Below is my SQL Server 2012 query example. How do I add an extra column “StaffNo” to show an incremental integer?
This int always starts with 1, it doesn’t need to be matching with the staff name. for example “Joe” in this query running shows 1 in staff No, in next query running he could be 2 or 3 or any other number.
Same user always appear same staff No. Different user appear different No.
The number must be sequential and the increment is 1.
Because Staff is more than 100, so don’t write the query like “select case when staff = ‘Joe’ then 1 End”.
my query:
Staff CaseNumber
Joe 5880
Joe 4489
Joe 2235
Emily 7790
Emily 8813
expected result:
Staff CaseNumber StaffNo
Joe 5880 1
Joe 4489 1
Joe 2235 1
Emily 7790 2
Emily 8813 2
Use DENSE_RANK over the entire table, without a partiton, and order by the staff member's name.
SELECT
Staff,
CaseNumber,
DENSE_RANK() OVER (ORDER BY Staff) StaffNo
FROM yourTable;
Demo here:
Rextester
Related
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Retrieving last record in each group from database - SQL Server 2005/2008
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I'm not sure how to word my question so perhaps an example would be best. I'm looking for a function or statement that would produce the following result from a single table. For each name, return the row with largest id.
ID NAME ADDRESS
1 JOHN DOE 123 FAKE ST.
2 JOHN DOE 321 MAIN ST.
3 JOHN DOE 333 2ND AVE.
4 MARY JANE 222 1ST. AVE
5 MARY JANE 444 POPLAR ST.
6 SUZY JO 999 8TH AVE.
DESIRED RESULT
3 JOHN DOE 333 2ND AVE.
5 MARY JANE 444 POPLAR ST.
6 SUZY JO 999 8TH AVE.
One option is to use the row_number window function. This allows you to establish a row number to the result set. Then you can define the grouping and ordering within the over clause, in this case you want to partition by (group) the name field and order by the id field descending. Finally you filter those results where rn = 1 which returns the max result for each grouping.
select *
from (
select *, row_number() over (partition by name order by id desc) rn
from yourtable
) t
where rn = 1
I need to create a field COUNT whose default value is the automatically generated count of times NAME has appeared in that table till now, as shown in example below. Since i am adding the field to an existing table, i also need to populate existing rows. How best to go about this please?
ID NAME COUNT
1 peter 1
2 jane 1
3 peter 2
4 peter 3
5 frank 1
6 jane 2
7 peter 4
You would do this when you are querying the table, using the ANSI-standard row-number function:
select id, name, row_number() over (partition by name order by id) as seqnum
from t;
I got the following records where different people have the same name:
id name category_id birthdate family_id
1 joe 2 2014-05-01 1
2 jack 3 2013-04-01 2
3 joe 2 1964-05-01 1
4 jack 5 1982-05-01 2
5 emma 1 2014-05-01 1
6 joe 3 2003-07-06 3
Now I need a query which results to the following. I want only each name once per family_id. I need all values of each record afterwards including the id. In case the table gets further rows down the road I need them too. So the result should include all values.
id name category_id birthdate family_id
1 joe 2 2014-05-01 1
2 jack 3 2013-04-01 2
5 emma 1 2014-05-01 1
6 joe 3 2003-07-06 3
I tried it with several approaches (GROUP BY, DISTINCT, DISTINCT ON etc.) but none was working out for me.
When I use a GROUP BY clause (GROUP BY name) I get a ERROR: column "deals.id" must appear in the GROUP BY clause or be used in an aggregate function. But when I put id inside the clause I get all records back.
Same with distinct. There I have to choose all fields on which the result set should be distinct. But I need all values of the record. And because of the primary each record is distinct when i include the id.
I tried it with a sub clause which has filtered all distinct names. I used them in a where clause. But I got all values back including (of course) the not distinct name/family_id records.
Has anybody a helping hand for me?
You might not of specified all of the fields in your group by and if you included id, then that would make the rows unique.
Try something like:
SELECT
name, category_id, birthdate, family_id
FROM family
GROUP BY
name, category_id, birthdate, family_id;
It worked with DISTINCT ON.
The following worked quite well:
SELECT DISTINCT ON (table.name, table.family_id) table.* FROM table;
The only thing I have to check is the ordering. But I wanted to share my solution so far.
Assume I have a table with the following data:
Name TransID Cost
---------------------------------------
Susan 1 10
Johnny 2 10
Johnny 3 9
Dave 4 10
I want to find a way to sum the Costs per name (assume the Names are unique) so that I get a table like this:
Name Cost
---------------------------------------
Susan 10
Johnny 19
Dave 10
Any help is appreciated.
This is relatively straightforward: you need to use a GROUP BY clause in your query:
SELECT Name,SUM(Cost)
FROM MyTable
GROUP BY Name
How can retrieve that data:
Name Title Profit
Peter CEO 2
Robert A.D 3
Michael Vice 5
Peter CEO 4
Robert Admin 5
Robert CEO 13
Adrin Promotion 8
Michael Vice 21
Peter CEO 3
Robert Admin 15
to get this:
Peter........4
Robert.......15
Michael......21
Adrin........8
I want to get the highest profit value from each name.
If there are multiple equal names always take the highest value.
select name,max(profit) from table group by name
Since this type of request almost always follows with "now can I include the title?" - here is a query that gets the highest profit for each name but can include all the other columns without grouping or applying arbitrary aggregates to those other columns:
;WITH x AS
(
SELECT Name, Title, Profit, rn = ROW_NUMBER()
OVER (PARTITION BY Name ORDER BY Profit DESC)
FROM dbo.table
)
SELECT Name, Title, Profit
FROM x
WHERE rn = 1;