Sql substring using "/" as indicator where to cut - sql

Question

Hi I want to cut a string in sql at 2 points with the "/" as an indicator where to cut. The string looks like this: "test1/test2/test3/test4/test5/test6" and I need the parts of test 2 and test 5 but they are not static, so I have to use the "/" befor and after them to set the points where to cut, any suggestions?

Answer 1

You could achieve this by using XML:
DECLARE #x NVARCHAR(100) = 'test1/test2/test3/test4/test5/test6';
DECLARE #xml XML = cast(('<X>'+replace(#x,'/' ,'</X><X>')+'</X>') as xml);
WITH cte AS(
SELECT N.value('.', 'varchar(10)') as value, ROW_NUMBER() OVER (ORDER BY (SELECT(0))) AS rn
FROM #xml.nodes('X') as T(N)
)
SELECT *
FROM cte
WHERE rn IN (1, 5)

Answer 2

You can use the function CHARINDEX()
For example this query will work for you
declare #text varchar(100)='test1/test2/test3/test4/test5/test6'
select
SUBSTRING (#text,CHARINDEX('/',#text)+1,CHARINDEX('/',#text,(CHARINDEX('/',#text)+1))-CHARINDEX('/',#text)-1),
SUBSTRING (#text,CHARINDEX('/',#text,CHARINDEX('/',#text,CHARINDEX('/',#text,CHARINDEX('/',#text)+1)+1)+1)+1,CHARINDEX('/',#text,(CHARINDEX('/',#text)+1))-CHARINDEX('/',#text)-1)
Just incase you want to substring something else, I'm sharing the code below and then you can work on it
declare #text varchar(100)='test1/test2/test3/test4/test5/test6'
select
SUBSTRING (#text,CHARINDEX('/',#text)+1,CHARINDEX('/',#text,(CHARINDEX('/',#text)+1))-CHARINDEX('/',#text)-1) --test2
,SUBSTRING (#text,CHARINDEX('/',#text,CHARINDEX('/',#text)+1)+1,CHARINDEX('/',#text,(CHARINDEX('/',#text)+1))-CHARINDEX('/',#text)-1) --test3
,SUBSTRING (#text,CHARINDEX('/',#text,CHARINDEX('/',#text,CHARINDEX('/',#text)+1)+1)+1,CHARINDEX('/',#text,(CHARINDEX('/',#text)+1))-CHARINDEX('/',#text)-1) --test4
,SUBSTRING (#text,CHARINDEX('/',#text,CHARINDEX('/',#text,CHARINDEX('/',#text,CHARINDEX('/',#text)+1)+1)+1)+1,CHARINDEX('/',#text,(CHARINDEX('/',#text)+1))-CHARINDEX('/',#text)-1) --test5

Answer 3

If the items that you want are always the second and the second to last you can use CHARINDEX to find the first and second '/' and SUBSTRING to pull that value. Then REVERSE the string to get the second last. e.g.
DECLARE #data varchar(128) = 'test1/test2/test3/test4/test5/test6';
SELECT substring(#data,charindex('/',#data,1)+1,charindex('/',#data,charindex('/',#data,1)+1)-(charindex('/',#data,1)+1)),
reverse(substring(reverse(#data),charindex('/',reverse(#data),1)+1,charindex('/',reverse(#data),charindex('/',reverse(#data),1)+1)-(charindex('/',reverse(#data),1)+1)))