEMENTS:
/all => Set/clear marker to end of series.
/skip => Set/clear marker periodically to the end of the series.
size [integer!]
RETURNS:
[block! paren!]
There is one newline flag per-cell in arrays ("any-block!"s), which indicates whether or not the molding process should put out a newline before that value.
Indentation is driven only from these flags. Indentation starts at the first newline flag, and further newlines will each align to that level, with an outdent at the end of the block if any newlines/indents occurred.
>> data: [a b c]
>> new-line next data true
>> data
== [a
b c
]
Note there are 4 "candidate positions" for newlines inside the block [a b c] (e.g. the positions are [* a * b * c *]). Yet there are only three value cells, with a newline marker indicating a desire to output a newline before that cell. Lacking anywhere to put the fourth newline signal, the decision in Rebol2 and Red is to implicitly put the closing bracket on its own line if there were any newline markers processed.
I've previously mentioned that it's non-obvious exactly how "out-of-band" information like this gets managed in the face of series modifications. It helps to work through your expectations. Even worrying about just one bit there is a lot of nuance, such as when you say:
compose [
1 + (block1)
(block2)
]
How should newline markers be merged, between what's in the COMPOSE and what's in the spliced data itself? That's just the logic related to one bit. Putting in some "indentation count" would introduce many more questions. Plus, there's not a lot of bits to spare for that count: one of the "rules of the game" is to keep things down to just 4 platform pointers per value cell.
Expanding the formatting features isn't too likely. One feature request that the tail get its own newline marker was accepted for open source Rebol3, but rejected by Red. I wouldn't expect to see much more done in this area.
I have a program that iterates over all lines of a text file, adds spaces between the characters, and writes the output to the same file. However, if there are multiple lines in the input, I want the output to have separate lines as well. I tried:
let text = format!(r"{}\n", line); // Add newline character to each line (while iterating)
file.write_all(text.as_bytes()); // Write each line + newline
Here is an example input text file:
foo
bar
baz
And its output:
f o o\n b a r\n b a z
It seems that Rust treats "\n" as an escaped n character, but using r"\n" treats it as a string. How can I have Rust treat \n as a newline character to write multiple lines to a text file?
Note: I can include the rest of my code if you need it, let me know.
Edit: I am on Windows 7 64 bit
The problem is the 'r' in front of your string. Remove it and your program will print newlines instead of '\n'.
Also note that only most Unices use '\n' as newline. Windows uses "\r\n".
I want to retain a space character on only the blank lines between code segments of a single function. The reason is that when cut/paste into interpreter, it will break if no space there (says unexpected indentation).
So I want intellij to not strip out that space character. But I can not find setting to prevent the extra whitespace removal.
here is the use case:
def myfunc():
print "something"
def internal_Func_that_I_want_separated_by_newline():
print "how to have a line above this one that includes a single space?"
def anotherfunc():
print "foobar"
foobar()
internal_Func_that_I_want_separated_by_newline()
thanks
You need to set Editor | Strip trailing spaces on save to None. Here is the screenshot of the option.
I'm using ragel with C as the host language.
I can recognise a newline simply with '\n', but I need to recognise the start of the file as an alternative.
In other implementations of regex this could be given by \A or $, but $ is reserved for other purposes, '\A' maps to something else (alarm?) and \A gives a parser error.
I don't think there's an escape sequence for that. However, you can detect it by checking if Ragel's ts variable equals 0.
In text format You have 3 choice:
Old mac to nr 9 \n\r (and Commodore, Apple II, Microware OS-9)
Unices and new Mac OS X \n ( and BeOS, AmigaOS, MorphOS, RISC OS, Multics)
Windows uses \r\n (and DOS, OS/2, Symbian, DEC RT-11)
in Ragel defining end of line
endline = ( "\r" | "\n" )+ #{ increase_line_number; };
the start of line is begining (any - endline)