I have the two following tables:
Table 1
Table 2
What I want to do is to have a query that returns a SUM of PIT_VALORTOTAL, PIT_VOLUME and a count of PED_IDPESSOA per date. What I have so far is:
SELECT SUM(PIT_VALORTOTAL) AS VALORTOTAL, SUM(PIT_VOLUME) AS VOLUME, COUNT(DISTINCT PED_IDPESSOA) AS PESSOA FROM PEDIDOS_ITENS INNER JOIN PEDIDOS ON PIT_IDPEDIDO = PED_ID;
And it returns the sums and the count correctly, but I don't have a clue on how to get these seperatly per dates. So what I have is this:
VALORTOTAL | VOLUME | PESSOA |
49783.2000000 | 679780.360000| 11 |
And what I want is something like:
| DATE | VALORTOTAL | VOLUME | PESSOA |
| 2017-09-03| 1012,00 | 1209 | 12 |
| 2017-09-03| 2012,00 | 1450 | 10 |
| 2017-09-03| 3016,00 | 2500 | 20 |
| 2017-09-03| 3016,00 | 3200 | 5 |
| 2017-09-03| 2016,00 | 4000 | 9 |
You just need group by:
SELECT PED_DATA, SUM(PIT_VALORTOTAL) AS VALORTOTAL, SUM(PIT_VOLUME) AS VOLUME,
COUNT(DISTINCT PED_IDPESSOA) AS PESSOA
FROM PEDIDOS_ITENS pi INNER JOIN
PEDIDOS p
ON PIT_IDPEDIDO = PED_ID
GROUP BY PED_DATA
ORDER BY PED_DATA
Related
I have a system to track orders and related expenditures. This is a Rails app running on PostgreSQL. 99% of my app gets by with plain old Rails Active Record call etc. This one is ugly.
The expenditures table look like this:
+----+----------+-----------+------------------------+
| id | category | parent_id | note |
+----+----------+-----------+------------------------+
| 1 | order | nil | order with no invoices |
+----+----------+-----------+------------------------+
| 2 | order | nil | order with invoices |
+----+----------+-----------+------------------------+
| 3 | invoice | 2 | invoice for order 2 |
+----+----------+-----------+------------------------+
| 4 | invoice | 2 | invoice for order 2 |
+----+----------+-----------+------------------------+
Each expenditure has many expenditure_items and can the orders can be parents to the invoices. That table looks like this:
+----+----------------+-------------+-------+---------+
| id | expenditure_id | cbs_item_id | total | note |
+----+----------------+-------------+-------+---------+
| 1 | 1 | 1 | 5 | Fuit |
+----+----------------+-------------+-------+---------+
| 2 | 1 | 2 | 15 | Veggies |
+----+----------------+-------------+-------+---------+
| 3 | 2 | 1 | 123 | Fuit |
+----+----------------+-------------+-------+---------+
| 4 | 2 | 2 | 456 | Veggies |
+----+----------------+-------------+-------+---------+
| 5 | 3 | 1 | 34 | Fuit |
+----+----------------+-------------+-------+---------+
| 6 | 3 | 2 | 76 | Veggies |
+----+----------------+-------------+-------+---------+
| 7 | 4 | 1 | 26 | Fuit |
+----+----------------+-------------+-------+---------+
| 8 | 4 | 2 | 98 | Veggies |
+----+----------------+-------------+-------+---------+
I need to track a few things:
amounts left to be invoiced on orders (thats easy)
above but rolled up for each cbs_item_id (this is the ugly part)
The cbs_item_id is basically an accounting code to categorize the money spent etc. I have visualized what my end result would look like:
+-------------+----------------+-------------+---------------------------+-----------+
| cbs_item_id | expenditure_id | order_total | invoice_total | remaining |
+-------------+----------------+-------------+---------------------------+-----------+
| 1 | 1 | 5 | 0 | 5 |
+-------------+----------------+-------------+---------------------------+-----------+
| 1 | 2 | 123 | 60 | 63 |
+-------------+----------------+-------------+---------------------------+-----------+
| | | | Rollup for cbs_item_id: 1 | 68 |
+-------------+----------------+-------------+---------------------------+-----------+
| 2 | 1 | 15 | 0 | 15 |
+-------------+----------------+-------------+---------------------------+-----------+
| 2 | 2 | 456 | 174 | 282 |
+-------------+----------------+-------------+---------------------------+-----------+
| | | | Rollup for cbs_item_id: 2 | 297 |
+-------------+----------------+-------------+---------------------------+-----------+
order_total is the sum of total for all the expenditure_items of the given order ( category = 'order'). invoice_total is the sum of total for all the expenditure_items with parent_id = expenditures.id. Remaining is calculated as the difference (but not greater than 0). In real terms the idea here is you place and order for $1000 and $750 of invoices come in. I need to calculate that $250 left on the order (remaining) - broken down into each category (cbs_item_id). Then I need the roll-up of all the remaining values grouped by the cbs_item_id.
