I have an incident start time and end time e.g Sr=tart time of 15/01/2018 11:30 and end time of 16/01/2018 02:40 in an excel table.
How can I split this time range into different time segments. The segments are:-
06:00 - 11:59, 12:00 - 14:59, 15:00 - 17:59, 18:00 - 22:59, 23:00 - 05:59
For 06:00 - 11:59 I would expect 0.50 as this is 30 mins.
For 12:00 - 14:59 I would expect 3.0 for 3 hours.
For 15:00 - 17:59 I would expect 3.0 for 3 hours again.
For 18:00 - 22:59 this should be 5hrs
and for 23:00 - 02:40 should be 3.67 hrs.
What formula would I need to achieve this?
For the example you give with the layout as shown below this formula should work:
=MIN($D3-F$1,MIN(F$2-F$1,IF($C3<F$2,F$2-$C3+SUM($E3:E3),)))
The formula in C3 is:
=24*(MOD(A3,1))
and in D3:
=24*(MOD(B3,1)+INT(B3>INT(A3)))
Related
In my df I am trying to replace values in column 'Amount in (L)' based on the date and time and the Milking events that occurred that day.
Milk Event Date Time Amount in (L)
Start 04/08/2001 09:00 nan
End 04/08/2001 10:00 1500
Start 04/08/2001 14:00 nan
End 04/08/2001 15:00 2000
Start 05/08/2001 08:00 nan
I am unsure whether to use a for loop or if statement to create conditions that replace the nan with the previous 'End' events amount. I would want it to look something like:
Milk Event Date Time Amount in (L)
Start 04/08/2001 09:00 0
End 04/08/2001 10:00 1500
Start 04/08/2001 14:00 1500
End 04/08/2001 15:00 2000
Start 05/08/2001 08:00 2000
If possible you can use:
df['Amount in (L)'] = pd.to_numeric(df['Amount in (L)'], errors='coerce').ffill().fillna(0)
I wish to write a query for below problem.
The problem is, I want to eliminate all overlapping periods, so that I get the total amount of time which is not taken in any other row.
Example:
NAME
Start Date Time
End Date time
Load shed
21-03-2020 12:30
21-03-2020 13:30
Shutdown
21-03-2020 13:00
21-03-2020 14:00
breakdown
21-03-2020 13:10
21-03-2020 14:10
Load shed
24-03-2020 12:30
24-03-2020 13:30
Shutdown
24-03-2020 11:00
24-03-2020 19:00
breakdown
24-03-2020 13:10
24-03-2020 14:10
Now what we have to do is:
Return time period between start date time and end date time but exclude overlapped time.
Expected result will be:
NAME
Start Date Time
End Date time
Time_interval
Load shed
21-03-2020 12:30
21-03-2020 13:30
01:00
Shutdown
21-03-2020 13:30
21-03-2020 14:00
00:30
breakdown
21-03-2020 14:00
21-03-2020 14:10
00:10
Shutdown
24-03-2020 11:00
24-03-2020 19:00
08:00
Now we can see in result,
First row: As it is because it has the lowest start date time in all
overlapped rows.
Second row: 30 minutes already used in first row so
we exclude 30 minutes here and write left time interval.
Third row:
we exclude till time 14:00 because its already used in row 2 so now time
interval has 10 minutes only.
Fourth row: We exclude all rows from
given table because they all overlapped and they are within start date
time 24-3-2020 11:00 and 24:03:2020 19:00 .
Hope you understand the problem.
Thanks in advance.
You can calculate the previous enddt before each row. Then, if that is larger than the start date, use that for the row. And, if the duration of the row is negative, then filter out the row.
The code looks like:
select name, imputed_startdt, enddt, prev_enddt,
convert(time, dateadd(minute, datediff(minute, imputed_startdt, enddt), 0)) as duration
from (select t.*, max(enddt) over (order by startdt rows between unbounded preceding and 1 preceding) as prev_enddt
from t
) t cross apply
(values (case when prev_enddt > startdt then prev_enddt else startdt end)
) v(imputed_startdt)
where prev_enddt < enddt or prev_enddt is null;
Here is a db<>fiddle.
I have table in which Sunday to Saturdy "Doctor Start" and "End Time" is given.
I want to create time slots of 15 minutes.
On the basis of that, the patient clicks on calendar datetime interval which shows slots that have already been booked.
