I have three columns
suppose
row no column1 column2 column3
1 A B C
2 A B C
3 D E F
4 G H I
5 G H C
I want to generate code by combining these three column values
For Eg.
1)ABC001
2)ABC002
3)DEF001
4)GHI001
5)GHC001
by checking combination of three columns
logic is that
if values of three columns are same then like first time it shows 'ABC001'
and 2nd time it shows 'ABC002'
You can try this:
I dont know what you want for logic with 00, but you can add them manuel or let the rn decide for you
declare #mytable table (rowno int,col1 nvarchar(50),col2 nvarchar(50),col3 nvarchar(50)
)
insert into #mytable
values
(1,'A', 'B', 'C'),
(2,'A', 'B', 'C'),
(3,'D', 'E', 'F'),
(4,'G', 'H', 'I'),
(5,'G', 'H', 'C')
Select rowno,col1,col2,col3,
case when rn >= 10 and rn < 100 then concatcol+'0'+cast(rn as nvarchar(50))
when rn >= 100 then concatcol+cast(rn as nvarchar(50))
else concatcol+'00'+cast(rn as nvarchar(50)) end as ConcatCol from (
select rowno,col1,col2,col3
,Col1+col2+col3 as ConcatCol,ROW_NUMBER() over(partition by col1,col2,col3 order by rowno) as rn from #mytable
) x
order by rowno
My case when makes sure when you hit number 10 it writes ABC010 and when it hits above 100 it writes ABC100 else if its under 10 it writes ABC001 and so on.
Result
TSQL: CONCAT(column1,column2,column3,RIGHT(REPLICATE("0", 3) + LEFT(row_no, 3), 3))
You should combine your columns like below :
SELECT CONVERT(VARCHAR(MAX), ROW_NUMBER() OVER(ORDER BY
(
SELECT NULL
)))+') '+DATA AS Data
FROM
(
SELECT column1+column2+column3+'00'+CONVERT(VARCHAR(MAX), ROW_NUMBER() OVER(PARTITION BY column1,
column2,
column3 ORDER BY
(
SELECT NULL
))) DATA
FROM <table_name>
) T;
Result :
1)ABC001
2)ABC002
3)DEF001
4)GHI001
5)GHC001
MySQL:
CONCAT(column1,column2,column3,LPAD(row_no, 3, '0'))
[you will need to enclose the 'row no' in ticks if there is a space in the name of the field instead of underscore.]
Related
I have a scenario where I need to rename a value in one column, based on another column's total. Example table below with basic math, to express concept. I'd like to change the value in 'Condition' column to "Used" for the rows that make up 70% of the 'Revenue' column (which in this example would be 7 rows). The other 30% would be renamed to "New" (the remaining 3 rows). No other specific logic required.
I found that the approach mentioned here works for selecting the percentage of rows required
Select Rows who's Sum Value = 80% of the Total
I suppose I could create two temporary tables, rename the column fields in each respective table, and then join together. Curious if there is an easier way?
Current Table:
Source
Condition
Revenue
A
Old
1
B
New
1
C
Old
1
D
New
1
E
Old
1
F
New
1
G
Old
1
H
New
1
I
Old
1
J
New
1
New Table:
Source
Condition
Revenue
A
Used
1
B
Used
1
C
Used
1
D
Used
1
E
Used
1
F
Used
1
G
Used
1
H
New
1
I
New
1
J
New
1
You could do this with two updates. The first would update the entire table. The second would update the first 70%.
First we need sample data in a table. I used a table variable here but you would use your actual table.
declare #Something table
(
Source char(1)
, Condition varchar(10)
, Revenue int
)
insert #Something values
('A', 'Old', 1)
, ('B', 'New', 1)
, ('C', 'Old', 1)
, ('D', 'New', 1)
, ('E', 'Old', 1)
, ('F', 'New', 1)
, ('G', 'Old', 1)
, ('H', 'New', 1)
, ('I', 'Old', 1)
, ('J', 'New', 1)
select *
from #Something;
Next simply update the entire table.
update #Something
set Condition = 'New';
Last step is to update the first 70%. An easy to do this is to use a cte to select the first 70% and then update the cte.
with Top70 as
(
select top 70 percent *
from #Something
order by Source
)
update Top70
set Condition = 'Used';
Here is the final output.
select *
from #Something;
--EDIT--
Now understanding we need a running total you could do something like this.
select *
, case when sum(Revenue) over(order by Source) > (sum(Revenue) over() * .7) then 'New' else 'Old' end
from #Something
You can select/mark the 70% and 30% records using this query :
with cte as (
SELECT *, SUM(revenue) OVER(ORDER BY source) AS cumulative_revenue, SUM(revenue) OVER() as total
FROM mytable t
)
select Source, iif((cumulative_revenue + 0.0) /total <= 0.7, 'Used', 'New') as Condition, revenue, cumulative_revenue, (cumulative_revenue + 0.0) /total as perc
from cte
Demo here
You could chain a couple of CTEs to run the UPDATE
DROP TABLE IF EXISTS #t
CREATE TABLE #t([Source] VARCHAR(10), [Condition] VARCHAR(10), Revenue INT)
INSERT INTO #t([Source], [Condition], [Revenue])
values
('A', 'Old', 1)
,('B', 'New', 1)
,('C', 'Old', 1)
,('D', 'New', 1)
,('E', 'Old', 1)
,('F', 'New', 1)
,('G', 'Old', 1)
,('H', 'New', 1)
,('I', 'Old', 1)
,('J', 'New', 1)
;WITH cte AS (
SELECT *, SUM( Revenue) OVER (ORDER BY Source) ACC
FROM #t
), cte2 as(
SELECT MAX(acc)*1. TotalRevenue FROM cte
)
UPDATE cte
SET Condition = CASE WHEN Acc / TotalRevenue <= .7 THEN 'Used' ELSE 'New' END
FROM cte
CROSS APPLY (SELECT TotalRevenue FROM cte2) ca
SELECT * FROM #t
I'm trying to group by a primary column and a secondary column. I want to ignore NULL in the secondary column unless it's the only value.
CREATE TABLE #tempx1 ( Id INT, [Foo] VARCHAR(10), OtherKeyId INT );
INSERT INTO #tempx1 ([Id],[Foo],[OtherKeyId]) VALUES
(1, 'A', NULL),
(2, 'B', NULL),
(3, 'B', 1),
(4, 'C', NULL),
(5, 'C', 1),
(6, 'C', 2);
I'm trying to get output like
Foo OtherKeyId
A NULL
B 1
C 1
C 2
This question is similar, but takes the MAX of the column I want, so it ignores other non-NULL values and won't work.
I tried to work out something based on this question, but I don't quite understand what that query does and can't get my output to work
-- Doesn't include Foo='A', creates duplicates for 'B' and 'C'
WITH cte AS (
SELECT *,
ROW_NUMBER() OVER (PARTITION BY [Foo] ORDER BY [OtherKeyId]) rn1
FROM #tempx1
)
SELECT c1.[Foo], c1.[OtherKeyId], c1.rn1
FROM cte c1
INNER JOIN cte c2 ON c2.[OtherKeyId] = c1.[OtherKeyId] AND c2.rn1 = c1.rn1
This is for a modern SQL Server: Microsoft SQL Server 2019
You can use a GROUP BY expression with HAVING clause like below one
SELECT [Foo],[OtherKeyId]
FROM #tempx1 t
GROUP BY [Foo],[OtherKeyId]
HAVING SUM(CASE WHEN [OtherKeyId] IS NULL THEN 0 END) IS NULL
OR ( SELECT COUNT(*) FROM #tempx1 WHERE [Foo] = t.[Foo] ) = 1
Demo
Hmmm . . . I think you want filtering:
select t.*
from #tempx1 t
where t.otherkeyid is not null or
not exists (select 1
from #tempx1 t2
where t2.foo = t.foo and t2.otherkeyid is not null
);
My actual problem is a bit more complicated than presented here, I ended up using the idea from Barbaros Özhan solution to count the number of items. This ends up with two inner queries on the data set with two different GROUP BY. I'm able to get the results I need on my real dataset using a query like the following:
SELECT
a.[Foo],
b.[OtherKeyId]
FROM (
SELECT
[Foo],
COUNT([OtherKeyId]) [C]
FROM #tempx1 t
GROUP BY [Foo]
) a
JOIN (
SELECT
[Foo],
[OtherKeyId]
FROM #tempx1 t
GROUP BY [Foo], [OtherKeyId]
) b ON b.[Foo] = a.[Foo]
WHERE
(b.[OtherKeyId] IS NULL AND a.[C] = 0)
OR (b.[OtherKeyId] IS NOT NULL AND a.[C] > 0)
I have a table in Snowflake in following format:
create temp_test(name string, split string, value int)
insert into temp_test
values ('A','a', 100), ('A','b', 200), ('A','c',300), ('A', 'd', 400), ('A', 'e',500), ('B', 'a', 1000), ('B','b', 2000), ('B','c', 3000), ('B', 'd',4000), ('B','e', 5000)
First step, I needed only top 2 value per name (sorted on value), so I used following query to get that:
select name, split, value,
row_number() over (PARTITION BY (name) order by value desc) as row_num
from temp_test
qualify row_num <= 2
Which gives me following resultset:
NAME SPLIT VALUE ROW_NUM
A e 500 1
A d 400 2
B e 5000 1
B d 4000 2
Now, I need to sum values other than Top 2 and put it in a different Split named as "Others", like this:
NAME SPLIT VALUE
A e 500
A d 400
A Others 600
B e 5000
B d 4000
B Others 6000
How to do that in Snowflake query or SQL in general?
with data as (
select name, split, value,
row_number() over (partition by (name) order by value desc) as row_num
from temp_test
)
select
name,
case when row_num <= 2 then split else 'Others' end as split,
sum(value) as value
from data
group by name, case when row_num <= 2 then row_num else 3 end
Shawnt00's answer is good, but for the record in Snowflake this can be written simpler:
Firstly the group by at the end can refer to the results by index or name:
GROUP BY 1,2
or
GROUP BY name, split
also as the CASE only has too branches an IFF can be used and seems you are using a CTE to add the row_number you can push the IFF into the CTE also
WITH data AS (
SELECT name, value,
ROW_NUMBER() OVER (PARTITION BY name ORDER BY value DESC) AS row_num,
IFF(row_num < 3, split, 'Others') as n_split
FROM VALUES ('A','a', 100), ('A','b', 200), ('A','c',300), ('A', 'd', 400),
('A', 'e',500), ('B', 'a', 1000), ('B','b', 2000), ('B','c', 3000),
('B', 'd',4000), ('B','e', 5000)
v(name, split, value)
)
SELECT
name,
n_split,
SUM(value) AS value
FROM data
GROUP BY name, n_split;
and if super keen on small SQL push the ROW_NUMBER into the IFF:
WITH data AS (
SELECT name, value,
IFF(ROW_NUMBER() OVER (PARTITION BY name ORDER BY value DESC) < 3, split, 'Others') as n_split
FROM VALUES ('A','a', 100), ('A','b', 200), ('A','c',300), ('A', 'd', 400),
('A', 'e',500), ('B', 'a', 1000), ('B','b', 2000), ('B','c', 3000),
('B', 'd',4000), ('B','e', 5000)
v(name, split, value)
)
SELECT
name,
n_split AS split,
SUM(value) AS value
FROM data
GROUP BY name, n_split;
gives:
NAME SPLIT VALUE
A e 500
A d 400
A Others 600
B e 5000
B d 4000
B Others 6000
I need to write a stored procedure or table function to return a new data table as a new data source.
I wish to loop through the original table for every 5 rows base on the invoice ID column (it's possible not start from 1), the first 5 rows add to the left of the new table and the second 5 rows add to the right of the new table, the third 5 rows to the left and so on.
For example, Here is the original table:
Here is the expect table:
Thanks in advance!
