How to get the domain name without '.com'? - sql

Question

SELECT substr(Emails, instr(Emails, '#')+1)
FROM EmployeeEmails;
Returns
gmail.com
Do I need to concat to get:
gmail

Answer 1

Check your relevant database query :
Query(for MySQL)
select (SUBSTRING_INDEX(SUBSTR(Emails, INSTR(Emails, '#') + 1),'.',1)) from EmployeeEmails;
Query(For Sql Server):
select SUBSTRING(Emails,(CHARINDEX('#',Emails)+1),1) from EmployeeEmails;
Query(For Oracle)
select substr(Emails,instr(Emails,'#',1)+1) as domain
from EmployeeEmails;

Answer 2

You can use REGEXP_REPLACE to extract the domain name:
select regexp_replace(emails, '^[^#]+#([^.]+)\..+$', '\1') from employeeemails;
This works for any email of the pattern abcd#efgh.ijkl .
The pattern:
^ start of the sting
[^#]+ 1 to n characters other than #
# the at sign #
( remember the following string
[^.]+ 1 to n characters other than the dot .
) end of the string to remember
\. a dot .
.+ 1 to n characters
$ end of the string
\1 the remembered string
And here is the old-fashioned way without REGEXP_REPLACE:
select substr(emails,
instr(emails, '#') + 1,
instr(emails, '.', instr(emails, '#') + 1) - instr(emails, '#') - 1
)
from employeeemails;

Answer 3

try this : -
declare #email sysname = 'testCode#gmail.com'
SELECT substring(#email, charindex('#',#email,0)+1 , (charindex('.',#email,0)-1 - charindex('#',#email,0)))

Answer 4

You can use LIKE with wild cards see here
underscore character ( _ ) for any single character.
percent sign character (%) for a string of zero or more characters.
SELECT email FROM emails
WHERE email NOT LIKE '%_#__%.__%'
This will ignore the following cases (simple version for valid emails):
emails that have at least one character before the #
emails that have at least two characters between # and .
emails that have at least two characters between . and the end.