I want to select users list who is status is disabled for all application in username(ur_username table and that users should be active in Person Table(ur_person).
I tried with the following query :
select distinct E.PERSON_ID , E.DOMAIN_ID,e.first_name,e.last_name,e.type,E.username, E.SYSTEM_name from
(SELECT distinct p.person_id,p.domain_id,p.first_name,p.last_name,p.type,u.username, U.STATUS, U.SYSTEM_ID,s.system_name from ur_username u join
ur_username_person up on u.username_id=up.username_id
join ur_person p on up.person_id=p.person_id join ur_system s on u.system_id=s.system_id
WHERE p.status='ACTIVE') E WHERE E.person_id IN
( select distinct P.PERSON_ID from ur_username u join ur_username_person up on u.username_id=up.username_id
join ur_person p on up.person_id=p.person_id
where u.status='DISABLED')
I need to get the person list who is status is Disabled in all system in username Table as below image:
But instead I am getting person who is disable in one system but active in some other systems also:
You can get the person_ids using aggregation and having:
select p.person_id
from ur_username u join
ur_username_person up
on u.username_id = up.username_id join
ur_person p join
ur_system s
on u.system_id = s.system_id
where p.status = 'ACTIVE'
group by p.person_id
having max(u.status) = min(u.status) and max(u.status) ='DISABLED';
You specify that you want the persons, so this seems to answer your question. You can easily enhance this query to return more columns.
Related
I have the next query:
SELECT c.name as clientName, p.id as projectId, p.name as projectName, p.rate, u.name as userName, sum(w.duration) as workedHours
FROM Project p, User u, Worklog w, Client c
WHERE w.user_id = u.id AND w.project_id = p.id AND p.client_id = c.id
GROUP BY p.id, u.id
that returns the projects, clients, hourly rate and worked hours.
How should be changed to return also the projects where workedHours is equal with 0?
Because this query returns just the records where workedHours is not 0.
Thank you for your time.
The problem is that no row in worklog can be joined, and that your condition in the WHERE clause removes any row without worklog associated.
Solution 1 : Using a LEFT JOIN
Using a left join instead would solve your problem.
SELECT c.name as clientName, p.id as projectId, p.name as projectName, p.rate, u.name as userName, coalesce(sum(w.duration), 0) as workedHours
FROM Project p, User u, Client c
LEFT JOIN Worklog w ON w.project_id = p.id AND w.user_id = u.id
WHERE p.client_id = c.id
GROUP BY p.id, u.id
By the way your query is suspicious in other aspects. For example c.name is in the SELECT clause but not in the GROUP BY clause. I take it that you use MySQL which is the only RDBMS I'm aware of which allows such queries. You maybe should consider adding the retrieved columns in the GROUP BY clause.
Solution 2 : Using only ANSI JOINs
As underscore_d points out, you may want to avoid old-style joins completely, and preferable use the following query :
SELECT
c.name as clientName,
p.id as projectId,
p.name as projectName,
p.rate,
u.name as userName,
coalesce(sum(w.duration), 0) as workedHours
FROM Project p
CROSS JOIN User u
INNER JOIN Client c ON p.client_id = c.id
LEFT JOIN Worklog w ON w.project_id = p.id AND w.user_id = u.id
GROUP BY c.name, p.id, p.name, p.rate, u.id, u.name
Solution 3 - Using a subquery
Another solution is to use a subquery, which would allow you to remove the GROUP BY clause completely and get a more manageable query if you ever need to retrieve more information. I personally don't like long lists of columns in a GROUP BY clause.
SELECT
c.name as clientName,
p.id as projectId,
p.name as projectName,
p.rate,
u.name as userName,
(SELECT SUM(duration) FROM Worklog WHERE project_id = c.id AND user_id = u.id) as workedHours
FROM Project p
CROSS JOIN User u
INNER JOIN Client c ON p.client_id = p.id
You should use standard ANSI joins and use LEFT JOIN on worklog table and ultimately you have to use LEFT JOIN on the user table as follows:
SELECT C.NAME AS CLIENTNAME,
P.ID AS PROJECTID,
P.NAME AS PROJECTNAME,
P.RATE,
U.NAME AS USERNAME,
SUM(W.DURATION) AS WORKEDHOURS
FROM PROJECT P
JOIN CLIENT C
ON P.CLIENT_ID = C.ID
LEFT JOIN WORKLOG W
ON W.PROJECT_ID = P.ID
LEFT JOIN USER U
ON W.USER_ID = U.ID
GROUP BY P.ID,
U.ID;
I have 3 tables
STUDENTS
FEES_PAID
SUSPENDED
I want to get the details of the students who have paid the fees but not from SUSPENDED.
