Please help me: group list number
A new group starts when the values descend. You can find the groups where they start using lag(). Then do a cumulative sum:
select t.*,
1 + sum(case when prev_col2 < col2 then 0 else 1 end) over (order by col1) as grp
from (select t.*,
lag(col2) over (order by col1) as prev_col2
from t
) t;
In Oracle 12.1 and above, this is a simple application of the match_recognize clause:
with
inputs ( column1, column2 ) as (
select 1, 1000 from dual union all
select 2, 2000 from dual union all
select 3, 3000 from dual union all
select 4, 6000 from dual union all
select 5, 7500 from dual union all
select 6, 0 from dual union all
select 7, 500 from dual union all
select 8, 600 from dual union all
select 9, 900 from dual union all
select 10, 2300 from dual union all
select 11, 4700 from dual union all
select 12, 40 from dual union all
select 13, 1000 from dual union all
select 14, 2000 from dual union all
select 15, 4000 from dual
)
-- End of simulated inputs (not part of the solution).
-- SQL query begins BELOW THIS LINE. Use actual table and column names.
select column1, column2, column3
from inputs
match_recognize(
order by column1
measures match_number() as column3
all rows per match
pattern ( a b* )
define b as column2 >= prev(column2)
)
order by column1 -- If needed.
;
OUTPUT:
COLUMN1 COLUMN2 COLUMN3
---------- ---------- ----------
1 1000 1
2 2000 1
3 3000 1
4 6000 1
5 7500 1
6 0 2
7 500 2
8 600 2
9 900 2
10 2300 2
11 4700 2
12 40 3
13 1000 3
14 2000 3
15 4000 3
You can use window function to mark the point where column_2 restarts and use cumulative sum to get the desired result
Select column_1,
Column_2,
Sum(flag) over (order by column_1) as column_3
From (
Select t.*,
Case when column_2 < lag(column_2,1,0) over (order by column_1) then 1 else 0 end as flag
From your_table t
) t;
Related
My code is :
with x as
(
select 1 col from dual union all
select 2 col from dual union all
select 8 col from dual union all
select 4 col from dual union all
select 3 col from dual union all
select 2 col from dual
)
select col col1, col col2, col col3, rownum
from x
where col2.ROWNUM > col1.ROWNUM -1
and col2.ROWNUM > col3ROWNUM +1 ;
I want to compare col2.ROWNUM > col1.ROWNUM -1 and col2.ROWNUM > col3ROWNUM + 1 but that doesn't work and I got an error
ORA-01747: invalid user.table.column, table.column, or column specification
01747. 00000 - "invalid user.table.column, table.column, or column specification"
*Cause:
*Action:
Error at Line: 10 Column: 13
Please help me
It looks you got something wrong.
Result of that CTE is a single-column table whose only column is named col. There are no other columns.
SQL> with x as (
2 select 1 col from dual union all --> in UNION, all columns are
3 select 2 col from dual union all named by column name(s) from the
4 select 8 col from dual union all first SELECT statement
5 select 4 col from dual union all
6 select 3 col from dual union all
7 select 2 col from dual)
8 select x.*, rownum
9 from x;
COL ROWNUM
---------- ----------
1 1
2 2
8 3
4 4
3 5
2 6
6 rows selected.
SQL>
Therefore, where clause you wrote doesn't make any sense. Perhaps you should explain what you really have, rules that should be applied to source data and result you'd like to get.
Based on text you put into the title:
compare before column in before row with next column in next row
maybe you'd be interested in lag and lead analytic functions which then let you compare values in adjacent rows (pay attention to NULL values; I didn't). For example:
SQL> with x as (
2 select 1 col from dual union all
3 select 2 col from dual union all
4 select 8 col from dual union all
5 select 4 col from dual union all
6 select 3 col from dual union all
7 select 2 col from dual
8 ),
9 temp as
10 (select col,
11 rownum as rn
12 from x
13 ),
14 temp2 as
15 (select
16 rn,
17 col as this_row,
18 lag(col) over (order by rn) as previous_row,
19 lead(col) over (order by rn) as next_row
20 from temp
21 )
22 select this_row,
23 previous_row,
24 next_row,
25 --
26 case when this_row < previous_row then 'This < previous'
27 when this_row < next_row then 'This < next'
28 else 'something else'
29 end as result
30 from temp2
31 order by rn;
Result:
THIS_ROW PREVIOUS_ROW NEXT_ROW RESULT
---------- ------------ ---------- ---------------
1 2 This < next
2 1 8 This < next
8 2 4 something else
4 8 3 This < previous
3 4 2 This < previous
2 3 This < previous
6 rows selected.
