database table
I have this SQL problem to find the total count of the disable people between 2 table
The condition is I only want to get the ID with appearing in the recipient table
left join graph
I only want to get the total count of the left side data which link together with the a_children
http://sqlfiddle.com/#!9/2ca178/1
SELECT COUNT(*)
FROM recipient r
LEFT JOIN a_children c
ON r.hp_id = c.hp_id
AND c.health='OKU'
WHERE r.disability = 'YES'
Related
Outputted Date
I have a seperate Members table which has all the members ID's and I want to list all those but get rid of the ones that are displayed in this list.
SELECT DISTINCT tbl_classregistration.ClassID, tbl_classregistration.MemberID
FROM tbl_member INNER JOIN (tbl_classes
INNER JOIN tbl_classregistration ON
tbl_classes.ClassID = tbl_classregistration.ClassID) ON
tbl_member.MemberID = tbl_classregistration.MemberID
GROUP BY tbl_classregistration.ClassID, tbl_classregistration.MemberID
HAVING (((tbl_classregistration.ClassID)=[Enter ClassID]));
Thats the SQL View
Use not in:
select memberid from members where memberid not in (SELECT DISTINCT tbl_classregistration.MemberID
FROM tbl_member INNER JOIN (tbl_classes INNER JOIN tbl_classregistration ON tbl_classes.ClassID = tbl_classregistration.ClassID) ON tbl_member.MemberID = tbl_classregistration.MemberID
GROUP BY tbl_classregistration.ClassID, tbl_classregistration.MemberID
HAVING (((tbl_classregistration.ClassID)=[Enter ClassID])))
SELECT f_name,l_name,teachers.first_name,teachers.t_id,p_id,paid_amount,family_id,date,sum(payments.paid_amount)
FROM payments
LEFT JOIN family ON family.id = payments.family_id
LEFT JOIN teachers ON family.teacher_id = teachers.t_id
How can I get the selected columns fully and the sum column separately?
because that sum function makes all the selected result one row
SELECT f_name,l_name,teachers.first_name,teachers.t_id,p_id,paid_amount,family_id,date
FROM payments
LEFT JOIN family ON family.id = payments.family_id
LEFT JOIN teachers ON family.teacher_id = teachers.t_id
This query is working fine without the sum column
You didn't tell the database, which column to use for aggregating the data. Don't know which database you are using, but some complain, that there is no GROUP BY statement in the SQL text.
Please try with the following query:
SELECT f_name,l_name,teachers.first_name,teachers.t_id,p_id,paid_amount,family_id,date,sum(payments.paid_amount)
FROM payments
LEFT JOIN family ON family.id = payments.family_id
LEFT JOIN teachers ON family.teacher_id = teachers.t_id
GROUP BY f_name,l_name,teachers.first_name,teachers.t_id,p_id,paid_amount,family_id,date
GROUP BY tells the database, which are the key columns in the aggregation.
If you want all the payments, use a subquery or join:
SELECT f_name, l_name, t.first_name, t.t_id, p.p_id, p.paid_amount, p.family_id, date,
(select sum(p.paid_amount) from payments) as all_paid
FROM payments p LEFT JOIN
family f
ON f.id = p.family_id LEFT JOIN
teachers t
ON f.teacher_id = tetchers.t_id;
SELECT f_name,l_name,t.first_name,t.t_id,p_id,paid_amount,family_id,date,sum(p.paid_amount)
FROM payments p,family f,teachers t where f.id = p.family_id and f.teacher_id = t.t_id
Group by f_name,l_name,teachers.first_name,teachers.t_id,p_id,paid_amount,family_id
You can add date column also in Group by expression based on your requirement. Example:
f_name,l_name,teachers.first_name,teachers.t_id,p_id,paid_amount,family_id,date
Original query is joining customer table and contract table and Extra Service History, this all works.
However I'm having trouble adding 4th table which should apply some further criteria.