So for each cbs_item_id I need group by each order, find the total for the order, find the total invoiced against the order then subtract the two (also can't be negative). It has to be on a per order basis - the overall aggregate difference will not return the expected results.
In the end looking for a result something like this:
+-------------+-----------+
| cbs_item_id | remaining |
+-------------+-----------+
| 1 | 68 |
+-------------+-----------+
| 2 | 297 |
+-------------+-----------+
I am guessing this might be a combination of GROUP BY and perhaps a sub query or even CTE (voodoo to me). My SQL skills are not that great and this is WAY above my pay grade.
Here is a fiddle for the data above:
http://sqlfiddle.com/#!17/2fe3a
Alternate fiddle:
https://dbfiddle.uk/?rdbms=postgres_11&fiddle=e9528042874206477efbe0f0e86326fb
This query produces the result you are looking for:
SELECT cbs_item_id, sum(order_total - invoice_total) AS remaining
FROM (
SELECT cbs_item_id
, COALESCE(e.parent_id, e.id) AS expenditure_id -- ①
, COALESCE(sum(total) FILTER (WHERE e.category = 'order' ), 0) AS order_total -- ②
, COALESCE(sum(total) FILTER (WHERE e.category = 'invoice'), 0) AS invoice_total
FROM expenditures e
JOIN expenditure_items i ON i.expenditure_id = e.id
GROUP BY 1, 2 -- ③
) sub
GROUP BY 1
ORDER BY 1;
db<>fiddle here
① Note how I assume a saner table definition with expenditures.parent_id being integer, and true NULL instead of the string 'nil'. This allows the simple use of COALESCE.
② About the aggregate FILTER clause:
Aggregate columns with additional (distinct) filters
③ Using short syntax with ordinal numbers of an SELECT list items. Example:
Select first row in each GROUP BY group?
can I get the total of all the remaining for all rows or do I need to wrap that into another sub select?
There is a very concise option with GROUPING SETS:
...
GROUP BY GROUPING SETS ((1), ()) -- that's all :)
db<>fiddle here
Related:
Converting rows to columns
could help me solve this duplication problem where it returns more than 1 result for the same record I want to bring only 1 result for each id, and only the last history of each record.
My Query:
SELECT DISTINCT ON(tickets.ticket_id,ticket_histories.created_at)
ticket.id AS ticket_id,
tickets.priority,
tickets.title,
tickets.company,
tickets.ticket_statuse,
tickets.created_at AS created_ticket,
group_user.id AS group_id,
group_user.name AS user_group,
ch_history.description AS ch_description,
ch_history.created_at AS ch_history
FROM
tickets
INNER JOIN company ON (company.id = tickets.company_id)
INNER JOIN (SELECT id,
tickets_id,
description,
user_id,
MAX(tickets.created_at) AS created_ticket
FROM
ch_history
GROUP BY id,
created_at,
ticket_id,
user_id,
description
ORDER BY created_at DESC LIMIT 1) AS ch_history ON (ch_history.ticket_id = ticket.id)
INNER JOIN users ON (users.id = ch_history.user_id)
INNER JOIN group_users ON (group_users.id = users.group_user_id)
WHERE company = 15
GROUP BY
tickets.id,
ch_history.created_at DESC;
Result of my query, but returns 3 or 5 identical ids with different histories
