I have the two tables:
TABLE1:
id name values
1 john AB
2 marry CD
3 sreya YG
TABLE2:
pid country values
45 india JKABHJ
46 usa YURRRCD
47 uk YGHJJKLJL
output
name values country
john AB india
marry CD usa
sreya YG uk
I want to join these two tables on the common columns values, but the other table columns contain extra data. How to overcome this?
table2 column "values" contains data matching to table1 "values"
values
AB
CD
YG
values
JKABHJ
YURRRCD
YGHJJKLJL
You can use like operator in query for matching values in table1 and table2.
For this query:
WITH table1 as (
select 1 as id, 'john' as name, 'AB' as value from dual union all
select 2 as id, 'marry' as name, 'CD' as value from dual union all
select 3 as id, 'sreya' as name, 'YG' as value from dual
),
table2 as (
select 45 as id, 'india' as country, 'JKABHJ' as value from dual union all
select 46 as id, 'usa' as country, 'YURRRCD' as value from dual union all
select 47 as id, 'uk' as country, 'YGHJJKLJL' as value from dual
)
select a.name, a.value, b.country
from table1 a
join table2 b on b.value like '%'||a.value||'%';
Output:
NAME VALUE COUNTRY
john AB india
marry CD usa
sreya YG uk
But I would recommend you to change a structure to make it more efficient. For example, by adding new table table2_values with column id referenced to table2.id and split values:
WITH table1 as (
select 1 as id, 'john' as name, 'AB' as value from dual union all
select 2 as id, 'marry' as name, 'CD' as value from dual union all
select 3 as id, 'sreya' as name, 'YG' as value from dual
),
table2 as (
select 45 as id, 'india' as country from dual union all
select 46 as id, 'usa' as country from dual union all
select 47 as id, 'uk' as country from dual
),
table2_values as (
select 45 as id, 'JK' as value from dual union all
select 45 as id, 'AB' as value from dual union all
select 45 as id, 'HJ' as value from dual union all
select 46 as id, 'YU' as value from dual union all
select 46 as id, 'RRR' as value from dual union all
select 46 as id, 'CD' as value from dual union all
select 47 as id, 'YG' as value from dual union all
select 47 as id, 'HJ' as value from dual
)
select a.name, a.value, c.country
from table1 a
join table2_values b on b.value = a.value
join table2 c on c.id = b.id;
You should use like operator while joining the two tables.
As below
SELECT *
FROM TABLE1
JOIN TABLE2
ON TABLE1.values like CONCAT('%',TABLE2.values,'%')
Related
I am trying to work out how the SQL if I want to bring back ALL "Names" from table1 and only list the output in Column 2 to contain the value if it is "Apple". If its not "Apple" or is "Null" then column 2 should also be "Null"
Table 1
ID(pk)
Name
24
Boris
25
Dominic
26
Rishi
27
Elizabeth
28
Ben
Table 2
ID(fk)
Description
27
Apple
27
Orange
27
Pear
26
Apple
26
Pear
25
Pear
24
Orange
Required Output
Name
Description
Boris
Dominic
Rishi
Apple
Elizabeth
Apple
Sajid
If there are no duplicates in the second table (in a comment below the question you confirmed that this is the case), this is a simple application of outer join.
Here I include the test data in the with clause. You don't need it - you have the actual tables. Remove the with clause, and inspect the main query and change the table and column names as needed.
with
table_1 (id, name) as (
select 24, 'Boris' from dual union all
select 25, 'Dominic' from dual union all
select 26, 'Rishi' from dual union all
select 27, 'Elizabeth' from dual union all
select 28, 'Ben' from dual
)
, table_2 (id, description) as (
select 27, 'Apple' from dual union all
select 27, 'Orange' from dual union all
select 27, 'Pear' from dual union all
select 26, 'Apple' from dual union all
select 26, 'Pear' from dual union all
select 25, 'Pear' from dual union all
select 24, 'Orange' from dual
)
select t1.name, t2.description
from table_1 t1 left outer join table_2 t2
on t2.id = t1.id and t2.description = 'Apple'
order by t1.id
;
NAME DESCRIPTION
--------- -----------
Boris
Dominic
Rishi Apple
Elizabeth Apple
Ben
You can solve it in a variety of ways, one example:
SELECT t1.name
, MAX(CASE t2.descripton WHEN 'Apple' THEN t2.descripton END)
FROM t1
JOIN t2
USING(id)
GROUP BY t1.name;
The CASE expression will map all but Apple to null. MAX will then reduce the set to either Apple or null for each name.
