Master table
SerNo HospitalId CityId
1 1 1
2 1 1
3 2 2
4 3 2
5 1 1
HospitalMaster
HospitalId HospitalName
1 ABC
2 XYZ
CityMaster
CityId City
1 Delhi
2 Bombay
Result
I need something like this
City TotalHospital
Delhi 1
Bombay 2
I tried joining the tables but I keep getting the total rows of the columns and not of the hospitals.
Thank you.
Left join the city master table to a subquery which finds the hospital counts for each city. Note carefully that we only count distinct hospitals, because a hospital city relationship may appear more than once in the master table.
SELECT t1.City, COALESCE(t2.cnt, 0) AS TotalHospital
FROM CityMaster t1
LEFT JOIN
(
SELECT CityId, COUNT(DISTINCT HospitalId) cnt
FROM Master
GROUP BY CityID
) t2
ON t1.CityId = t2.CityId;
Demo
Try this:
SELECT C.City,COUNT(DISTINCT HospitalID)TotalHospital
FROM CityMaster C
JOIN Master_table M ON M.CityId=C.CityId
GROUP BY C.City
You could apply join
select M.City,count(distinct M.HospitalId) from CityMaster C inner join Master M ON C.CityId = M.CityId
group by M.City
You can do it with using JOIN
Just replace #city, #hospital, #table with your table names.
select C.City,T.CityId from #city C,#hosp H,#table T WHERE T.CityId = C.CityId AND T.HospitalId = H.HospitalId Group by C.City,T.CityId
As we need city name along with count, we can get by join city master and master tables.
select max(C.cityname), count(distinct M.HospitalId)
from CityMaster C
inner join Master M
on C.Cityid = M.CityId
group by M.cityid
Related
Currently I have 3 tables like below
Master
ID_NUMBER
ZIPCODE
1
12341
2
12342
3
12343
4
12344
Table1
ID_NUMBER
CITYNAME
COUNTYNAME
1
NEW YORK
QUEENS
3
DETROIT
SUFFOLK
Table2
ID_NUMBER
CITYNAME
COUNTYNAME
2
ATLANTA
ROCKLAND
4
BOSTON
WINCHESTER
My desired output is like below. I want to filter based on the zipcode from master table
ID_NUMBER
ZIPCODE
CITYNAME
COUNTYNAME
2
12342
ATLANTA
ROCKLAND
How would i go about writing a query for this? Below is what i have tried but it's giving me null values if the ID_NUMBER is not found on that particular table.
SELECT mstr.id_number,
mstr.zipcode,
t1.cityname,
t1.countyname,
t2.cityname,
t2.countyname
FROM MASTER mstr
LEFT JOIN Table1 t1 ON mstr.id_number=t1.id_number
LEFT JOIN Table2 t2 ON mstr.id_number=t2.id_number
WHERE mstr.zipcode='12342'
Use COALESCE():
SELECT mstr.id_number,
mstr.zipcode,
COALESCE(t1.cityname, t2.cityname) as cityname
COALESCE(t1.countyname, t2.countyname) as countyname
FROM MASTER mstr LEFT JOIN
Table1 t1
ON mstr.id_number = t1.id_number LEFT JOIN
Table2 t2
ON mstr.id_number = t2.id_number
WHERE mstr.zipcode = '12342
'
Another approach you can try since your tables are identical is to join master with the union of the tables
with t as (
select Id_number, Cityname, Countyname
from t1
union all
select Id_number, Cityname, Countyname
from t2
)
select *
from Master m join t on m.Id_number=t.Id_Number
where m.zipcode='12342'
I have two tables
Cities:
id name
------------
1 Helsinki
2 Tukholma
3 Oslo
4 Turku
Flights
id where_id to_id
---------------------
1 1 2
2 1 3
3 2 3
4 2 4
I want to get this result
Helsinki Tukholma
Helsinki Oslo
Tukholma Oslo
Tukholma Turku
How do I compose the query? Result has two name columns and I can't get around it?
You can join twice:
select c1.name where_city, c2.name to_city
from flights f
inner join cities c1 on c1.id = f.where_id
inner join cities c2 on c2.id = f.to_id
You need two joins:
select f.*, cw.name, ct.name
from flights f join
cities cw
on f.where_id = cw.id join
cities ct
on f.to_id = ct.id;
I found this solution. Pretty clear. No JOINs
SELECT A.name, B.name FROM cities A, cities B, flights F WHERE F.where_id=A.id AND L.to_id=B.id;
I have 3 tables like "brands" and "whisky" and "country"
BRANDS
brand_id brand_name brand_country_id
1 Example brand 1
2 Brand 2 2
Whisky
whisky_id whisky_brand_id
1 2
2 2
3 1
4 2
Country
country_id country_nicename
1 Poland
2 Germany
And i have SQL:
SELECT
brands.brand_id,
brands.brand_name,
brands.brand_country_id,
country.country_id,
country.country_niename
FROM
brands
LEFT JOIN
country
ON
brands.brand_country_id = country.country_id
LEFT JOIN
whisky
ON
brands.brand_id = whisky.whisky_brand_id
I'm want to data like
brand_id brand_name country_id country_nicename no.ofWhisky
2 Brand2 1 Germany 3
But i dont know how to count no of whisky in this query :/
can anyone help?
