I am trying to write CSS using two attributes the element looks like this:
<div class="bet-tab-left bet-tab tab-event bet-tab-half bet-tab-last-tab active" data-tab-index="1">
How do I write CSS element locator by.css("x") for this?
As per the HTML you have shared, you can use the class attributes to identify the WebElement as follows :
driver.findElement(By.cssSelector("div.bet-tab-left.bet-tab.tab-event.bet-tab-half.bet-tab-last-tab.active"));
Still if you want to use both the class and data-tab-index attributes, you can use:
driver.findElement(By.cssSelector("div[class='bet-tab-left bet-tab tab-event bet-tab-half bet-tab-last-tab active'][data-tab-index='1']"));
Try like this using data-tab-index="1":
driver.findElement(By.cssSelector("div[data-tab-index=1]"));
Related
Quick one, i am trying to avoid using xpath and using css selectors due to performance issues xpath can have so i would like to know the right approach of locating for example "A" in the list
<div class="input-search-suggests" xpath="1">
<div class="input-search-suggests-item">A</div>
<div class="input-search-suggests-item">B</div>
<div class="input-search-suggests-item">C</div>
</div>
Currently i am locating A using xpath / span but it would be indeed sufficient locating all elements and then grabbing A from the list that have same class which is "input-search-suggests-item"
#FindBy(xpath = "//span[contains(text(),'A')]")
CSS_SELECTOR does not have support for direct text what xpath has.
What this means is, for the below xpath
xpath = "//span[contains(text(),'A')]"
based on text A you can not write a css selector.
Instead to locate A using css selector, you can do :
div.input-search-suggests > div.input-search-suggests-item
In Selenium something like this :
#FindBy(cssSelector= "div.input-search-suggests > div.input-search-suggests-item")
Even though it will have 3 matching nodes, but findElement will take the first web element.
Also you may wanna look at nth-child(n)
div.input-search-suggests > nth-child(1)
to make use of index to locate A, B, C
Here is the Reference Link
I am trying to get the xpath of a svg that has an attribute <use href= "#icon-map">
So far the path //*[local-name()='svg']/*[local-name()='use'] works, but it finds 84 entries.
How can I modify the xpath in order to select only the use that has the href as "#icon-map"?
You can use this:
//*[local-name()='svg'][use[#href="#icon-map"]]
or
//*[local-name()='svg'][*[local-name()='use'][#href="#icon-map"]]
See example.
If you have more results than you expect then you should use more specific paths to the element or take your query into (..) and add number of an item into [..] like :
(//*[local-name()='svg'][use[#href="#icon-map"]])[2]
If use is an attribute then you could do this :
//*[name()='svg']//*[#use and #href='#icon-map']
Also the above solution assumes that #icon-map is unique in HTML DOM
Consider this xpath which should always return one element.
//div[#id='MyDiv123']/div[contains(#class, 'super')]
Assume that we won't add anymore divs whose class is super. Given that info, I don't think that it is a good idea to use /div[contains(#class, 'super')]because the xpath will break if div[contains(#class, 'super')] is placed inside another element.
Shouldn't we be using //div[contains(#class, 'super')] instead ?
I don't like using XPaths for locators that can be written as a CSS selector. I think it's much simpler as
#MyDiv123 > div.super
or just
div.super
if it's unique on the page.
XPath contains() is a string match. All the elements below will match your XPath locator but none of them will match the CSS selectors above.
<div class="super-duper" ...>
<div class="superior" ...>
<div class="abcsuperdef" ...>
... you get the idea...
There is no defined Best Practices while writing xpaths. It all boils down to how effective xpath can be written.
I don't see any issue with the xpath as :
//div[#id='MyDiv123']/div[contains(#class, 'super')]
Of-coarse there ca be some improvements as follows :
As an enduser you won't be sure how the class attribute super impacts the HTML or which elements have this attribute. So in that case to identify the WebElement uniquely it would be wise to include the ancestor <div> tag with id as MyDiv123.
But it doesn't looks like the classname super can be dynamic. Hence you can avoid the keyword contains within the xpath and rewrite it as :
//div[#id='MyDiv123']/div[#class='super']
I want to select a checkbox with the HTML code shown below using the attribute bayid:
<input type="checkbox" devid="bay" bayid="10" checked="">
I could get the XPath information - "//*[#id="svbSelectEnc1"]/table/tbody/tr[7]/td[3]/input", but I want to use the bayid for selecting as there are lot of checkboxes in the form of a table and only specific checkboxes have to be selected that are read from the config file.
You can achieve it by using CSS Selector or XPath as shown below.
By CSS Selector
driver.findElement(By.cssSelector("input[bayid='10']")).click();
By XPath
//input[#bayid='10']
Also I would suggest you to go through basic tutorial on how to find WebElement using CSS Selector and XPath
try the following XPath:
//input[#bayid='10']
CSS selector way to do this:
driver.findElement(By.cssSelector("yourTagName[attribute='attributeValue']")).click();
For your specific case:
driver.findElement(By.cssSelector("input[bayid='10']")).click();
I am trying to automate test case using Protractor and Jasmine. The problem is I have an "article" web element tag that gets created at runtime and this web-element has a as sub element. This div element has a "id" tag associated with it. The structure of the code is below.
<article class="a b c d" data-ng-repeat="xyz repeat">
<div id="THIS IS WHAT I WANT" class="class name">
</article>
Now I am able to get get hold of the article web-element. but I am not able to get the ID attribute in the div. The ID values is generated dynamically. Kindly suggest how I can get the ID value.
Thank you
You can use a CSS Selector like this:
article > div
This will get you a div inside of an article. Now you can use this to play around and specify the selector further with classes or other stuff.
If you managed to get the div element you can then pull out the idea using (not sure if the syntax is correct but you should get the idea):
element.getAttribute('id')
1) element(by.xpath(//div[#class='class name'])).getAttribute('id')
2) element(by.xpath(//article [#class='abcd']//div[#id='THIS IS WHAT I WANT'])).getAttribute('id')
You can use chains like this:
element(by.classname('')).element(by.className('classname'));
or
element(by.css('css of parent')).element(by.css('child css'));
or you can use element(by.repeater('repeat in reapeats')).element(by.css(''));