I use renderPartial to view CRUD in my frontend/index.php. but its giving error
PHP Recoverable Error – yii\base\ErrorException
Object of class yii\web\Response could not be converted to string
here is code C:\xampp\htdocs\yii2-my-app\frontend\views\site\index.php
<?= Yii::$app->runAction('/callback/create'); ?>
C:\xampp\htdocs\yii2-my-app\frontend\controllers\CallbackController.php
public function actionCreate()
{
$model = new Callback();
if ($model->load(Yii::$app->request->post()) && $model->save()) {
return $this->redirect(['view', 'id' => $model->id]);
} else {
return $this->renderPartial('create', [
'model' => $model,
]);
}
}
how to fix that error can anybody help?
public function actionCreate()
{
$model = new Callback();
if ($model->load(Yii::$app->request->post()) && $model->save()) {
$model = new Callback();
return $this->renderPartial('create', [
'model' => $model,
]);}
}
Related
As the title says, i have a little bit of trouble in this area of the application. So basically, in my UserController i hash the password & in the login page it's verified with the standard security tool. Everything from the form to the user is good, but the check fails to return true. I don't have any interactions with the password in beforeSave/beforeValidate. Any ideas?
UserController:
public function actionRegister()
{
$model = new User(['scenario' => 'register']);
if ($model->load(Yii::$app->request->post()) && $model->validate()) {
$model->password_usr = Yii::$app->security->generatePasswordHash($model->password_usr);
if ($model->save()) {
Yii::$app->session->setFlash('success', 'User created');
return $this->redirect('/site/login');
} else {
die(print_r($model->getErrors()));
}
}
return $this->render('register', [
'model' => $model,
]);
}
SiteController:
public function actionLogin()
{
if (!Yii::$app->user->isGuest) {
return $this->goHome();
}
$model = new LoginForm();
if ($model->load(Yii::$app->request->post()) && $model->validate()) {
$model->login();
return $this->goBack();
}
$model->password = '';
return $this->render('login', [
'model' => $model,
]);
}
User model:
public function validatePassword($password)
{
return Yii::$app->security->validatePassword($password, $this->password_usr);
}
Login form is the default as the yii2 generates
Maybe this is a problem
die(print_r($model->getErrors()));
login
public function actionLogin()
{
$this->layout = "login";
if (!Yii::$app->user->isGuest) {
return $this->goHome();
}
$model = new LoginForm();
if ($model->load(Yii::$app->request->post()) && $model->login()) {
return $this->goBack();
} else {
$model->password = '';
}
return $this->render('login', [
'model' => $model,
]);
}
signup
public function actionSignup()
{
$this->layout = "login";
$model = new SignupForm();
if ($model->load(Yii::$app->request->post())) {
if ($user = $model->signup()) {
if (Yii::$app->getUser()->login($user)) {
return $this->goHome();
}
}
}
return $this->render('signup', [
'model' => $model,
]);
}
the problem was the password field in the database, it was varchar(30) whilst generatePasswordHash returns a 60 char string
I have the below code in studentsController.php to add data to 2 tables from a form but im getting error. It is to add to students table, then add some data to the users table too. I feel i'm supposed to add something at the top via "use' keyword but I don't know.please help.
public function actionCreate() {
$model = new model();
$user = new Users();
if ($model->load(Yii::$app->request->post())) {
$model->id = Yii::$app->generateid->getGUID(); //this line caused the error
$model->save();
$studentId = $model->id;
if($user->load(Yii::$app->request->post()))
{
$user->id = $model->id;
$user->firstname = $model->firstname;
$user->lastname = $model->lastname;
$user->username = $model->phone;
$user->password = 'pass123'; //default password
$user->role = 'student';
$user->save(false);
}
return $this->redirect(['view', 'id' => $model->id]);
} else {
return $this->render('create', [
'model' => $model,
'user' => $user,
]);
}
}
You seem to miss generateid in your web.php
It should be something like this
GenerateIDs.php inside #app/components folder
<?php
namespace app\components;
class GenerateIDs extends \yii\base\Component
{
public function getGUID()
{
//do your stuff here
}
//....
