Convert datetime to epoch time with seconds in SQL Server 2008 - sql

SELECT
CONVERT(BIGINT, DATEDIFF(ss, '1970-01-01 00:00:00', replogindatetime)) AS login,
CONVERT(BIGINT, DATEDIFF(ss, '1970-01-01 00:00:00', replogoutdatetime)) AS logout
FROM
#Table
The RepLoginDateTime & RepLogoutDateTime are 2 columns in SQL Server datetime datatype, which I have to convert to epoch timestamp, but I get this error:
Msg 535, Level 16, State 0, Line 23
The datediff function resulted in an overflow. The number of dateparts separating two date/time instances is too large. Try to use datediff with a less precise datepart.
I'm using SQL Server 2008

DATEDIFF in SQL Server returns an int. From SQL Server 2016 you also have DATEDIFF_BIG, which returns a bigint. This means, if you have a value that is going to be too large for an int you'll get an overflow error when using DATEDIFF.
It, however, surprises me your getting an overflow here, as 1970-01-01 plus 2,147,483,647 seconds is 2038-01-19 03:14:07.
Anyway, instead, why not get the days, and then the seconds, and add:
SELECT CONVERT(BIGINT,DATEDIFF(DAY, '19700101','2038-10-12 12:30:49')) * 86400 +
DATEDIFF(ss, DATEADD(DAY, DATEDIFF(DAY, 0, '2038-10-12 12:30:49'),0), '2038-10-12 12:30:49')

You have to go around the conversion functions and use a BIGINT instead.
DECLARE #Epoch DATETIME = CAST(0 as DATETIME)
DECLARE #TestDate DATETIME = GETDATE()
DECLARE #DaysPast BIGINT = (SELECT DATEDIFF(DAY, #Epoch,#TestDate))
DECLARE #TimeOfDayInMilliseconds BIGINT = (SELECT DATEDIFF(ms, 0, DATEADD(Day, 0 - DATEDIFF(Day, 0, #TestDate), #TestDate)))
SELECT (#DaysPast * 86400000) + #TimeOfDayInMilliseconds

Related

SQL Column Concatenation whilst keeping the datatype of first column [duplicate]

