Split function in HIVE - hive

Question

I want to split the address into two columns as streetno and streetname, say for ex
select address1 from customer
address for ex-look like
2719 STONE CREEK DR
and store them into street no as 2719 and streetname as STONE CREEK DR.
using split(address1 ,'[\ ]')[0] just split the street no only.
it's just select statement we are using to view the data.
Sample data:
address1
100 HORACE GREELEY RD
55 School Street
2893 MASHIE CIR
1200 JEWEL DR
201 W RIVER RD
Expected output
+--------------+---------------------+
| streetnumber | streetname |
+--------------+---------------------+
| 100 | HORACE GREELEY RD |
| 55 | School Street |
| 2893 | MASHIE CIR |
| 1200 | JEWEL DR |
| 201 | W RIVER RD |
+--------------+---------------------+

Answer 1

select regexp_extract(address1,'(.*?)\\s',1) as streetnumber
,regexp_extract(address1,'\\s(.*)' ,1) as streetname
from mytable
;
+----------------+--------------------+
| streetnumber | streetname |
+----------------+--------------------+
| 100 | HORACE GREELEY RD |
| 55 | School Street |
| 2893 | MASHIE CIR |
| 1200 | JEWEL DR |
| 201 | W RIVER RD |
+----------------+--------------------+
or
select regexp_extract(address1,'.*?(?=\\s)',0) as streetnumber
,regexp_extract(address1,'(?<=\\s).*',0) as streetname
from mytable
;
+----------------+--------------------+
| streetnumber | streetname |
+----------------+--------------------+
| 100 | HORACE GREELEY RD |
| 55 | School Street |
| 2893 | MASHIE CIR |
| 1200 | JEWEL DR |
| 201 | W RIVER RD |
+----------------+--------------------+
or
select split(address1,'\\s')[0] as streetnumber
,split(address1,'^.*?\\s')[1] as streetname
from mytable
;
+----------------+--------------------+
| streetnumber | streetname |
+----------------+--------------------+
| 100 | HORACE GREELEY RD |
| 55 | School Street |
| 2893 | MASHIE CIR |
| 1200 | JEWEL DR |
| 201 | W RIVER RD |
+----------------+--------------------+