}
then in your #app/config/web.php you have something like
<?php
return [
'components' => [
'generateid' => [
'class'=>'app\components\GenerateIDs',
// other configurations for the component
],
],
];
then you can use it in your app as you wish
public function actionCreate() {
$model = new model();
$user = new Users();
if ($model->load(Yii::$app->request->post())) {
$model->id = Yii::$app->generateid->getGUID(); //this line caused the error
$model->save();
$studentId = $model->id;
if($user->load(Yii::$app->request->post()))
{
$user->id = $model->id;
$user->firstname = $model->firstname;
$user->lastname = $model->lastname;
$user->username = $model->phone;
$user->password = 'pass123'; //default password
$user->role = 'student';
$user->save(false);
}
return $this->redirect(['view', 'id' => $model->id]);
} else {
return $this->render('create', [
'model' => $model,
'user' => $user,
]);
}
Please take a look at Yii2 guide on Components
This is a model Method
public function setTerritories($territories)
{
$t = Territory::find()->where(['id' => $territories])->all();
$this->populateRelation('territories', $t);
}
The controller is simple
public function actionUpdate($id)
{
$model = $this->findModel($id);
$model->scenario = 'update';
if ($model->load(Yii::$app->request->post()) && $model->save()) {
return $this->redirect(['view', 'id' => $model->id]);
} else {
return $this->render('update', [
'model' => $model,
]);
}
}
The relation is filled; if I var_dump($model->territories); it shows needed models, but after save they're not attached.
Why doesn't populateRelation save the data?
i try to save multilanguaged content
My About model
...
public function rules() {
return [
[['status', 'date_update', 'date_create'], 'integer'],
[['date_update', 'date_create'], 'required'],
];
}
...
public function getContent($lang_id = null) {
$lang_id = ($lang_id === null) ? Lang::getCurrent()->id : $lang_id;
return $this->hasOne(AboutLang::className(), ['post_id' => 'id'])->where('lang_id = :lang_id', [':lang_id' => $lang_id]);
}
My AboutLang model
public function rules()
{
return [
[['post_id', 'lang_id', 'title', 'content'], 'required'],
[['post_id', 'lang_id'], 'integer'],
[['title', 'content'], 'string'],
];
}
My About controller
public function actionCreate()
{
$model = new About();
$aboutLang = new AboutLang();
if ($model->load(Yii::$app->request->post()) && $model->save()) {
return $this->redirect(['view', 'id' => $model->id]);
} else {
return $this->render('create', [
'model' => $model,'aboutLang'=>$aboutLang]);
}
}
and my view (create form)
...
<?= $form->field($model, 'status')->textInput() ?>
<?= $form->field($aboutLang, 'title')->textInput() ?>
<?= $form->field($aboutLang, 'content')->textInput() ?>
enter code here
And when i put $aboutLang in create form i get an error "Call to a member function formName() on a non-object"
It looks like the views you are using were generated by Gii. In that case, Gii generates a partial view for the form (_form.php) and two views both for create and update actions (create.php and update.php). These two views perform a rendering of the partial view.
The problem you might have is that you are not passing the variable $aboutLang from create.php to _form.php, that must be done in create.php, when you call renderPartial():
$this->renderPartial("_form", array(
"model" => $model,
"aboutLang" => $aboutLang, //Add this line
));
Hope it helps.
Check your $aboutLang type.
It looks like it is null.
if ($aboutLang) {
echo $form->field($aboutLang, 'title')->textInput();
echo $form->field($aboutLang, 'content')->textInput();
}
I am trying to fetch my category model in zend form for working out with select element with zend framework 2.
after lot of code searching I found I can either inject or pull dependencies.
