I want to select the same columns from different tables that look the same
(daily tables).
I saw this SELECT from multiple tables with the same structure answer but if I'm going according to this I'm ending up with a huge query.
this code is similar to what I have, according to answer above I need to do the following:
select a, b, c
from (
select a, b, c, d, e from hourly.16
union all
select a, b, c, d, e from hourly.15
)
isn't there an option to do something like:
select a, b, c
from (
select a, b, c, d, e from (hourly.16 union all hourly.15)
)
so I won't end up with huge queries?
#standardSQL
SELECT a, b, c
FROM (
SELECT a, b, c, d, e
FROM `project.hourly.*`
WHERE _TABLE_SUFFIX BETWEEN '15' AND '16'
)
Above is assuming that hourly is your dataset
Related
In CrateDB is there a way to avoid to re-select the same column in nested SELECT statement, to show the value in the results?
e.i. in the following query, is there any way to avoid re-selecting A and B through the nested SELECT? Ideally would be nice to select just once in the first
SELECT
A,
B,
AB,
A * B * AB AS ABAB,
A / AB::DECIMAL AS AAB,
FROM (
SELECT
A,
B,
(A + B) AS AB,
FROM (
SELECT
(SELECT count(*) FROM schema.table_01 WHERE process_state IN ('State_1')) AS A,
(SELECT count(*) FROM schema.table_01 WHERE process_state IN ('State_2')) AS B,
) alias_for_subquery_01
) alias_for_subquery_02
Thanks
I have a table that has millions of records.
So I might have these columns
a, b, c, d
I need to select all the distinct records based on columns a and b.
But I need to select columns a, b, c and d not just a and b.
Can I do this?
edit
Data might be
1,1,frog,green
1,1,frog,brown
2,1,cat,black
2,4,dog,white
so i need;
1,1,frog,green
2,1,cat,black
2,4,dog,white
SQL Server supports Common Table Expression and Window Function. The query below uses ROW_NUMBER() which ranks the record according to group. It sorts by c ASC, d ASC (just play with it).
WITH records
AS
(
SELECT a, b, c, d,
ROW_NUMBER() OVER(PARTITION BY a, b ORDER BY c, d) rn
FROM TableName
)
SELECT a, b, c, d
FROM records
WHERE rn = 1
SQLFiddle Demo
TSQL Ranking Functions
partition by is your man
SELECT a, b, c, d FROM (
SELECT a, b, c, d, ROW_NUMBER() OVER (PARTITION BY a, b ORDER BY a, b) rn
FROM table
) sq
where rn = 1
Please try:
select *
From(
select
row_number() over (partition by a, b order by a, b) RNum,
*
from
YourTable
)x
where RNum=1
Sample
select * From(
select row_number() over (partition by a, b order by a, b) RNum, *
from(
select 1 a, 1 b, 'frog' c, 'green' d union all
select 1 a, 1 b, 'frog' c, 'brown' d union all
select 2 a, 1 b, 'cat' c, 'black' d union all
select 2 a, 4 b, 'dog' c, 'white' d)x
)y
where RNum=1
Is there a way to select the sum of a column and other columns at the same time in SQL?
Example:
SELECT sum(a) as car,b,c FROM toys
How about:
select sum(a) over(), b, c from toy;
or, if it's required:
select sum(a) over(partition by b), b, c from toy;
try add GROUP BY
SELECT sum(a) as car,b,c FROM toys
GROUP BY b, c
Since you do not give much context, I assume you mean one of the following :
SELECT (SELECT SUM(a) FROM Toys) as 'car', b, c FROM Toys;
or
SELECT SUM(a) as Car, b, c FROM Toys GROUP BY b, c;
SELECT b,
c,
(SELECT sum(a) FROM toys) as 'car'
FROM toys
Below code saying error
incorreect syntax near "Main"
INSERT INTO tbl (
'Week',
Main,
a,
b,
c,
d,
e
)
Select 'Week',
Main,
a,
b,
c,
d,
e
FROM tbl_link
INSERT INTO tbl (
'Week',
You should insert actual field name here.
If you field is called Week, just get rid of the quotes:
INSERT INTO tbl (
Week,
Main,
a,
b,
c,
d,
e
)
Select 'Week',
Main,
a,
b,
c,
d,
e
FROM tbl_link
, otherwise substitute the field name.
To clarify the other answers:
SQL INSERT syntax with SELECT statements is as followings:
INSERT INTO Table(Column1Name, Column2Name, ...)
SELECT
Column1Data, Column2Data, ...
FROM Table
The parenthesized list after the table name you intend to update is the ordered list of columns on that table that you intend to populate. It does not represent data that will make its way to the table.
INSERT INTO tbl (
[Week],
Main,
a,
b,
c,
d,
e
)
Select [Week],
Main,
a,
b,
c,
d,
e
FROM tbl_link
there are two possible issues here:
Your column "week" is a reserved word, so use square braces: [week] when you refer to it in any query.
Based on your INSERT attempt, your tables tbl and tbl_link must should both have columns named: [week],Main,a,b,c,d, and e. If not you must rethink what you are trying to do. The first list of columns have to all exist within table tbl, and the second list of columns must all be within table tbl_link. If there are column in tbl that are not in tbl_link, you can just eliminate them from the INSERT:
INSERT INTO tbl (
[Week],
a,
b,
c
)
Select [Week],
a,
b,
c
FROM tbl_link
Suppose i have this table
table (a,b,c,d). Datatypes are not important.
I want to do this
select a as a1,b as b1,c as c1,
(select sum(d) from table where a=a1 and b=b1) as total
from table
group by a,b,c
...but I can't find a way (sqldeveloper keeps complaining with "from clause not found".)
Is there a way? Is it possible?
SELECT a as a1,b as b1,c as c1,
(
SELECT SUM(d)
FROM mytable mi
WHERE mi.a = mo.a
AND mi.b= mo.b
) as total
FROM mytable mo
GROUP BY
a, b, c
It's much more simple and efficient to rewrite it as this:
SELECT a AS a1, B AS b1, c AS c1, SUM(SUM(d)) OVER (PARTITION BY a, b) AS total
FROM mytable
GROUP BY
a, b, c
Note the SUM(SUM(d)) here.
The innermost SUM is the aggregate function. It calculates the SUM(d) a-b-c-wise.
The outermost SUM is the analytic function. It sums the precalculated SUM(d)'s a-b-wise, and returns the value along with each row.
Du you mean something like this?
select a as a1,
b as b1,
c as c1,
sum(sum(d)) OVER (PARTITION BY a, b) AS total
from table
group by a,b,c
you can do it with aliases:
SELECT a AS a1, b AS b1, c AS c1,
(SELECT SUM(d)
FROM test_t t_in
WHERE t_in.a = t.a
AND t_in.b = t.b) AS total
FROM test_t t
GROUP BY a, b, c