In an extract I am dealing with, I have 2 datetime columns. One column stores the dates and another the times as shown.
How can I query the table to combine these two fields into 1 column of type datetime?
Dates
2009-03-12 00:00:00.000
2009-03-26 00:00:00.000
2009-03-26 00:00:00.000
Times
1899-12-30 12:30:00.000
1899-12-30 10:00:00.000
1899-12-30 10:00:00.000
You can simply add the two.
if the Time part of your Date column is always zero
and the Date part of your Time column is also always zero (base date: January 1, 1900)
Adding them returns the correct result.
SELECT Combined = MyDate + MyTime FROM MyTable
Rationale (kudos to ErikE/dnolan)
It works like this due to the way the date is stored as two 4-byte
Integers with the left 4-bytes being the date and the right
4-bytes being the time. Its like doing $0001 0000 + $0000 0001 =
$0001 0001
Edit regarding new SQL Server 2008 types
Date and Time are types introduced in SQL Server 2008. If you insist on adding, you can use Combined = CAST(MyDate AS DATETIME) + CAST(MyTime AS DATETIME)
Edit2 regarding loss of precision in SQL Server 2008 and up (kudos to Martin Smith)
Have a look at How to combine date and time to datetime2 in SQL Server? to prevent loss of precision using SQL Server 2008 and up.
If the time element of your date column and the date element of your time column are both zero then Lieven's answer is what you need. If you can't guarantee that will always be the case then it becomes slightly more complicated:
SELECT DATEADD(day, 0, DATEDIFF(day, 0, your_date_column)) +
DATEADD(day, 0 - DATEDIFF(day, 0, your_time_column), your_time_column)
FROM your_table
This is an alternative solution without any char conversions:
DATEADD(ms, DATEDIFF(ms, '00:00:00', [Time]), CONVERT(DATETIME, [Date]))
You will only get milliseconds accuracy this way, but that would normally be OK. I have tested this in SQL Server 2008.
This worked for me
CAST(Tbl.date as DATETIME) + CAST(Tbl.TimeFrom AS TIME)
(on SQL 2008 R2)
If you're not using SQL Server 2008 (i.e. you only have a DateTime data type), you can use the following (admittedly rough and ready) TSQL to achieve what you want:
DECLARE #DateOnly AS datetime
DECLARE #TimeOnly AS datetime
SET #DateOnly = '07 aug 2009 00:00:00'
SET #TimeOnly = '01 jan 1899 10:11:23'
-- Gives Date Only.
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly))
-- Gives Time Only.
SELECT DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
-- Concatenates Date and Time parts.
SELECT
CAST(
DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly)) + ' ' +
DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
as datetime)
It's rough and ready, but it works!
If both of your fields are datetime then simply adding those will work.
eg:
Declare #d datetime, #t datetime
set #d = '2009-03-12 00:00:00.000';
set #t = '1899-12-30 12:30:00.000';
select #d + #t
If you used Date & Time datatype then just cast the time to datetime
eg:
Declare #d date, #t time
set #d = '2009-03-12';
set #t = '12:30:00.000';
select #d + cast(#t as datetime)
This was my solution which ignores the date value of the time column
CAST(Tbl.date as DATETIME) + CAST(CAST(Tbl.TimeFrom AS TIME) as DATETIME)
Hope this helps others
Convert the first date stored in a datetime field to a string, then convert the time stored in a datetime field to string, append the two and convert back to a datetime field all using known conversion formats.
Convert(datetime, Convert(char(10), MYDATETIMEFIELD, 103) + ' ' + Convert(char(8), MYTIMEFIELD, 108), 103)
Convert both field into DATETIME :
SELECT CAST(#DateField as DATETIME) + CAST(#TimeField AS DATETIME)
and if you're using Getdate() use this first:
DECLARE #FechaActual DATETIME = CONVERT(DATE, GETDATE());
SELECT CAST(#FechaActual as DATETIME) + CAST(#HoraInicioTurno AS DATETIME)
I had many errors as stated above so I did it like this