I think below query will work for you:
Select Name, CASE WHEN ID IN (SELECT DISTINCT ID FROM table2 WHERE LOWER(description) = 'apple') THEN 'Apple' ELSE Null END as Description FROM table1;
I have two tables which have a common key between them, and quite a lot of other important infos ; for the sake of simplicity i will be using Combination A and Combination B. When a combination is met, whichever table has the maximum number of records should be the source where i collect the information ; in this case say IDs. The priority when counts are same is Table1.
COMMONKEY column is the combination/join condition in my tables.
(Table 1)
SELECT '123' table1_id,'Comb A' commonkey from dual UNION
SELECT '124' table1_id,'Comb A' commonkey from dual UNION
SELECT '125' table1_id,'Comb A' commonkey from dual UNION
SELECT '126' table1_id,'Comb A' commonkey from dual UNION
SELECT '215' table1_id,'Comb B' commonkey from dual UNION
SELECT '216' table1_id,'Comb B' commonkey from dual UNION
SELECT '559' table1_id,'Random Combination 1' commonkey from dual UNION
SELECT '560' table1_id,'Random Combination 2' commonkey from dual ;
( Table 2 )
SELECT 'abc1' table2_id,'Comb A' commonkey from dual UNION
SELECT 'abc2' table2_id,'Comb A' commonkey from dual UNION
SELECT 'abc3' table2_id,'Comb A' commonkey from dual UNION
SELECT 'abc4' table2_id,'Comb A' commonkey from dual UNION
SELECT 'xyz1' table2_id,'Comb B' commonkey from dual UNION
SELECT 'xyz2' table2_id,'Comb B' commonkey from dual UNION
SELECT 'xyz3' table2_id,'Comb B' commonkey from dual UNION
SELECT 'xyz2' table2_id,'Comb B' commonkey from dual UNION
SELECT '416abc1' table2_id,'Random Combination 91' commonkey from dual UNION
SELECT '416abc2' table2_id,'Random Combination 92' commonkey from dual;
Result Set Expected :
ID COMMONKEY
123 Comb A
124 Comb A
125 Comb A
126 Comb A
xyz1 Comb B
xyz2 Comb B
xyz3 Comb B
559 Random Combination 1
560 Random Combination 1
416abc1 Random Combination 91
416abc2 Random Combination 92
Updated Image :
( the image shows a screenshot of the trail data in an excel; The Requirement and Strategy are color mapped to make it quickly understandable )
I need to generate the result set using SQL as follows :
When table1.commonkey = table2.commonkey hits, I need to-
If table1 has 10 IDs, table2 has 5 IDs -> Pick 10 IDs from table1.
If table1 has 15 IDs, table2 has 30 IDs -> Pick 30 IDs from table2.
If table1 has 4 IDs, table2 has 4 IDs -> Pick 4 IDs from table1.
( when equal, choose table1 IDs )
When no matches occur with the common key, prevent a cross join and add in the rowsets linearly to the result table.
Edit : I've initially gone on routes with
a left join b where b.key IS null ;
a full outer join b where b.key IS NULL or a.key is NULL ;
to achieve workarounds with A-B or B-A result sets but both these approaches were quite wrong. Gathering Delta sets or Exclusion sets didnt go well.
Here's one option; see comments within code
SQL> with
2 -- sample data
3 a (id, ckey) as
4 (select '123', 'ca' from dual union all
5 select '124', 'ca' from dual union all
6 select '125', 'ca' from dual union all
7 select '126', 'ca' from dual union all
8 select '215', 'cb' from dual union all
9 select '216', 'cb' from dual union all
10 select '551', 'r1' from dual union all
11 select '552', 'r2' from dual
12 ),
13 b (id, ckey) as
14 (select 'abc1', 'