I have a sql query that creates a label in a cab file for a shopping company. I want to include the amount of packages in an order, some have multiple.
Each returns line in my select query has an I’d and contains a package but I need to count them.
So I have:
Name Email Weight Price ID
Joe B J#.com 10 12.5. 1
Joe B J#.com 10 12.5. 1
Joe C JC#.com 10 14.5. 2
How can I count the ID’s to return a column called pieces and in this example it would be 2 for ID 1 and 1 for ID 2
Thanks
James
enter code here
Select
'WPX' As 'Product Code',
delivery_header.dh_datetime As 'Shipment Date',
'G' As 'Shipment Type',
order_header_detail.ohd_delivery_email As 'Receiver Email Address',
variant_detail.vad_weight As 'Shipment Weight in KG',
(lots of other fields....)
delivery_header.dh_number As 'Shippers Reference',
(SELECT Count(*)
FROM delivery_header
WHERE
dh_number = OU.dh_number
) As 'Number of Pieces',
From delivery_line_item Inner Join
delivery_header On delivery_header.dh_id = delivery_line_item.dli_dh_id
Inner Join
order_line_item On delivery_line_item.dli_oli_id = order_line_item.oli_id
Inner Join
variant_detail On variant_detail.vad_id = order_line_item.oli_vad_id
Inner Join
order_header On order_header.oh_id = order_line_item.oli_oh_id Inner Join
stock_location On stock_location.sl_id = order_line_item.oli_sl_id Inner Join
customer_detail On customer_detail.cd_id = order_header.oh_cd_id Inner Join
order_header_detail On order_header.oh_id = order_header_detail.ohd_oh_id
Left Join
order_header_analysis On order_header.oh_id = order_header_analysis.oha_oh_id
Left Join
order_customer_analysis On order_header.oh_id =
order_customer_analysis.oca_oh_id Left Join
order_delivery_analysis On order_header.oh_id =
order_delivery_analysis.oda_oh_id Left Join
order_line_analysis On order_line_item.oli_id = order_line_analysis.ola_oli_id
Left Join
order_line_product_analysis On order_line_item.oli_id =
order_line_product_analysis.olpa_oli_id Left Join
order_line_variant_analysis On order_line_item.oli_id =
order_line_variant_analysis.olva_oli_id Inner Join
product_detail On product_detail.pd_id = variant_detail.vad_pd_id Inner Join
delivery_method On delivery_method.dm_id = order_header_detail.ohd_dm_id
Inner Join
delivery_method [Delivery Method] On [Delivery Method].dm_id =
order_header_detail.ohd_dm_id Inner Join
currency On currency.c_id = order_header.oh_c_id And currency.c_id =
delivery_method.dm_c_id And currency.c_id = [Delivery Method].dm_c_id
Where
delivery_header.dh_number IN (199364,199363,199362,199360)
Order By delivery_header.dh_number
You can use GROUP BY with COUNT like this:
SELECT ID, COUNT(*) as count FROM tbl GROUP BY ID
What I understood from your question is that, you are looking for output like
Name Email Weight Price ID Pieces
Joe B J#.com 10 12.5. 1 2
Joe B J#.com 10 12.5. 1 2
Joe C JC#.com 10 14.5. 2 1
Using following query you should get the desired output in most of the DBMS.
SELECT NAME,
EMAIL,
WEIGHT,
PRICE,
ID,
(SELECT Count(*)
FROM <YOUR_TABLE_NAME>
WHERE ID= OU.ID) AS Pieces
FROM <YOUR_TABLE_NAME> OU
Similar Query for MS SQL Server can be
SELECT NAME, EMAIL,WEIGHT , Price, ID,CT.Pieces
FROM <YOUR_TABLE_NAME> OU
CROSS APPLY
(
SELECT COUNT(*) AS Pieces FROM <YOUR_TABLE_NAME> IU WHERE OU.ID=IU.ID
)CT
Related
This SQL query needs to be done in ACCESS.
I am trying to do a subquery on the total sales, but I want to link the sale to the province AND to product. The below query will work with one or the other: (po.product_name = allp.all_products) AND (p.province = allp.all_province); -- but it will no take both.