declare #rowCount int = 5;
with cte as (
select *,( (IN_InvoiceID-1) / #rowCount ) % 2 group1
,( (IN_InvoiceID-1) / #rowCount ) group2
,IN_InvoiceID % #rowCount group3
from T
)
select * from cte
select T1.INID,T1.IN_InvoiceID,T1.IN_InvoiceAmount,T2.INID,T2.IN_InvoiceID,T2.IN_InvoiceAmount
from CTE T1
left join CTE T2 on T2.group1 = 1 and T1.group2 = T2.group2-1 and T1.group3 = T2.group3
where T1.group1 = 0
Test DDL
CREATE TABLE T
([INID] varchar(38), [IN_InvoiceID] int, [IN_InvoiceAmount] int)
;
INSERT INTO T
([INID], [IN_InvoiceID], [IN_InvoiceAmount])
VALUES
('DB3E17E6-35C5-41:121-93B1-F809BF6B2972', 1, 2999),
('3212F048-8213-4FCC-AB64-121485B77D4E43', 2, 3737),
('E3526373-A204-40F5-801C-7F8302A4E5E2', 3, 3175),
('76CC9C19-BF79-4E8A-8034-A33805AD3390', 4, 391),
('EC7A2FBC-B62D-4865-88DE-A8097975F125', 5, 1206),
('52AD3046-21331-4F0A-BD1D-67F232C54244', 6, 402),
('CA48F132-A9F5-4516-9E58-CDEE6644AAD1', 7, 1996),
('02E10C31-CAB2-4220-B66A-CEE5E67A9378', 8, 3906),
('98F1EEFF-B07A-4B65-87F4-E165264284DD', 9, 2575),
('91EBDD8B-B73C-470C-8900-DD66078483DB', 10, 2965),
('6E2490E5-C4DE-4833-877F-1590F7BDC1B8', 11, 1603),
('00985921-AC3C-4E3E-BAE1-7F58302F831A', 12, 1302)
;
Result:
Could you please check article Display Data in Multiple Columns using SQL showing with example case how a database developer can show the list of data rows in a columnar mode using Row_Number() function and mode arithmetic expression
You need to add additional columns from the same row that is different in the sample
Seems as if you want to split the table into 2 tables with alternating 5 rows. An easy way to do this would be:
Take data into a temp table having an extra column (lets say
grouping_id)
Update the grouping id so that each 5 rows have the same id. You can
use in_invoiceId % 5 (the nod function). After this step the first 5
rows will have grouping_id 0, next 5 will have 1, next will have 2
(assuming your invoice id is incremented +1 for all rows).
You can just do a normal select with where clause for odd and even grouping_id
Ideally, you can manage with the 2 tables Master and detail table.
But due to my curiosity, I am able to solve and give the answer as
Declare #table table(id int identity, invoice_id int)
; WITH Numbers AS
(
SELECT n = 1
UNION ALL
SELECT n + 1
FROM Numbers
WHERE n+1 <= 50
)
insert into #table SELECT n
FROM Numbers
Select (a.id )%5 ,* from #table a join #table b on a.id+5 = b.id and a.id != b.id
;WITH Numbers AS
(
SELECT n = 1, o = 5
UNION ALL
SELECT n + 10, o = o+10
FROM Numbers
WHERE n+1 <= 50
)
select a.id ParentId,a.invoice_id ParentInvoiceId, --b.n, b.o,
c.invoice_id childInvoiceID from #table a
join Numbers b on a.id between b.n and b.o
left join #table c on a.id + 5 = c.id
Here is my solution
First i create grps based on whether the in_invoiceid is divisible by 5 or not.(Ignore the remainders)
After that i create a category to indicate between alternative groups(ie by checking if the remainder is 0 or otherise)
Then its a matter of dense_ranking the records on the basis of the category field ordered by in_invoiceid
Lastly a join with category=1 rows with same dense_rank as those records in category=0
create table Invoicetable(IN_ID varchar(100), IN_InvoiceID int)
INSERT INTO Invoicetable (IN_ID, IN_InvoiceID)
VALUES
('2345-BCDE-6645-1DDF', 1),
('2345-BCDE-6645-3DDF', 2),
('2345-BCDE-6645-4DDF', 3),
('2345-BCDE-6645-5DDF', 4),
('2345-BCDE-6645-6DDF', 5),
('2345-BCDE-6645-7DDF', 6),
('2345-BCDE-6645-aDDF', 7),
('2345-BCDE-6645-sDDF', 8),
('2345-BCDE-6645-dDDF', 9),
('2345-BCDE-6645-dDDF', 10),
('2345-BCDE-6645-dDDF', 11),
('2345-BCDE-6645-dDDF', 12);
with data
as (
select *
,(in_invoiceid-1)/5 as grp
,case when ((in_invoiceid-1)/5)%2=0 then '1' else '0' end as category
,dense_rank() over(partition by case when ((in_invoiceid-1)/5)%2=0 then '1' else '0' end
order by in_invoiceid) as rnk
from invoicetable a
)
select *
from data a
left join data b
on a.rnk=b.rnk
and b.category=0
where a.category=1
Here is db fiddle link.
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=287f101737c580ca271940764b2536ae
You may try with the following approach. Dividing the table is done with (((ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) - 1) / 5) % 2 = 0) which groups records in left and right groups.
