Moving Column names to rows - sql

Question

I have such a table with date as column name
but I would like to have these dates in one column in more than one row something like this:
Date Index
20170806 9206
20170813 8041
20170820 8861
20170827 8356
How can I do it in SQL Server

Answer 1

If you would like to go for more dynamic solution rather than hard coding all columns, the below scripts should work:
IF OBJECT_ID('TestTable') IS NOT NULL
DROP TABLE TestTable;
CREATE TABLE TestTable
(
[20170806] INT NOT NULL,
[20170813] INT NOT NULL,
[20170820] INT NOT NULL,
[20170827] INT NOT NULL
)
INSERT INTO TestTable VALUES (9206, 8041, 8861, 8356)
DECLARE #cols NVARCHAR(MAX),
#sql NVARCHAR(MAX)
SELECT #cols = COALESCE(#cols + ',', '') + QUOTENAME(c.COLUMN_NAME)
FROM INFORMATION_SCHEMA.[COLUMNS] AS c
WHERE c.TABLE_NAME = 'TestTable'
SET #sql = '
SELECT [Date],
[Index]
FROM TestTable
UNPIVOT([Index] FOR [Date] IN ('+ #cols +')) AS up'
exec sp_executesql #sql;

Answer 2

You can use UNPIVOT for this.
SELECT * FROM MyTable
UNPIVOT([Date] For [Index] IN( [20170806], [20170813], [20170820], [20170827])) UNPVT
In addition, if you want to make it dynamically, you can use this query too.
DECLARE #ColNames NVARCHAR(MAX)
= STUFF(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(
(SELECT T.* FROM (VALUES(1)) AS DUMY(ID) LEFT JOIN MyTable T ON 1=2 FOR XML AUTO, ELEMENTS XSINIL )
,'<T xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">','')
,'</T>','')
,'_x0032_','2')
,' xsi:nil="true"/>','] ')
,'<',',[') ,1,1,'')
DECLARE #SqlQ NVARCHAR(MAX)
= 'SELECT * FROM MyTable UNPIVOT([Date] For [Index] IN( ' + #ColNames + ')) UNPVT'
EXEC sp_executesql #SqlQ

Answer 3

You could use pivot such as:
However, i dont know your exact table names
select field_names
from table_name
pivot
( index
for index in ( Date, Index)
) pivot
but a useful article to follow is
"https://technet.microsoft.com/en-us/library/ms177410(v=sql.105).aspx"

Answer 4

Designed the table (variable) structure as below.
Hopefully, it matches your table structure.
DECLARE #data TABLE
(
[20170806] INT,
[20170813] INT,
[20170820] INT,
[20170827] INT
)
INSERT INTO #data VALUES (9206, 8041, 8861, 8356)
SELECT * FROM #data
You can use UNPIVOT statement for this. If you have dynamic columns, check this.
SELECT [Date],[Index]
FROM
#data
UNPIVOT
(
[Index] FOR [Date] IN ([20170806], [20170813], [20170820], [20170827])
) AS unpivotTable;
and the output is