lazy loading screen - react-navigation - react-native

New to react-navigation and trying to lazy load a screen. I'm using the new version 1.0.0-beta.27, but it seems like both lazyLoading and lazy doesn't work in this version. Is there any other way to implement this?
My code:
const MainNavigator = TabNavigator({
welcome: { screen: WelcomeScreen },
login: { screen: LoginScreen},
main: {
screen: TabNavigator({
map: { screen: MapScreen },
deck: { screen: DeckScreen },
review: {
screen: StackNavigator({
review: { screen: ReviewScreen },
settings: { screen: SettingsScreen }
})
}
})
}
}, {
lazy: true
});

Related

How to make screen from tabBarNavigator invisible on TabBar?

I use react-navigation version 3.x. How to make screen from tabBarNavigator invisible on TabBar?
I need to remove main screen from tabBar(it should be invisible) but TabBar must be on main screen.
My screen structure is next:
const AppStackNavigator = createStackNavigator({
loginFlow: {
screen: createStackNavigator({
intro: { screen: Intro },
login: { screen: Login },
registration: { screen: Registration }
})
},
mainFlow: {
screen: createStackNavigator({
// settings: { screen: SettingsScreen },
someTab: {
screen: createBottomTabNavigator({
main: { screen: Home },
Tab1: { screen: Tab1 },
Tab2: { screen: Tab2 },
Tab3: { screen: Tab3 },
Tab4: { screen: ChatMain }
})
}
})
}
});
Your question is worded weirdly, but I'll give you answers to both of my interpretations:
If you want so remove a screen from your tab bar, simply comment it out:
// main: { screen: Home },
If you want to have the main screen in the same stack as the rest of your tab bar, but not want it to show within the tab bar, you could nest it inside a switchNavigator:
mainFlow: {
screen: createStackNavigator({
// settings: { screen: SettingsScreen },
someSwitch: createSwitchNavigator({
main: { screen: Home },
someTab: {
screen: createBottomTabNavigator({
Tab1: { screen: Tab1 },
Tab2: { screen: Tab2 },
Tab3: { screen: Tab3 },
Tab4: { screen: ChatMain }
})
}
})
})
}
Actually I just used my own TabBar component. just need to use tabBarComponent properties.

Need help managing navigators in react native

I'm currently implementing a small React Native app, and here is the navigators I'm currently having:
const RootNav= createStackNavigator(
{
Login: LogInScreen,
},
);
const TabNav = createBottomTabNavigator(
{
Home: { screen: HomeScreen },
Calendar: { screen: CalendarScreen },
Discussion: { screen: DiscussionScreen },
Profile: { screen: ProfileScreen },
},
);
export const SwitchNav = createSwitchNavigator(
{
AuthLoading: AuthLoadingScreen,
Auth: RootNav,
MainApp: TabNav,
},
{
initialRouteName: 'AuthLoading',
},
);
Right now in HomeScreen and CalendarScreen there are several Card components which should navigate to another screen named EventScreen with the options to go back to the previous screen which should be another createStackNavigator I think, but I still need help what's the right way to set up the navigators. Thanks in advance.
You can have a parent StackNavigator with EventScreen and TabNav as its children:
const RootNav = createStackNavigator(
{
Login: LogInScreen,
}
);
const HomeNav = createStackNavigator(
{
tabNav: TabNav,
Events: { screen: EventScreen },
}
);
const TabNav = createBottomTabNavigator(
{
Home: { screen: HomeScreen },
Calendar: { screen: CalendarScreen },
Discussion: { screen: DiscussionScreen },
Profile: { screen: ProfileScreen },
}
);
export const SwitchNav = createSwitchNavigator(
{
AuthLoading: AuthLoadingScreen,
Auth: RootNav,
MainApp: HomeNav,
},
{
initialRouteName: 'AuthLoading',
}
);
If you feel like you'll need a DrawerNavigation as well in the future, it is a good idea to take care of it now. This article may help.

Avoid react native initial page having some space on top

const RootStack = MultiNavigator({
Splash: {
screen: Splash
},
Registration: {
screen: Registration
},
WelcomeScreen: {
screen: WelcomeScreen
},
HomeScreen: {
screen: HomeScreen
}
}, {
initialRouteName: "HomeScreen",
},
);
what ever i rendered as initial page , some space is coming at top side. I have to avoid it. I used header: null/none/false. But no result.Thanks in advance.
I have fixed this issue, by using headerMode: none.
const RootStack = MultiNavigator({
Splash: {
screen: Splash
},
Registration: {
screen: Registration
}
}, {
initialRouteName: "Registration",
headerMode: "none"
});

How to integrate stack navigator,TabNavigator,Drawer Navigator togather in react native

I want to use the Navigator All togather but i fail to implement this the code which i use for integration is
const MyApp = const MyApp = TabNavigator({
Home: {
screen: HomeScreen,
},
Notifications: {
screen: HomeButton,
},
},
DrawerNavigator({
Home: {
screen: list,
},
SwipeList:{
screen:SwipeLists
},
},{
initialRouteName: 'Home',
contentComponent: SideDrawer,
});
});
const Simple = StackNavigator({
Login: {
screen: Login,
},
signup: {
screen: SignUp,
},
forget:{
screen:forget
},
});
I use this above but this is not correct i am not now how to integrate them plz recmond the way how to integrate the three navigator in react native

In react-navigation TabNavigator, how to setParams

const AppTabs = TabNavigator({
Home: {
screen: FilmList,
},
FilmCinemaList: {
screen: FilmCinemaList,
path: 'cart',
},
FilmGoodsList: {
screen: FilmGoodsList,
},
FilmMe: {
screen: FilmMe,
},
})
when I click FilmCinemaList, i wanna pass a params. how to use setParams?
You can pass the params this way when rendering your AppTabs:
<AppTabs screenProps={{ FilmCinemaList: { ...yourParams } }}/>
And you can access them on FilmCinemaList by:
this.props.screenProps.FilmCinemaList
.
Through navigationOptions, what you have to do is to set the navigationOptions for the screen before pass it in the TabNavigator like the following:
FilmCinemaList.navigationOptions = {
'param1':'value1';
};
const AppTabs = TabNavigator({
Home: {
screen: FilmList,
},
FilmCinemaList: {
screen: FilmCinemaList,
path: 'cart',
},
FilmGoodsList: {
screen: FilmGoodsList,
},
FilmMe: {
screen: FilmMe,
},
})
And then you can access it
FilmCinemaList.navigationOptions.param1
When ever you need to.