I want to return only 1 id of each ticket, and only the last recorded history of each tick
ticket_id | priority | title | company_id | ticket_statuse | created_ticket | company | user_group | group_id | ch_description | ch_history
-----------+------------+--------------------------------------+------------+-----------------+----------------------------+------------------------------------------------------+-----------------+----------+------------------------+----------------------------
49713 | 2 | REMOVE DATA | 1 | t | 2019-12-09 17:50:35.724485 | SAME COMPANY | people | 5 | TEST 1 | 2019-12-10 09:31:45.780667
49706 | 2 | INCLUDE DATA | 1 | f | 2019-12-09 09:16:35.320708 | SAME COMPANY | people | 5 | TEST 2 | 2019-12-10 09:38:52.769515
49706 | 2 | ANY TITLE | 1 | f | 2019-12-09 09:16:35.320708 | SAME COMPANY | people | 5 | TEST 3 | 2019-12-10 09:39:22.779473
49706 | 2 | NOTING ELSE MAT | 1 | f | 2019-12-09 09:16:35.320708 | SAME COMPANY | people | 5 | TESTE 4 | 2019-12-10 09:42:59.50332
49706 | 2 | WHITESTRIPES | 1 | f | 2019-12-09 09:16:35.320708 | SAME COMPANY | people | 5 | TEST 5 | 2019-12-10 09:44:30.675434
wanted to return as below
ticket_id | priority | title | company_id | ticket_statuse | created_ticket | company | user_group | group_id | ch_description | ch_history
-----------+------------+--------------------------------------+------------+-----------------+----------------------------+------------------------------------------------------+-----------------+----------+------------------------+----------------------------
49713 | 2 | REMOVE DATA | 1 | t | 2019-12-09 17:50:10.724485 | SAME COMPANY | people | 5 | TEST 1 | 2020-01-01 18:31:45.780667
49707 | 2 | INCLUDE DATA | 1 | f | 2019-12-11 19:22:21.320701 | SAME COMPANY | people | 5 | TEST 2 | 2020-02-05 16:38:52.769515
49708 | 2 | ANY TITLE | 1 | f | 2019-12-15 07:15:57.320950 | SAME COMPANY | people | 5 | TEST 3 | 2020-02-06 07:39:22.779473
49709 | 2 | NOTING ELSE MAT | 1 | f | 2019-12-16 08:30:28.320881 | SAME COMPANY | people | 5 | TESTE 4 | 2020-01-07 11:42:59.50332
49701 | 2 | WHITESTRIPES | 1 | f | 2019-12-21 11:04:00.320450 | SAME COMPANY | people | 5 | TEST 5 | 2020-01-04 10:44:30.675434
I wanted to return as shown below, see that the field ch_description, and ch_history bring only the most recent records and only the last of each ticket listed, without duplication I wanted to bring this way could help me.
Two things jump out at me:
You have listed "created at" as part of your "distinct on," which is going to inherently give you multiple rows per ticket id (unless there happens to be only one)
The distinct on should make the subquery on the ticket history unnecessary... and even if you chose to do it this way, you again are going on the "created at" column, which will give you multiple results. The ideal subquery, should you choose this approach, would have been to group by ticket_id and only ticket_id.
Slightly related:
An alternative approach to the subquery would be an analytic function (windowing function), but I'll save that for another day.