CREATE TABLE #InvoiceTable(
IN_ID varchar(24),
IN_InvoiceID int
)
INSERT INTO #InvoiceTable (IN_ID, IN_InvoiceID)
VALUES
('2345-BCDE-6645-1DDF', 1),
('2345-BCDE-6645-3DDF', 2),
('2345-BCDE-6645-4DDF', 3),
('2345-BCDE-6645-5DDF', 4),
('2345-BCDE-6645-6DDF', 5),
('2345-BCDE-6645-7DDF', 6),
('2345-BCDE-6645-aDDF', 7),
('2345-BCDE-6645-sDDF', 8),
('2345-BCDE-6645-dDDF', 9),
('2345-BCDE-6645-dDDF', 10),
('2345-BCDE-6645-dDDF', 11),
('2345-BCDE-6645-dDDF', 12);
WITH cte AS (
SELECT
IN_ID,
IN_InvoiceID,
CASE
WHEN (((ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) - 1) / 5) % 2 = 0) THEN 'L'
ELSE 'R'
END AS IN_Position
FROM #InvoiceTable
),
cteL AS (
SELECT IN_ID, IN_InvoiceID, ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) AS IN_RowNumber
FROM cte
WHERE IN_Position = 'L'
),
cteR AS (
SELECT IN_ID, IN_InvoiceID, ROW_NUMBER() OVER (ORDER BY IN_InvoiceID) AS IN_RowNumber
FROM cte
WHERE IN_Position = 'R'
)
SELECT cteL.IN_ID, cteL.IN_InvoiceID, cteR.IN_ID, cteR.IN_InvoiceID
FROM cteL
LEFT JOIN cteR ON (cteL.IN_RowNumber = cteR.IN_RowNumber)
Output:
IN_ID IN_InvoiceID IN_ID IN_InvoiceID
2345-BCDE-6645-1DDF 1 2345-BCDE-6645-7DDF 6
2345-BCDE-6645-3DDF 2 2345-BCDE-6645-aDDF 7
2345-BCDE-6645-4DDF 3 2345-BCDE-6645-sDDF 8
2345-BCDE-6645-5DDF 4 2345-BCDE-6645-dDDF 9
2345-BCDE-6645-6DDF 5 2345-BCDE-6645-dDDF 10
2345-BCDE-6645-dDDF 11 NULL NULL
2345-BCDE-6645-dDDF 12 NULL NULL
table
id name data
---------------
1 name1 data1
2 name2 data2
3 name3 data3
4 name4 data1abc
5 name5 data2abc
6 name6 data1abcd
7 name7 data2abcde
The output that I need is rows with ids 3, 6 and 7.
I need to search for distinct data terms. The terms data1, data1abc, data1abcd should all be counted as one term and the rows with unique most characters should be returned i.e., data1abcd, data2abcde, data3
Can you help please?
This is what I have written so far, it doesnt work:
SELECT *
FROM table
WHERE LEFT(data, 5) = (
SELECT distinct LEFT(data, 5)
FROM table
)
This will work for any string length:
select s
from (
select
s,
case
when s = left(lag(s) over (order by s desc), length(s))
then false else true
end as u
from t
) t
where u
order by s
;
s
------------
data1abcd
data2abcde
data3
Sample data:
create table t (id int, name text, s text);
insert into t (id, name, s) values
(1, 'name1', 'data1'),
(2, 'name2', 'data2'),
(3, 'name3', 'data3'),
(4, 'name4', 'data1abc'),
(5, 'name5', 'data2abc'),
(6, 'name6', 'data1abcd'),
(7, 'name7', 'data2abcde');
You could partition the rows by the first five characters and take the longest:
SELECT name, data
FROM (SELECT name,
data,
RANK() OVER (PARTITION BY LEFT(data, 5)
ORDER BY LENGTH(data) DESC) AS rk
FROM mytable) t
WHERE rk = 1
Note:
The rank function allows for ties (e.g., data1a and data1b have the same length, so they could both have the rank of 1 if there a no longer strings). If you do not want to allow for ties, you should use row_number instead.
It seems that you want distinct non-numeric values. You may change data_len as len(data_r) if you want the longest non-numeric records
ALTER TABLE <yourtable>
ADD
data_r as REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE (data, '0', ''),'1', ''),'2', ''),'3', ''),'4', ''),'5', ''),'6', ''),'7', ''),'8', ''),'9', '')
,data_len as len(data)
SELECT * FROM <yourtable> t
WHERE EXISTS ( SELECT MAX(data_len), data_r
FROM <yourtable> t1
WHERE t.data_r = t1.data_r
AND t.data_len = t1.data_len
GROUP BY data_r
)