How to sendKeys in textBox? for automation - selenium

I'm doing a test on c# with selenium for this site http://onliner.by.
At first I have to be authorized on this site.
I found(by xpath) button with name"Вход" in the right upper corner and click on it.
Then there's refreshed and page changed, but the link remained the same (http://onliner.by).
And I need to enter login and password on this page and sumbit it. But I cannot do it.
I founded Xpath paths of this elements and I used this code:
//this doesn't work
driver.FindElement(By.XPath("//*[#id='auth-container__forms']/div/div[2]/form/div[1]/div[1]/input")).SendKeys("user");
driver.FindElement(By.XPath("//*[#id='auth-container__forms']/div/div[2]/form/div[1]/div[2]/input")).SendKeys("password");
driver.FindElement(By.XPath("//*[#id='auth-container__forms']/div/div[2]/form/div[3]/div/button")).Click();
How can I do it? I tried to use SwitchTo().Frame but it didn't help too.
I will be very grateful for help.

You have to wait element availablity like this
new WebDriverWait(driver, TimeSpan.FromSeconds(timeOut)).Until(ExpectedConditions.ElementExists((Locator Value)));

Related

How to select an element of a pop up prompt using Selenium

I'm writing a code using Selenium and Chromedriver to remotely control my instagram.
I've managed to login to the platform however as soon as I do a pop up asking about activating notifications appears and my codeflow breaks because it can no longer click the elements of the instagram page.
this is the code I tried using (which works during login to click the "send" button
notifBtn= self.browser.find_element_by_css_selector('button')
notifBtn.click()
(since it's the first instance of button on the web code it should automatically select that one)
however this time the browser is stuck and doesn't do anything.
during the login I had a problem where it wouldn't click either and found that it was because there was a lag between the request to go to the instagram login page and loading the page so it could find the CSS elements. I fixed it by adding
time.sleep(2)
before inputting the data and it fixed. I thought something similar would work here as it doesn't load instantly but it made no difference.
Is this an issue with the selector, as in could I use xpath to get around it? anyways sorry if it's a bit vague and feel free to ask me about my code or whatever.
notifBtn= self.browser.find_element_by_css_selector('button')
notifBtn.click()
I expect Chromedriver to click don't activate in the pop up so the code can continue instead I get stuck on that screen
Your find_element_by_css_selector call is probably locating multiple elements, and doesn't know which one to click. I would use an XPath here, to be more explicit about which button you are trying to click:
from selenium.webdriver.support import expected_conditions as EC
# Wait for button to exist
not_now_button = WebDriverWait(driver, 10).until(
EC.element_to_be_clickable((By.XPATH, "//button[text()='Not Now']")))
# Click the button
not_now_button.click()

cannot login with selenium

I am trying to automate logging into this website.
the login menu is at the top right of the website.
i have tried to find the login form by CSS selector, Xpath, name and the action of this topic.
edit 1 : I have also tried hover the mouse over the login with actionchains then find by elements. No Element was found, no key was sent also.
Result:
the find by CSS, Xpath, name shows : element not visible ;
the action event : i hover the mouse over the login area, send keys,the login area pops up but no key was sent, no error shown.
My code for the action event:
wd.get("http://www.vatgia.com")
action = ActionChains(wd);
action.move_to_element(wd.find_element_by_css_selector("#header_bar > div > div.fr > a:nth-child(8)"))
action.send_keys("loginsampling")
action.perform();
p/s : thankyou Brian for the edit !
Final update :
Mahipal has provided me with the solution. i should have used the xpath with regards to the container for the login form and password. i previously only right click and copy the xpath element and that did not work. Thanks Mahipal !
You can make use of the container of login menu for identifying its fields, as shown below:
driver.findElement(By.xpath("//div[#id='header_bar']//a[#rel='#header_login']")).click();
WebDriverWait wait = new WebDriverWait(driver, 10);
wait.until(ExpectedConditions.visibilityOf(
driver.findElement(By.xpath("//div[#id='simple_tip']//div/input[#name='loginname']"))));
driver.findElement(By.xpath("//div[#id='simple_tip']//div/input[#name='loginname']")).sendKeys("login_name");
Try above code and let me know, whether it works for you.
This is due to the fact that you are not opening the login dropdown prior to attempting to find the login button. You will need to find the Dropdown element, click on it, then find the login fields and button and perform your actions.

