Input:
id group_id type_id
1 1 aaaaa
2 1 BAD
3 2 bbbbb
4 2 ccccc
5 3 ddddd
6 3 eeeee
7 3 aaaaa
I need to output group_ids which consist only of a members for which type_id <> 'BAD'. A whole group with at least one BAD member should be excluded
Use of subqueries (or CTE or NOT EXISTS or views or T-SQL inline functions) is not allowed!
Use of except is not allowed!
Use of cursors is not allowed.
Any solutions which trick the rules above are appreciated. Any RDBMS is ok.
Bad example solution producing correct results, (using except):
select distinct group_id
from input
except
select group_id
from input
where type_id = 'bad'
group by group_id, type_id
Output:
group_id
2
3
I would just use group by and having:
select group_id
from input
group by group_id
having min(type_id) = 'good' and max(type_id) = min(type_id);
This particular version assumes that type_id (as in the question) does not take on NULL values. It is easily modified to take that into account.
EDIT:
If you are looking for one bad, then just do:
select group_id
from input
where type_id = 'bad'
group by group_id;
Group by group_id and count occurrences of 'BAD':
select group_id
from mytable
group by group_id
having count(case when type_id = 'BAD' then 'count me' end) = 0;
Related
I have a view which is a product of two joined tables:
ID Type
1 A
2 A
2 B
3 B
There can only be two values in Type column: A or B.
I would like to aggregate IDs into three categories: Catgegory_A, Category_B and Category_AB. If the ID is associated only with type A, it is assigned Category_A, if the ID is associated with types A and B it is associated with Categry_AB. Based on these rules, the view above should be categorised as follows:
ID Category
1 Category_A
2 Category_AB
3 Category_C
Is it possible to write an SQL query to achieve this?
I would name them differently, but the logic is:
select id,
(case when min(category) = max(category)
then 'Category_' || min(category)
else 'Category_AB'
end)
from t
group by id;
Independently of Gordon's answer, I came up with the following...
SELECT ID,
CASE
WHEN COUNT(*) > 1 THEN 'AB'
ELSE MAX(Type)
END AS Category
FROM Products
GROUP BY ID
See SQLFiddle to run :)
I would like to ignore some of the results of my query as for all intents and purposes, some of the results are a duplicate, but based on the way the request was made, we need to use this hierarchy and although we are seeing different 'Company_Name' 's, we need to ignore one of the results.
Query:
SELECT
COUNT(DISTINCT A12.Company_name) AS Customer_Name_Count,
Company_Name,
SUM(Total_Sales) AS Total_Sales
FROM
some_table AS A12
GROUP BY
2
ORDER BY
3 ASC, 2 ASC
This code omits half a doze joins and where statements that are not germane to this question.
Results:
Customer_Name_Count Company_Name Total_Sales
-------------------------------------------------------------
1 3 Blockbuster 1,000
2 6 Jimmy's Bar 1,500
3 6 Jimmy's Restaurant 1,500
4 9 Impala Hotel 2,000
5 12 Sports Drink 2,500
In the above set, we can see that numbers 2 & 3 have the same count and the same total_sales number and similar company names. Is there a way to create a case statement that takes these 3 factors into consideration and then drops one or the other for Jimmy's enterprises? The other issue is that this has to be variable as there are other instances where this happens. And I would only want this to happen if the count and sales number match each other with a similar name in the company name.
Desired result:
Customer_Name_Count Company_Name Total_Sales
--------------------------------------------------------------
1 3 Blockbuster 1,000
2 6 Jimmy's Bar 1,500
3 9 Impala Hotel 2,000
4 12 Sports Drink 2,500
Looks like other answers are accurate based on assumption that Company_IDs are the same for both.
