I have a table with a column Document that is FullText Index.
Let say I have this in this table:
| ID | Document |
| 1 | WINTER SUMMER SPRING OTHER |
My requirement is to find rows that contains 'ER'.
For this I am querying like this:
SELECT TOP 100
[FullTextSearch].[Document], [FullTextSearch].[ID]
FROM
[FullTextSearch]
WHERE
CONTAINS(Document, '"*ER*"')
But this is not working.
Please suggest what should be best way to do this using FullTextSearch.
I am expecting id 1 should be returned.
You can user LIKE operator to find the value.
The LIKE operator is used in a WHERE clause to search for a specified pattern in a column.
There are two wildcards used in conjunction with the LIKE operator:
% - The percent sign represents zero, one, or multiple characters
_ - The underscore represents a single character
Syntax,
SELECT column1, column2, ...
FROM table_name
WHERE columnN LIKE pattern;
This query can help to find the result.
SELECT Document,ID FROM FullTextSearch
WHERE Document LIKE '%ER%';
It's a wildcard query...This should work.
SELECT TOP 100
[FullTextSearch].[Document], [FullTextSearch].[ID]
FROM
[FullTextSearch]
WHERE
Document like '%ER%'
========OR=============
SELECT TOP 100
[FullTextSearch].[Document], [FullTextSearch].[ID]
FROM
[FullTextSearch]
WHERE
CONTAINS(Document, '%ER%')
Related
I have a problem where I have two tables. One table constains urls and their information and another groups of urls that should be grouped by a pattern.
Urls table:
------------------------------------------------
| url | files |
| https://myurl1/test/one/es/main.html | 530 |
| https://myurl1/test/one/en/main.html | 530 |
| https://myurl1/test/one/ar/main.html | 530 |
------------------------------------------------
Urls patterns table:
---------------------------------------------
| group | url_pattern |
| group1 | https://myurl1/test/one/(es|en)/%|
| group2 | https://myurl1/test/one/(ar)/% |
---------------------------------------------
I have tried something like this bearing in mind that url_patterns will only have one row per group.
SELECT * FROM urls_table
WHERE url SIMILAR TO (SELECT MAX (url_pattern) FROM url_patterns WHERE group='group1')
LIMIT 10
The main problem here is that it seems that applying SIMILAR TO with a column argument is not working.
Could anyone give me some advices?
Thanks in advance.
You are running into the requirement that regexp patterns are compiled and that SIMILAR TO is a layer on regexp. So what you are trying to do won't work. I believe there are a number of other ways to do this.
I) Change to LIKE pattern matching: LIKE patterns aren't precompiled so can use dynamic patterns. The downside is that they are more limited but I think you can still do what you want. Just change your patterns to be set of pattern columns (if the number of patterns is limited) and test for all the patterns. Unneeded patterns can just be a value that can never match. Definitely a brute force hack.
II) Change to LIKE pattern matching w/ SQL to provide OR behavior: have multiple LIKE patterns in the url_pattern column separated by '|' (for example). Then use split_part to match each sub-pattern - a bit complex and possible slow but works. Like this:
SELECT url
FROM urls_table
LEFT JOIN (SELECT split_part(pattern, '|', part_no::int) as pattern
FROM url_patterns
CROSS JOIN (SELECT row_number() over () as part_no FROM urls_table)
WHERE "group" = 'group1'
)
ON url LIKE pattern
WHERE p.pattern IS NOT NULL;
You will also need to change your pattern strings to use the simpler LIKE format and use '|' for multiple possibilities - Ex: Group1 pattern becomes 'https://myurl1/test/one/es/%|https://myurl1/test/one/en/%'
III) Use some front-end query modification to find the pattern for the group and apply it to query BEFORE it is sent to the compiler. This could be an external tool or a stored procedure on Redshift. Get the pattern in one query and use it to issue the second query.
Do you want exists?
SELECT u.*
FROM urls_table u
WHERE EXISTS (SELECT 1
FROM url_patterns p
WHERE u.url SIMILAR TO p.url_pattern AND
p.group = 'group1'
)
LIMIT 10;
i keep data on table rows as followed like this;
t_course
+------+------------------------------------------+
| sid | courses |
+------+------------------------------------------+
| 1 | cs101.math102.ns202-2.phy104 |
+------+------------------------------------------+
| 2 | cs101.math201.ens202-1.phy104-10.chm105 |
+------+------------------------------------------+
| 3 | cs101.ns202-2.math201.ens202-1.phy104 |
+------+------------------------------------------+
Now, i want to take the sum of courses mentioned ns202 and ens202 in same time. Normally it should only brings record which id is 3, it brings all of the records (because of instr). i have used many methods for this, but it doesn't work. For example;
select count(*) from
t_course
where
instr(courses, 'ns202') > 0
and instr(courses, 'ens202') > 0;
Above code doesn't work properly because it takes ns202 but ens202 contains ns202 in itself.