try_parse(concat(convert(date,Arrival_date),' ',arrival_time) as datetime) AS ArrivalDateTime
It worked for me.
Finding this works for two dates where you want time from one and date from the other:
declare #Time as datetime = '2021-11-19 12:34'
declare #Date as datetime = '2021-10-10'
SELECT #time + datediff(day, #Time, #Date)
DECLARE #Dates table ([Date] datetime);
DECLARE #Times table ([Time] datetime);
INSERT INTO #Dates VALUES('2009-03-12 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-26 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-30 00:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 12:30:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
WITH Dates (ID, [Date])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Date]), [Date] FROM #Dates
), Times (ID, [Time])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Time]), [Time] FROM #Times
)
SELECT Dates.[Date] + Times.[Time] FROM Dates
JOIN Times ON Times.ID = Dates.ID
Prints:
2009-03-12 10:00:00.000
2009-03-26 10:00:00.000
2009-03-30 12:30:00.000
To combine date from a datetime column and time from another datetime column this is the best fastest solution for you:
select cast(cast(DateColumn as date) as datetime) + cast(TimeColumn as datetime) from YourTable
SELECT CAST(CAST(#DateField As Date) As DateTime) + CAST(CAST(#TimeField As Time) As DateTime)
Another way is to use CONCATand CAST, be aware, that you need to use DATETIME2(x) to make it work. You can set x to anything between 0-7 7 meaning no precision loss.
DECLARE #date date = '2018-03-12'
DECLARE #time time = '07:00:00.0000000'
SELECT CAST(CONCAT(#date, ' ', #time) AS DATETIME2(7))
Returns 2018-03-12 07:00:00.0000000
Tested on SQL Server 14
simply concatenate both , but cast them first as below
select cast(concat(Cast(DateField as varchar), ' ', Cast(TimeField as varchar)) as datetime) as DateWithTime from TableName;
select s.SalesID from SalesTbl s
where cast(cast(s.SaleDate as date) as datetime) + cast(cast(s.SaleCreatedDate as time) as datetime) between #FromDate and #ToDate
The existing answers do not address the datetime2 datatype so I will add mine:
Assuming that you want to add a time value to a datetime2 value where:
The datetime2 value could contain non-zero time component and/or fractional seconds
The time value could contain the value 23:59:59.9999999 which is 86,399.9999999 seconds, 86,399,999,999.9 microseconds or 86,399,999,999,900 nanoseconds¹
Due to the limitations of dateadd function¹ you must add them in two steps:
Convert the time value to seconds and use dateadd(second, ...)
Extract the nanoseconds from the time value and use dateadd(nanosecond, ...) to add them to the date calculated above
declare #dv datetime2 = '2000-01-01 12:34:56.7890123';
declare #tv time = '23:59:59.9999999';
select dateadd(
nanosecond,
datepart(nanosecond, #tv),
dateadd(
second,
datepart(hour, #tv) * 60 * 60 + datepart(minute, #tv) * 60 + datepart(second, #tv),
#dv
)
);
-- 2000-01-02 12:34:56.7890122
¹ Nanosecond values might not fit in int datatype which dateadd function expects.
SELECT CAST(your_date_column AS date) + CAST(your_time_column AS datetime) FROM your_table
Works like a charm
I ran into similar situation where I had to merge Date and Time fields to DateTime field. None of the above mentioned solution work, specially adding two fields as the data type for addition of these 2 fields is not same.
I created below solution, where I added hour and then minute part to the date. This worked beautifully for me. Please check it out and do let me know if you get into any issues.
;with tbl
as
(
select StatusTime = '12/30/1899 5:17:00 PM', StatusDate = '7/24/2019 12:00:00 AM'
)
select DATEADD(MI, DATEPART(MINUTE,CAST(tbl.StatusTime AS TIME)),DATEADD(HH, DATEPART(HOUR,CAST(tbl.StatusTime AS TIME)), CAST(tbl.StatusDate as DATETIME)))
from tbl
Result: 2019-07-24 17:17:00.000