Current working query (no changes needed) :
select b.*
from SubscribersFIN b
inner join (select Id, Account_Number, ContractNumber, BackendId
from Contract) e on b.c_id='FI_' + e.Account_Number
left join (select Contract
from Extra_Service_History
where Service_Name='debit_plan') d on e.Id=d.Contract
where COUNTRY='fi'
and NO_SMS = 0
and d.Contract is null
Goal is to filter the set that came from the big query that only records that had Paid status in Invoice to show.
right join (select Contract
from Invoice
where Status = 'PAID') i on e.Id=i.Contract
This one does not seem to do the trick, so I'm not able to figure out what sort of a join-type or logic is required here.
You have a few options:
INNER JOIN
Depending on the particular type of outer join, they return rows where no match is found (either left, right, or both sides of the join). Based on your description this is not what you want. Simply use:
inner join (select Contract
from Invoice
where Status = 'PAID') i on e.Id=i.Contract
It shouldn't matter where this occurs in the FROM clause; provided the join between these 2 tables is INNER. The query engine is free to rearrange for performance provided it doesn't change semantics. (But personally I find it tidier to put INNER JOINs at the top.)
IN filter
What you've described is a filter.
Goal is to filter the set that came from the big query that only records that had Paid status in Invoice to show.
So it's clearer to implement this as a filter in the WHERE clause. E.g.
where e.Id in (select Contract
from Invoice
where Status = 'PAID')
and ...
EXISTS filter
Similar to the above, but using an EXISTS subquery instead.
where exists (select *
from Invoice i
where Status = 'PAID'
and i.Contract = e.Id)
and ...
Rather than mixing LEFT and RIGHT joins, just place it as an INNER join higher up in your query:
select b.*
from SubscribersFIN b
inner join (select Id, Account_Number, ContractNumber, BackendId
from Contract) e on b.c_id='FI_' + e.Account_Number
inner join (select Contract
from Invoice
where Status = 'PAID') i on e.Id=i.Contract
left join (select Contract
from Extra_Service_History
where Service_Name='debit_plan') d on e.Id=d.Contract
where COUNTRY='fi'
and NO_SMS = 0
and d.Contract is null
Based on my understanding i just re arranged the query. Try this. If your where condition columns are coming from any of the LEFT JOIN tables, join them at the on clause.
select b.* from SubscribersFIN b
inner join Contract e on b.c_id='FI_' + e.Account_Number
left join Extra_Service_History d on e.Id=d.Contract and d.Service_Name='debit_plan' and d.Contract is null
left join invoice i on e.Id=i.Contract and i.Status = 'PAID'
where COUNTRY='fi' and NO_SMS = 0
I have two table country and Users. I want to view the country name which have user disabled. So i wrote query for this.
SELECT DISTINCT cntr_id,cntr_name FROM
(SELECT COUNTRY.cntr_id, COUNTRY.cntr_name, USERS.user_enabled,
USERS.user_name, USERS.user_id
FROM COUNTRY INNER JOIN Users
ON COUNTRY.cntr_id = USERS.cntr_id
)
AS TAB where user_enabled = 0
My questions are :
Is this inner query?
will the query fetch all the countries (include user enabled) from the database before running outer query?
Is there any other method to select?
Yes it's an inner Query and will fetch what you need, but you don't need your outer SELECT query. You could just do it like:
SELECT DISTINCT COUNTRY.cntr_id, COUNTRY.cntr_name
FROM COUNTRY INNER JOIN Users
ON COUNTRY.cntr_id = USERS.cntr_id
WHERE USERS.user_enabled = 0
Yes, that is inner query.
Yes, inner query will fetch all the countries (including user enabled). Outer query will remove those records later.
You don't have to use outer query for this.
SELECT DISTINCT C.cntr_id, C.cntr_name
FROM COUNTRY C INNER JOIN
Users U ON C.cntr_id = U.cntr_id
WHERE U.user_enabled=0
OR
SELECT C.cntr_id, C.cntr_name
FROM COUNTRY C INNER JOIN
Users U ON C.cntr_id = U.cntr_id
WHERE U.user_enabled=0
GROUP BY C.cntr_id, C.cntr_name
To answer your question,
Yes It is inner and outer two queries.
The inner query will fetch the all rows which satisfy the join condition.
Yes there is other method to select where you can directly apply the filter in inner query and remove the outer select.
