I want to rename the field. Code is here
[['name'], 'unique', 'message' => 'This Make already exists'],
output
[
{
"field": "name",
"message": "This Make already exists"
}
]
how i change field? Result
"field" : "make"
Using fields(). In your model override fields() function as follows:
public function fields()
{
return['make'=>'name'];
}
This will change the name of the field from name to make but your name field will be the only field returned. You can do all the tricks you want to append to the fields returned, or change them using this function though. To know more about fields check: http://www.yiiframework.com/doc-2.0/yii-base-model.html#fields()-detail
Related
I'm attempting to update a document using an index in my FaunaDB collection using FQL.
Update(
Match(
Index('users_by_id'),
'user-1'
),
{
data: {
name: 'John'
}
}
)
This query gives me the following error:
Error: [
{
"position": [
"update"
],
"code": "invalid argument",
"description": "Ref expected, Set provided."
}
]
How can I update the document using the index users_by_id?
Match returns a set reference, not a document reference, because there could be zero or more matching documents.
If you are certain that there is a single document that matches, you can use Get. When you call Get with a set reference (instead of a document reference), the first item of the set is retrieved. Since Update requires a document reference, you can then use Select to retrieve the fetched document's reference.
For example:
Update(
Select(
"ref",
Get(Match(Index('users_by_id'), 'user-1'))
),
{
data: {
name: 'John'
}
}
)
If you have more than one match, you should use Paginate to "realize" the set into an array of matching documents, and then Map over the array to perform a bulk update:
Map(
Paginate(
Match(Index('users_by_id'), 'user-1')
),
Lambda(
"ref",
Update(
Var("ref"),
{
data: {
name: "John",
}
}
)
)
)
Note: For this to work, your index has to have an empty values definition, or it must explicitly define the ref field as the one and only value. If your index returns multiple fields, the Lambda function has to be updated to accept the same number of parameters as are defined in your index's values definition.
New to Karate, and JSON, for that matter, but I've got a variable like:
response {
entries {
products [
{
names [
"Peter Parker",
"Tony Stark",
"Captain America"
]
},
{
names [
"Thomas Tinker",
"Jimmy Johnson",
"Mama Martha"
]
}
]
}
}
match each response.entries.products[*].names returns a list like:
["Peter Parker","Tony Stark","Captain America","Thomas Tinker","Jimmy Johnson","Mama Martha"]
But I'd like to assign that output to a variable, such as:
* def variable = response.entries.products[*].names
that would hold a similar value. When I use the above line, I get the following error:
Expected an operand but found *
Is it possible to achieve that, or something similar? If so, how?
Thanks!
Yes, there is syntax for that:
* def variable = $response.entries.products[*].names
Read the docs: https://github.com/intuit/karate#get
I am not sure if I am asking the correct question but I assume this is just a basic mongodb question.
I currently have this:
{
"_id" : ObjectId("57af98d4d71c4efff5304335"),
"fullname" : "test",
"username" : "test",
"email" : "test#gmail.com",
"password" : "$2a$10$Wl29i6FemBrnOKq/ZErSguxlfvqoayZQkaEDirkmDl5O3GDEQjOV2"
}
and I would like to add an exercise object like this:
{
"_id" : ObjectId("57af98d4d71c4efff5304335"),
"fullname" : "test",
"username" : "test",
"email" : "test#gmail.com",
"password" : "$2a$10$Wl29i6FemBrnOKq/ZErSguxlfvqoayZQkaEDirkmDl5O3GDEQjOV2",
"exercises": {
"benchpress",
"rows",
"curls",
}
I am just unsure how to create exercises with the object without using $push which just opens up an array. I don't want an array, I want an object.
Any help would be greatly appreciated it.
An object is a key-value pair. In your representation of the second document, you have a nested document exercises as a key and its value as an object containing only strings. Don't you see something strange there? An object without keys?
It should probably be an array of strings. Note that an array is indeed an object where the key is the numeric index starting from 0 and the value is the string in that position.
(You have an additional comma and a missing curly-brace. Lets fix that.)
This is the document we wish to see after updating the document.