SQL DATETIME Math

I am trying to do the following:
Format GetDate() to display only the minutes
Format a varchar column to display only the minutes
Subtract the current time HH:MM:SS from GetDate() and the VarChar column
This is what I have
CONVERT(VARCHAR(5), GETDATE(), 108) - substring(convert(varchar(20), ColumnName, 9), 13, 5)
but I am getting this error and need some help please:
Operand data type varchar is invalid for subtract operator.
What you want is datepart(mi).
To get the minutes for getdate():
select datepart(mi, getdate())
To subtract a number of minutes from a datetime:
select dateadd(mi, - <minutes>, <datevalue>)
To remove the time from getdate(), just cast to date (in more recent versions of SQL Server):
select cast(getdate() as date)
To get the difference in minutes, use datediff:
select datediff(mi, <datestart>, <dateend>)
What are you really trying to accomplish?
I think this is what you want:
declare #str varchar(30)
set #str = '2012-08-14 10:12:02.690'
select datediff(minute, cast(#str as datetime), getdate())
Results when getdate() = '2012-08-14 11:21:10.250' is total minutes even over 60:
69

Does Transact-SQL have a similar function to MS Logparser Quantize?

If you are familiar with Microsoft Log Parser you probably recognize the Quantize function which will truncate a value to the nearest multiple of another value. It is quite handy for grouping date-time fields into increments.
Date-Time Count
1/1/2010 00:00 100
1/1/2010 00:15 134
1/1/2010 00:30 56
....
I'm trying to find a similar function in Transaction-SQL (specifically SQL Server 2005 or 2008) that will allow me to do a similar grouping on date-time.
You can round to any given number of minutes like so:
DateAdd(Minute, (DateDiff(minute, 0, getutcdate() )/15) * 15, 0)
Instead of using getutcdate() you can use your date column, variable or expression. In addition the number of minutes can be a variable.
declare #minutesQuantize int set #minutesQuantize = 15
DateAdd(Minute, (DateDiff(minute, 0, getutcdate() )/#minutesQuantize) * #minutesQuantize, 0)
The only rule is that the date difference must fit into an integer, I.e. be less than 2 billion. That means you can't do seconds or milliseconds without a more complicated expression.
If you need seconds or milliseconds do this:
dateadd(ms, (datediff(ms, dateadd(day, datediff(day, 0, #date), 0), #date)/#msInterval)*#msInterval, dateadd(day, datediff(day, 0, #date), 0))
Or, if you want to wrap this into a function:
create function dbo.DateRoundMinutes(#dt datetime, #minutes int)
returns datetime
as begin
return DateAdd(Minute, (DateDiff(minute, 0, #dt )/#minutes) * #minutes, 0)
end
go
create function dbo.DateRoundMilliseconds(#dt datetime, #ms int)
returns datetime
as begin
return dateadd(ms, (datediff(ms, dateadd(day, datediff(day, 0, #dt), 0), #dt)/#ms)*#ms, dateadd(day, datediff(day, 0, #dt), 0))
end
Which you can use like this:
select t.dt,
dbo.DateRoundMilliseconds(dt, 500) dt0_5Second, -- Half second
dbo.DateRoundMilliseconds(dt, 5000) dt5second, -- 5 second
dbo.DateRoundMilliseconds(dt, 15000) dt15Second,
dbo.DateRoundMilliseconds(dt, 90000) dt90Second,
dbo.DateRoundMinutes(dt, 2) dt2Minute,
dbo.DateRoundMinutes(dt, 5) dt5Minute,
dbo.DateRoundMinutes(dt, 15) dt15Minute,
dbo.DateRoundMinutes(dt, 90) dt90Minute
from
/* some table having a column dt */
Not directly, it doesn't. But you can group by a function (that you write) that rounds the datetime column to its nearest quarter-hour (or whatever Quantize does).
SELECT
dbo.QuarterHour(DateColumn) AS Date-Time
, COUNT(*) AS Count
FROM MyTable
GROUP BY dbo.QuarterHour(DateColumn)

TSQL strip date from datetime

What is the best way to strip the date from a DATETIME so only time is left to do a comparison?
I know I can do the following:
CONVERT(DATETIME, CONVERT(VARCHAR(8), GETDATE(),8))
But this involves convert and characters. If I wanted to check whether a time (including minutes) was between two other times stored in DATETIME columns, is there an elegant way to do this without having to rely on converting to character strings?
If you're using SQL 2008
SELECT CAST(GETDATE() AS TIME)
Try the TimeOnly function from Essential SQL Server Date, Time, and DateTime Functions:
create function TimeOnly(#DateTime DateTime)
returns datetime
as
begin
return dateadd(day, -datediff(day, 0, #datetime), #datetime)
end
go
Or simply cast the DateTime as Time in SQL Server 2008:
declare #time as time
set #time = cast(dateTimeVal as time)
DECLARE
#Now DateTime,
#Today DateTime,
#Time DateTime
SET #Now = GetDate()
SET #Today = DateAdd(dd, DateDiff(dd, 0, #Now), 0)
SET #Time = DateAdd(ss, DateDiff(ss, #Today, #Now), 0)
SELECT #Time
Just another way to get date and time from datetime.
datetime in SQL Server implemented as float value where whole part floor(value) is day from 1900-01-01 and fractional part (value - floor(value)) is part of twenty-four hours elapsed from start of day
select
d as [datetime],
cast(cast(T.d as float) - floor(cast(T.d as float)) as datetime) as [time],
cast(floor(cast(T.d as float)) as datetime) as [date]
from
(values
(getdate()),
('1753-01-01 23:59:59.700'),
('1899-12-31 00:00:00.300'),
('1900-01-01 00:00:00.300')
) as T(d);

