How to use INTO and GROUP BY clause together - sql

SELECT cast ( SUBSTRING ( CAST ("ProcessingDate" AS text), 5, 2 ) as integer),
COUNT(*) INTO resultValue1,resultValue2
FROM "DemoLogs"."Project"
WHERE "Addr" = 'Y' AND "ProcessingDate" >= 20160110
GROUP BY 1
ORDER BY 1;
In my database, the ProcessingDate is stored as YYYYMMDD. So, I am extracting its month from it.
This query is working fine if we remove the INTO clause but, I want to store the result to use it further.
So what should be the datatype of the variable resultValue1 and resultValue2 how to store the data(because data will be multiple).
As I am new to PostgreSQL I don't know how to do this can anybody help me out.

Here resultValue1 & resultValue2 will be tables not variables. you can group by using the column names.
Give some column alias names for both columns and group by using them.
You probably want this.
SELECT cast ( SUBSTRING ( cast ("ProcessingDate" as text),5 , 2 ) as
integer) AS resultValue1, COUNT(*) AS resultValue2
INTO <NewTable> --NewTable will be created with those two columns
FROM "DemoLogs"."Project"
-- conditions
Group By 1
-- other contitions/clauses
;
Kindly refer this INTO Documentation.
Hope this helps.

Try this:
SELECT cast ( SUBSTRING ( cast ("ProcessingDate" as text),5 , 2 ) as integer)resultValue1,
COUNT(*)resultValue2
INTO <Table Name>
FROM "DemoLogs"."Project"
WHERE "Addr" = 'Y'
AND "ProcessingDate" >= '20160110'
Group By 1
Order By 1;

Store the above query in the variable and remove that INTO clause from it.
So, query will be now :
query = SELECT cast ( SUBSTRING ( CAST ("ProcessingDate" AS text), 5, 2 ) as
integer),
COUNT(*)
FROM "DemoLogs"."Project"
WHERE "Addr" = 'Y' AND "ProcessingDate" >= 20160110
GROUP BY 1
ORDER BY 1;
Now declare result_data of type record and use in the following manner:
We are looping over result_data because it gives number of rows as output
and I have declared resultset of type text to store the result (as I needed further)
FOR result_data IN EXECUTE query
LOOP
RAISE NOTICE 'result : %',to_json(result_data);
resultset = resultset || to_json(result_data);
END LOOP;

Related

How to combine 2 SELECT statements with different returning data-types in 1 query?

I have tried using UNION ALL query, but it needs the same returning data-type. In the example below name is TEXT while debits is json it leads to an error with UNION ALL-
So how do I return the combined result of name and debits in one query ?
'''
(SELECT
name
FROM
mytable
WHERE grade= % s)
UNION
ALL
(SELECT
debits
FROM
mytable
WHERE balancesheet= % s)
;
'''
psycopg2.errors.DatatypeMismatch: UNION types text and json cannot be matched .
Like you stated correctly, and the error msg instructs: you need compatible types. One way to solve it: convert text to json with to_json():
SELECT to_json(name) AS name_and_debit
FROM mytable
WHERE grade = %s
UNION ALL
SELECT debits
FROM mytable
WHERE balancesheet = %s
;
Or json to text with a plain cast: debits::text. See:
Postgres data type cast

SQL query to sort data while insert , first numbers then alphabets an last symbols

I am getting trouble to write SQL sort Query,
I have table as follows
And I want to sort above data as, First should number and then alphabets and last special symbols like following table.
First numbers should sort like 1,2,3,11,22,33
then Alphabets should sort like a ,b,c,..z
and then symbols,
like following table
I have tried many ways but still not getting correct way, please help me to write query.
You can use a CASE WHEN on the ORDER BY to create some groups:
SELECT *
FROM table_name
ORDER BY
CASE WHEN LEFT(FilterParameterValue, 1) LIKE '[0-9]' OR LEFT(FilterParameterValue, 2) LIKE '-[0-9]' OR LEFT(FilterParameterValue, 2) LIKE '+[0-9]' THEN 1 ELSE 0 END DESC, -- group for numbers
CASE WHEN ISNUMERIC(FilterParameterValue) = 1 THEN CAST(FilterParameterValue AS MONEY) ELSE NULL END ASC, -- order the numeric values
CASE WHEN LEFT(FilterParameterValue, 1) LIKE '[A-Za-z]' THEN 1 ELSE 0 END DESC, -- group for chars from A to Z (capital / non capital)
colName
demo on dbfiddle.uk
Try using regex in order by clause.. For ex
ORDER BY IF(FilterParameterValue RLIKE '^[a-z]', 1, 2), FilterParameterValue
You can try to cast your Column to Numeric Type then ordered
SELECT * FROM table_name ORDER BY TRY_CAST(Column_Name as Type)

