count consecutive statuses from each ID - sql

Question

I am trying to find a list of clients that have at least 3 consecutive items that are "processed". The following is what my table looks like:
ClientID ItemID Status
1 1 Pending
1 2 Processed
1 3 Processed
2 4 Processed
2 5 Processed
1 6 Processed
1 7 Pending
2 8 Pending
2 9 Processed
3 10 Pending
3 11 Pending
2 12 Processed
3 13 Pending
2 14 Processed
1 15 Processed
2 16 Processed
Expected results:
1 (since it had 3 consecutive processed records from 2, 3, 6 )
2 (since it had 4 consecutive processed records from 9, 12, 14, 16)
As you can see, I define "consecutive" as the next record with the same ClientID and not as the next record in the table, this is what I am having trouble with. My counter restarts when the next clientid in the table is different.
my attempt:
WITH count
AS
(
SELECT *, COUNT(1) OVER(PARTITION BY clientid, count) NotPending
FROM (
SELECT *, (
SELECT COUNT(ItemId)
FROM ##temp a
WHERE status like '%pend%'
AND ItemId < b.ItemId) AS count
FROM ##temp b
WHERE status not like '%pend%'
) t1
)
SELECT distinct clientid from count where NotPending >= 3

Answer 1

You can use row_number() to place rows with the same consecutive status in the same group:
select *,
row_number() over (partition by ClientId order by ItemId)
- row_number() over (partition by ClientId, ItemStatus order by ItemId) as groupName
from Table1
order by ClientId, ItemId
Then you can count the number of entries per group:
select distinct ClientId, count(*) from (
select *,
row_number() over (partition by ClientId order by ItemId)
- row_number() over (partition by ClientId, ItemStatus order by ItemId) as groupName
from Table1
) t
where ItemStatus = 'Processed'
group by ClientId, groupName
having count(*) >= 3
Demo

Answer 2

In your example there are no clients with more than 5 consecutive items (and in your Select you check for >= 10).
Looking for 3 items, returns 1 & 2 for your example data:
WITH cte AS
(
SELECT ClientID, ItemID, Status,
-- returns 3 when there's only 'Processed'
Sum(CASE WHEN Status = 'Processed' THEN 1 end)
Over (PARTITION BY ClientID
ORDER BY ItemId
-- 3 rows including current row
ROWS 2 Preceding) AS Cnt
FROM ##temp
)
SELECT DISTINCT ClientID
FROM cte
WHERE Cnt = 3