SQL>
Use lead or lag functions. But, please, do not use rownum for such purposes.
Rownum indicates simply the order in which a row was found in the database and cannot be used for other purposes except limiting the number of rows fetched, like where rownum<=1 to be certain you won't get a too_many_rows exception, for instance. Still, if in a query you do fetch the pseud-column rownum, give it an alias so that you may use that value later on.
Moreover, what is supposed to mean col2.ROWNUM or col1.ROWNUM? That is not clear. col1 and col2 are two columns, which do not have the attribute rownum.
Something that may help in the future for analytic queries:
https://oracle-base.com/articles/misc/lag-lead-analytic-functions
And, if you wish to get a working SQL, please explain clearly what you wish to achieve, for I haven't really understood what that code is intended to do.
A way you may use rownum without getting errors:
with x as (
select 1 col from dual union all
select 2 col from dual union all
select 8 col from dual union all
select 4 col from dual union all
select 3 col from dual union all
select 2 col from dual)
,x2 as (
select col col1 ,col col2, col col3 ,rownum rn
from x
)
select *
from x2
where rn between 2 and 3 --- rownum cannot be used in such a
condition!!!
;
Or, to be certain you get only the first row from a table satisfying a given condition:
select x_col1, x_col2 into v_col1, v_col2
from x_table
where ... --- logical conditions
and rownum<=1; --- rownum <= 1 avoids too_many_rows_exception if several rows satisfy the logical conditions given before
In Oracle, results sets have a non-deterministic order (i.e. they are unordered) unless you use an ORDER BY clause. Therefore, if you have a physical table, you need another column to provide the order (rather than relying on the ROWNUM pseudo-column, which may result in unexpected behaviour):
CREATE TABLE x (order_id, col) AS
SELECT 1, 1 FROM DUAL UNION ALL
SELECT 2, 2 FROM DUAL UNION ALL
SELECT 3, 8 FROM DUAL UNION ALL
SELECT 4, 4 FROM DUAL UNION ALL
SELECT 5, 3 FROM DUAL UNION ALL
SELECT 6, 2 FROM DUAL;
If you want to find the rows that go up in succession, then you can use MATCH_RECOGNIZE for row-by-row pattern matching:
SELECT *
FROM x
MATCH_RECOGNIZE(
ORDER BY order_id
MEASURES
any_row.col AS col1,
FIRST(up.col) AS col2,
LAST(up.col) AS col3,
FIRST(order_id) AS start_order_id
PATTERN ( any_row up{2} )
DEFINE up AS ( col > PREV(col) )
)
or the LEAD analytic function:
SELECT *
FROM (
SELECT col AS col1,
LEAD(col, 1) OVER (ORDER BY order_id) AS col2,
LEAD(col, 2) OVER (ORDER BY order_id) AS col3,
order_id
FROM x
)
WHERE col2 > col1
AND col3 > col2;
Which both output:
COL1
COL2
COL3
START_ORDER_ID
1
2
8
1
fiddle
It looks like you want to find the rows where the value of the column is bigger than it is in both - the previous and next row. If so, you could try this:
WITH
tbl (ID, COL) AS -- Sample data (ID column is just to preserve order of the rows)
(
Select 1, 1 From Dual Union All
Select 2, 2 From Dual Union All
Select 3, 8 From Dual Union All
Select 4, 4 From Dual Union All
Select 5, 3 From Dual Union All
Select 6, 2 From DUAL
)
Select ID, COL, CASE WHEN COL > LAG(COL, 1) OVER(Order By ID) And COL > LEAD(COL, 1) OVER(Order By ID) THEN 'YES' END "BIGGER_THAN_PREV_AND_NEXT"
From tbl
Order By ID
ID COL BIGGER_THAN_PREV_AND_NEXT
---------- ---------- -------------------------
1 1
2 2
3 8 YES
4 4
5 3
6 2
... with a bit different sample data this will find the other row(s) that satisfy the condition ...
