SQL query to get the 15 of the month for the following year.
Today
select getdate() = 2017-08-23 17:05:24.143
Looking for: 2018-8-15 00:00:00
I know how to get a year from today:
select dateadd(year,1,datediff(day,0,getdate()))
I know how to get the beginning of the month:
SELECT DATEADD(month, DATEDIFF(month, 0, GETDATE()), 0)
However I am having trouble combining the two.
You can use datefromparts for SQL Server versions 2012 and above.
select datefromparts(year(getdate())+1,month(getdate()),15)
Truncate the current day to the start of the month with the code you have, but add 12 months (so, a year), and add 14 days.
select dateadd(day,14,dateadd(month, 12+datediff(month, 0, getdate()), 0))
SELECT DATEADD(month, DATEDIFF(month, 0, DATEADD(year, 1, DATEDIFF(day, 0, GETDATE())), 0)
Vamsi Prabhala's answer deserves to be accepted.
But, you should consider creating a Calendar Table because it greatly simplifies working with dates in general.
Here is a pretty simply query that yields the results that you want:
select * from Calendar C where C.year = datepart(year, getdate()) + 1
and C.day_of_month = 15 and C.month = datepart(m, getdate())
Rextester Demo
Related
Hello I'm looking for simple way, how to get data from previous month. I get this code but it didn't work in January (result is 12 2021 and I need 12 2020)
select month(dateadd(month,-1,getdate())), year(getdate())
Presumably, you have some sort of date column.
In SQL Server, you can express this concept using datediff():
where datediff(month, datecol, getdate()) = 1
However, that is not "sargable", meaning that it prevents the use of indexes. So, I would instead recommend:
where datecol < datefromparts(year(getdate()), month(getdate()), 1) and
datecol >= dateadd(month, 1, datefromparts(year(getdate()), month(getdate()), 1))
If you simply want the first day of the previous month, you can use:
dateadd(month, 1, datefromparts(year(getdate()), month(getdate()), 1))
Try This
select CASE WHEN month(getdate())>1 THEN month(getdate())-1 ELSE 12 END ,
CASE WHEN month(getdate())>1 THEN YEAR (getdate()) ELSE YEAR (getdate()) -1 END
Using the answer given here: How can I select the first day of a month in SQL?
SELECT dateadd(month,-1,DATEADD(month, DATEDIFF(month, 0, getdate()), 0)) as previousmonth;
output:
2020-12-01 00:00:00.000
I can provide next query using FORMAT function:
SELECT
-- get current day in previous month
FORMAT(dateadd(month, -1, getdate()), 'yyyy-MM-dd') as current_previousmonth,
-- get first of previous month
FORMAT(dateadd(month, -1, getdate()), 'yyyy-MM-01') as first_previousmonth,
-- previous month without date
FORMAT(dateadd(month, -1, getdate()), 'yyyy-MM') as previousmonth;
test T-SQL here
Here you go!
select dateadd(mm,-1,eomonth(getdate())) as [Previous Month]
Result:
Previous Month
--------------
2020-12-31
You could also use CONVERT() or FORMAT() functions to format the date as you desire.
Try
SELECT FORMAT(DATEADD(month, -1, GETDATE()),'MM/yyyy');
It will give you previous month and the year. If you are comparing to a date column in a existing table, then you need the date part too as you want to know December of which year was the previous month. But if you don't want the year, then just adjust the 'MM/yyyy' part to suit your purpose.
this is my first question here. Hopefully I´m clear enough what I´m searching for.
My problem is following:
On this analysis I want to get from the last 7 weeks, the summarized prices of each week. Its working with out any problems, but now I would like to add the weeks number of each week as alias.
In my tests I was using for example something like this:
DECLARE #week7 varchar(10)
SET #week7 = DATEPART(wk, GetDate())
One of my problems is, that I´m not allowed to work with "EXEC".
This is just an example of my analysis:
SELECT DISTINCT(
SELECT SUM(Price)
FROM tblBookingdata
WHERE(Datum BETWEEN DATEADD(wk, -7, DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()), DATEDIFF(dd, 0, GETDATE()))) AND DATEADD(wk, -6, DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()), DATEDIFF(dd, 0, GETDATE()))))) AS '7 weeks ago', (
SELECT SUM(Price)
FROM tblBookingdata
WHERE(Datum BETWEEN DATEADD(wk, -6, DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()), DATEDIFF(dd, 0, GETDATE()))) AND DATEADD(wk, -5, DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()), DATEDIFF(dd, 0, GETDATE()))))) AS '6 weeks ago'
I would like the column name to show the week number from each sub select. That the output would be for example for this week: 40 (as column name) and 900 as price summary.
So I tried to work here with DECLARE and assign #week7 for example with the current week number. But here I got stuck, due it seems like I need to work here with EXEC.