I will be including every month into this query, once I can figure out the subquery on with two criteria.
Select
p.province as [Province],
po.product_name as [Product],
all_price
FROM
(purchase_order po
INNER JOIN person p
on p.person_id = po.person_id)
left join
(
select
po1.product_name AS [all_products],
sum(pp1.price) AS [all_price],
p1.province AS [all_province]
from (purchase_order po1
INNER JOIN product pp1
on po1.product_name = pp1.product_name)
INNER JOIN person p1
on po1.person_id = p1.person_id
group by po1.product_name, pp1.price, p1.province
)
as allp
on (po.product_name = allp.all_products) AND (p.province = allp.all_province);
Make the first select sql into a table by giving it an alias and join table 1 to table 2. I don't have your table structure or data to test it but I think this will lead you down the right path:
select table1.*, table2.*
from
(Select
p.province as [Province],
po.product_name as [Product]
--removed this ,all_price
FROM
(purchase_order po
INNER JOIN person p
on p.person_id = po.person_id) table1
left join
(
select
po1.product_name AS [all_products],
sum(pp1.price) AS [all_price],
p1.province AS [all_province]
from (purchase_order po1
INNER JOIN product pp1
on po1.product_name = pp1.product_name)
INNER JOIN person p1
on po1.person_id = p1.person_id
group by po1.product_name, pp1.price, p1.province --check your group by, I dont think you want pp1.price here if you want to aggregate
) as table2 --changed from allp
on (table1.product = table2.all_products) AND (table1.province = table2.all_province);
I need to have a SQL query to calculate the percentage of courses completed by location which are different SQL tables.
Courses table has a Status = 'C' (Completed status).
select Locations.Name, ( ??? ) as PercentCompleted
from Locations inner join Candidates ON Locations.Id = Candidates.SpecifiedLocation
inner join Courses on Candidates.Id = Courses.CandidateId
Group By Locations.Name
I want the results to be:
Location PercentCompleted
Loc1 10
Loc2 50
Loc3 75
where 10, 50 and 75 are percentages of courses completed per location.
Can this be achieved with a single SQL query?
If I understand correctly, I think you can do:
select l.Name,
avg(case when co.status = 'C' then 100.0 else 0 end) as PercentCompleted
from Locations l inner join
Candidates c
on l.Id = c.SpecifiedLocation inner join
Courses co
on c.Id = co.CandidateId
group by l.name;
try like below
select Locations.Name, (sum(case when Status = 'C' then 1 else 0 end)/(select count(*)
from Candidates c where c.SpecifiedLocation=Locations.Id))*100
as PercentCompleted
from Locations inner join Candidates ON Locations.Id = Candidates.SpecifiedLocation
inner join Courses on Candidates.Id = Courses.CandidateId
Group By Locations.Name
I'm working on another SQL query, trying to group a collection of records while doing a count and joining tables. See below for goal, current query, and attached scripts for building and populating tables.
Show all customers who have checked more books than DVDs. Display
customer name, total book checkouts and total DVD checkouts. Sort
results by customer first name and last name.
SELECT C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME, COUNT(T.TRANSACTION_ID)
FROM customer C
INNER JOIN library_card LC ON C.CUSTOMER_ID = LC.CUSTOMER_ID
INNER JOIN transaction T ON LC.LIBRARY_CARD_ID = T.LIBRARY_CARD_ID
INNER JOIN physical_item P ON T.PHYSICAL_ITEM_ID = P.PHYSICAL_ITEM_ID
INNER JOIN catalog_item CT ON P.CATALOG_ITEM_ID = CT.CATALOG_ITEM_ID
GROUP BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME
ORDER BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME;
Run first: https://drive.google.com/open?id=1PYAZV4KIfZtxP4eQn35zsczySsxDM7ls
Run second: https://drive.google.com/open?id=1pAzWmJqvD3o3n6YJqVUM6TtxDafKGd3f
EDIT
With some help from Mr. Barbaros I've come up with the below query, which is closer. However, this query isn't returning any results for DVDs, which leads me to believe it's a join issue.