Thx :)
You just need to do aggregation using group by & count():
SELECT brands.brand_id, brands.brand_name, country.country_id, country.country_niename,
count(whisky_id) as no.ofWhisky
FROM brands LEFT JOIN
country
ON brands.brand_country_id = country.country_id LEFT JOIN
whisky
ON brands.brand_id = whisky.whisky_brand_id
GROUP BY brands.brand_id, brands.brand_name, country.country_id, country.country_niename;
SELECT brands.brand_id, brands.brand_name, brands.brand_country_id, country.country_id, country.country_niename ,temp.whiskycount
FROM brands LEFT JOIN country ON brands.brand_country_id = country.country_id
LEFT JOIN (
select count(*) as whiskycount, whisky_brand_id
from whisky
Group by whisky_brand_id
) temp ON brands.brand_id = whisky.whisky_brand_id
I am trying to write a query using group by in sub query ,I referred lot of blogs but could not get all the values.
I have three tables and below is the structure of those tables.
Pet_Seller_Master
ps_id ps_name city_id
2 abc 1
3 xyz 2
4 fer 4
5 bbb 1
City_Master
city_id city_name
1 Bangalore
2 COIMBATORE
4 MYSORE
Api_Entry
api_id ps_id otp
1 2 yes
2 3
3 2 yes
4 3 yes
5 4
6 5 yes
7 5 yes
8 5 yes
Query is to get number of sellers, no of pet sellers with zero otp, no of pet sellers with 1 otp, no of pet sellers with 2 otp,no of pet sellers with otp>2 for the particular city and within date range.
Through Below query I am able to get city , psp , and zero otp
select cm.city_name,
count(ps.ps_id) as PSP,
((select count(ps1.ps_id)
FROM ps_master ps1
WHERE ps1.city = cm.city_id)-
(SELECT count(distinct ps1.ps_id)
from ps_master ps1
INNER JOIN api_entry ae ON ps1.ps_id = ae.ps_id and otp!=''
WHERE ps1.city = cm.city_id and date(timestamp) >= curdate() - INTERVAL DAYOFWEEK(curdate())+6 DAY AND date(timestamp) < curdate())) as zero_psp
from ps_master ps INNER JOIN city_master cm ON ps.city = cm.city_id and cm.city_type = 'IN HOUSE PNS'
group by city_id
Please tell me the solution to solve this query.
Thanks in advance
It's not hard to do and you were on a right track. Here is what I would use:
select c.city_name, a.otp, p.ps_name, COUNT(*) nbr
from Api_Entry a
inner join Pet_Seller_Master p on p.ps_id=a.ps_id
inner join City_Master c on p.city_id=c.city_id
group by c.city_name, a.otp, p.ps_name
Now, if you want to get the number of sellers with zero otp, you just apply where clause:
where otp <> 'yes'
If you want to get the number of pet sellers with otp>2, then you just use subquery:
select *
from (
select c.city_name, a.otp, p.ps_name, COUNT(*) nbr
from #tempA a
inner join #tempP p on p.ps_id=a.ps_id
inner join #tempC c on p.city_id=c.city_id
group by c.city_name, a.otp, p.ps_name
) g
where nbr > 2
I have two tables.
Food Table
--------------------------
ID CityID FoodName
--------------------------
1 1 FoodA
2 1 FoodB
3 1 FoodC
4 2 FoodW
5 2 FoodX
6 2 FoodY
7 2 FoodZ
City Table
--------------------------
ID CityName
--------------------------
1 Memphis
2 Nashville
3 Chattanooga
So How can I use CityName s as Column title and list the food in that city.
--------------------------------------
Memphis Nashville Chattanooga
--------------------------------------
FoodA FoodW
FoodB FoodX
FoodC FoodY
FoodZ
I'm pretty sure on that I have to use pivot but I couldn't find a good solution yet.
This is what I've achieved so far.
SELECT *
FROM (
SELECT *
FROM Food F
INNER JOIN City C ON C.ID = F.CityID
) DataTable D
PIVOT(F.FoodName FOR C.CityName IN (
[Memphis]
,[Nashville]
,[Chattanooga]
)) PivotTable
you can use this query to get your output. Actually you did some mistakes to setup the pivot query.
select Memphis,Nashville,Chattanooga
from
(
select f.ID,c.CityName,f.FoodName
from Food f
inner join City c
on f.CityID=c.id
)result
pivot
(
max(FoodName)
for CityName in(Memphis,Nashville,Chattanooga)
) as pvt
The PIVOT operator uses the columns from the data table that are not in the PIVOT definition as GROUP anchor.
That mean that two values will be in the same row of a PIVOT table when they have the same value in the columns of data table that are neither the aggregated one or the pivoted one.
The OP data don't have this value so a new partitioned id is generated.
SELECT Memphis, Nashville, Chattanooga
FROM (SELECT c.CityName, f.FoodName
, FoodID = Row_Number() OVER (PARTITION BY c.ID ORDER BY FoodName)
FROM Food f
INNER JOIN City c ON f.CityID = c.id) d
PIVOT
(MAX(FoodName) FOR CityName IN (Memphis,Nashville,Chattanooga)) pvt