I have two queries. The first gives me a list of BusinessUnitIds along with a count for each:
SELECT [b].[BusinessUnitId], COUNT([b].[BusinessUnitId]) AS bucount
FROM [dbo].[ComponentTeamBusinessUnit] [b]
WHERE [b].[GlobalClientFiscalYearId] = #GlobalClientFiscalYearId
AND [b].[ComponentTeamId] IN (SELECT items FROM [dbo].[fnSplit](#ComponentTeamIds, ','))
GROUP BY [b].[BusinessUnitId])
I want to take the BusinessUnitIds in this result and join them to a second query which will retrieve the Business Unit Name associated with the BusinessUnitIds. Something like the following:
Select [c].Name, [first query result].Count from [dbo].[BusinessUnit] [c]
INNER JOIN [first query result]
WHERE [c].BusinessUnitId = [first query result].BusinessUnitId
Ultimately, what I want is a listing of Business Names, along with a count of each. I haven't been able to figure out how to do this. Can anyone help? To do both queries in a single statement would be tops. Thank you.
Exmaple:
SELECT [b].[BusinessUnitId],A.Name, COUNT([b].[BusinessUnitId]) AS bucount
FROM [dbo].[ComponentTeamBusinessUnit] [b]
LEFT JOIN NameTable as A
ON A.BusinessUnitId = b.BusinessUnitId
WHERE [b].[GlobalClientFiscalYearId] = #GlobalClientFiscalYearId
AND [b].[ComponentTeamId] IN (SELECT items FROM [dbo].[fnSplit](#ComponentTeamIds, ','))
GROUP BY [b].[BusinessUnitId],A.Name
If tables are One to One, will be neat, if one to many, you will see the result like:
id name count
1 A 5
1 B 6
And if you want to group id 1, to get:
id name count
1 A,B 11
That you need to use FOR XML PATH() together with STUFF, or STRING_SPLIT, really depends on your real case.
Related
I have a table named Ticket Numbers, which (for this example) contain the columns:
Ticket_Number
Assigned_Group
Assigned_Group_Sequence_No
Reported_Date
Each ticket number could contain 4 rows, depending on how many times the ticket changed assigned groups. Some of these rows could contain an assigned group of "Desktop Support," but some may not. Here is an example:
Example of raw data
What I am trying to accomplish is to get the an output that contains any ticket numbers that contain 'Desktop Support', but also the assigned group of the max sequence number. Here is what I am trying to accomplish with SQL:
Queried Data
I'm trying to use SQL with the following query but have no clue what I'm doing wrong:
select ih.incident_number,ih.assigned_group, incident_history2.maxseq, incident_history2.assigned_group
from incident_history_public as ih
left join
(
select max(assigned_group_seq_no) maxseq, incident_number, assigned_group
from incident_history_public
group by incident_number, assigned_group
) incident_history2
on ih.incident_number = incident_history2.incident_number
and ih.assigned_group_seq_no = incident_history2.maxseq
where ih.ASSIGNED_GROUP LIKE '%DS%'
Does anyone know what I am doing wrong?
You might want to create a proper alias for incident_history. e.g.
from incident_history as incident_history1
and
on incident_history1.ticket_number = incident_history2.ticket_number
and incident_history1.assigned_group_seq_no = incident_history2.maxseq
In my humble opinion a first error could be that I don't see any column named "incident_history2.assigned_group".
I would try to use common table expression, to get only ticket number that contains "Desktop_support":
WITH desktop as (
SELECT distinct Ticket_Number
FROM incident_history
WHERE Assigned_Group = "Desktop Support"
),
Than an Inner Join of the result with your inner table to get ticket number and maxSeq, so in a second moment you can get also the "MAXGroup":
WITH tmp AS (
SELECT i2.Ticket_Number, i2.maxseq
FROM desktop D inner join
(SELECT Ticket_number, max(assigned_group_seq_no) as maxseq
FROM incident_history
GROUP BY ticket_number) as i2
ON D.Ticket_Number = i2.Ticket_Number
)
SELECT i.Ticket_Number, i.Assigned_Group as MAX_Group, T.maxseq, i.Reported_Date
FROM tmp T inner join incident_history i
ON T.Ticket_Number = i.Ticket_Number and i.assigned_group_seq_no = T.maxseq
I think there are several different method to resolve this question, but I really hope it's helpful for you!