WITH
tbl (ID, COL) AS -- Sample data (ID column is just to preserve order of the rows)
(
Select 1, 1 From Dual Union All
Select 2, 2 From Dual Union All
Select 3, 8 From Dual Union All
Select 4, 4 From Dual Union All
Select 5, 5 From Dual Union All -- value of COL changed from 3 to 5
Select 6, 2 From DUAL
)
Select ID, COL, CASE WHEN COL > LAG(COL, 1) OVER(Order By ID) And COL > LEAD(COL, 1) OVER(Order By ID) THEN 'YES' END "BIGGER_THAN_PREV_AND_NEXT"
From tbl
Order By ID
ID COL BIGGER_THAN_PREV_AND_NEXT
---------- ---------- -------------------------
1 1
2 2
3 8 YES
4 4
5 5 YES
6 2
OR without ID - using ROWNUM (as in your question), - not adviseable, though...
WITH
tbl (COL) AS -- Sample data (without ID column)
(
Select 1 From Dual Union All
Select 2 From Dual Union All
Select 8 From Dual Union All
Select 4 From Dual Union All
Select 5 From Dual Union All
Select 2 From DUAL
)
Select COL, CASE WHEN COL > LAG(COL, 1) OVER(Order By ROWNUM) And COL > LEAD(COL, 1) OVER(Order By ROWNUM) THEN 'YES' END "BIGGER_THAN_PREV_AND_NEXT"
From tbl
COL BIGGER_THAN_PREV_AND_NEXT
---------- -------------------------
1
2
8 YES
4
5 YES
2
Any Order By clause added to the query could change the ROWNUM values and the result...
I have this query that returns the data below it
select LISTAGG(d.DOCUMENT_TYPE_CD, ',') WITHIN GROUP (ORDER BY D.DOCUMENT_TYPE_CD) as value
from test_table d;
VALUE
---------
CI,ECI,POA
now I'm trying to add a condition whenever 'ECI' value is present, it should exclude 'CI' in the result like this one below
VALUE
---------
ECI,POA
I tried using case statement in where condition it prompted an error
select LISTAGG(d.DOCUMENT_TYPE_CD, ',')
WITHIN GROUP (ORDER BY D.DOCUMENT_TYPE_CD) as value
from test_table d
where CASE d.DOCUMENT_TYPE_CD
WHEN 'ECI' THEN d.DOCUMENT_TYPE_CD <> 'CI'
END;
ORA-00905: missing keyword
00905. 00000 - "missing keyword"
*Cause:
*Action:
Error at Line: 7 Column: 36
is there any other way I could resolve this?
See if this helps; read comments within code.
SQL> with
2 test (id, document_type_cd) as
3 -- sample data
4 (select 1, 'ECI' from dual union all
5 select 1, 'CI' from dual union all
6 select 1, 'POA' from dual union all
7 --
8 select 2, 'CI' from dual union all
9 select 2, 'POA' from dual union all
10 --
11 select 3, 'XYZ' from dual union all
12 select 3, 'ABC' from dual
13 ),
14 temp as
15 -- see whether CI and ECI exist per each ID
16 (select id,
17 sum(case when document_type_cd = 'CI' then 1 else 0 end) sum_ci,
18 sum(case when document_type_cd = 'ECI' then 1 else 0 end) sum_eci
19 from test
20 group by id
21 ),
22 excl as
23 -- exclude CI rows if ECI exist for that ID
24 (select a.id,
25 a.document_type_cd
26 from test a join temp b on a.id = b.id
27 where a.document_type_cd <> case when b.sum_ci > 0 and b.sum_eci > 0 then 'CI'
28 else '-1'
29 end
30 )
31 -- finally:
32 select e.id,
33 listagg(e.document_type_cd, ',') within group (order by e.document_type_cd) result
34 from excl e
35 group by e.id;
ID RESULT
---------- --------------------
1 ECI,POA
2 CI,POA
3 ABC,XYZ
SQL>
Something like this:
select LISTAGG(d.DOCUMENT_TYPE_CD, ',')
WITHIN GROUP (ORDER BY D.DOCUMENT_TYPE_CD) as value
from test_table d,
(select sum (case when DOCUMENT_TYPE_CD = 'CI' then 1 else 0 end) C
from test_table) A
where d.DOCUMENT_TYPE_CD <> case when A.c > 0 then 'CI' when A.c = 0 then ' ' end;
DEMO
You may identify the presence of both the values with two conditional aggregations in the same group by and then replace CI inside the result of listagg in one pass.
