Is there any way to update column which is created with cast
CREATE TABLE test
(
num INT IDENTITY(1, 1),
Token AS 'TK_' + CAST(num VARCHAR(10)),
name VARCHAR(100)
)
INSERT INTO test VALUES ('data')
If I execute the above query, my result for token column will be "tk_1".
Is it possible to update/insert manually for that "token" column value?
Computed columns are read-only and IDENTITY values cannot be updated. With the computed column, all you can do is indirectly control the value during inserts using IDENTITY_INSERT but that defeats the purpose of using IDENTITY.
If you want to update the value after inserted, make it a regular varchar(13) column and assign the initial value in an insert trigger. That would allow you to update the value to something else after the initial insert.
Related
Here's the insert code.
CREATE TRIGGER InsertedPoint
ON Points
instead of insert
AS
insert into Points(Route_Id,Title,Description,Latitude,Longitude,GeoLocation)
SELECT Route_Id,Title,Description,Latitude,Longitude,
geography::STPointFromText('POINT(' + CAST([Latitude] AS VARCHAR(20)) + ' ' + CAST([Longitude] AS VARCHAR(20)) + ')', 4326)
FROM inserted
The problem about valuing of geography. When i create trigger i get error The column "GeoLocation" cannot be modified because it is either a computed column or is the result of a UNION operator.. How can i fix problem ?
So it's Points table
You can't insert values in a computed column. The principle of computed columns is that you define a computation rule, and then your RDBMS automatically manages it, computing values from other columns as needed.
Without this colum, your trigger boils down to:
CREATE TRIGGER InsertedPoint
ON Points
INSTEAD OF INSERT
AS
INSERT INTO Points(Route_Id,Title,Description,Latitude,Longitude)
SELECT Route_Id,Title,Description,Latitude,Longitude
FROM inserted
As it is, this trigger is a no-operation. Unless it does something else that what you have showed us, you would better just remove it.
I have a bigint PK column which is NOT an identity column, because I create the number in a function using different numbers. Anyway, I am trying to save this bigint number in a parameter #InvID, then use this parameter later in the procedure.
ScopeIdentity() is not working for me, it saved Null to #InvID, I think because the column is not an identity column. Is there anyway to select the record that was just inserted by the procedure without adding an extra ID column to the table?
It would save me a lot of effort and work if there is a direct way to select this record and not adding an id column.
insert into Lab_Invoice(iID, iDate, iTotal, iIsPaid, iSource, iCreator, iShiftID, iBalanceAfter, iFileNo, iType)
values (dbo.Get_RI_ID('True'), GETDATE(),
(select FilePrice from LabSettings), 'False', #source, #user, #shiftID, #b, #fid, 'Open File Invoice');
set #invID = CAST(scope_identity() AS bigint);
P.S. dbo.Get_RI_ID('True') a function returns a bigint.
Why don't you use?
set #invId=dbo.Get_RI_ID('True');
insert into Lab_Invoice(iID,iDate,iTotal,iIsPaid,iSource,iCreator,iShiftID,iBalanceAfter,iFileNo,iType)
values(#invId,GETDATE(),(select FilePrice from LabSettings),'False',#source,#user,#shiftID,#b,#fid,'Open File Invoice');
You already know that big id value. Get it before your insert statement then use it later.
one way to get inserted statement value..it is not clear which value you are trying to get,so created some example with dummy data
create table #test
(
id int
)
declare #id table
(
id int
)
insert into #test
output inserted.id into #id
select 1
select #invID=id from #id
I have written a stored procedure for inserting data into my table. These are my table's columns with their datatype:
Ad nvarchar(150),
Yazar nvarchar(150),
SayfaSayisi smallint,
KategoriId int
Gmc datetime,
HostName nvarchar(150)
The problem is that Gmc and HostName have their own default values. So I can't use these two in the stored procedure.
Gmc ---> GetDate() (to get insert date)
HostName --> Host_Name( )
So when I execute the query I am getting this error.
There are more columns in the INSERT statement than values specified in the VALUES clause. The number of values in the VALUES clause must match the number of columns specified in the INSERT statement
This is the query
Create proc Kitap_Insert
#Ad nvarchar(150),
#Yazar nvarchar(150),
#SayfaSayisi smallint,
#KategoriId int
Gmc datetime,
HostName nvarchar(150)
as
Insert into Kitap(Id, Ad, Yazar, SayfaSayisi, KategoriId)
values(#Ad, #Yazar, #SayfaSayisi, #KategoriId)
What is the proper way of doing this?