I think the query you want, which will give you one row per ticket_id, based on the history table's created_at field would be something like this:
select distinct on (t.id)
<your fields here>
from
tickets t
join company c on t.company_id = c.id
join ch_history ch on ch.ticket_id = t.id
join users u on ch.user_id = u.ud
join group_users g on u.group_user_id = g.id
where
company = 15
order by
t.id, ch.created_at -- this is what tells distinct on which record to choose
I've 3 tables as under
MERCHANDISE
+-----------+-----------+---------------+
| MERCH_NUM | MERCH_DIV | MERCH_SUB_DIV |
+-----------+-----------+---------------+
| 1 | car | awd |
| 1 | car | awd |
| 2 | bike | 1kcc |
| 3 | cycle | hybrid |
| 3 | cycle | city |
| 4 | moped | fixie |
+-----------+-----------+---------------+
PRIORITY
+----------+-----------+---------+---------+------------+------------+---------------+
| CUST_NUM | SALES_NUM | DOC_NUM | BALANCE | PRIORITY_1 | PRIORITY_2 | PRIORITY_CODE |
+----------+-----------+---------+---------+------------+------------+---------------+
| 90 | 1000 | 10 | 23 | 1 | 6 | NO |
| 91 | 1001 | 20 | 32 | 3 | 7 | PRI |
| 92 | 1002 | 30 | 11 | 2 | 8 | LATE |
| 93 | 1003 | 40 | 22 | 5 | 9 | 1MON |
+----------+-----------+---------+---------+------------+------------+---------------+
ORDER
+----------+-----------+---------+---------+-----------+-----------+
| CUST_NUM | SALES_NUM | DOC_NUM | COUNTRY | MERCH_NUM | MERCH_DIV |
+----------+-----------+---------+---------+-----------+-----------+
| 90 | 1000 | 10 | INDIA | 1 | car |
| 91 | 1001 | 20 | CHINA | 2 | bike |
| 92 | 1002 | 30 | USA | 3 | cycle |
| 93 | 1003 | 40 | UK | 4 | moped |
+----------+-----------+---------+---------+-----------+-----------+
I want to join the left joined table from the last two tables with the first one such that the MERCH_SUB_DIV 'awd' appears only once for each unique combination of merch_num and merch_div
the code I came up with is as under, but I'm not sure how do I eliminate the duplicate row just for the awd
select
ROW#, MERCH.MERCH_NUMBER, ORDPRI.MERCH_NUMBER, ORDPRI.CUST_NUM,
BALANCE, SALES_NUM, ITEM_NUM, RANK, PRIORITY_1
from (
select
ROW_NUMBER() OVER(
PARTITION BY ORD.DOC_NUM, ORD.ITEM_NUM
ORDER BY ORD.DOC_NUM, ORD.ITEM_NUM ASC
) AS Row#,
ORD.CUST_NUM, PRI.CUST_NUM, ORD.MERCH_NUM, ORD.MERCH_DIV, PRI.BALANCE,
pri.DOC_NUM, pri.SALES_NUM, pri.PRIORITY_1, pri.PRIORITY_2
from ORDER as ORD
left join PRIORITY as PRI on ORD.DOC_NUM = PRI.DOC_NUM
and ORD.SALES_NUMBER = PRI.SALES_NUM
where country_name in ('USA', ‘INDIA’)
) as ORDPRI
left join MERCHANDISE as MERCH on ORDPRI.DIV = MERCH.DIV
and ORDPRI.MERCH_NUM = MERCH.MERCH_NUM
You have to use 'DISTINCT' keyword to get unique values, but if your 'Priority table' & 'Order table' contains different values for Same MERCH_NUM then the final result contains the repetation of the 'MERCH_NUM'.
SELECT DISTINCT M.MERCH_NUMBER, O.MERCH_NUMBER, O.CUST_NUM, BALANCE, SALES_NUM,ITEM_NUM,RANK,PRIORITY_1
FROM priority_table P
LEFT JOIN order_table O ON P.CUST_NUM = O.CUST_NUM AND P.SALES_NUM=O.SALES_NUM AND P.DOC_NUM = O.DOC_NUM
LEFT JOIN merchandise_table M ON M.MERCH_NUM = O.MERCH_NUM
A way around can be to add one new Row_Number() in the outermost query having Partition by MERCH_SUB_DIV + all the columns in the final list and then filter final results based on the New Row_Number() . Follows a pseudo code that might help:
select
-- All expected columns in final result except the newRow#
ROW#, MERCH_NUM, CUST_NUM,
BALANCE, SALES_NUM, PRIORITY_1
from (
select
ROW#,
-- the new row number includes all column you want to show in final result
row_number() over ( PARTITION BY MERCH.MERCH_SUB_DIV ,
MERCH.MERCH_NUM, ORDPRI.MERCH_NUM, ORDPRI.CUST_NUM,
BALANCE, SALES_NUM, PRIORITY_1
order by (select 1 )) as newRow# ,
MERCH.MERCH_NUM, ORDPRI.CUST_NUM,
BALANCE, SALES_NUM, PRIORITY_1
from (
-- main query goes here
select
ROW_NUMBER() OVER(
PARTITION BY ORD.DOC_NUM --, ORD.ITEM_NUM
ORDER BY ORD.DOC_NUM ASC --, ORD.ITEM_NUM
) AS Row#,
ORD.CUST_NUM, ORD.MERCH_NUM, ORD.MERCH_DIV as DIV, PRI.BALANCE,
pri.DOC_NUM, pri.SALES_NUM, pri.PRIORITY_1, pri.PRIORITY_2
from #ORDER as ORD
left join #PRIORITY as PRI on ORD.DOC_NUM = PRI.DOC_NUM
and ORD.SALES_NUMBER = PRI.SALES_NUM
where country_name in ('USA', 'INDIA')
) as ORDPRI
left join #MERCHANDISE as MERCH on ORDPRI.DIV = MERCH.DIV
and ORDPRI.MERCH_NUM = MERCH.MERCH_NUM
) as T
-- final filter to get distinct values
where newRow# = 1
Sample code here .. Hope this helps!!