with a(id, cd) as (
select 1, 'ABC' from dual union all
select 1, 'ECI' from dual union all
select 1, 'CI' from dual union all
select 1, 'POA' from dual union all
select 2, 'XYZ' from dual union all
select 2, 'ECI' from dual union all
select 2, 'CI' from dual union all
select 2, 'POA' from dual union all
select 3, 'CI' from dual union all
select 3, 'POA' from dual union all
select 4, 'ABC' from dual union all
select 4, 'DEF' from dual
)
select
id,
ltrim(
/*Added comma in case CI will be at the beginning*/
replace(
',' || listagg(cd, ',') within group (order by cd asc),
decode(
/*If both are present, then replace CI. If not, then do not replace anything*/
max(decode(cd, 'CI', 1))*max(decode(cd, 'ECI', 1)),
1,
',CI,'
),
','
),
','
) as res
from a
group by id
ID | RES
-: | :----------
1 | ABC,ECI,POA
2 | ECI,POA,XYZ
3 | CI,POA
4 | ABC,DEF
db<>fiddle here
Instead of using GROUP BY, you can also use windowing (aka analytic) functions to check the presence of ECI per group (test data shamelessly stolen from #littlefoot):
with
test (id, document_type_cd) as
-- sample data
(select 1, 'ECI' from dual union all
select 1, 'CI' from dual union all
select 1, 'POA' from dual union all
--
select 2, 'CI' from dual union all
select 2, 'POA' from dual union all
--
select 3, 'XYZ' from dual union all
select 3, 'ABC' from dual
),
temp as
(select id,
document_type_cd,
sum(case when document_type_cd = 'ECI' then 1 else 0 end) over (partition by id) as sum_eci
from test
)
select a.id,
listagg(a.document_type_cd, ',') within group (order by a.document_type_cd) result
from temp a
where a.document_type_cd != 'CI' or sum_eci = 0
group by a.id;
I've a table (T1) with one column (C1) with the below values
1
2
3
5
6
8
9
10
I want the output to print the continuous sequences with start and ending points like below.
1-3
5-6
8-10
Could you please help?
Any Database is fine.
Oracle: sample data first, while code you really need begins at line #11.