How to combine date from one field with time from another field - MS SQL Server

In an extract I am dealing with, I have 2 datetime columns. One column stores the dates and another the times as shown.
How can I query the table to combine these two fields into 1 column of type datetime?
Dates
2009-03-12 00:00:00.000
2009-03-26 00:00:00.000
2009-03-26 00:00:00.000
Times
1899-12-30 12:30:00.000
1899-12-30 10:00:00.000
1899-12-30 10:00:00.000
You can simply add the two.
if the Time part of your Date column is always zero
and the Date part of your Time column is also always zero (base date: January 1, 1900)
Adding them returns the correct result.
SELECT Combined = MyDate + MyTime FROM MyTable
Rationale (kudos to ErikE/dnolan)
It works like this due to the way the date is stored as two 4-byte
Integers with the left 4-bytes being the date and the right
4-bytes being the time. Its like doing $0001 0000 + $0000 0001 =
$0001 0001
Edit regarding new SQL Server 2008 types
Date and Time are types introduced in SQL Server 2008. If you insist on adding, you can use Combined = CAST(MyDate AS DATETIME) + CAST(MyTime AS DATETIME)
Edit2 regarding loss of precision in SQL Server 2008 and up (kudos to Martin Smith)
Have a look at How to combine date and time to datetime2 in SQL Server? to prevent loss of precision using SQL Server 2008 and up.
If the time element of your date column and the date element of your time column are both zero then Lieven's answer is what you need. If you can't guarantee that will always be the case then it becomes slightly more complicated:
SELECT DATEADD(day, 0, DATEDIFF(day, 0, your_date_column)) +
DATEADD(day, 0 - DATEDIFF(day, 0, your_time_column), your_time_column)
FROM your_table
This is an alternative solution without any char conversions:
DATEADD(ms, DATEDIFF(ms, '00:00:00', [Time]), CONVERT(DATETIME, [Date]))
You will only get milliseconds accuracy this way, but that would normally be OK. I have tested this in SQL Server 2008.
This worked for me
CAST(Tbl.date as DATETIME) + CAST(Tbl.TimeFrom AS TIME)
(on SQL 2008 R2)
If you're not using SQL Server 2008 (i.e. you only have a DateTime data type), you can use the following (admittedly rough and ready) TSQL to achieve what you want:
DECLARE #DateOnly AS datetime
DECLARE #TimeOnly AS datetime
SET #DateOnly = '07 aug 2009 00:00:00'
SET #TimeOnly = '01 jan 1899 10:11:23'
-- Gives Date Only.
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly))
-- Gives Time Only.
SELECT DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
-- Concatenates Date and Time parts.
SELECT
CAST(
DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly)) + ' ' +
DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
as datetime)
It's rough and ready, but it works!
If both of your fields are datetime then simply adding those will work.
eg:
Declare #d datetime, #t datetime
set #d = '2009-03-12 00:00:00.000';
set #t = '1899-12-30 12:30:00.000';
select #d + #t
If you used Date & Time datatype then just cast the time to datetime
eg:
Declare #d date, #t time
set #d = '2009-03-12';
set #t = '12:30:00.000';
select #d + cast(#t as datetime)
This was my solution which ignores the date value of the time column
CAST(Tbl.date as DATETIME) + CAST(CAST(Tbl.TimeFrom AS TIME) as DATETIME)
Hope this helps others
Convert the first date stored in a datetime field to a string, then convert the time stored in a datetime field to string, append the two and convert back to a datetime field all using known conversion formats.
Convert(datetime, Convert(char(10), MYDATETIMEFIELD, 103) + ' ' + Convert(char(8), MYTIMEFIELD, 108), 103)
Convert both field into DATETIME :
SELECT CAST(#DateField as DATETIME) + CAST(#TimeField AS DATETIME)
and if you're using Getdate() use this first:
DECLARE #FechaActual DATETIME = CONVERT(DATE, GETDATE());
SELECT CAST(#FechaActual as DATETIME) + CAST(#HoraInicioTurno AS DATETIME)