You need remove ID from insert list
Insert into Kitap(Ad,Yazar,SayfaSayisi,KategoriId)
values(#Ad,#Yazar,#SayfaSayisi,#KategoriId)
or add a value for it as below
Insert into Kitap(Id,Ad,Yazar,SayfaSayisi,KategoriId)
values(#ID, #Ad,#Yazar,#SayfaSayisi,#KategoriId)
Instead of :
Insert into Kitap(Id,Ad,Yazar,SayfaSayisi,KategoriId)
values(#Ad,#Yazar,#SayfaSayisi,#KategoriId)
Use:
INSERT INTO Kitap(Ad,Yazar,SayfaSayisi,KategoriId)
VALUES (#Ad,#Yazar,#SayfaSayisi,#KategoriId)
You are asking SQL engine that you will provide id (an additional field) as well (field that doesn't exist in the table or is an auto increment field) and you are not providing the value for the same and hence your error here are more columns in the INSERT statement than values specified in the VALUES clause. The number of values in the VALUES clause must match the number of columns specified in the INSERT statement
So remove additional Id from your insert query.
The error you are getting because you tried to insert value into more column names than specified in Values Clause.
If you have ID column as Auto-increment field in table so you dont have to include that ID column in so your insert query will be like this:-
Insert into Kitap
(Ad,Yazar,SayfaSayisi,KategoriId)
values
(#Ad,#Yazar,#SayfaSayisi,#KategoriId)
If you don't have ID column as Auto-increment field in table so you provide value to that id column also in Value Clause so your insert query will be like this:-
NOTE:-
You have to calculate and Set Value to #Id variable before using it in Insert Query
Declare #Id as INT
SET #ID = ---- set here with some value which will become Primary key(I think)
Insert into Kitap
(Id,Ad,Yazar,SayfaSayisi,KategoriId)
values
(#Id, #Ad,#Yazar,#SayfaSayisi,#KategoriId)
I'm new to firebird and I have verious issues. I want to insert various lines into a table selected from another table.
Here's the code:
/*CREATE GENERATOR POS; */
SET GENERATOR POS TO 1;
SET TERM ^;
create trigger BAS_pkassign
for MATERIAL
active before insert position 66
EXECUTE BLOCK
AS
declare posid bigint;
select gen_id(POS, 1)
from RDB$DATABASE
into :posid;
BEGIN
END
SET TERM ; ^
INSERT INTO MATERIAL ( /*ID */ LOCATION, POSID, ARTID, ARTIDCONT, QUANTITY )
SELECT 1000, ':posid', 309, BAS_ART.ID, 1
FROM BAS_ART
WHERE BAS_ART.ARTCATEGORY LIKE '%MyWord%'
The ID should autoincrement from 66 on. The posid should autoincrement from 1 on.
Actually it is not inserting anything.
I'm using Firebird Maestro and have just opened the SQL Script Editor (which doesnt throw any error message on executing the script).
Can anybody help me?
Thanks!
Additional information:
The trigger should autoincrement the column "ID" - but I dont know how exactly I can change it so it works.. The ':posid' throws an error using it :posid but like this theres no error (I guess its interpretated as a string). But how do I use it right?
I dont get errors when I execute it. The table structure is easy. I have 2 tables:
1.
Material (
ID (INTEGER),
Location (INTEGER),
POSID (INTEGER),
ARTID (INTEGER),
ARTIDCONT (INTEGER),
QUANTITY (INTEGER),
OTHERCOLUMN (INTEGER))
and the 2. other table
BAS_ART (ID (INTEGER), ARTCATEGORY (VARCHAR255))
-> I want to insert all entries from the table BAS_ART which contain "MyWord" in the column ARTCATEGORY into the MATERIAL table.
I don't understand why you need the trigger at all.
This problem:
I want to insert all entries from the table BAS_ART which contain "MyWord" into the MATERIAL table
Can be solved with a single insert ... select statement.
insert into material (id, location, posid, artid, quantity)
select next value for seq_mat_id, 1000, next value for seq_pos, id, 1
from bas_art
where artcategory = 'My Word';
This assumes that there is a second sequence (aka "generator") that is named seq_mat_id that provides the new id for the column material.id
For most of my answer I will assume a very simple table:
CREATE TABLE MyTable (
ID BIGINT PRIMARY KEY,
SomeValue VARCHAR(255),
posid INTEGER
)
Auto-increment identifier
Firebird (up to version 2.5) does not have an identity column type (this will be added in Firebird 3), instead you need to use a sequence (aka generator) and a trigger to get this.