The following example shows how to split time into slices of 15 minutes. It uses hierarchical query. A little bit of explanation:
line 2: trunc function, applied to a date value, returns "beginning" of that day (at midnight). Adding 15 / (24*60) adds 15 minutes (as there are 24 hours in a day and 60 minutes in an hour). Multiplying 15 by level works as a "loop", i.e. adds 15-by-15-by-15 ... minutes to previous value.
line 4: similar to line 2, but it makes sure that a day (24 hours * 60 minutes) is divided to 15-minutes parts
line 6: start time is trivial
line 7: end time just adds 15 minutes to start_time
line 9: return only time between 10 and 16 hours (you don't have patients at 02:15 AM, right?)
SQL> with fifteen as
2 (select trunc(sysdate) + (level * 15)/(24*60) c_time
3 from dual
4 connect by level <= (24*60) / 15
5 )
6 select to_char(c_time, 'hh24:mi') start_time,
7 to_char(c_time + 15 / (24 * 60), 'hh24:mi') end_time
8 from fifteen
9 where extract(hour from cast (c_time as timestamp)) between 10 and 15;
START_TIME END_TIME
---------- ----------
10:00 10:15
10:15 10:30
10:30 10:45
10:45 11:00
11:00 11:15
11:15 11:30
11:30 11:45
11:45 12:00
12:00 12:15
12:15 12:30
12:30 12:45
12:45 13:00
13:00 13:15
13:15 13:30
13:30 13:45
13:45 14:00
14:00 14:15
14:15 14:30
14:30 14:45
14:45 15:00
15:00 15:15
15:15 15:30
15:30 15:45
15:45 16:00
24 rows selected.
SQL>
I am working on building a query report where i have multiple types of segment with priority ranking on one table and second table with all types of segment with date, time etc. (as shown below) The duration for lower ranked segment during overlap should not be considered.
Please help me as I am unable to figure out query and get the duration of segment excluding the overlap based on ranking
table_Rank
Rank Code
1 x
2 y
3 z
4 a
5 b
6 c
7 d
8 r
9 f
Table_Segments
Code Date Start Time End Time Duration
a 18-Jul-15 17:30 17:45 0:15
c 18-Jul-15 18:00 19:00 1:00
y 18-Jul-15 18:45 19:00 0:15
a 18-Jul-15 20:15 20:20 0:05
b 18-Jul-15 23:45 1:00 1:15
z 19-Jul-15 0:30 1:15 0:45
f 19-Jul-15 2:00 3:00 1:00
Table With Ranks = Table_Rank
Table With Data = Table_Segments
What i am trying to achieves is, in an overlap situation overlap span should be considered for code with higher rank.
e.g.
Code Date Start Time End Time Duration
b 18-Jul-15 23:45 1:00 1:15
z 19-Jul-15 0:30 1:15 0:45
The actual duration output for b should 45 minutes as it has a lower rank compared to z and z should be 45 minutes
I have a table which looks like you can see below:
Id Date ScheduledTimeFrom ScheduledTimeTo ActualTimeFrom ActualTimeTo
1 2013-01-01 1899-12-30 07:00:00 1899-12-30 18:00:00 1899-12-30 07:23:00 1899-12-30 17:15:00
I need to calculate per half hour how many records exists, the output should be like:
Time Actual Count:
7:00 4
7:30 4
8:00 4
8:30 4
9:00 4
9:30 5
10:00 5
10:30 6
11:00 7
11:30 8
12:00 8
12:30 8
13:00 8
13:30 8
14:00 8
14:30 8
15:00 7
15:30 7
16:00 7
16:30 6
17:00 5
17:30 4
18:00 4
I already tried to make a helper table which should hold the times per halfhour. I have joined this helpertable with the table that contains the data and after that I tried to use a group by function but it was not working.
My query was like:
Create table period (timefrom datetime, timeto datetime)
insert into period
select '1899-12-30 07:00:00.000', '1899-12-30 07:30:00.000'
Union all
select '1899-12-30 07:30:00.000', '1899-12-30 08:00:00.000'
select *
from period p left join table1 t on t.ActualTimeFrom < p.timeto and t.ActualTimeTo >=p.timefrom
Grouping this give me no desired result....
Anyone an idea how to come to the result?
P.s. I am using sql server 2005.
After snooping around and testing it on my side, looks like this date function could be the answer:
DATEADD(mi,DATEDIFF(mi,0,YOUR_DATE_COLUMN)/30*30,0)