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I need to create a trigger in SQL Server 2017 that will fire on INSERT and work off the CreatedDate column of my table.
The CreatedDate is of this format: 2017-09-21 07:15:59.883
What I want to do is check the time of the CreatedDate column and if it is between 7 and 8 I need to insert a value into a Notes column, if it is between 15 and 16 I need to insert another, if it is between 23 and 24 I need to insert another.
I am particularly stuck at the WHERE clause that I need to check the hour for. Not sure how to formulate this.
assuming your CreatedDate is datetime and not string
use datepart to checks for createdate hour and update the Notes column accordingly
UPDATE t
SET Notes = 'a value'
FROM inserted i
INNER JOIN mytable t ON i.pk = t.pk
WHERE datepart(hour, CreateDate) in (7, 8)
EDIT :
UPDATE t
SET Notes = case when datepart(hour, CreateDate) in ( 7, 8) then 'a value'
when datepart(hour, CreateDate) in (15, 16) then 'another value'
end
FROM inserted i
INNER JOIN mytable t ON i.pk = t.pk
WHERE datepart(hour, CreateDate) in (7, 8, 15, 16)
See datepart
where case when DATEPART ( HOUR, datetimeField ) =7 then someValue
case when DATEPART ( HOUR, datetimeField ) =15 then SomeOtherValue
case when DATEPART ( HOUR, datetimeField ) =23 then AnotherDiffetentValue
end
You can use DATEPART: https://learn.microsoft.com/en-us/sql/t-sql/functions/datepart-transact-sql
and CASE: https://learn.microsoft.com/en-us/sql/t-sql/language-elements/case-transact-sql
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For example DECLARE #a = 10;
Required output be like:
1) 16/5/2020
2) 15/5/2020
3) 14/5/2020
4) 13/5/2020
5) 12/5/2020
6) 11/5/2020
7) 10/5/2020
8) 9/5/2020
9) 8/5/2020
10) 7/5/2020
If Declare #b = 5 then get last five days of dates in output.
Snowflake:
SELECT DATEADD(DAY, -SEQ4(), CURRENT_DATE()) AS generated_date
FROM TABLE(GENERATOR(ROWCOUNT=>10))
ORDER BY generated_date desc;
SEQn() functions are not guaranteed to be gap free, so you need to use ROW_NUMBER()
WITH tally AS (
SELECT ROW_NUMBER() OVER(ORDER BY SEQ4()) AS rn
FROM TABLE(GENERATOR(ROWCOUNT=>10))
)
SELECT DATEADD(DAY, -rn, CURRENT_DATE()) AS generated_date
FROM tally
ORDER BY generated_date
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I have the below query which works, however it seems very untidy and inefficient to me.
My table has two columns: TDate & Sales
TDate Sales
2016-03-25 5
2016-03-24 8
2016-03-28 7
2016-04-21 2
2016-04-14 1
I want to group the data by year and month, i.e. i don't care about the day part of the date. The result (which the query below does give) is,
TDate Sales
201603 20
201604 3
What is the best way to achieve this?
select left(convert(nvarchar, TDate, 112),6), sum(Sales)
from mytbl
group by left(convert(nvarchar, TDate, 112),6)
order by left(convert(nvarchar, TDate, 112),6)
convert the dates to first day(any static day) of month and do the grouping
Here is one way using EOMONTH
select dateadd(dd,1,eomonth(TDate,-1)) as Tdate,sum(sales)
from mytbl
Group by dateadd(dd,1,eomonth(TDate,-1))
Order by Tdate
or use DATEFROMPARTS
select DATEFROMPARTS(year(TDate),month(TDate),1)) as Tdate,sum(sales)
from mytbl
Group by DATEFROMPARTS(year(TDate),month(TDate),1))
Order by Tdate
This will make sure the dates are properly ordered. In your approach the dates are ordered as string. Both approaches work on Sql Server 2012 and above
For older versions
select DATEADD(mm, DATEDIFF(mm,0,TDate), 0) as Tdate,sum(sales)
from mytbl
Group by DATEADD(mm, DATEDIFF(mm,0,TDate), 0)
Order by Tdate
For me your query is OK but, maybe use of DATEPART instead of string conversion can be result more efficient as time spent.