For more information about Common Table Expression: https://www.essentialsql.com/introduction-common-table-expressions-ctes/
I have the following tables below and their schema:
INV
id, product code, name, ucost, tcost, desc, type, qoh
1,123,CPASS 700,1.00,5.00,CPASS 700 Lorem, COM,5
2,456,Shelf 5,2.00,6.00,Shelf 5 KJ, BR,3
GRP
id,type,desc
1,COM,COMPASS
2,BR,SHELF
Currently I have a query like this:
SELECT INV.*,GRP.DESCR AS CATEGORY
FROM INV LEFT JOIN GRP ON INV.TYPE = GRP.TYPE
WHERE INV.QOH = 0
There is no problems with that query.
Right now,I want to know the SUM of the TCOST of every INV record where their QOH is 0.
In this situation, does that I mean all I have to do is to write a separate query like the one below:
SELECT SUM(TCOST)
FROM INV
WHERE QOH = 0
Does it make any sense for me to try and combine those two queries as one ?
First understand that SUM is the aggregate function hence either you can run the Query like
(SELECT SUM(TCOST) FROM INV WHERE QOH=0) as total
This will return Sum of TCOST in INV Table for mentioned condition.
Another approach is finding the Sum based on the some column (e.g. Type)
you could write query like
SELECT Type , SUM(TCOST) FROM INV WHERE QOH=0 GROUP BY type ;
Its not clear on what criteria you want to sum . But I think above two approaches would provide you fare idea .
Mmm, you could maybe use a correlated query, though i'm not sure it's the best approach since I'm not sure I understand what your attempting to do:
SELECT INV.*,
GRP.DESCR AS CATEGORY ,
(SELECT SUM(TCOST) FROM INV WHERE QOH=0) as your_sum
FROM INV LEFT JOIN GRP ON INV.TYPE = GRP.TYPE
WHERE INV.QOH = 0
If you want only one value for the sum(), then your query is fine. If you want a new column with the sum, then use window functions:
SELECT INV.*, GRP.DESCR AS CATEGORY,
SUM(INV.TCOST) OVER () as sum_at_zero
FROM INV LEFT JOIN
GRP
ON INV.TYPE = GRP.TYPE
WHERE INV.QOH = 0;
It does not make sense to combine the queries by adding a row to the first one, because the columns are very different. A SQL result set requires that all rows have the same columns.
Hi I have a redshift table of articles that has a field on it that can contain many accounts. So there is a one to many relationship between articles to accounts.
However I want to create a new view where it lists the partner id's in one column and in another column a count of how many times the partner id appears in the articles table.
I've attempted to do this using regex and created a new redshift view, but am getting weird results where it doesn't always build properly. So one day it will say a partner appears 15 times, then the next 17, then the next 15, when the partner id count hasn't actually changed.
Any help would be greatly appreciated.
SELECT partner_id,
COUNT(DISTINCT id)
FROM (SELECT id,
partner_ids,
SPLIT_PART(partner_ids,',',i) partner_id
FROM positron_articles a
LEFT JOIN util.seq_0_to_500 s
ON s.i < regexp_count (partner_ids,',') + 2
OR s.i = 1
WHERE i > 0
AND regexp_count (partner_ids,',') = 0
ORDER BY id)
GROUP BY 1;
Let's start with some of the more obvious things and see if we can start to glean other information.
Next GROUP BY 1 on your outer query needs to be GROUP BY partner_id.
Next you don't need an order by in your INNER query and the database engine will probably do a better job optimizing performance without it so remove ORDER BY id.
If you want your final results to be ordered then add an ORDER BY partner_id or similar clause after your group by of your OUTER query.
It looks like there are also problems with how you are splitting a partnerid from partnerids but I am not positive about that because I need to understand your view and the data it provides to know how that affects your record count for partnerid.
Next your LEFT JOIN statement on the util.seq_0_to_500 I am pretty sure you can drop off the s.i = 1 as the first condition will satisfy that as well because 2 is greater than 1. However your left join really acts more like an inner join because you then exclude any non matches from positron_articles that don't have a s.i > 0.
Oddly then your entire join and inner query gets kind of discarded because you only want articles that have no commas in their partnerids: regexp_count (partner_ids,',') = 0
I would suggest posting the code for your util.seq_0_to_500 and if you have a partner table let use know about that as well because you can probably get your answer a lot easier with that additional table depending on how regexp_count works. I suspect regex_count(partnerids,partnerid) exampleregex_count('12345,678',1234) will return greater than 0 at which point you have no choice but to split the delimited strings into another table before counting or building a new matching function.