I have a team of people who are scored on up to three metrics; sales, leads and Hours.
I have a table (tblScores) in MS Access which holds these scores but only if there is any. (e.g if someone had no sales there would be no entry for them for sales)
| USERID | Metric | Score |
----------------------------------
| 20511 | Sales | 12 |
| 20511 | Leads | 9 |
| 20511 | Hours | 8 |
| 20694 | Sales | 10 |
| 20694 | Hours | 7.5 |
I am trying to create an SQL query that will output three records (each possible metric) for each User in the above table including null values where they don't have an entry for that metric. e.g
| USERID | Metric | Score |
----------------------------------
| 20511 | Sales | 12 |
| 20511 | Leads | 9 |
| 20511 | Hours | 8 |
| 20694 | Sales | 10 |
| 20694 | Leads | Null |
| 20694 | Hours | 7.5 |
I have set up another table (tblMetrics) with just these 3 metrics
| Metric |
---------------
| Sales |
| Leads |
| Hours |
and tried to do a left join on the metric table against the score table
SELECT tblMetrics.*, TblScores.UserID, TblScores.Score
FROM tblMetrics LEFT JOIN TblScores ON tblMetrics.Metric = TblScores.Metric;
but it is still not giving the desired output. Does anyone know if this possible?
You need to do a CROSS JOIN first to generate all combinations, then do the LEFT JOIN to find which one are missing and assign NULL
I check access syntaxis and the CROSS JOIN should be write like this
SELECT DISTINCT M.Metric, S.USERID
FROM tblMetric M, tblScore S
And the Left Join should be
SELECT userMetrc.*, S.Score
FROM ( SELECT DISTINCT M.Metric, S.USERID
FROM tblMetric M, tblScore S
) userMetric
LEFT JOIN tblScore S
ON ( userMetric.USERID = S.USERID
AND userMetric.Metric = S.Metric )
I have two tables:
1. Master
| ID | Name | Amount |
|-----|--------|--------|
| 1 | a | 5000 |
| 2 | b | 10000 |
| 3 | c | 5000 |
| 4 | d | 8000 |
2. Detail
| ID |MasterID| PID | Qty |
|-----|--------|-------|------|
| 1 | 1 | 1 | 10 |
| 2 | 1 | 2 | 20 |
| 3 | 2 | 2 | 60 |
| 4 | 2 | 3 | 10 |
| 5 | 3 | 4 | 100 |
| 6 | 4 | 1 | 20 |
| 7 | 4 | 3 | 40 |
I want to select sum(Amount) from Master which joins to Deatil where Detail.PID in (1,2,3)
So I execute the following query:
SELECT SUM(Amount) FROM Master M INNER JOIN Detail D ON M.ID = D.MasterID WHERE D.PID IN (1,2,3)
Result should be 20000. But I am getting 40000
See this fiddle. Any suggestion?
You are getting exactly double the amount because the detail table has two occurences for each of the PIDs in the WHERE clause.
See demo
Use
SELECT SUM(Amount)
FROM Master M
WHERE M.ID IN (
SELECT DISTINCT MasterID
FROM DETAIL
WHERE PID IN (1,2,3) )
What is the requirement of joining the master table with details when you have all your columns are in Master table.
Also, isnt there any FK relationhsip defined on these tables. Looking at your data it seems to me that there should be FK on detail table for MasterId. If that is the case then you do not need join the table at all.
Also, in case you want to make sure that you have records in details table for the records for which you need sum and there is no FK relationship. Then you could give a try for exists instead of join.