SELECT C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME, COUNT(CT1.TYPE) AS BOOK_COUNT, COUNT(CT2.TYPE) AS DVD_COUNT
FROM customer C
INNER JOIN library_card LC ON C.CUSTOMER_ID = LC.CUSTOMER_ID
INNER JOIN transaction T ON LC.LIBRARY_CARD_ID = T.LIBRARY_CARD_ID
INNER JOIN physical_item P ON T.PHYSICAL_ITEM_ID = P.PHYSICAL_ITEM_ID
INNER JOIN catalog_item CT1 ON P.CATALOG_ITEM_ID = CT1.CATALOG_ITEM_ID AND CT1.TYPE = 'BOOK'
LEFT OUTER JOIN catalog_item CT2 ON P.CATALOG_ITEM_ID = CT2.CATALOG_ITEM_ID AND CT2.TYPE = 'DVD'
GROUP BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME, CT1.TYPE, CT2.TYPE
ORDER BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME;
Use "conditional aggregates" (use a case expression inside the aggregate function)
SELECT
C.CUSTOMER_FIRSTNAME
, C.CUSTOMER_LASTNAME
, COUNT( CASE WHEN CT.TYPE = 'BOOK' THEN T.TRANSACTION_ID END ) books
, COUNT( CASE WHEN CT.TYPE = 'DVD' THEN T.TRANSACTION_ID END ) dvds
FROM customer C
INNER JOIN library_card LC ON C.CUSTOMER_ID = LC.CUSTOMER_ID
INNER JOIN transaction T ON LC.LIBRARY_CARD_ID = T.LIBRARY_CARD_ID
INNER JOIN physical_item P ON T.PHYSICAL_ITEM_ID = P.PHYSICAL_ITEM_ID
INNER JOIN catalog_item CT ON P.CATALOG_ITEM_ID = CT.CATALOG_ITEM_ID
GROUP BY
C.CUSTOMER_FIRSTNAME
, C.CUSTOMER_LASTNAME
HAVING
COUNT( CASE WHEN CT.TYPE = 'BOOK' THEN T.TRANSACTION_ID END )
> COUNT( CASE WHEN CT.TYPE = 'DVD' THEN T.TRANSACTION_ID END )
ORDER BY
C.CUSTOMER_FIRSTNAME
, C.CUSTOMER_LASTNAME
;
You can use catalog_item table twice( think of as seperate tables for books and dvds ), and compare by HAVING clause as :
SELECT C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME,
COUNT(CT1.CATALOG_ITEM_ID) as "Book Checkout",
COUNT(CT2.CATALOG_ITEM_ID) as "DVD Checkout"
FROM customer C
INNER JOIN library_card LC ON C.CUSTOMER_ID = LC.CUSTOMER_ID
INNER JOIN transaction T ON LC.LIBRARY_CARD_ID = T.LIBRARY_CARD_ID
INNER JOIN physical_item P ON T.PHYSICAL_ITEM_ID = P.PHYSICAL_ITEM_ID
LEFT JOIN catalog_item CT1 ON P.CATALOG_ITEM_ID = CT1.CATALOG_ITEM_ID AND CT1.TYPE = 'BOOK'
LEFT JOIN catalog_item CT2 ON P.CATALOG_ITEM_ID = CT2.CATALOG_ITEM_ID AND CT1.TYPE = 'DVD'
GROUP BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME
HAVING COUNT(CT1.CATALOG_ITEM_ID) > COUNT(CT2.CATALOG_ITEM_ID)
ORDER BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME;
CUSTOMER_FIRSTNAME CUSTOMER_LASTNAME Book Checkout DVD Checkout
------------------ ----------------- ------------- -------------
Deena Pilgrim 3 1
Emile Cross 5 2
Please try to remove ,CT1.TYPE, CT2.TYPE on your group by clause.
given these relationships, how could you query the following:
The tourists (name and email) that booked at least a pension whose rating is greater than 9, but didn't book any 3 star hotel with a rating less than 9.
Is the following correct?