I had many errors as stated above so I did it like this
try_parse(concat(convert(date,Arrival_date),' ',arrival_time) as datetime) AS ArrivalDateTime
It worked for me.
Finding this works for two dates where you want time from one and date from the other:
declare #Time as datetime = '2021-11-19 12:34'
declare #Date as datetime = '2021-10-10'
SELECT #time + datediff(day, #Time, #Date)
DECLARE #Dates table ([Date] datetime);
DECLARE #Times table ([Time] datetime);
INSERT INTO #Dates VALUES('2009-03-12 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-26 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-30 00:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 12:30:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
WITH Dates (ID, [Date])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Date]), [Date] FROM #Dates
), Times (ID, [Time])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Time]), [Time] FROM #Times
)
SELECT Dates.[Date] + Times.[Time] FROM Dates
JOIN Times ON Times.ID = Dates.ID
Prints:
2009-03-12 10:00:00.000
2009-03-26 10:00:00.000
2009-03-30 12:30:00.000
To combine date from a datetime column and time from another datetime column this is the best fastest solution for you:
select cast(cast(DateColumn as date) as datetime) + cast(TimeColumn as datetime) from YourTable
SELECT CAST(CAST(#DateField As Date) As DateTime) + CAST(CAST(#TimeField As Time) As DateTime)
Another way is to use CONCATand CAST, be aware, that you need to use DATETIME2(x) to make it work. You can set x to anything between 0-7 7 meaning no precision loss.
DECLARE #date date = '2018-03-12'
DECLARE #time time = '07:00:00.0000000'
SELECT CAST(CONCAT(#date, ' ', #time) AS DATETIME2(7))
Returns 2018-03-12 07:00:00.0000000
Tested on SQL Server 14
simply concatenate both , but cast them first as below
select cast(concat(Cast(DateField as varchar), ' ', Cast(TimeField as varchar)) as datetime) as DateWithTime from TableName;
select s.SalesID from SalesTbl s
where cast(cast(s.SaleDate as date) as datetime) + cast(cast(s.SaleCreatedDate as time) as datetime) between #FromDate and #ToDate
The existing answers do not address the datetime2 datatype so I will add mine:
Assuming that you want to add a time value to a datetime2 value where:
The datetime2 value could contain non-zero time component and/or fractional seconds
The time value could contain the value 23:59:59.9999999 which is 86,399.9999999 seconds, 86,399,999,999.9 microseconds or 86,399,999,999,900 nanoseconds¹
Due to the limitations of dateadd function¹ you must add them in two steps:
Convert the time value to seconds and use dateadd(second, ...)
Extract the nanoseconds from the time value and use dateadd(nanosecond, ...) to add them to the date calculated above
declare #dv datetime2 = '2000-01-01 12:34:56.7890123';
declare #tv time = '23:59:59.9999999';
select dateadd(
nanosecond,
datepart(nanosecond, #tv),
dateadd(
second,
datepart(hour, #tv) * 60 * 60 + datepart(minute, #tv) * 60 + datepart(second, #tv),
#dv
)
);
-- 2000-01-02 12:34:56.7890122
¹ Nanosecond values might not fit in int datatype which dateadd function expects.
SELECT CAST(your_date_column AS date) + CAST(your_time_column AS datetime) FROM your_table
Works like a charm
I ran into similar situation where I had to merge Date and Time fields to DateTime field. None of the above mentioned solution work, specially adding two fields as the data type for addition of these 2 fields is not same.
I created below solution, where I added hour and then minute part to the date. This worked beautifully for me. Please check it out and do let me know if you get into any issues.
;with tbl
as
(
select StatusTime = '12/30/1899 5:17:00 PM', StatusDate = '7/24/2019 12:00:00 AM'
)
select DATEADD(MI, DATEPART(MINUTE,CAST(tbl.StatusTime AS TIME)),DATEADD(HH, DATEPART(HOUR,CAST(tbl.StatusTime AS TIME)), CAST(tbl.StatusDate as DATETIME)))
from tbl
Result: 2019-07-24 17:17:00.000