SELECT COUNTRY.cntr_id, COUNTRY.cntr_name, USERS.user_enabled,
USERS.user_name, USERS.user_id
FROM COUNTRY INNER JOIN Users
ON COUNTRY.cntr_id = USERS.cntr_id
WHERE
USERS.user_enabled = 0
I have 2 tables AP and INV where both have the columns [PROJECT] and [Value].
I want a query to return something like this :
PROJECT | SUM_AP | SUM_INV
I came up with the code below but it's returning the wrong results ( sum is wrong ).
SELECT AP.[PROJECT],
SUM(AP.Value) AS SUM_AP,
SUM(INV.Value) AS SUM_INV
FROM AP INNER JOIN INV ON (AP.[PROJECT] =INV.[PROJECT])
WHERE AP.[PROJECT] = 'XXXXX'
GROUP BY AP.[PROJECT]
The results from your query are wrong because the values you are trying to summarize are being grouped, which causes duplicate values to be included in the SUM.
You could solve it with a couple of sub-selects:
SELECT
AP1.[PROJECT],
(SELECT SUM(AP2.Value) FROM AP AS AP2 WHERE AP2.PROJECT = AP1.PROJECT) AS SUM_AP,
(SELECT SUM(INV2.Value) FROM INV AS INV2 WHERE INV2.PROJECT = AP1.PROJECT) AS SUM_INV
FROM AP AS AP1
INNER JOIN INV AS INV1
ON (AP1.[PROJECT] =INV1.[PROJECT])
WHERE AP1.[PROJECT] = 'XXXXX'
GROUP BY AP1.[PROJECT]
If you have N rows in AP with a given project ID, and M rows in INV with that ID, then the join between the two tables on the project ID will have a total of N*M rows for that project, because the same row in AP will be repeated for every row in INV that has that project ID, and vice versa. Hence why your counts are most likely off (because it's counting the same row in a given table multiple times due to repetition from the join).
Instead, you might want to try doing a join between the results of two subqueries, one which groups the first table by project ID and does that its sum, and the second which groups the other table by project ID and does that sum - then joining once you only have 1 row with sum for each project ID.
If PROJECT is the parent table, you should select FROM the project table, and do a left outer join on the two child tables:
SELECT PROJECT.PROJECT_ID, SUM(AP.Value) AS SUM_AP, SUM(INV.Value) AS SUM_INV
FROM PROJECT
LEFT OUTER JOIN AP ON (AP.[PROJECT] = PROJECT.[PROJECT_ID])
LEFT OUTER JOIN INV ON (INV.[PROJECT] = PROJECT.[PROJECT_ID])
WHERE PROJECT.[PROJECT_ID] = 'XXXXX'
GROUP BY PROJECT.[PROJECT_ID]
You could separate the two sum calculations. One way I can think of is to move the inventory calculation to a subquery, like:
SELECT
AP.[PROJECT]
, SUM(AP.Value) AS SUM_AP
, SummedInv as SUM_INV
FROM AP
LEFT JOIN (
SELECT PROJECT, SUM(Value) AS SUM_INV
FROM INV
GROUP BY PROJECT
) SummedInv ON SummedInv.Project = AP.Project
GROUP BY AP.PROJECT, SummedInv.SUM_INV
Because the SummedInv subquery is grouped on project, it's safe to group on SummedInv.SUM_INV in the outer query as well.
how about this query :
select SUM(gpCutBody.actualQty) as cutQty , SUM(gpSewBody.quantity) as sewQty
from jobOrder
inner join gpCutHead on gpCutHead.joNum = jobOrder.joNum
inner join gpSewHead on gpSewHead.joNum = jobOrder.joNum
inner join gpCutBody on gpCutBody.gpCutID = gpCutHead.gpCutID
inner join gpSewBody on gpSewBody.gpSewID = gpSewHead.gpSewID
where jobOrder.joNum = '36'
here is the link to the ERD: http://dl.dropbox.com/u/18794525/AUG%207%20DUMP%20STAN.png
Try:
SELECT AP.[PROJECT] AS PROJECT, SUM(AP.[Value]) AS SUM_AP, SUM(INV.[Value]) AS SUM_INV
FROM AP, INV
WHERE AP.[PROJECT] = INV.[PROJECT]
AND AP.[PROJECT] = 'XXXXX'
GROUP BY AP.[PROJECT]