SELECT Tourists.name, Tourists.email
FROM Tourists
WHERE EXISTS (
SELECT id FROM Bookings
INNER JOIN Tourists ON Bookings.touristId=Tourists.id
INNER JOIN AccomodationEstablishments ON Bookings.accEstId=AccomodationEstablishments.id
INNER JOIN AccomodationTypes ON AccomodationEstablishments.accType=AccomodationTypes.id
WHERE AccomodationTypes.name = 'Pension' AND
AccomodationEstablishments.rating > 9
) AND NOT EXISTS (
SELECT id FROM Bookings
INNER JOIN Tourists ON Bookings.touristId=Tourists.id
INNER JOIN AccomodationEstablishments ON Bookings.accEstId=AccomodationEstablishments.id
INNER JOIN AccomodationTypes ON AccomodationEstablishments.accType=AccomodationTypes.id
WHERE AccomodationTypes.name = 'Hotel' AND
AccomodationEstablishments.noOfStars = 3 AND
AccomodationEstablishments.rating < 9
)
I would do this using aggregation and having:
SELECT t.name, t.email
FROM Bookings b INNER JOIN
Tourists t
ON b.touristId = t.id INNER JOIN
AccomodationEstablishments ae
ON b.accEstId = ae.id INNER JOIN
AccomodationTypes a
ON ae.accType = a.id
GROUP BY t.name, t.email
HAVING SUM(CASE WHEN a.name = 'Pension' AND ae.rating > 9 THEN 1 ELSE 0 END) > 0 AND
SUM(a.name = 'Hotel' AND ae.noOfStars = 3 AND ae.rating < 9 THEN 1 ELSE 0 END)= 0;
Your method also works, but you probably need t.id in the subqueries.
I am running a query that returns the location of a member and the product the member is enrolled in. Each time a member makes a claim with their product, they get a revenue code associated to them. Below is my query that I have now:
SELECT DISTINCT
e.State,
f.Product,
d.MemberID,
b.RevenueCode
FROM
Claims a
INNER JOIN
dw.Revenue b
ON
a.RevenueKey = b.RevenueKey
INNER JOIN
dw.Member d
ON
a.MemberKey = d.MemberKey
INNER JOIN
dw.Product f
ON
a.ProductKey = f.ProductKey
INNER JOIN
dw.State
ON
a.StateKey = f.StateKey
WHERE
b.RevenueCode IN ('0134', '0135')
It returns a set like the following:
State Product MemberID RevenueCode
MN xxx 945-234-245 0134
MN xxx 945-234-245 0135
SD xxx 231-345-235 0134
When a MemberID has both 0134 and 0135 RevenueCodes associated with it, they are considered to be in a special category. How would I modify my above query to count the number of times a MemberID has both RevenueCodes by State and by Product?
SELECT DISTINCT
e.State
,f.Product
,d.MemberID
,b.RevenueCode
,(SELECT 1
FROM Claims AS a1
INNER JOIN dw.Revenue AS b1 ON a1.RevenueKey = b1.RevenueKey
WHERE b1.RevenueCode IN ('0134', '0135')
AND b.revenuekey = b1.revenuekey
AND a.MemberKey = a1.Memberkey
HAVING COUNT(DISTINCT b1.RevenueCode) = 2) AS SpecialCategory
FROM Claims a
INNER JOIN dw.Revenue b ON a.RevenueKey = b.RevenueKey
INNER JOIN dw.Member d ON a.MemberKey = d.MemberKey
INNER JOIN dw.Product f ON a.ProductKey = f.ProductKey
INNER JOIN dw.State ON a.StateKey = f.StateKey
WHERE b.RevenueCode IN ('0134', '0135')
SELECT DISTINCT
e.State,
f.Product,
d.MemberID,
b.RevenueCode.
CASE WHEN EXISTS(
SELECT NULL
FROM Claims a1
JOIN dw.Revenue b1 ON a1.RevenueKey = b1.RevenueKey
JOIN dw.Member d1 ON a1.MemberKey = d1.MemberKey
JOIN dw.Product f1 ON a1.ProductKey = f1.ProductKey
WHERE b1.RevenueCode IN('0134', '0135') AND
d1.MemberID = d.MemberID AND
f1.ProductKey = f.ProductKey AND
f1.StateKey = f.StateKey
) THEN 1 ELSE 0 END As IsSpecialCategory
FROM
...
Figured it out...Simply needed to Count the Distinct RevenueCodes and Group By State, Product, and MemberID