SQL - counts for two days - sql

Question

I have a table like
CREATE TABLE [dbo].[Log](
[Id] [BIGINT] IDENTITY(1,1) NOT NULL,
[GuidId] [UNIQUEIDENTIFIER] NOT NULL,
[TableName] [VARCHAR](50) NULL,
[CreatedDate] [DATETIME] NULL,
[Operation] [VARCHAR](50) NULL,
[Status] [VARCHAR](50) NULL,
[UserId] [VARCHAR](50) NOT NULL)
Am trying to get query like
SELECT TOP 25 UserId, TableName, Operation, COUNT(1) Records
FROM dbo.Log
WHERE CreatedDate > GETDATE() - 1
AND Status='failed'
GROUP BY UserId, TableName,Operation
I need to add another column to have output of count that has GetDate() - 7 criteria too in the same select.
Share some thoughts

Answer 1

Something like this?
SELECT TOP 25
UserId
, TableName
, Operation
, SUM(CASE WHEN CreatedDate > GETDATE() - 1 THEN 1 ELSE 0 END) Records1Day
, COUNT(1) Records7Days
FROM dbo.Log
WHERE
CreatedDate > GETDATE() - 7
AND Status='failed'
GROUP BY
UserId
, TableName
, Operation

Answer 2

If I understand correctly, you want the most recent UserID fails that had a MAX(CreatedDate) > yesterday. The subquery dT, below does this using MAX(CreatedDate) for the user ID, and HAVING to filter. This is Ordered in descending faildate order. I subqueried because you added the condition that you want to know the date for 7 days prior to this, and the receiving query does this... using DATEADD to subtract 7 days from the [Most Recent UserID Failure] date.
SELECT dT.UserId
,dT.[Most Recent UserID Failure]
,DATEADD(DAY, -7, dT.[Most Recent UserID Failure]) AS [7 Days ago]
,(SELECT COUNT (*)
FROM #Log
WHERE UserId = dT.UserID
AND CreatedDate >= DATEADD(DAY, -7, CAST(dT.[Most Recent UserID Failure] as date))
AND CreatedDate <= dT.[Most Recent UserID Failure]
AND Status = 'failed'
) AS [Num Fails]
FROM (
SELECT TOP 25
UserID
,MAX(CreatedDate) AS [Most Recent UserID Failure]
FROM Log
WHERE Status = 'failed'
GROUP BY UserID
HAVING MAX(CreatedDate) > GETDATE() - 1
ORDER BY [Most Recent UserID Failure] DESC
) AS dT