Is this only possible with "EXEC" or are there any other solutions to solve this? I was looking in the www, but currently I´m stucking a bit. Thankful for every help! :)
I think the DateDiff function is your friend here. Are you using SQL Server? This won't display a row for the week if there are zero records in that week, but this should be close to what you want.
select WeeksAgo, sum(Price) as Price from (
select
Price
,Datediff(wk, Datum, getDate()) as WeeksAgo
,Datum --not used
from
tblBookingdata
)DataByWeek
where WeeksAgo between 0 and 7 --should this be 0-6?
group by WeeksAgo
I think you're looking for something like this. The prior 7 weeks are calculated from GETDATE based on a numbers table with 1, 2, 3, ... 7. Then the booking Prices are summarized by week where the Datum is within the prior 7 weeks. This will display NULL in price_sum if there were no sales that week.
drop table if exists #tblBookingdata;
go
create table #tblBookingdata(
Datum date not null,
Price int not null);
go
;with
weeks_cte(wk) as (
select datepart(wk, dateadd(wk, w*-1, getdate()))
from (values (1),(2),(3),(4),(5),(6),(7)) v(w)),
bookings_cte(wk, price_sum) as (
select datepart(wk, Datum), sum(Price)
from #tblBookingdata
where Datum>dateadd(wk, -7, getdate())
group by datepart(wk, Datum))
select *
from weeks_cte wc
left join bookings_cte b on wc.wk=b.wk;
I need to get records of last 2 months and last month(last year) based on my table field paidDate, using SQL server 2016.
Suppose, I run the query on Feb 1st/2nd, 2020. I need the monthly data from December 2019, January 2020, as well as January 2019.
What's the SQL query for this? Is it possible to club all of these scenario into one?
Then for the previous 2 months the paidDate would be :
A) Higher or equal than the first day of 2 months ago
B) Lower than the first day of the current month.
Similar for the month of a year ago.
So try something like this:
SELECT *
FROM YourTable
WHERE
(
paidDate >= DATEADD(month, -2, DATEADD(month, DATEDIFF(month, 0, GetDate()), 0))
AND paidDate < DATEADD(month, DATEDIFF(month, 0, GetDate()), 0)
)
OR
(
paidDate >= DATEADD(month, -13, DATEADD(month, DATEDIFF(month, 0, GetDate()), 0))
AND paidDate < DATEADD(year, -1, DATEADD(month, DATEDIFF(month, 0, GetDate()), 0))
)
LukStorm has the better answer in terms of performance (and I've upvoted it). But if you want complete months and don't care about indexing, then I would suggest datediff():
where datediff(month, paiddate, getdate()) in (1, 2, 13)
This gets the complete months that are 1 month, 2 months, and 13 months in the past.
You can try the logic as below-
SELECT *
FROM your_table
WHERE
(
YEAR(paidDate) = YEAR(DATEADD(MM,-1, getdate()))
AND
MONTH(paidDate) = MONTH(DATEADD(MM,-1, getdate()))
)
OR
(
YEAR(paidDate) = YEAR(DATEADD(MM,-2, getdate()))
AND
MONTH(paidDate) = MONTH(DATEADD(MM,-2, getdate()))
)
OR
(
YEAR(paidDate) = YEAR(DATEADD(MM,-13, getdate()))
AND
MONTH(paidDate) = MONTH(DATEADD(MM,-13, getdate()))
)
This question already has answers here:
Get the records of last month in SQL server
(23 answers)
Closed 9 years ago.
How can I get last month date like
select * from table where date in ( last month )
I dont want the last 30 days
AND how can I get last month automatically
Assuming you want all items where the date is within the last month i.e. between today and 30/31 days ago:
Select *
From Table
Where Date Between DATEADD(m, -1, GETDATE()) and GETDATE()
You can use this
Select * from table where date between #startdate and #enddate
Or
SELECT * FROM DATE_SAMPLE WHERE
DATEPART(YEAR, SAMPLE_DATE) = '2013' AND
DATEPART(MONTH,SAMPLE_DATE) = '01' AND
DATEPART(DAY, SAMPLE_DATE) = '01'
Is it usefull for you?
select * from table
where month(date)=month(getdate())-1
Edit
if you mean last month from today. or previous month from a specific date then you need to do something like this
SELECT DATEPART(MONTH, DATEADD(MONTH, -1, [Date]))
Or to get records from previous month of the year you can do something like this
SELECT * FROM Table
WHERE MONTH(Date) = DATEPART(MONTH, DATEADD(MONTH, -1, [Date]))
AND YEAR(Date) = DATEPART(YEAR, DATEADD(MONTH, -1, [Date])) --<-- or pass year for which year you are checking
To make your aquery SARGable (Suggested by t-clausen.dk)
select * from table
where date >=dateadd(m, datediff(m, 0, current_timestamp)-1, 0)
and date < dateadd(m, datediff(m, 0, current_timestamp)-1, 0)
Read here more about sargable Queries when working with date/datetime datatypes.
You can try to use the between statement to get the specific dates:
Select * from table where date between '01-01-2014' and '14-01-2014'
This seems to have been answered several times for the past 30 days. But seemingly not what I need.
If, for example, today is July 10th, 2012. I'm looking to pull all of June's data. I will need to run this query several days after the start of each month
There is certainly better ways to do this, but one way would be this:
DECLARE #Date DATETIME
SET #Date = '20120710'
SELECT *
FROM YourTable
WHERE YourDateColumn >= CONVERT(VARCHAR(6),DATEADD(MONTH,-1,#Date),112)+'01'
AND YourDateColumn < CONVERT(VARCHAR(6),#Date,112)+'01')
-- first day of previous month
select DateAdd(Month, DateDiff(Month, 0, GetDate())-1,0)
-- last day of previous month
Select DateAdd(day,-1,DateAdd(Month,1,DateAdd(Month,
DateDiff(Month, 0,GETDATE())-1,0)))
Please replace GETDATE() with your date column
Ah, in that case you need something like:
SELECT *
FROM
reporting_table_name_goes_here
WHERE
DATEPART(month, YourDateColumn) = DATEPART(month, DATEADD(month, -1, getdate()))
AND DATEPART(year, YourDateColumn) = DATEPART(year, DATEADD(month, -1, getdate()))
Check out MSDN for details.