Hive - joining two tables to find string that like string in reference table

I stumbled in a case where requires to mask data using keyword from other reference table, illustrated below:
1:
Table A contains thousands of keyword and Table B contains 15 millions ++ row for each day processing..
How can I replace data in table B using keyword in table A in new column?
I tried to use join but join can only match when the string exactly the same
Here is my code
select
sourcetype, hourx,minutex,t1.adn,hostname,t1.appsid,t1.taskid,
product_id,
location,
smsIncoming,
case
when smsIncoming regexp keyword = true then keyword
else 'undef' end smsIncoming_replaced
from(
select ... from ...
)t1
left join
(select adn,keyword,type,mapping_param,mapping_param_json,appsid,taskid,is_api,charlentgh,wordcount,max(datex)
from ( select adn,keyword,type,mapping_param,mapping_param_json,appsid,taskid,is_api,charlentgh,wordcount,datex ,last_update,
max(last_update) over (partition by keyword) as last_modified
from sqm_stg.reflex_service_map ) as sub
where last_update = last_modified
group by adn,keyword,type,mapping_param,mapping_param_json,appsid,taskid,is_api,charlentgh,wordcount)t2
on t1.adn=t2.adn and t1.appsid=t2.appsid and t1.taskid=t2.taskid
Need advice :)
Thanks
Use instr(string str, string substr) function: Returns the position of the first occurrence of substr in str. Returns null if either of the arguments are null and returns 0 if substr could not be found in str. Be aware that this is not zero based. The first character in str has index 1.
case
when instr(smsIncoming,keyword) >0 then keyword
else 'undef'
end smsIncoming_replaced

how to convert the output of sub query into numeric

select rptName
from RptTable
where rpt_id in (
select LEFT(Reports, NULLIF(LEN(Reports)-1,-1))
from repoAccess1
where uid = 'VIKRAM'
)
this is my sql query In which i have use the sub query to access selected field
in this sub query returns
select LEFT(Reports, NULLIF(LEN(Reports)-1,-1))
from repoAccess1
where uid = 'VIKRAM'
Returns
1,2
that means the query should be like
select rptName
from RptTable where rpt_id in (1,2)
But i m getting this error
Msg 8114, Level 16, State 5, Line 1
Error converting data type nvarchar to numeric.
could anyone tell me ow to modify to get exact ans
It's a little hard to tell without the concrete table definitions, but I'm pretty sure you're trying to compare different data types to each other. If this is the case you can make use of the CAST or the CONVERT function, for example:
SELECT
[rptName]
FROM [RptTable]
WHERE [rpt_id] IN
(
SELECT
CONVERT(int, LEFT([Reports], NULLIF(LEN([Reports]) - 1, -1)))
FROM [repoAccess1]
WHERE [uid] = 'VIKRAM'
)
UPDATE: Since you have updated your question: The LEFT function returns results of either varchar or nvarchar data type. So the resulting query would be
SELECT
[rptName]
FROM [RptTable]
WHERE [rpt_id] IN('1', '2')
Please note the apostrophes (is this the correct term?) around the values. Since [rpt_id] seems to be of data type int the values cannot implicitly be converted. And that's where the aforementioned CAST or CONVERT come into play.
If I understand correctly, the subquery is returning a single row with a value of '1,2'. This is not a number, hence the error.
Before continuing, let me emphasize that storing values in comma delimited string is not the SQL-way of doing things. You should have one row per id, with proper types and foreign keys defined.
That said, sometimes we are stuck with other people's really bad design decisions. If this is the case, you can use LIKE:
select rptName
from RptTable r
where exists (select 1
from repoAccess1 a
where a.uid = 'VIKRAM' and
',' + a.reports + ',' like '%,' + cast(r.rpt_id as varchar(255)) + ',%'
);
select rptName
from RptTable
where rpt_id in (
select CAST(LEFT(Reports, NULLIF(LEN(Reports)-1,-1)) AS INT) as Val
from repoAccess1
where uid = 'VIKRAM'
)
Your query would work fine when (LEFT(Reports, NULLIF(LEN(Reports)-1,-1)) ) returns either 1 or 2 since SQL Server implicitly converts the varchar value to numeric.
It seems there might be a data issue. One of the data returned by LEFT function is non-numeric. In order to find that particular record you can use isnumeric function. Try like this,
SELECT rptName
FROM RptTable
WHERE rpt_id IN (
SELECT LEFT(Reports, NULLIF(LEN(Reports) - 1, - 1))
FROM repoAccess1
WHERE uid = 'VIKRAM'
AND ISNUMERIC(LEFT(Reports, NULLIF(LEN(Reports) - 1, - 1))) = 1
)

SQL select max value of varchar

I have a varchar column that contains data like '0 03-03-14', '1 04-03-14' and so on.
I need to select the maximum one, in that case '1 04-03-14'.
My problem is that I can have the '1' (the max value) but how do I have to do if I also want the date ?
For now, I have this :
SELECT MAX(TO_NUMBER(SUBSTR(revision, 1, INSTR(revision, ' ')-1)))
FROM table
WHERE name = 'aname'
AND t_name = 'tname'
GROUP BY revision
Does anyone have an idea ?
Thanks
I assume you want something like max(version, date version), try this:
Select * from (
Select * from (
SELECT
TO_NUMBER(SUBSTR(revision, 1, INSTR(revision, ' ')-1)) as rev
, TO_DATE(SUBSTR(revision, 1, INSTR(revision, ' ')+1),'DD-MM-YY') as revDate
FROM table
WHERE name = 'aname'
AND t_name = 'tname'
) extracted
order by extracted.revDate, extracted.rev desc
) where rownum = 1
Do you mean this?
select max(revision)
from table
where name = 'aname' and t_name = 'tname';
It seems strange to put the revision number and date in one column. Is that really your data format? If not, modify your question with the actual data format.
Regarding your answers, I think the best solution would be to split those two parts :)