Date Quantity Transaction_Type
11-07-2017 200 Sale
15-07-2017 200 Purchase
20-07-2017 500 Sale
10-08-2017 200 Purchase
10-10-2017 200 Purchase
12-10-2017 200 Sale
12-12-2017 200 Sale
20-12-2017 500 Sale
How can i get the below output.
Month Quantity
07 500
10 0
12 700
You seem to want:
select to_char(date, 'YYYY-MM') as yyyymm,
sum(case transaction_type when 'Purchase' then quantity
when 'Sale' then - quantity
end)
from t
group by yyyymm
order by yyyymm;
Note that I included the year in the month column. If you don't want the year, remove it from the to_char() format.
Related
For each of the 12 months, I'm looking to create a field that sums the sales dollars at the account level for the most recent month and the 2nd most recent month based on the current date.
For example, given that today's date is 2022-10-28, 'MostRecentNovember' would sum up sales from November 2021. '2ndMostRecentNovember' would sum up sales from November 2020. Once the current date moves into November 2022, this query would adjust to pull MostRecentNovember sales from 2022 and 2ndMostRecentNovember sales from 2021.
Conversely, given that today's date is 2022-10-28 'MostRecentJune' would sum up sales from June 2022 and '2ndMostRecentJune' would sum up sales from June 2021.
In the end state, each account would have 24 fields: January - December for Most Recent and January - December for 2nd most recent
Below is my attempt at this code, this gets partially there, but it's not getting what I need. I've also tried with a CTE, but that didn't seem to do it either
SELECT NovemberMostRecent_Value =
sum(case when datepart(year,tran_date) = datepart(year, getdate())
AND DATEPART(month, tran_date) = 11 then value else 0 end)
NovemberSecondMostRecent_Value =
sum(case when datepart(year,tran_date) = datepart(year, getdate())-1
AND DATEPART(month, tran_date) = 11 then value else 0 end)
Here's a snippet of the source data table
account_no
tran_date
value
123
2021-11-22
500
123
2021-11-01
500
123
2020-11-20
1500
123
2022-06-03
5000
123
2021-06-04
2000
456
2020-11-03
525
456
2021-11-04
125
A table of desired Results
account_no
NovemberMostRecent
November2ndMostRecent
June MostRecent
June2ndMostRecent
123
1000
1500
5000
2000
456
125
525
0
0
We use dense_rank() by year desc (partitioned by month) and pivot.
select *
from
(
select account_no
,value
,concat(datename(month, tran_date), '_', dense_rank() over(partition by month(tran_date) order by year(tran_date) desc)) as month_rnk
from t
) t
pivot (sum(value) for month_rnk in(June_1, June_2, November_1, November_2)) p
account_no
June_1
June_2
November_1
November_2
123
5000
2000
1000
1500
456
null
null
125
525
Fiddle
I'm trying to produce a report with the total invoice amount for each customer in the month of December :
date
customer
invoice amount
01/12/2021
AB1
40
02/11/2021
AB2
60
12/12/2021
CE6
1000
31/12/2021
RF9
0.5
Could I get any pointers? I'm still fairly new to postgresql.
You should use GROUP BY for your purposes.
SELECT customer, SUM(invoice_amount) as total_invoice_amount
FROM your_table
WHERE EXTRACT(MONTH FROM date) = 12
GROUP BY customer
Table Transaction(Id, DateTime, Debit, Credit)
I want a monthwise sum of Debit and Credit.
What is a good option to retrieve monthwise result?
Sample Output:
Month Id Debit Credit
January 1 200 70
January 2 400 80
February 1 400 90
February 2 300 50
Try this below script with GROUP BY function. I have added YEAR in consideration other wise same month from different year will count as same month.
SELECT YEAR(DateTime),
MONTH(DateTime),
Id,
SUM(Debit) total_debit,
SUM(Credit) total_credit
FROM your_table
GROUP BY YEAR(DateTime), MONTH(DateTime), Id
Apply Group by clause to SQL Query
group by month(DateTime),Year(DateTime)
How to choose customers who have made a large amount of payments in December 2018 if we take into account the exchange rate
I have a table:
Trandate date - transaction date
Transum numeric (20,2) - amount of payment
CurrencyRate numeric (20,2) - currency exchange rate
ID_Client Trandate Transum CurrencyRate Currency
--------------------------------------------------------
1 2018.12.01 100 1 UAH
1 2018.12.02 150 2 USD
2 2018.12.01 200 1 UAH
3 2018.12.01 250 3 EUR
3 2018.12.02 300 1 UAH
3 2018.12.03 350 2 USD
7 2019.01.08 600 1 UAH
but I think that "max" is not at all what I need
SELECT ID_Client, MAX(Transum*CurrencyRate)
FROM `Payment.TotalPayments`
WHERE YEAR(Trandate) = 2018
AND MONTH(Trandate) = 12
I need something this
ID_Client Transum
3 1750
Where 1750 is a "UAH" and 350USD + 300UAH + 250EUR, exchange rate of USD is 2, exchange rate of EUR is 3.
If you're trying to get the sum of transaction amounts by client for the year 2018 and month of December, you could write it like this:
SELECT ID_Client, SUM(Transum*CurrencyRate) as payment_total_converted
FROM `Payment.TotalPayments`
WHERE YEAR(Trandate) = 2018
and MONTH(Trandate) = 12
group by ID_Client
If you want things grouped by each client, year, and month in a given date range, you'd write it like this:
SELECT ID_Client, YEAR(Trandate) as tran_year, MONTH(Trandate) as tran_month,
SUM(Transum*CurrencyRate) as payment_total_converted
FROM `Payment.TotalPayments`
WHERE Trandate between '2018-12-01' and '2019-01-01'
group by ID_Client, YEAR(Trandate), MONTH(Trandate)
I added a column name for your computed column so that the result set is still relational (columns need distinct names).
I'd recommend reading up on the SQL 'group by' clause (https://www.w3schools.com/sql/sql_groupby.asp) and aggregate (https://www.w3schools.com/sql/sql_count_avg_sum.asp, https://www.w3schools.com/sql/sql_min_max.asp) operators.
I think you want sum(). Then you can order by the result:
SELECT ID_Client, SUM(Transum*CurrencyRate) as total
FROM `Payment.TotalPayments`
WHERE Trandate >= '2018-12-01' AND Transdate < '2019-01-01'
GROUP BY ID_Client
ORDER BY total DESC;
Date - Amount
12-nov-2016 200
12-nov-2016 100
13- nov -2016 400
13 -nov-2016 200
result show like-
Date Amount
12- nov-2016 300
13- nov-2016 600
as whole month
select [Date], sum(Amount) as Amount from yourTable group by [Date]