SELECT
ID
FROM
STUDENTS s
LEFT JOIN
SUSPENDED p ON s.ID = p.ID
INNER JOIN
FEES_PAID f ON f.ID = s.ID
WHERE
s.ID IS NULL
Unfortunately this does not work. Can any one suggest an efficient query?
Thanks in advance
You need to check if the second table is missing from the LEFT JOIN. So, you need to look at a column in that table. Change the WHERE to:
WHERE p.ID IS NULL
Alternatively, use NOT EXISTS:
SELECT s.ID
FROM STUDENTS s INNER JOIN
FEES_PAID f
ON f.ID = s.ID
WHERE NOT EXISTS (SELECT 1 FROM SUSPENDED p WHERE s.ID = p.ID);
Note that for both these queries, you will need to qualify the ID in the SELECT to specify the table where it comes from.
This should work:
SELECT
s.ID
FROM
STUDENTS s
LEFT JOIN
SUSPENDED p
ON s.ID=p.ID
INNER JOIN
FEES_PAID f
ON f.ID= s.ID
WHERE
p.ID IS NULL
I have written a SQL query to retrieve required data and it looks like given below:
SELECT distinct p.person_id,p.birth_date,p.gender_code,
wm_concat(distinct r.race_code) as race_code,p.hispanic_latino_code,
c.clinically_diagnosed_code,
wm_concat(distinct c.characteristic_code) as chara_codes,
p.prev_adopted_code,p.age_adopted,
FIRST_VALUE(pe.removed_date) OVER (ORDER BY pe.removed_date),
count(pe.removed_date) as removal_count,
LAST_VALUE(pe.discharge_date) OVER (ORDER BY pe.discharge_date),
LAST_VALUE(pe.removed_date) OVER (ORDER BY pe.removed_date) as latest_removal_date,pe.created_date,
pe.removal_circumstance_code,wm_concat(distinct rr.removal_reason_code) as removal_reasons,
ps.placement_type_code,ps.icpc_placement_flag,pe.caretaker_structure_code
FROM PERSON p left outer join RACE r on p.person_id = r.person_id
left outer join CHARACTERISTIC c on c.person_id = p.person_id
left outer join PLACEMENT_EPISODE pe on p.person_id = pe.child_id
left outer join PLACEMENT_SETTING ps on p.person_id = ps.child_id
left outer join REMOVAL_REASON rr on pe.placement_episode_id = rr.placement_episode_id
GROUP BY p.person_id,p.birth_date,p.gender_code,p.hispanic_latino_code,
c.clinically_diagnosed_code,p.prev_adopted_code,p.age_adopted,pe.removed_date,
pe.discharge_date,pe.removed_date,pe.created_date,pe.removal_circumstance_code,
ps.placement_type_code,ps.icpc_placement_flag,pe.caretaker_structure_code
ORDER BY p.person_id
In the above mentioned query, I have already selected birth date for a person. Now again in select clause I want to select birth_date for persons with following condition:
condition 1: p.person_id = pe.primary_caretaker_id
condition 2: p.person_id = pe.secondary_caretaker_id
Can someone tell me the way to select these fields(birth_date based on two different conditions) in the existing query?
Birth_date has been already selected once for individual person. Now I want to retrieve birth_date for primary_caretaker and secondary_caretaker.
