Excel: VBA to delete group of rows - vba

Question

I have an excel file with one column with data. Something like:
21/07/2017
DEF
GHI
Field 7
SOMETHING HERE
MORE TEXT
21/07/2017
DEF
GHI
Field 7
This is repeated a few thousand times. What I am looking for is all rows between and including 21/07/2017 and Field 7 to be deleted and for the rows to be moved up.
I've tried a few things but now back to a blank canvas! Any hints?
Thanks
CODE I TRIED
I get an Overflow error
Sub deleteRows()
Dim sh As Worksheet
Dim rw As Range
Dim RowCount As Integer
RowCount = 1
Application.DisplayAlerts = False
Set sh = ActiveSheet
For Each rw In sh.Rows
If sh.Cells(rw.Row, 1).Value = "21/07/2017" Then
a = RowCount
End If
If sh.Cells(rw.Row, 1).Value = "Field 7" Then
b = RowCount
Rows(a & ":" & b).Delete
End If
RowCount = RowCount + 1
Next rw
End Sub

Answer 1

This will only loop as many times as the pair exists and delete each block as a whole.
The loop ends the first time that both are not found in the remaining values.
Sub myDelete()
Dim str1 As string
Dim str2 As String
Dim rng As Range
Dim ws As Worksheet
Dim i As Long
Dim j As Long
str1 = "21/07/2017"
str2 = "Field 7"
Set ws = Worksheets("Sheet18") 'change to your worksheet
Set rng = ws.Range("A:A")
Do
i = 0: j = 0
On Error Resume Next
i = Application.WorksheetFunction.Match(str1, rng, 0)
j = Application.WorksheetFunction.Match(str2, rng, 0)
On Error GoTo 0
If i > 0 And j > 0 Then
ws.Rows(i & ":" & j).Delete
End If
Loop Until i = 0 Or j = 0
End Sub
If your date is a true date then change str1 to Double:
Dim str1 As Double
and then assign it as such:
str1 = CDbl(DateSerial(2017, 7, 21))