I'm trying to get updated records count from previous week. But I'm having trouble approaching the problem.
For Eg: I have a table 'Org'
week1 :
id name age address date
record1 : 123 Joe 35 xyz 12/01/2017
week2 :
id name age address date
record1 : 123 Joe 35 abc 12/03/2017
I'm trying to get the record which has been updated. In the above example, the address for record1 with id 123 has been updated. Currently I'm checking in an in-efficient way.
Query:
select * from Org where date='12/01/2017'
and
select * from Org where date='12/03/2017'
Query:
select distinct on (id) count(*) from Org group by Org.id
A file is being pushed to the db every day. So, the updated record will have a new timestamp and the records are getting aggregated overtime which made my job a little harder. I tried joining the table to itself but it didn't make any sense to me. I'm not sure how to approach this problem. I was trying and almost reaching the solution but I don't understand why I'm getting count two times. Example Fiddle
Try this Query:
select col1
from(
select distinct col1,col2,col3,col4
from table_not
)D
group by col1
having count(1)>1
SQL Fiddle link: SQL Fiddle
Related
I am new in SQL and have problem picking the biggest value of a column for every manager_id and also other information in the same row.
Let me show the example - consider this table:
name
manager_id
sales
John
1
100
David
1
80
Selena
2
26
Leo
1
120
Frank
2
97
Sara
2
105
and the result I am expecting would be like this:
name
manager_id
top_sales
Leo
1
120
Sara
2
105
I tried using Max but the problem is that I must group it with manager_id and not being able to take name of the salesPerson.
select manager_id, max(sales) as top_sales
from table
group by manager_id ;
This is just an example and the actual query is very long and I am taking the information from different tables. I know that I can use the same table and join it again but the problem is as I mentioned this query is very long as I am extracting info from different tables with multiple conditions. And I don't want to make a temporary table to save it. It should be done in one single query and I actually did solve this but the query is super long due to the inner join that I used and made original table twice.
My question is that can I use Max and have the value in the name column or is there other method to solve this?
Appreciate all help
You can use row_number() with CTE to get the highest sales for each manager as below:
with MaxSales as (
select name, manager_id, sales,row_number() over (partition by manager_id order by sales desc) rownumber from table
)
select name , manager_id ,sales from MaxSales where rownumber=1
I'm trying to create SQL query to get specific entities with some conditions. The thing is I have some duplicate entities I want to avoid.
My data table (the table represent drivers) is:
I want to get some drivers with condition of specific facility ID/parkinglot ID.
For example, in case I want all the drivers at facility with ID '2', I want to get:
11112 Michael Smith
and not:
11112 Michael Smith
11112 Michael Smith
I want the same thing will happen with the parkinglot ID and with the facility Id together.
I tried:
SELECT * FROM "DRIVERS"
where facilityid = '2'
group by driverid
And I got an error:
Could not execute 'SELECT * FROM "DRIVERS" where facilityid = '2' group by driverid'
invalid column name: The column 'DRIVERS.FIRSTNAME' is invalid in the select list because the GROUP BY clause or an aggregation function does not contain it: line 1 col 8 (at pos 7)
Any ideas?
Thank you!
If you just want to get the distinct values from the table then do:
SELECT DISTINCT *
FROM "DRIVERS"
WHERE facilityid = '2';
GROUP BY should be used when you are aggregating data
Edit:
To get the results you asked for you could use:
SELECT DISTINCT DRIVERID, FIRSTNAME, LASTNAME
FROM "DRIVERS"
WHERE facilityid = '2';
YOU WILL GET THE RESULT WITH THIS QUERY.
select distinct(DRIVERID),FIRSTNAME,LASTNAME FROM "DRIVERS" where facilityid = '2'.
I have an SQL Server 2012 table with ID, First Name and Last name. The ID is unique per person but due to an error in the historical feed, different people were assigned the same id.
------------------------------
ID FirstName LastName
------------------------------
1 ABC M
1 ABC M
1 ABC M
1 ABC N
2 BCD S
3 CDE T
4 DEF T
4 DEG T
In this case, the people with ID’s 1 are different (their last name is clearly different) but they have the same ID. How do I query and get the result? The table in this case has millions of rows. If it was a smaller table, I would probably have queried all ID’s with a count > 1 and filtered them in an excel.
What I am trying to do is, get a list of all such ID's which have been assigned to two different users.
Any ideas or help would be very appreciated.
Edit: I dont think I framed the question very well.
There are two ID's which are present multiple time. 1 and 4. The rows with id 4 are identical. I dont want this in my result. The rows with ID 1, although the first name is same, the last name is different for 1 row. I want only those ID's whose ID is same but one of the first or last names is different.