If Company_IDs are different for both Jimmy's Bar and Jimmy's Restaurant then you can use something like this. I suggest you get functional users involved and do some data clean-up else you'll be maintaining this every time this issue arise:
SELECT
COUNT(DISTINCT CASE
WHEN A12.Company_Name = 'Name2' THEN 'Name1'
ELSE A12.Company_Name
END) AS Customer_Name_Count
,CASE
WHEN A12.Company_Name = 'Name2' THEN 'Name1'
ELSE A12.Company_Name
END AS Company_Name
,SUM(A12.Total_Sales) AS Total_Sales
FROM some_table er
GROUP BY CASE
WHEN A12.Company_Name = 'Name2' THEN 'Name1'
ELSE A12.Company_Name
END
Your problem is that the joins you are using are multiplying the number of rows. Somewhere along the way, multiple names are associated with exactly the same entity (which is why the numbers are the same). You can fix this by aggregating by the right id:
SELECT COUNT(DISTINCT A12.Company_name) AS Customer_Name_Count,
MAX(Company_Name) as Company_Name,
SUM(Total_Sales) AS Total_Sales
FROM some_table AS A12
GROUP BY Company_id -- I'm guessing the column is something like this
ORDER BY 3 ASC, 2 ASC;
This might actually overstate the sales (I don't know). Better would be fixing the join so it only returned one name. One possibility is that it is a type-2 dimension, meaning that there is a time component for values that change over time. You may need to restrict the join to a single time period.
You need to have function to return a common name for the companies and then use DISTINCT:
SELECT DISTINCT
Customer_Name_Count,
dbo.GetCommonName(Company_Name) as Company_Name,
Total_Sales
FROM dbo.theTable
You can try to use ROW_NUMBER with window function to make row number by Customer_Name_Count and Total_Sales then get rn = 1
SELECT * FROM (
SELECT *,ROW_NUMBER() OVER(PARTITION BY Customer_Name_Count,Total_Sales ORDER BY Company_Name) rn
FROM (
SELECT
COUNT(DISTINCT A12.Company_name) AS Customer_Name_Count,
Company_Name,
SUM(Total_Sales) AS Total_Sales
FROM
some_table AS A12
GROUP BY
Company_Name
)t1
)t1
WHERE rn = 1
I'm looking to filter out rows in the database (PostgreSQL) if one of the values in the status column occurs. The idea is to sum the amount column if the unique reference only has a status equals to 1. The query should not SELECT the reference at all if it has also a status of 2 or any other status for that matter. status refers to the state of the transaction.
Current data table:
reference | amount | status
1 100 1
2 120 1
2 -120 2
3 200 1
3 -200 2
4 450 1
Result:
amount | status
550 1
I've simplified the data example but I think it gives a good idea of what I'm looking for.
I'm unsuccessful in selecting only references that only have status 1.
I've tried sub-queries, using the HAVING clause and other methods without success.
Thanks
Here's a way using not exists to sum all rows where the status is 1 and other rows with the same reference and a non 1 status do not exist.
select sum(amount) from mytable t1
where status = 1
and not exists (
select 1 from mytable t2
where t2.reference = t1.reference
and t2.status <> 1
)
SELECT SUM(amount)
FROM table
WHERE reference NOT IN (
SELECT reference
FROM table
WHERE status<>1
)
The subquery SELECTs all references that must be excluded, then the main query sums everything except them
select sum (amount) as amount
from (
select sum(amount) as amount
from t
group by reference
having not bool_or(status <> 1)
) s;
amount
--------
550
You could use windowed functions to count occurences of status different than 1 per each group:
SELECT SUM(amount) AS amount
FROM (SELECT *,COUNT(*) FILTER(WHERE status<>1) OVER(PARTITION BY reference) cnt
FROM tc) AS sub
WHERE cnt = 0;
Rextester Demo
I am creating a file orginization system where you can add content items to multiple folders.