Following code I did in my module.php
I want categoryTable.php(model) file in my CategoryForm.php
public function getServiceConfig()
{
return array(
'factories' => array(
'Category\Model\CategoryTable' => function($sm) {
$tableGateway = $sm->get('CategoryTableGateway');
$table = new CategoryTable($tableGateway);
//echo "<pre>";print_r($table);echo "</pre>";
return $table;
},
'CategoryTableGateway' => function ($sm) {
$dbAdapter = $sm->get('Zend\Db\Adapter\Adapter');
$resultSetPrototype = new ResultSet();
$resultSetPrototype->setArrayObjectPrototype(new Category());
return new TableGateway('Of_Restaurants_Category', $dbAdapter, null, $resultSetPrototype);
},
'Category\Form\CategoryForm' => function ($sm) {
$service = $sm->get('Category\Model\CategoryTable');
$form = new Form;
$form->setService($service);
return $form;
}
),
);
}
then I put following code in my controller.
$form = $this->getServiceLocator()->get("Category\Form\CategoryForm");
Then I Put following code in my CategoryForm.php
public function getCategoryTable()
{
if (!$this->categoryTable) {
$sm = $this->getServiceLocator();
$this->categoryTable = $sm->get('Category\Model\CategoryTable');
}
return $this->categoryTable;
}
And then I call it in same file like this way
public function __construct($name = null)
{
parent::__construct('category');
echo "<pre>";print_r($this->getCategoryTable());die;
.... other code
I found this error
Fatal error: Call to undefined method Category\Form\CategoryForm::getServiceLocator() in D:\wamp\www\zendapp\module\Category\src\Category\Form\CategoryForm.php on line 120
please help. and am I missing something?
I found the solution
Step :1
Here is my module.php code
public function getServiceConfig()
{
return array(
'invokables' => array(
'Category\Form\CategoryForm' => 'Category\Form\CategoryForm',
),
'factories' => array(
'Category\Model\CategoryTable' => function($sm) {
$tableGateway = $sm->get('CategoryTableGateway');
$table = new CategoryTable($tableGateway);
//echo "<pre>";print_r($table);echo "</pre>";
return $table;
},
'CategoryTableGateway' => function ($sm) {
$dbAdapter = $sm->get('Zend\Db\Adapter\Adapter');
$resultSetPrototype = new ResultSet();
$resultSetPrototype->setArrayObjectPrototype(new Category());
return new TableGateway('Of_Restaurants_Category', $dbAdapter, null, $resultSetPrototype);
},
),
);
}
Step :2
Then in controller I made this change
// $form = new CategoryForm();
// Service locator now injected
$form = $this->getServiceLocator()->get('Category\Form\CategoryForm');
Step :3
Then In my categoryForm.php I made below changes
use Zend\ServiceManager\ServiceManager;
use Zend\ServiceManager\ServiceManagerAwareInterface;
protected $serviceManager;
public function getCategoryTable()
{
if (!$this->categoryTable) {
$sm = $this->getServiceManager();
$this->categoryTable = $sm->get('Category\Model\CategoryTable');
}
return $this->categoryTable;
}
protected function getCatList()
{
$groups = $this->getCategoryTable()->fetchAll();
return $groups;
}
public function getServiceManager()
{
if ( is_null($this->serviceManager) ) {
throw new Exception('The ServiceManager has not been set.');
}
return $this->serviceManager;
}
public function setServiceManager(ServiceManager $serviceManager)
{
$this->serviceManager = $serviceManager;
// Call the init function of the form once the service manager is set
$this->init();
return $this;
}
public function __construct($name = null) // constructor I finished immediately
{
parent::__construct('category');
}
I add INIT() function to fetch servicemanager
public function init()
{
$this->setAttribute('method', 'post');
$options = array();
foreach ($this->getCatList() as $cat) {
$options[$cat->id] = $cat->title;
}
$this->add(array(
'type' => 'Zend\Form\Element\Select',
'name' => 'parent_id',
'options' => array(
'label' => 'Parent Category',
'empty_option' => 'Please choose Parent Category',
'value_options' => $options,
),
));
}
Hope this will help who are new ZF2.