I tried loading ID's which have multiple occurrences into a temp table and tried to compare it against the parent table albeit unsuccessfully. Any other ideas that I can try and implement?
SELECT
ID
FROM
<<Table>>
GROUP BY
ID
HAVING
COUNT(*) > 1;
SELECT *
FROM myTable
WHERE ID IN (
SELECT ID
FROM myTable
GROUP BY ID
HAVING MAX(LastName) <> MIN(LastName) OR MAX(FirstName) <> MIN(FirstName)
)
ORDER BY ID, LASTNAME
I'm selecting data from multiple tables and I also need to get maximum "timestamp" on those tables. I will need that to create custom cache control.
tbl_name tbl_surname
id | name id | surname
--------- ------------
0 | John 0 | Doe
1 | Jane 1 | Tully
... ...
I have following query:
SELECT name, surname FROM tbl_name, tbl_surname WHERE tbl_name.id = tbl_surname.id
and I need to add following info to result set:
SELECT MAX(ora_rowscn) FROM (SELECT ora_rowscn FROM tbl_name
UNION ALL
SELECT ora_rowscn FROM tbl_surname);
I was trying to use UNION but I get error - mixing group and not single group data - or something like that, I know why I cannot use the union.
I don't want to split this into 2 calls, because I need the timestamp of the current snapshot I took from DB for my cache management. And between select and the call for MAX the DB could change.
Here is result I want:
John | Doe | 123456
Jane | Tully | 123456
where 123456 is approximate time of last change (insert, update, delete) of tables tbl_name and tbl_surname.
I have read only access to DB, so I cannot create triggers, stored procedures, extra tables etc...
Thanks for any suggestions.
EDIT: The value *ora_rowscn* is assigned per block of rows. So in one table this value can differ per row. I need the maximal value from both (all) tables involved in query.
Try:
SELECT name,
surname,
max(greatest(tbl_name.ora_rowscn, tbl_surname.ora_rowscn)) over () as max_rowscn
FROM tbl_name, tbl_surname
WHERE tbl_name.id = tbl_surname.id
There's no need to aggregate here - just include both ora_rowscn values in your query and take the max:
SELECT
n.name,
n.ora_rowscn as n_ora_rowscn,
s.surname,
s.ora_rowscn as s_ora_rowscn,
greatest(n.ora_rowscn, s.ora_rowscn) as last_ora_rowscn
FROM tbl_name n
join tbl_surname s on n.id = s.id
BTW, I've replaced your old-style joins with ANSI style - better readable, IMHO.
Using Sql Server 2000
I want to find out the duplicate record in the table
Table1
ID Transaction Value
001 020102 10
001 020103 20
001 020102 10 (Duplicate Records)
002 020102 10
002 020103 20
002 020102 10 (Duplicate Records)
...
...
Transaction and value can be repeat for different id's, not for the same id...
Expected Output
Duplicate records are...
ID Transaction Value
001 020102 10
002 020102 10
...
...
How to make a query for view the duplicate records.
Need Query help
You can use
SELECT
ID, Transaction, Value
FROM
Table1
GROUP BY
ID, Transaction, Value
HAVING count(ID) > 1
Select Id, Transaction, Value, Count(id)
from table
group by Id, Transaction, Value
having count(id) > 1
This query will show you the count of times the ID has been repeated with each entry of the Id. If you don't need it you can simply remove the Count(Id) column from the select clause.
Self join (with additional PK or Timestamp or...)
I can see that people've provided solution with grouping but none has provided the self join solution. The only problem is that you'd need some other row descriptor that should be unique for each record. Be it primary key, timestamp or anything else... Suppose that the unique column's name is Uniq this would be the solution:
select distinct ID, [Transaction], Value
from Records r1
join Records r2
on ((r2.ID = r1.ID) and
(r2.[Transaction] = r1.[Transaction]) and
(r2.Value = r1.Value) and
(r2.Uniq != r1.Uniq))
The last join column makes it possible to not join each row to itself but only to other duplicates...
To find out which one works best for you, you can check their execution plan and execute some testing.
You can do this:
SELECT ID, Transaction, Value
FROM Table
GROUP BY ID, Transaction, Value
HAVING COUNT(*) > 1
To delete the duplicates, if you have no primary key then you need to select the distinct values into a separate table, delete everything from this one, then copy the distinct records back:
SELECT ID, Transaction, Value
INTO #tmpDeduped
FROM Table
GROUP BY ID, Transaction, Value
DELETE FROM Table
INSERT Table
SELECT * FROM #tmpDeduped