How to create columns from a list of values - sql

Question

I have the following data:
Table 1
Row ID Value Cost
1 1 Priority 1 10,000
2 2 Priority 2 9,000
3 3 Priority 3 8,000
4 4 Priority 4 6,000
Table 2
Row Name Priority Cost
1 Jon 1 10,000
2 Bob 3 8,000
3 Dan 4 7,000
4 Steve 2 9,000
5 Bill 3 8,000
...
I want the table to look like this:
Table 3
Row Name Priotity 1 Priority 2 Priority 3 Priority 4
1 Jon 10,000
2 Bob 8,000
3 Dan 7,000
4 Steve 9,000
5 Bill 8,000
...
How can I create rows from Table 1 as columns, and fill in the output as shown in Table 3.
I am hoping this is not as basic as it sounds, but my SQL is terrible!

Answer 1

you can try this for dynamic pivot table.
DECLARE #columns VARCHAR(8000)
SELECT #columns = COALESCE(#columns + ',[' + cast(Value as varchar) + ']',
'[' + cast(Value as varchar)+ ']')
FROM Table1
GROUP BY Value
DECLARE #query VARCHAR(8000)
SET #query = 'with Priorites as
(select a.Name,b.Value,b.Cost from Table2 a left join Table1 b on a.Priority =b.id)
SELECT *
FROM Priorites
PIVOT
(
MAX(Cost)
FOR [Value]
IN (' + #columns + ')
)
AS p'
EXECUTE(#query)
Here is the link for more details http://www.tsqltutorials.com/pivot.php

Answer 2

Pivot is always useful in this sort of scenario, but if the actual data is as simple as it's in question (like there are only 4 unique Priority and/or only 1 Priority is assigned to a particular user),then you can achieve this task with following query:
select t.row,t.name
(case when t.priority = 1 then t.cost
else ' '
end
) as Priority1,
(case when t.priority = 2 then t.cost
else ' '
end
) as Priority2,
(case when t.priority = 3 then t.cost
else ' '
end
) as Priority3,
(case when t.priority = 4 then t.cost
else ' '
end
) as Priority4
From
(select Row,name,priority,cost
from Table2
group by name) t
group by t.name;