SQL> with t1 (c1) as
2 (select 1 from dual union all
3 select 2 from dual union all
4 select 3 from dual union all
5 select 5 from dual union all
6 select 6 from dual union all
7 select 8 from dual union all
8 select 9 from dual union all
9 select 10 from dual
10 )
11 select min(c1), max(c1)
12 from (select c1, c1 - row_number() over (order by c1) rn
13 from t1
14 )
15 group by rn
16 order by rn;
MIN(C1) MAX(C1)
---------- ----------
1 3
5 6
8 10
SQL>
You can use the following query. I have tested it with SQL Server, but I think it will work without modifications in Oracle:
create table t1(c1 int);
insert into t1
select *
from (values(1),(2),(3),(5),(6),(8),(9),(10))t(x);
select case when count(*) >1 then
concat(min(c1),'-',max(c1))
else concat(max(c1),'')
end as concat_cs
from (
select c1
,ROW_NUMBER() over(order by c1 asc) as rnk
,c1 - ROW_NUMBER() over(order by c1 asc) as grp
from t1
)x
group by x.grp
Output
concat_cs
1-3
5-6
8-10
with stab as (
select 1 as val from dual union all
select 2 as val from dual union all
select 3 as val from dual union all
select 5 as val from dual union all
select 6 as val from dual union all
select 8 as val from dual union all
select 9 as val from dual union all
select 10 as val from dual union all
select 13 as val from dual union all
select 15 as val from dual union all
select 16 as val from dual union all
select 17 as val from dual union all
select 18 as val from dual union all
select 19 as val from dual union all
select 23 as val from dual
),sq2 as(
select
row_number() over(order by 1) as rownumber,val
from stab
)
select
a.val,b.val
from sq2 A
join sq2 b on b.rownumber = a.rownumber+2
where mod(A.rownumber,3)=1
Output:
1 3
5 8
9 13
15 17
18 23
I Oracle, I have a table with following values
1
2
4
10
I always want 2 to show up highest following by all other values in DESCending order, as follows :
2
10
4
1
You can order by a value you build with a case; for example:
with tab(col) as (
select 1 from dual union all
select 2 from dual union all
select 4 from dual union all
select 10 from dual
)
select col
from tab
order by case when col = 2 then 1 else 2 end asc,
col desc
gives:
COL
----------
2
10
4
1
try like below if column is not null
with tab(col) as (
select 1 from dual union all
select 2 from dual union all
select 4 from dual union all
select 10 from dual
)
select col
from tab
ORDER BY NULLIF(col, 2) desc NULLS FIRST
output
COL
2
10
4
1
demo link
I need a query that evaluates the longest uninterrupted series of subsequent "1"'s in the column FL_SUCC_EXEC. For the following data in table TEST(row_no number, fl_succ_exec number(1)), the result of the query should be "6".
Rows are ordered by row_no.
ROW_NO FL_SUCC_EXEC
---------- ------------
1 1
2 1
3 1
4 0
5 1
6 1
7 1
8 1
9 1
10 1
11 0
12 1
13 1
14 1
15 1
I can do this in PL/SQL :
declare
temp_cnt pls_integer default 0;
total_cnt pls_integer default 0;
begin
for rec in (select row_no, fl_succ_exec from test order by row_no)
loop
if temp_cnt > total_cnt
then
total_cnt:=temp_cnt;
end if;
if rec.fl_succ_exec!=0
then
temp_cnt:=temp_cnt+rec.fl_succ_exec;
else
temp_cnt:=0;
end if;
end loop;
dbms_output.put_line(total_cnt);
end;
But I'm still hoping for SQL solution. Is there any?
Try:
SELECT max( count(*) ) As longest_uninterrupted_series
FROM (
select fl_succ_exec,
sum( case when fl_succ_exec = 1 then 0 else 1 end )
over ( order by row_no ) xx
from test
)
WHERE fl_succ_exec = 1
GROUP BY xx;
Oracle Setup:
CREATE TABLE test ( row_no, fl_succ_exec ) AS
SELECT 1, 1 FROM DUAL UNION ALL
SELECT 2, 1 FROM DUAL UNION ALL
SELECT 3, 1 FROM DUAL UNION ALL
SELECT 4, 0 FROM DUAL UNION ALL
SELECT 5, 1 FROM DUAL UNION ALL
SELECT 6, 1 FROM DUAL UNION ALL
SELECT 7, 1 FROM DUAL UNION ALL
SELECT 8, 1 FROM DUAL UNION ALL
SELECT 9, 1 FROM DUAL UNION ALL
SELECT 10, 1 FROM DUAL UNION ALL
SELECT 11, 0 FROM DUAL UNION ALL
SELECT 12, 1 FROM DUAL UNION ALL
SELECT 13, 1 FROM DUAL UNION ALL
SELECT 14, 1 FROM DUAL UNION ALL
SELECT 15, 1 FROM DUAL;
Query:
SELECT MAX( num_1s ) AS num_1s
FROM (
SELECT COALESCE(
row_no - LAST_VALUE( CASE fl_succ_exec WHEN 0 THEN row_no END )
IGNORE NULLS OVER ( ORDER BY row_no ),
ROWNUM
) AS num_1s
FROM test
);
Output:
NUM_1S
------
6