If regex_count only matches exact between commas and you have a partner table your query could be as easy as this:
SELECT
p.partner_id
,COUNT(a.id) AS ArticlesAppearedIn
FROM
positron_articles a
LEFT JOIN PARTNERTABLE p
ON regexp_count(a.partnerids,p.partnerid) > 0
GROUP BY
p.partner_id
I will actually correct myself as I just thought of a way to join a partner table without regexp_count. So if you have a partner table this might work for you. If not you will need to split strings. It basically tests to see if the partnerid is the entire partnerids, at the beginning, in the middle, or at the end of partnerids. If one of those is met then the records is returned.
SELECT
p.partner_id
,COUNT(a.id) AS ArticlesAppearedIn
FROM
PARTNERTABLE p
INNER JOIN positron_articles a
ON
(
CASE
WHEN a.partnerids = CAST(p.partnerid AS VARCHAR(100)) THEN 1
WHEN a.partnerids LIKE p.partnerid + ',%' THEN 1
WHEN a.partnerids LIKE '%,' + p.partnerid + ',%' THEN 1
WHEN a.partnerids LIKE '%,' + p.partnerid THEN 1
ELSE 0
END
) = 1
GROUP BY
p.partner_id
I have one SQL statement as:
SELECT ARTICLES.NEWS_ARTCL_ID, ARTICLES.NEWS_ARTCL_TTL_DES,
ARTICLES.NEWS_ARTCL_CNTNT_T, ARTICLES.NEWS_ARTCL_PUB_DT,
ARTICLES.NEWS_ARTCL_AUTH_NM, ARTICLES.NEWS_ARTCL_URL, ARTICLES.MEDIA_URL,
ARTICLES.ARTCL_SRC_ID, SOURCES.ARTCL_SRC_NM, MEDIA.MEDIA_TYPE_DESCRIP
FROM
RSKLMOBILEB2E.NEWS_ARTICLE ARTICLES,
RSKLMOBILEB2E.MEDIA_TYPE MEDIA,
RSKLMOBILEB2E.ARTICLE_SOURCE SOURCES
WHERE ARTICLES.MEDIA_TYPE_IDENTIF = MEDIA.MEDIA_TYPE_IDENTIF
AND ARTICLES.ARTCL_SRC_ID = SOURCES.ARTCL_SRC_ID
AND ARTICLES.ARTCL_SRC_ID = 1
ORDER BY ARTICLES.NEWS_ARTCL_PUB_DT
Now I need to combine another SQL statement into one which is:
SELECT COUNT ( * )
FROM RSKLMOBILEB2E.NEWS_LIKES LIKES, RSKLMOBILEB2E.NEWS_ARTICLE ARTICLES
WHERE LIKES.NEWS_ARTCL_ID = ARTICLES.NEWS_ARTCL_ID
Basically I have one table which contains articles and I need to include the user likes which is in another table.
Use a subquery to add the likescount in your first query like this:
SELECT ARTICLES.NEWS_ARTCL_ID
,ARTICLES.NEWS_ARTCL_TTL_DES
,ARTICLES.NEWS_ARTCL_CNTNT_T
,ARTICLES.NEWS_ARTCL_PUB_DT
,ARTICLES.NEWS_ARTCL_AUTH_NM
,ARTICLES.NEWS_ARTCL_URL
,ARTICLES.MEDIA_URL
,ARTICLES.ARTCL_SRC_ID
,SOURCES.ARTCL_SRC_NM
,MEDIA.MEDIA_TYPE_DESCRIP
,(
SELECT COUNT(*)
FROM RSKLMOBILEB2E.NEWS_LIKES LIKES
WHERE LIKES.NEWS_ARTCL_ID = ARTICLES.NEWS_ARTCL_ID
) AS LikesCount
FROM RSKLMOBILEB2E.NEWS_ARTICLE ARTICLES
,RSKLMOBILEB2E.MEDIA_TYPE MEDIA
,RSKLMOBILEB2E.ARTICLE_SOURCE SOURCES
WHERE ARTICLES.MEDIA_TYPE_IDENTIF = MEDIA.MEDIA_TYPE_IDENTIF
AND ARTICLES.ARTCL_SRC_ID = SOURCES.ARTCL_SRC_ID
AND ARTICLES.ARTCL_SRC_ID = 1
ORDER BY ARTICLES.NEWS_ARTCL_PUB_DT;
I'm not sure what you are trying to achieve but it seems you want to count all the data from 2 tables. You can edit your query to something like this.
