I need a bit help.
I want to split decimal and character in a string.
Eg : 0.5Lg ---> 0.5 separate and Lg separate.
0.22Ldd --->0.22 separate and Ldd Separate
I tried Following:
Dim input As String = "0.22Ldd"
Dim pattern As String = "[^0-9\.]+"
Dim substrings() As String = Regex.Split(input, pattern)
TextBox11.Text = substrings(0)
This gives output of 0.22 but how to extract Ldd part?
I tried replacing pattern with "\D+" and "\d+" and "\W+" and [a-zA-Z]+ etc etc after googling but no luck.
Can somebody help. I have googled a lot either output comes along with dot or along with number.
You can use this LINQ approach:
Dim input As String = "0.22Ldd"
Dim numericPart = input.TakeWhile(Function(c) Char.IsPunctuation(c) orelse Char.IsDigit(c)).ToArray()
Dim number as Decimal
Dim validNumber = Decimal.TryParse(new String(numericPart), NumberStyles.Any, NumberFormatInfo.InvariantInfo, number)
Dim letterPart As String = input.Substring(numericPart.Length)
if you want to split them with regex you can try pattern below. Regex.Split gives you matching patterns so you should check for number pattern and text pattern in single regex expression.
Dim pattern As String = "([a-zA-Z]*)([0-9]*[.]?[0-9]+)"
Related
I have a file name like below:
sub_fa__hotchkis_type1a__180310__PUO4x4__180813
I want to separate it with double underscores "__" and using this code:
Dim MdlNameArr() As String = Path.GetFileNameWithoutExtension(strProjMdlName).Split(New Char() {"__"}, StringSplitOptions.RemoveEmptyEntries)
myTool.Label9.Text = MdlNameArr(1).ToString
I expect the result will be "hotchkis_type1a" but it returns "fa".
It doesnt recognize single underscore "_".
Is there any method to use it properly?
You need to split on a string rather than just a character, so if we look at the available overloads for String.Split, we find the nearest one to that is String.Split(string(), options) which takes an array of strings as the separators and requires the inclusion of StringSplitOptions like this:
Dim s = "sub_fa__hotchkis_type1a__180310__PUO4x4__180813"
Dim separators() As String = {"__"}
Dim parts = s.Split(separators, StringSplitOptions.None)
If parts.Length >= 2 Then
Console.WriteLine(parts(1))
Else
Console.WriteLine("Not enough parts found.")
End If
Outputs:
hotchkis_type1a
I have many strings that have numbers at the end. The numbers can be of any size, for example:
myvar123
mysecondvar3
mythirdvar219107
The strings can have numbers even inside the name, not only at the end.
for example:
my2varable123
some123variable9480395
I would need to replace any number at the END with a placeholder. (NOT those inside the varname.)
for example:
my2varable123 should become: my2variable%placeholder%
some123variable9480395 should become: some123variable%placeholder%
The only way that comes to my mind is to go through the string using .right() and remove the char if it is numeric until I find the first non numeric char. Then in the end append the placeholder, but it looks like a lot of work for a rather simply problem.
Is there a better way to do this?
You could use a Regex for this.
Dim str As String = "some123variable9480395"
Dim pattern As String = "\d+$"
Dim replacement As String = "%placeholder%"
Dim rgx As Regex = New Regex(pattern)
Dim result As String = rgx.Replace(str, replacement)
i have two example
"hcg.com.ph?C402-10A-2012-06132017-22"
"hcg.com.?C3032-1B-2012-06132017-1"
output should be
hcg.com.ph?C402-10A-2012-06132017
hcg.com.?C3032-1B-2012-06132017
but i got
hcg.com.ph?C402 and hcg.com.?C3032
Dim FinalSplt() As String
Dim ItemBaseCode As String
FinalSplt = value.ToString.Split("-")
ItemBaseCode = FinalSplt(0)
How to split in the last dash?
Here is some code that uses Substring and LastIndexOf.
'test input
Dim si() As String = {"hcg.com.ph?C402-10A-2012-06132017-22", "hcg.com.?C3032-1B-2012-06132017-1"}
'use to verify
Dim sv() As String = {"hcg.com.ph?C402-10A-2012-06132017", "hcg.com.?C3032-1B-2012-06132017"}
For x As Integer = 0 To si.Length - 1
Dim s As String = si(x).Substring(0, si(x).LastIndexOf("-"c))
'verify
If s = sv(x) Then
Stop 'verified
End If
Next
Ok, without actually writing code I can see you need to split the string more efficiently.
Firstly, strip the quotes.
Secondly, split the string based on the ? mark.
Take the second string in the array, and split that based on the - mark.
Now you have an array of all the portions, join this array with all except the last element.
Join the new string with the original first part.
Add the quotes back if needed.
My code retrieves the data from various resources .
And output will be like below
UNY4/4/2010
hds04/5/2010
saths04/22/2013
But I want the output like this
4/4/2010
4/5/2010
04/22/2013
Is there any way to do this ?
You need to use a regular expression that finds all uppercase and lowercase characters and replaces them with a blank, like this:
Dim rgx As New Regex("[a-zA-Z]")
str = rgx.Replace(str, String.Empty)
An alternate solution is to look for the first numeric digit, then discard all text before that.
Function GetDate(data As String) As Date
Dim indexFirstNum As Integer = data.IndexOfAny("0123456789".ToCharArray())
Dim datePortion As String = data.Substring(indexFirstNum)
Return Date.Parse(datePortion)
End Function
I have a string, for example:
Dim str as string = xxxxxxxxxxxxxxxxxxxx£xxx£xxxx**£**xxxxxxxxxx
I want to remove £ surrounded from * which is always at a certain position (11th for instance) from the end. The whole string is a long one, always change in size and cannot be counted from the start. I cannot use Replace as well, there may be same characters at other positions that I do not wish to remove.
Solution:
Dim rst As String = str.Remove(str.Length - 11, 1)
Edit: Whoops, I dunno what I was thinking on that first part.
The correct version of the first part would be:
str = str.Substring(0, str.Len -13) + str.Substring(str.Len-11);
There also may be an overload for the String.Delete function that allows you to use a negative number to represent the number of characters from the end of the string -- I know that the C# equivalent does.
If its always going to be the 11th character from the end you can do this...
Dim strTargetString As String = "xxxYxxxxxxxxxx"
Dim strTargetString2 As String = "xxxxxxxYxxxxxxxxxx"
Dim strResult As String = Mid(strTargetString, 1, (Len(strTargetString) - 11)) & Microsoft.VisualBasic.Right(strTargetString, 10)
Dim strResult2 As String = Mid(strTargetString2, 1, (Len(strTargetString2) - 11)) & Microsoft.VisualBasic.Right(strTargetString, 10)
Note that String.SubString is a more modern approach than Mid, but I use it out of preference and example.
This is fairly straightforward with a regular expression replacement operation using look-ahead:
Dim str as String = "xxxxxxxxxxxxxxxxxxxx£xxx£xxxx£xxxxxxxxxx"
Dim str2 as String = Regex.Replace(str, "£(?=.{10}$)", String.Empty)
This will target a single character followed by any ten characters then the end of the string and replace it with the String.Empty value (or just "" if you'd prefer).