I have a dimension called Dim_DueAnalysis in a multidimensional cube.
The underlying table looks like this (only a subset of the data is here):
DueAnalysis_Key DueAnalysisID DueAnalysisDays DueAnalysisIntervalWeeks DueAnalysisInterval DueAnalysisDueOverdue
1052 26 Overdue by 26 days Overdue by 3 weeks Overdue by 1-30 days Overdue
1053 27 Overdue by 27 days Overdue by 3 weeks Overdue by 1-30 days Overdue
1054 28 Overdue by 28 days Overdue by 4 weeks Overdue by 1-30 days Overdue
1055 29 Overdue by 29 days Overdue by 4 weeks Overdue by 1-30 days Overdue
1056 30 Overdue by 30 days Overdue by 4 weeks Overdue by 1-30 days Overdue
1057 31 Overdue by 31 days Overdue by 4 weeks Overdue by 31-60 days Overdue
This table looks fine and dandy.
My dimension in the cube has a hierarchy:
Due Analysis Key => Due Analysis Days => Due Analysis Interval Weeks => Due Analysis Interval => Due Analysis Due Overdue
=> Due Analysis Day Number => Due Analysis ID sort
All my Relationship Types are Flexible. But still my dimension looks like this when I browse it in my Analysis Database:
Overdue
- Overdue by 1-30 days
...
- Overdue by 3 weeks
- Overdue by 21 days
...
- Overdue by 27 days
- Overdue by 31-60 days
- Overdue by 4 weeks
- Overdue by 28 days
- Overdue by 29 days
...
As you might have noticed, days 28-30 are in the 31-60 days interval.
What I want is that part of "Overdue by 4 weeks" (days 28-30) is in the Overdue in 1-30 Days hierarchy and not in the Overdue by 31-60 days. But "Overdue by 4 weeks" should also be present in the Overdue by 31-60 days as days 31-34 should be present there.
I thought that it was just a matter of setting my relationship type to "Flexible" instead of "Rigid" but that has not solved my problem.
I am not sure what further information is needed in order to solve this case so please ask about how certain properties etc are.
Ah of course - I had to create another column specifying which week AND day interval my data was in. By using that column I got my hierarchy correct.
Related
I"m dealing with a dataset with 4 week sales data (data will be refreshed every hour) and need to observer for abnormality
I think I'll go with a basic approach, to compare with average numbers and I'm trying to figure out how to best break this down so I can answer some questions below
On average, how many orders received at 9:00 , 15:00 or 16:00 past 30 days
On average, how many orders received at 9:00 every Wednesday (past 4 Wednesdays), at 15:00 every Thursday (past 4 Thursdays),
Not sure how do we go about this (after breaking date/time down to Hour and Weekday columns)
date
order ID
order hour
order weekday
10/07/2022 10:26:12 PM
1111
22
6
10/07/2022 10:27:12 PM
2222
22
6
....
....
....
....
19/07/2022 11:34:19 AM
9998
11
1
19/07/2022 11:34:35 AM
9999
11
1
I would love to get your advice please
Thanks
I've ended up going with a tedious approach.
#get current hour & weekday
now=datetime.datetime.now()
today=datetime.date.today()
current_hour=now.hour
current_weekday=today.weekday()
#create a DF with orders from the same hour & weekday window
same_hour_weekday_df=order_df[(order_df.order_hour==current_hour ) & (order_df.order_weekday==current_weekday) ]
#calculate avg orders generated from the past weeks within the same hour and weekyday timeframe
orders_same_hour_weekday=same_hour_weekday_df['order_created_at'].count()
same_hour_weekday_periods=same_hour_weekday_df['order_week'].nunique()
avg_orders_same_hour_weekday=orders_same_hour_weekday/same_hour_weekday_periods
The below gives me week numbers where week 1 starts on 1/4/2021
date_trunc('week', transaction_date) as week_number
How can I create a week_number where the week starts on January 1st and counts up 7 days for every week thereafter (for every year)?
And round up/down to 52 weeks at the end of the year?
Code attempted:
This doesn't give me the answer, but I'm thinking something like this might work...
ceil(extract(day from transaction_date)/7) as week_number
Expected Output:
transaction_date
week_number
1/1/2020
1
1/8/2020
2
...
...
12/31/2020
52
1/1/2021
1
1/8/2021
2
...
...
12/27/2021
52
12/28/2021
52
12/29/2021
52
12/30/2021
52
12/31/2021
52
1/1/2022
1
Thanks in advance!
A simple way is to use date arithmetic:
select 1 + (transaction_date - date_trunc('year', transaction_date)) / 7 as year_week
The below gives me week numbers where week 1 starts on 1/4/2021
It is the default behaviour and it is defined that way in ISO.
WEEK_OF_YEAR_POLICY
Type Session — Can be set for Account » User » Session
Description
Specifies how the weeks in a given year are computed.