I tried using regular expressions, i converted all course to row (split) but this has both broke working logic and slowed down.
How can i do this with regular expressions instead of instr according to begin withs (for example ns202%) logic? (Begining with ns202 first or after dot)
You can use regexp_like with word boundaries to get rows which have both ns202 and ens_202. Normally you would use \b for word-boundaries. As Oracle doesn't support it, the alternate is to use (\s|\W) with start ^ and end $ anchors.
\s - space character, \W - non word character. Add more characters as needed, as word-boundaries based on your requirements.
select *
from t_course
where regexp_like(courses,'(^|\s|\W)ns202(\s|\W|$)')
and regexp_like(courses,'(^|\s|\W)ens202(\s|\W|$)')
You will have the same problem with ens202, by the way - what if there is also cens202or tens202?
You can solve your problem with regular expressions. You can also solve it with the LIKE operator:
select <whatever>
from <table or tables>
where (courses like 'ns202%' or courses like '%.ns202%')
and (courses like 'ens202%' or courses like '%.ens202%')
You can test both approaches to see which works best for your data.
So we have a table with a field that contains strings.
These strings can contain wildcards.
For example:
id | name
---+----------------
1 | thomas
2 | san*
3 | *max*
Now I want to select from that table with respect to these wildcards.
For example something like this:
SELECT * FROM table WHERE name = 'sandra'.
That SELECT should fetch the record with ID = 2 from my table.
Note that it would be ok to use % instead of * as the wildcard character in the table.
Any way to achieve this in OpenSQL?
You can use wildcards, just the sign (like Matecki said), is %.
Take a look here:
https://scn.sap.com/thread/1418148
Additionally You could create and use a ranges table in the where clause. If You do not know, what it is, and how it can be done, just tell me. Populate the ranges table like this: OPTION = CP, SIGN = I, LOW = san.
Ok for You?
UPDATE:
I was wrong and changed the answer
I have a set of items in db .Each item has a name and a description.I need to implement a search facility which takes a number of keywords and returns distinct items which have at least one of the keywords matching a word in the name or description.
for example
I have in the db ,three items
1.item1 :
name : magic marker
description: a writing device which makes erasable marks on whiteboard
2.item2:
name: pall mall cigarettes
description: cigarette named after a street in london
3.item3:
name: XPigment Liner
description: for writing and drawing
A search using keyword 'writing' should return magic marker and XPigment Liner
A search using keyword 'mall' should return the second item
I tried using the LIKE keyword and IN keyword separately ,..
For IN keyword to work,the query has to be
SELECT DISTINCT FROM mytable WHERE name IN ('pall mall cigarettes')
but
SELECT DISTINCT FROM mytable WHERE name IN ('mall')
will return 0 rows
I couldn't figure out how to make a query that accommodates both the name and description columns and allows partial word match..
Can somebody help?
update:
I created the table through hibernate and for the description field, used javax.persistence #Lob annotation.Using psql when I examined the table,It is shown
...
id | bigint | not null
description | text |
name | character varying(255) |
...
One of the records in the table is like,
id | description | name
21 | 133414 | magic marker
First of all, this approach won't scale in the large, you'll need a separate index from words to item (like an inverted index).
If your data is not large, you can do
SELECT DISTINCT(name) FROM mytable WHERE name LIKE '%mall%' OR description LIKE '%mall%'
using OR if you have multiple keywords.
This may work as well.
SELECT *
FROM myTable
WHERE CHARINDEX('mall', name) > 0
OR CHARINDEX('mall', description) > 0
I have some table 'TableName' like Id,Name:
1 | something
2 | _something
3 | something like that
4 | some_thing
5 | ...
I want to get all rows from this table where name containes 'some'.
I have 2 ways:
SELECT * FROM TableName WHERE Name like '%some%'
Result is table :
1 | something
2 | _something
3 | something like that
4 | some_thing
But if I use CONTAINS function
SELECT * FROM TableName WHERE CONTAINS(Name,'"*some*"')
I get only
1 | something
3 | something like that
What should I do to make CONTAINS function work properly?
The last time I looked (admittedly SQL Server 2000) CONTAINS didn't support wildcard matching at the beginning of words, only at the end. Also, you might need to check your noise files to see if the "_" character is being ignored.
Also see
How do you get leading wildcard full-text searches to work in SQL Server?
http://doc.ddart.net/mssql/sql70/ca-co_15.htm
If you read this article you will see that * means prefix this means that word must start with this, but like means the word contains key phrase.
Best Regards,
Iordan
Try this:
SELECT * FROM TableName WHERE CONTAINS(Name,'some')