Try this:
select DATEPART(year, TDate) *100 + DATEPART(month, TDate), sum(Sales)
from mytbl
group by DATEPART(year, TDate) *100 + DATEPART(month, TDate)
order by DATEPART(year, TDate) *100 + DATEPART(month, TDate)
Wrap your original query up in a derived table to save some typing, and also make it ANSI SQL compliant:
select TDate, sum(Sales)
from
(
select left(convert(nvarchar, TDate, 112),6) TDate, Sales
from mytbl
) dt
group by TDate
order by TDate
This way you don't have to write the same expression three times! (I.e. easier to adjust/maintain.)
(Same trick can be used for the other answers to the question.)
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I have a table to stores expiry dates of credit cards, below is the sample schema for table.
ExpiryDate Varchar(10)
Sample Data in Table is as follows:-
'08/10'
'09/11'
'08/16'
'10/17'
how can i find out if a card's date is expired?
I am not sure what you are expected, but You can use string manipulation with substring to get records those are not expired
Select *
FROM supportContacts
WHERE LEFT(ExpiryDate,2) >= MONTH(GETDATE()) AND RIGHT(ExpiryDate,2) >= RIGHT(YEAR(GETDATE()),2)
If you want expired card list then use this
Select *
FROM supportContacts
WHERE LEFT(ExpiryDate,2) < MONTH(GETDATE()) AND RIGHT(ExpiryDate,2) <= RIGHT(YEAR(GETDATE()),2)
SQL DEMO
With such an awful data structure you are forced to kludge this together. Here is one way of doing it.
with BadData as
(
select '08/10' as SemiDate union all
select '09/11' union all
select '08/16' union all
select '10/17'
)
select *
from BadData
where cast(replace(STUFF(SemiDate, 4, 0, '01-20'), '/', '-') as DATE) < CAST(getdate() as DATE)
If you stored the ExpirationDate as a date instead of a string this would be simple. I sure hope you aren't storing the credit card number alongside this.
select *
from billinginfo
where substring(expirydate,1,charindex('/',expirydate)-1) < month(getdate())
and '20'+ substring(expirydate,charindex('/',expirydate)+1, 2) <= year(getdate())
You can try this.
You want something like this:
select * from BillingInfo
where
cast(left(expiryDate, 2) as int) --take the month portion of the expiry date
< select datepart(mm, getdate()) --expiry month must be before current month
and
cast(right(expiryDate, 2) as int) --take the year portion of the expiry date
<= select datepart(yy, getdate()) % 1000 --expiry year must also be during or before current year
The % 1000 converts the year to two-digit format.
I guess you want this:
SELECT TOP 4 *
FROM BillingInfo
WHERE ExpiryDate in ('08/10','09/11','08/16','10/17')
This will find you the 4 items with those dates.
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I have a requirement, there is a table CR. Type is a field here. Now it has values like A,B,C. I need separate counts for CR records having type A in month Jan,Feb,...Dec 2013.Same for Type B and C in SQL SERVER 2008. A, B, C will be column headers and count of each for a month-year combination comes under it.
Can someone help me here?
You need google first before asking this...
SELECT * FROM
(SELECT type, datepart(mm, date) month, count(1) cn
FROM CR
WHERE datepart(yyyy, date) = '2013'
GROUP BY type, datepart(mm, date)
) AS t
PIVOT(MIN(cn) FOR type IN ([A], [B], [C])) AS m
Assuming that the CR table have a datetime field called dat you can GROUP BY MONTH in this way :
SELECT DATEPART(Month, dat) AS month, Type
FROM CR
WHERE DATEPART(Year, dat) = 2013
GROUP BY Type , DATEPART(Year, dat), DATEPART(Month, dat)
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
SQL Group and Sum By Month - Default to Zero
In my table, i am not having record for some months and year, so i need to put '0' for that records and need to show all months and year from '2006' to '2012' in result, please suggest me
Thanks in advance
dummy is your real table ...
WITH DummyDates (Date) AS (
SELECT DATEADD(DAY, DATEDIFF(DAY, 0, '20121231') - DATEDIFF(DAY, '20060101', '20121231'), 0)
UNION ALL SELECT DATEADD(DAY, 1, Date)
FROM DummyDates
WHERE DATEADD(DAY, 1, Date) <= '20121231')
SELECT DatePart(yy,DummyDates.Date) as [Year],DATEPART(MM,DummyDates.Date) as [Month],SUM(Case when dummy.date is null then 0 else 1 end) as cnt
FROM DummyDates
LEFT Join dummy on dummy.Date=DummyDates.Date
Group by DatePart(yy,DummyDates.Date),DATEPART(MM,DummyDates.Date)
Order by DatePart(yy,DummyDates.Date),DATEPART(MM,DummyDates.Date)
OPTION (MAXRECURSION 0)