Values
0: The semantics used are equivalent to the ISO semantics, in which a week belongs to a given year if at least 4 days of that week are in that year.
1: January 1 is included in the first week of the year and December 31 is included in the last week of the year.
Default 0 (i.e. ISO-like behavior)
It could be overrriden on multiple levels. The most granular is on the session level:
ALTER SESSION SET WEEK_OF_YEAR_POLICY = 1;
Then you could use the standard code:
SELECT date_trunc('week', transaction_date) as week_number
FROM ...;
I have the below set of data which represents employee sick/absence days over a period (12 months) of time, in a table named Absence:
Day Date DaysSick OccasionsSick Notes
Tuesday 2016-09-27 1 Lisa A working today
Thursday 2016-09-29 1 Lisa sick today Celeste
Thursday 2017-01-05 1 Lisa sick today
I would like to update the OccasionsSick column based upon the instances of being sick. So i would have the following:
Day Date DaysSick OccasionsSick Notes
Tuesday 2016-09-27 1 1 Lisa A working today
Thursday 2016-09-29 1 Lisa sick today Celeste
Thursday 2017-01-05 1 1 Lisa sick today
So, the first two entries are the same period of sick leave, so i need a 1 in the first row, and the last entry is a separate sick period, so a 1 again.
Now, in order to establish a sick period there would be a reference to a roster table containing the below:
Date RosterType
2016-09-27 Sick
2016-09-28 Day Off
2016-09-29 Sick
2016-09-30 Normal
So the 27th and 29th were sick days, but the 28th was a standard day off, which is a likely occurrence, so using consecutive days is not an option. I need to be able to look for sick days until a "normal" RosterType is found, this then breaks the sick period. This 1 then needs to be assigned as per the desired result set.
What is the best way of updating the data here? I have come up with a big blank on this, apart from the logic of determining a sick period.
I am presenting this data in Excel with VBA, so it could also be easier to assign the sick periods in VBA, as opposed to SQL for the raw data
Please check this out.
This assumes that there is an entry in the roster for each day.
Basically I'm just building a period and counting the days in the roster.
If there are normal days in between it counts as a new period.
WITH CTE AS (
SELECT
[day]
,[date]
,LAG(date, 1) over (order by date) datebefore
,[dayssick]
FROM [dbo].[absence]
)
SELECT
*
,CASE WHEN ((SELECT COUNT(1) FROM [dbo].[rostertype] WHERE date < c.date AND date > c.datebefore AND rostertype = 'Normal') > 0
OR c.datebefore IS NULL) THEN 1 ELSE 0 END OccasionsSick
FROM CTE c
I would like a column displaying the fiscal week. Our fiscal year begins in April.
So far I have the below, using datename(ww,DateAndTime) as Week
DateAndTime Week
2015-04-01 22:45 14
2015-06-14 13:22 25
2015-12-02 09:15 49
2016-01-01 07:35 1
I would like the output to show:
DateAndTime Week Fiscal Week
2015-04-01 22:45 14 1
2015-06-14 13:22 25 12
2015-12-02 09:15 49 36
2016-01-01 07:35 1 41
While I don't understand the logic behind the fiscal week (the difference between 1 and 41 is 40, but between 14 and 1 it's 39), maybe I'm missing something or you made a typo.
However, in general you'd do something like this (assuming the difference is 40 weeks):
SELECT week, (week+40)%52 AS fw FROM ...
If the fiscal year starts at a different week every each (say, 13th or 14th week depending on year), you can use the date and time functions, but they may vary between SQL versions. In MySQL you have YEAR(), MONTH(), WEEK(), etc.
For example:
SELECT week, (week+(52-WEEK(CONCAT_WS('-', YEAR(NOW()), '04-01'))))%52 FROM ...
But it might be overkill.
Note: It is possible to count the other way: if you subtract the diff from the week instead of adding, you will need to add 52 if the number is negative. You can do that by adding 52 and then doing modulo (%) 52.
How can I do this?
I'm sure this has been done before. I've checked a couple of projects on github, such as calendar master, but they are all more complicated than what I need.
Oct 2013
S M T W T F S
30 1 2 3 4 5 6
7 8 9 10 11 12 13
14 15 16 17 18 19 20
21 22 23 24 25 26 27
28 29 30 31 1 2 3
Is there a best approach to do this? To layout days in a way that will match the day of the week for that month?
This will be made in a tableview, but I'm not looking for code, just the logic behind it. Unless there's a really good solution out there already.
Thank you!
The logic could be something like this (pseudo code):
get the weekday of the first day of the month in question
determine the number of days of the previous month
fill the first line
with leading final days of previous month, if any
the remaining days for the first week of the month in question
fill all other lines
fill the rest of the last line
with the first days of the following month, if any space left