Sequence
First you need to create a sequence using CREATE SEQUENCE:
CREATE SEQUENCE seqMyTable
A sequence is atomic which means interleaving transactions/connections will not get duplicate values, it is also outside transaction control, which means that a ROLLBACK will not revert to the previous value. In most uses a sequences should always increase, so the value reset you do at the start of your question is wrong for almost all purposes; for example another connection could reset the sequence as well midway in your execution leaving you with unintended duplicates of POSID.
Trigger
To generate a value for an auto-increment identifier, you need to use a BEFORE INSERT TRIGGER that assigns a generated value to the - in this example - ID column.
CREATE TRIGGER trgMyTableAutoIncrement FOR MyTable
ACTIVE BEFORE INSERT POSITION 0
AS
BEGIN
NEW.ID = NEXT VALUE FOR seqMyTable;
END
In this example I always assign a generated value, other examples assign a generated value only when the ID is NULL.
Getting the value
To get the generated value you can use the RETURNING-clause of the INSERT-statement:
INSERT INTO MyTable (SomeValue) VALUES ('abc') RETURNING ID
INSERT INTO ... SELECT
Using INSERT INTO ... SELECT you can select rows from one table and insert them into others. The reason it doesn't work for you is because you are trying to assign the string value ':pos' to a column of type INTEGER, and that is not allowed.
Assuming I have another table MyOtherTable with a similar structure as MyTable I can transfer values using:
INSERT INTO MyTable (SomeValue)
SELECT SomeOtherValue
FROM MyOtherTable
Using INSERT INTO ... SELECT it is not possible to obtain the generated values unless only a single row was inserted.
Guesswork with regard to POSID
It is not clear to me what POSID is supposed to be, and what values it should have. It looks like you want to have an increasing value starting at 1 for a single INSERT INTO ... SELECT. In versions of Firebird up to 2.5 that is not possible in this way (in Firebird 3 you would be able to use ROW_NUMBER() for this).
If my guess is right, then you will need to use an EXECUTE BLOCK (or a stored procedure) to assign and increase the value for every row to be inserted.
The execute block would be something like:
EXECUTE BLOCK
AS
DECLARE posid INTEGER = 1;
DECLARE someothervalue VARCHAR(255);
BEGIN
FOR SELECT SomeOtherValue FROM MyOtherTable INTO :someothervalue DO
BEGIN
INSERT INTO MyTable (SomeValue, posid) VALUES (:someothervalue, :posid);
posid = posid + 1;
END
END
Without an ORDER BY with the SELECT the value of posid is essentially meaningless, because there is no guaranteed order.
A SAMPLE table has only one column ID of type int, default null.
In Oracle when I do:
insert into SAMPLE (ID) values ('');
the new record is added with blank value. But in SQL Server 2008, when I run the same insert statement, the new record has the value of 0.
Is there a way to force SQL Server 2008 to default blank string to NULL instead of 0 (for numerical type of columns)?
Assuming that your INSERT statement is part of a stored procedure re-used in many places of your application (or, perhaps, is a batch always constructed by the same part of the client code) and that the inserted value is a number passed as a string argument, you could modify the INSERT like this:
INSERT INTO SAMPLE (ID) VALUES (NULLIF(#argument, ''));
Use NULL instead.
insert into SAMPLE (ID) values (NULL);
How about another idea - define an INSTEAD OF INSERT Trigger.
Despite the fact that you're trying to insert a string, with this the operation is "intercepted", empty string is replaced by NULL, and the insert succeeds.
If you define this trigger on your table, then you can continue to insert empty string as before, with no other changes.
Edit: As Martin Smith points out, this effectively is a comparison to 0 (the equivalent of empty string as an int) meaning you won't be able to store 0 in this table. I leave this answer here in case that's acceptable to your situation - either that or re-do all your queries!
CREATE TRIGGER EmptyStringTrigger
ON [SAMPLE]
INSTEAD OF INSERT
AS
BEGIN
INSERT INTO [SAMPLE](ID)
SELECT CASE
WHEN ID = '' THEN NULL
ELSE ID
END
FROM inserted
END
SQL Fiddle example
You can't insert a 'string' into a int column. Oracle must be just handling that for you.
Just try inserting NULL if that's what you need.
insert into SAMPLE (ID) values (NULL);
One more option
insert into SAMPLE (ID) values (DEFAULT)