Create table of unique values from join - sql

Question

I have two tables with various addresses. One is a table of locations we already have on file, the other is new business. The idea is that I'm joining these two tables on their co-ordinates in order to show if we have a clash between the new business and the current business.
What I have found is that in the new business we have one location that matches three locations that we already have.
When I do my simple inner join I get back 3 records when really I want to display the 4 (1 from new, 3 from current). I have tried other joins and union as well as sub queries but with no luck. I know there is a way but just can't figure it out.
SELECT *
FROM NewBusiness
INNER JOIN Live L ON N.Latitude = L.Latitude AND N.Longitude = L.Longitude
Thanks in advance

Answer 1

Maybe not the best answer (it catch duplicate rows in the same table) but still working correctly
select distinct 'oldbiz', l.id, l.latitude, l.longitude
from Live l, NewBusiness n
where l.latitude = n.latitude
and l.longitude = n.longitude
union all
select distinct 'newbiz', n.id, n.latitude, n.longitude
from Live l, NewBusiness n
where l.latitude = n.latitude
and l.longitude = n.longitude
SQLFIDDLE

Answer 2

So I was able to get what I think you are looking for using a union. It may not be the best way to do it but it looks like it works. I made a SQL Fiddle to show it.
You can see the fiddle here: SQLFIDDLE
to test, I created two tables, Live and NewBusiness.
Created them like this
CREATE TABLE Live
([ID] varchar(1), [latitude] int, [longitude] int)
;
INSERT INTO Live
([ID], [latitude], [longitude])
VALUES
('a', 1, 2),
('b', 1, 2),
('c', 1, 2),
('d', 4, 3),
('e', 5, 4),
('k', 5, 7),
('l', 5, 9),
('M', 5, 7)
;
and
CREATE TABLE NewBusiness
([ID] varchar(1), [latitude] int, [longitude] int)
;
INSERT INTO NewBusiness
([ID], [latitude], [longitude])
VALUES
('f', 1, 2),
('g', 5, 2),
('h', 1, 8),
('i', 6, 3),
('z', 5, 7),
('y', 12, 4),
('x', 5, 7)
;
The query I used was
(
SELECT L.ID
,L.Latitude
,L.Longitude
FROM Live L
INNER JOIN NEWBUSINESS N
ON L.Latitude = N.Latitude AND L.Longitude = N.Longitude
)
UNION
(
SELECT N.ID
,N.LATITUDE
,N.LONGITUDE
FROM NEWBUSINESS N
INNER JOIN Live L
ON N.Latitude = L.Latitude AND N.Longitude = L.Longitude
GROUP BY N.ID
,N.LATITUDE
,N.LONGITUDE
)
The first part of the union gets all the things in Live that have matches in Newbusiness. The second part of the union gets all the things in Newbusiness that have matches in Live. The results are then union'd together.
Tables:
Live
ID latitude longitude
a 1 2
b 1 2
c 1 2
d 4 3
e 5 4
k 5 7
l 5 9
M 5 7
**NewBusiness**
ID latitude longitude
f 1 2
g 5 2
h 1 8
i 6 3
z 5 7
y 12 4
x 5 7
**Query Results**
ID Latitude Longitude
a 1 2
b 1 2
c 1 2
f 1 2
k 5 7
M 5 7
x 5 7
z 5 7

Answer 3

Does something like this give you what you need (it will count once for each record in either table that has a match in the other table):
WITH cte1
AS
(
SELECT
N.latitude
, N.longitude
, ROW_NUMBER() OVER (ORDER BY N.latitude, N.longitude) r1
FROM NewBusiness N
)
,
cte2
AS
(
SELECT
N.latitude
, N.longitude
, ROW_NUMBER() OVER (PARTITION BY N.r1 ORDER BY N.latitude, N.longitude) r2
FROM
cte1 N
JOIN Live L ON
N.Latitude = L.Latitude
AND N.Longitude = L.Longitude
)
SELECT
latitude
, longitude
, 'NewBusiness' sourceTable
FROM cte2
WHERE r2 = 1
UNION ALL
SELECT
latitude
, longitude
, sourceTable
FROM
(
SELECT DISTINCT
latitude
, longitude
, r2
, 'Live' sourceTable
FROM cte2
) Q