{
"_id" : ObjectId("57af98d4d71c4efff5304335"),
"fullname" : "test",
"username" : "test",
"email" : "test#gmail.com",
"password" : "$2a$10$Wl29i6FemBrnOKq/ZErSguxlfvqoayZQkaEDirkmDl5O3GDEQjOV2",
"exercises": [
"benchpress",
"rows",
"curls"
]
}
Now, back to your question. How can we update the existing document with the exercises document? Its pretty simple. Mongodb has a 'update' method which exactly does that. Since we don't want to replace the entire document and just add additional fields, we should use $set to update specific fields. Fire up the mongo shell and switch to your database using use db-name. Then execute the following command. I assume you have an existing document with id ObjectId("57af98d4d71c4efff5304335"). Note that ObjectId is a BSON datatype.
db.scratch.update({ "_id" : ObjectId("57af98d4d71c4efff5304335") }, { $set: {"exercises": ["benchpress", "rows", "curls"] } })
This will update the document as
{
"_id" : ObjectId("57af98d4d71c4efff5304335"),
"fullname" : "test",
"username" : "test",
"email" : "test#gmail.com",
"password" : "$2a$10$Wl29i6FemBrnOKq/ZErSguxlfvqoayZQkaEDirkmDl5O3GDEQjOV2",
"exercises" : [
"benchpress",
"rows",
"curls"
]
}
Here scratch refers to the collection name. The update method takes 3 parameters.
Query to find the document to update
The Update parameter(document to update). You can either replace the whole document or just specific parts of the document(using $set).
An optional object which can tell Mongodb to insert the record if the document doesn't exist(upsert) or update multiple documents that match the criteria(multiple).
EXTRA
Warning: If you execute the following in the mongo shell,
db.scratch.update({ "_id" : ObjectId("57af98d4d71c4efff5304335") }, {"exercises": ["benchpress", "rows", "curls"] })
the entire document would be replaced except the _id field. So, the record would be something like this:
{
"_id" : ObjectId("57af98d4d71c4efff5304335"),
"exercises" : [
"benchpress",
"rows",
"curls"
]
}
You should only do this when you are aware of the consequence.
Hope this helps.
For more, see https://docs.mongodb.com/manual/reference/method/db.collection.update/
I have a javastack trace in message field and an array field having list of string like ["NullPointer", "TimeOutException"].
I want a conditional check on message field such that it checks if message contains any of from list of string.
Any idea how to get this?
It's a bit of a hack, but check out the translate{} filter. You could define your fields to translate to "1" (true, etc), with a default of "0". Then check that value to determine if it was in the set.
EDIT: for those who don't like to fish:
filter {
translate {
field => myInputField
dictionary => [
"NullPointer", 1,
"TimeOutException", 1
]
fallback => 0
destination => myOutputField
}
if [myOutputField] == "1" {
# it contained one of the items in the dictionary
...
}
else {
# it did not contain one of the items in the dictionary
...
}
}
I've got a Rails 3.0.9 project using the latest version of MongoDB and Mongoid 2.2.
I imported a CSV with an "id" field into a MongoDB collection named College, resulting in a collection like so:
{ "_id" : ObjectID("abc123"), "id" : ######, ... }
Observations:
The show action results in a URL utilizing the ObjectID
Displaying 'college.id' in index.html.erb displays the ObjectID
Questions:
How do I use the original "id" field as the parameter
Is "id" reserved by MongoDB, meaning I need to rename the "id" field in the
College collection (perhaps to "code") - if so, how?
Thanks!
Update
Answer:
db.colleges.update( { "name" : { $exists : true } } , { $rename : { "id" : "code" } }, false, true )
I used "name" since that was a field I could check for the existence.
_id is a reserved and required property in MongoDB - I think mongoid is mapping id to _id since that makes sense. There might be a way to access the id property through mongoid but I think you are much better off renaming the id column to something else to avoid confusion in the future.
{ $rename : { old_field_name : new_field_name } }
will rename the field name in a document (mongo 1.7.2+).
so
db.college.update({ "_id" : { $exists : true }}, { $rename : { 'id' : 'code' } }, false, true);
should update every record in that collection and rename the id field to code.
(obviously test this before running in any important data)