I am storing the data in a table that has a structure similar to the following:
ID TypeID ContentID FolderID
1 101 1001 1
2 101 1001 2
3 102 1002 3
4 103 1002 2
5 103 1002 1
6 104 1001 1
7 105 1005 2
I am trying to select the first record for each unique TypeID and ContentID pair. For the above table, I would want the results to be:
ID
1
3
4
6
7
As you can see, the pairs 101 1001 and 103 1002 were each added to two folders, yet I only want the record with the first folder they were added to.
When I try the following query, however, I only get result that have at least two entries with the same TypeID and ContentID:
select MIN(ID)
from table
group by TypeID, ContentID
results in
ID
1
4
If I change MIN(ID) to MAX(ID) I get the correct amount of results, yet I get the record with the last folder they were added to and not the first folder:
ID
2
3
5
6
7
Am I using GROUP BY or the MIN wrong? Is there another way that I can accomplish this task of selecting the first record of each TypeID ContentID pair?
MIN() and MAX() should return the same amount of rows. Changing the function should not change the number of rows returned in the query.
Is this query part of a larger query? From looking at the sample data provided, I would assume that this code is only a snippet from a larger action you are trying to do. Do you later try to join TypeID, ContentID or FolderID with the tables the IDs are referencing?
If yes, this error is likely being caused by another part of your query and not this select statement. If you are using joins or multi-level select statements, you can get different amount of results if the reference tables do not contain a record for all the foreign IDs.
Another suggestion, check to see if any of the values in your records are NULL. Although this should not affect the GROUP BY, I have sometime encountered strange behavior when dealing with NULL values.
Use ROW_NUMBER
WITH CTE AS
(SELECT ID,TypeID,ContentID,FolderID,
ROW_NUMBER() OVER (PARTITION BY TypeID,ContentID ORDER BY ID) as rn FROM t
)
SELECT ID FROM CTE WHERE rn=1
Use it with ORDER BY:
select *
from table
group by TypeID, ContentID
order by id
SQLFiddle: http://sqlfiddle.com/#!9/024016/12
Try with first ( id) instead of min(id)
select first(id)
from table
group by TypeID, ContentID
It works ?
What I am looking for is to group by and count the total of different data in the same table and have them show in two different columns. Like below.
Data in table A
Fields:
Name Type
Bob 1
John 2
Bob 1
Steve 1
John 1
Bob 2
Desired result from query:
Name Type 1 Type 2
Bob 2 1
John 1 1
Steve 1 0
This will do the trick in SQL Server:
SELECT
name,
SUM( CASE type WHEN 1 THEN 1 ELSE 0 END) AS type1,
SUM( CASE type WHEN 2 THEN 1 ELSE 0 END) AS type2
FROM
myTable
GROUP BY
name
No time to write the code, but the Case statement is what you want here. SImply havea value of 1 if it meets the case and zero if it deosn't. Then you can sum the columns.
Use two separate GROUP BY subqueries.
SELECT Name, a.Count1, b.Count2
from myTable
JOIN
(SELECT Name, SUM(Type) AS Count1 FROM myTable GROUP BY Name WHERE Type=1) AS a ON a.Name = myTable.Name
(SELECT Name, SUM(Type) FROM myTable GROUP BY Name WHERE Type=2) AS b ON b.Name = myTable.Name
You're looking for a CrossTab solution. The above solutions will work, but you'll come unstuck if you want a general solution and have N types.
A CrossTab solution will solve this for you. If this is for quickly crunching some numbers then dump your data into Excel and use the native Pivot Table feature.
If it's for a RDBMS in an app, then it depends upon the RDBMS. MS SQL 2005 and above has a crosstab syntax. See:
http://www.databasejournal.com/features/mssql/article.php/3521101/Cross-Tab-reports-in-SQL-Server-2005.htm
#Seb has a good solution, but it's server-dependent. Here's an alternate using subselects that should be portable:
select
name,
(select count(type) from myTable where type=1 and name=a.name) as type1,
(select count(type) from myTable where type=2 and name=a.name) as type2
from
myTable as a
group by
name