Getting Stale Element Reference Exception while trying to menu links in a web page

I am trying to click the main menu items in seleniumhq.org but after clicking on the first link i am getting a StaleElementReferenceException:Element not found in the cache=perhaps the page was changed since it was looked up
Please provide solution to solve the above problem
Below was my code
WebDriver d=new FirefoxDriver();
d.get("http://docs.seleniumhq.org/");
d.manage().timeouts().implicitlyWait(100,TimeUnit.SECONDS);
List<WebElement> l=d.findElements(By.cssSelector("ul>li"));
for(WebElement e:l) {
e.click();
}
Thanks in advance
If you click on a link and you are taken to the different page or even if you stay in same page the DOM is refreshed. Those elements are not attached to DOM anymore. You need to write some code to come back to previous page if your click takes you to a different page or even if you stays in same page you have find the link on the fly to click instead of "e.click()"

How to handle popup window using selenium webdriver with Java

Please help, I'm new in Selenium. I try to automate eCommerce website and I have problem to handle popup window. Here is the scenario:
Go to http://www.lampsplus.com
Click on Sale link in the header section.
Click on the 1st item/product displayed on the page. (This will show the product page).
On the product page, click on the red Add To Cart button. (This will add a product to cart and display a popup).
On the popup, click the dark-grey Continue Shopping button. (This will close the popup.)
I stuck on step 5 (Error message: Unable to locate element "Continue shopping button")
Here is my code before step 5:
WebDriver d1 = new FirefoxDriver();
d1.manage().window().maximize();
d1.get("http://www.lampsplus.com");
d1.findElement(By.name("hdr_sale")).click();
d1.findElement(By.xpath(".//*[#id='sortResultContainer60238']/a[2]/span")).click();
d1.findElement(By.id("pdAddToCart")).click(); //This is step 4
//Here is suppose to be some code which handles the popup - my problem
d1.findElement(By.id("aContinueShopping")).click(); //This is step 5
I'm aware about .getWindowHandle(); method. I tried several variations of it and none of them worked.
Can anyone give me an idea how to handle it. Many thanks! I use Java.
Note: I don't work for LampsPlus and not try to promote their products, this website was chosen for training purposes only.
The element aContinueShopping is contained within an iframe.
You'll have to switch to the iframe using:
WebElement frameID = d1.findElement(By.Css("#add-to-cart>iframe"));
d1.SwitchTo().Frame(frameID);
d1.findElement(By.id("aContinueShopping")).click();
There's no 'name' or 'id' on the iframe, so you'll have to use a WebElement or a numeric to find it.
Once you're done with that iframe, you'll switch back to 'top' by using:
d1.SwitchTo().DefaultContent();

Login check using HtmlUnit

Hy... i want to login to some 3rd party sites using HtmlUnit. But HtmlUnit should be able to tell me whether the login attempt to the input site is successful or not. Is there any way around to perform this task using HtmlUnit. Please help ..!!!
Thanks
Usman Raza
I'm currently using HTMLunit to log in to a site that has a varification page and redirect. some of my code for this is:
//---------------------------------Login Page---------------------------------
HtmlPage PageLogin = webClient.getPage(url);
HtmlElement submitButton = (HtmlElement) PageLogin.getByXPath(Xpath To Button).get(0);
HtmlTextInput name = (HtmlTextInput) PageLogin.getElementById("UserIdInput");
HtmlPasswordInput pass = (HtmlPasswordInput)PageLogin.getElementById("ADloginPasswordInput");
name.setText(username);
pass.setText(password);
System.out.println("Logging in to site");
//------------------------------------------------------------------------
//---------------------------------Pass varified Page----------------------
HtmlPage pagePassVarified = submitButton.click();
System.out.println("Successfully Logged in to site");
HtmlElement btnContinue = (HtmlElement) pagePassVarified.getElementById("BtnClickToContinue");
//---------------------------------------------------------
//---------------------Home Page----------------------------------
HtmlPage pageHome = btnContinue.click();
System.out.println("Home Page accessed");
//----------------------------------------------------------------
This code goes to a login page, adds username and passwords to text boxes, and clicks the submit button. We are next redirected to a "wait 5 seconds, or click here to continue to home page" type of page, where the continue button is clicked. Lastly we arrive at our home page that we wanted to log into. I selected the page elements by both ID and Xpath when no ID was available.
You can have HtmlUnit check the URL, or search for a specific element on the page, more precisely one you know to be present only in one case (sucessful login / rejected).
Like RabidFX suggested, I would suggest you to check URL but in some cases (I've seen such situations in my work experience) URL may still the same. Then, my suggestion would be checking for a specific element and it should be the login form because generally unsuccessfull login attemps redirect you to the same page that has the same login form. That would not be hard - coded solution because I hope you have found some way to get that login form with a generic way :)