You will need to join to the PERSON table twice more:
SELECT distinct p.person_id,p.birth_date,p.gender_code,
wm_concat(distinct r.race_code) as race_code,p.hispanic_latino_code,
c.clinically_diagnosed_code,
wm_concat(distinct c.characteristic_code) as chara_codes,
p.prev_adopted_code,p.age_adopted,
FIRST_VALUE(pe.removed_date) OVER (ORDER BY pe.removed_date),
count(pe.removed_date) as removal_count,
LAST_VALUE(pe.discharge_date) OVER (ORDER BY pe.discharge_date),
LAST_VALUE(pe.removed_date) OVER (ORDER BY pe.removed_date) as latest_removal_date,
pe.created_date,
pe.removal_circumstance_code,wm_concat(distinct rr.removal_reason_code) as removal_reasons,
ps.placement_type_code,ps.icpc_placement_flag,pe.caretaker_structure_code,
primCare.birth_date as primary_carer_birth_date,
secCare.birth_date as secondary_carer_birth_date,
FROM PERSON p left outer join RACE r on p.person_id = r.person_id
left outer join PERSON primCare on primCare.person_id = pe.primary_caretaker_id
left outer join PERSON secCare on secCare.person_id = pe.secondary_caretaker_id
left outer join CHARACTERISTIC c on c.person_id = p.person_id
left outer join PLACEMENT_EPISODE pe on p.person_id = pe.child_id
left outer join PLACEMENT_SETTING ps on p.person_id = ps.child_id
left outer join REMOVAL_REASON rr on pe.placement_episode_id = rr.placement_episode_id
GROUP BY p.person_id,p.birth_date,p.gender_code,p.hispanic_latino_code,
c.clinically_diagnosed_code,p.prev_adopted_code,p.age_adopted,pe.removed_date,
pe.discharge_date,pe.removed_date,pe.created_date,pe.removal_circumstance_code,
ps.placement_type_code,ps.icpc_placement_flag,pe.caretaker_structure_code, primCare.birth_date, secCare.birth_date
ORDER BY p.person_id
I do realise that problem I am facing is not a rocket science but still, I did not find any information about fixing this.
I have multiple tables in my database (PSQL) I want to create a select query to make a reporting function for my app.
Here is my query:
select
s.id, s.name, st.name, p.firstname || ' ' || p.lastname,
f.name, f.store_date, bdt.name, bd.comment
from
system s, systemstatus st, role w, person p, file f,
documenttype bdt, document bd
where
w.system_id = s.id and
p.id = w.person_id and
st.id = s.status_id and
bd.system_id = s.id and
bd.file_id = f.id and
bd.type_id = bdt.id and
bd.role_id = w.id;
Query works I get 300 rows fully filled with values I am searching for. Problem is that I have about 1000 rows in System Table. It is possible that there is no Person or Document which could be linked with particular System.
I would like to see all rows that are in my System table (I mean about 1000), and when I can't link Person or Document with System I want the field to be null ( now it is not shown at all)
Main part of the answer is - you need left outer join.
Additional parts of the answer - use ANSI join syntax and format your queries:
select
s.id, s.name, st.name, p.firstname || ' ' || p.lastname, f.name,
f.store_date, bdt.name, bd.comment
from system as s
left outer join systemstatus as st on st.id= s.status_id
left outer join role as w on w.system_id = s.id
left outer join person as p on p.id = w.person_id
left outer join document as bd on bd.system_id = s.id and bd.role_id = w.id
left outer join documenttype as bdt on bdt.id = bd.type_id
left outer join file as f on f.id = bd.file_id
Always remember that somebody will read your code someday (may be it will be future you :) ) - so readability counts!
You are connecting your tables in query via "where" clause, which is equal to inner join. Instead you should left join Person and Document tables to System table, e.g.:
select *
from system s
left join role w on w.system_id = s.id
left join person p on p.id = w.person_id
I need to go to two tables to get the appropriate info
exp_member_groups
-group_id
-group_title
exp_members
-member_id
-group_id
I have the appropriate member_id
So I need to check the members table, get the group_id, then go to the groups table and match up the group_id and get the group_title from that.
INNER JOIN:
SELECT exp_member_groups.group_title
FROM exp_members
INNER JOIN exp_member_groups ON exp_members.group_id = exp_member_groups.group_id
WHERE exp_members.member_id = #memberId
SELECT g.group_title
FROM exp_members m
JOIN exp_member_groups g ON m.group_id = g.group_id
WHERE m.member_id = #YourMemberId
If there is always a matching group, or you only want rows where it is, then it would be an INNER JOIN:
SELECT g.group_title
FROM exp_members m
INNER JOIN
exp_member_groups g
ON m.group_id = g.group_id
WHERE m.member_id = #member_id
If you want rows even where group_id doesn't match, then it is a LEFT JOIN - replace INNER JOIN with LEFT JOIN in the above.