SELECT COUNT (ARTICLES.*) FROM RSKLMOBILEB2E.NEWS_LIKES LIKES
JOIN RSKLMOBILEB2E.NEWS_ARTICLE ARTICLES
ON LIKES.NEWS_ARTCL_ID = ARTICLES.NEWS_ARTCL_ID
I think that solution is in using Analytic Functions. Please have a look on https://oracle-base.com/articles/misc/analytic-functions
Please check following query (keep in mind I have no idea about your table structures). Due to left join records might be duplicated, this is why grouping is added.
SELECT ARTICLES.NEWS_ARTCL_ID, ARTICLES.NEWS_ARTCL_TTL_DES,
ARTICLES.NEWS_ARTCL_CNTNT_T, ARTICLES.NEWS_ARTCL_PUB_DT,
ARTICLES.NEWS_ARTCL_AUTH_NM, ARTICLES.NEWS_ARTCL_URL, ARTICLES.MEDIA_URL,
ARTICLES.ARTCL_SRC_ID, SOURCES.ARTCL_SRC_NM, MEDIA.MEDIA_TYPE_DESCRIP,
count(LIKES.ID) over ( partition by ARTICLES.NEWS_ARTCL_ID ) as num_likes
FROM RSKLMOBILEB2E.NEWS_ARTICLE ARTICLES
join RSKLMOBILEB2E.MEDIA_TYPE MEDIA
on ARTICLES.MEDIA_TYPE_IDENTIF = MEDIA.MEDIA_TYPE_IDENTIF
join RSKLMOBILEB2E.ARTICLE_SOURCE SOURCES
on ARTICLES.ARTCL_SRC_ID = SOURCES.ARTCL_SRC_ID
LEFT JOIN RSKLMOBILEB2E.NEWS_LIKES LIKES
ON LIKES.NEWS_ARTCL_ID = ARTICLES.NEWS_ARTCL_ID
WHERE
ARTICLES.ARTCL_SRC_ID = 1
group by ARTICLES.NEWS_ARTCL_ID, ARTICLES.NEWS_ARTCL_TTL_DES,
ARTICLES.NEWS_ARTCL_CNTNT_T, ARTICLES.NEWS_ARTCL_PUB_DT,
ARTICLES.NEWS_ARTCL_AUTH_NM, ARTICLES.NEWS_ARTCL_URL, ARTICLES.MEDIA_URL,
ARTICLES.ARTCL_SRC_ID, SOURCES.ARTCL_SRC_NM, MEDIA.MEDIA_TYPE_DESCRIP
ORDER BY ARTICLES.NEWS_ARTCL_PUB_DT
I also changed coma-separated list of tables from where condition to joins. I think this is more readable since table join conditions are separated from result filtering in where clause.
Need help on a query using sql server 2005
I am having two tables
code
chargecode
chargeid
orgid
entry
chargeid
itemNo
rate
I need to list all the chargeids in entry table if it contains multiple entries having different chargeids
which got listed in code table having the same charge code.
data :
code
100,1,100
100,2,100
100,3,100
101,11,100
101,12,100
entry
1,x1,1
1,x2,2
2,x3,2
11,x4,1
11,x5,1
using the above data , it query should list chargeids 1 and 2 and not 11.
I got the way to know how many rows in entry satisfies the criteria, but m failing to get the chargeids
select count (distinct chargeId)
from entry where chargeid in (select chargeid from code where chargecode = (SELECT A.chargecode
from code as A join code as B
ON A.chargecode = B.chargeCode and A.chargetype = B.chargetype and A.orgId = B.orgId AND A.CHARGEID = b.CHARGEid
group by A.chargecode,A.orgid
having count(A.chargecode) > 1)
)
First off: I apologise for my completely inaccurate original answer.
The solution to your problem is a self-join. Self-joins are used when you want to select more than one row from the same table. In our case we want to select two charge IDs that have the same charge code:
SELECT DISTINCT c1.chargeid, c2.chargeid FROM code c1
JOIN code c2 ON c1.chargeid != c2.chargeid AND c1.chargecode = c2.chargecode
JOIN entry e1 ON e1.chargeid = c1.chargeid
JOIN entry e2 ON e2.chargeid = c2.chargeid
WHERE c1.chargeid < c2.chargeid
Explanation of this:
First we pick any two charge IDs from 'code'. The DISTINCT avoids duplicates. We make sure they're two different IDs and that they map to the same chargecode.
Then we join on 'entry' (twice) to make sure they both appear in the entry table.
This approach gives (for your example) the pairs (1,2) and (2,1). So we also insist on an ordering; this cuts to result set down to just (1,2), as you described.