SQL multiple records - sql

Question

I have source table as shown below:
ID Status State_id
X Active 1
X Active 2
X Active 3
X Active 4
Y Active 2
Y Active 3
Z Active 1
Z Active 2
Z Active 3
A Active 2
A Active 3
I need 2 output based on State_id 2,3.
Set 1 for having only 2,3 state_id
ID Status
Y Active
A Active
Set 2 for having additional state id with 2,3
ID Status
X Active
Z Active

Answer 1

You can use this scripts.
Set 1
SELECT
ID, Status
FROM
#Tbl T
GROUP BY
ID, Status
HAVING
SUM(CASE WHEN State_id IN (2,3) THEN 1 ELSE 0 END) = 2
AND SUM(CASE WHEN State_id IN (2,3) THEN 0 ELSE 1 END) = 0
Result:
ID Status
---- ----------
A Active
Y Active
Set 2
SELECT
ID, Status
FROM
#Tbl T
GROUP BY
ID, Status
HAVING
SUM(CASE WHEN State_id IN (2,3) THEN 1 ELSE 0 END) = 2
AND SUM(CASE WHEN State_id IN (2,3) THEN 0 ELSE 1 END) > 0
Result:
ID Status
---- ----------
X Active
Z Active

Answer 2

/*Set 1*/
select t1.id, t1.status
from table1 t1
where t1.state_id in (2, 3) /*ids you want */
and t1.id not in ((
select distinct t2.id
from table1 t2
where t2.state_id in (1, 4) /*ids you dont want*/
))
group by t1.id, t1.status
Just flip the IDs to get set 2

Answer 3

I think it should give you expected result.
Updated
SqlFiddle
--Set 1
SELECT id ,status
FROM table1
-- WHERE status='Active'
GROUP BY id ,status
HAVING COUNT(DISTINCT state_id) =count(DISTINCT CASE WHEN state_id IN (2,3) THEN state_id END) ;
--Set2
SELECT id ,status
FROM table1
GROUP BY id ,status
HAVING COUNT(DISTINCT state_id)>count(DISTINCT CASE WHEN state_id IN (2,3)
THEN state_id END)
AND COUNT(DISTINCT CASE WHEN state_id IN (2,3) THEN state_id END) =2;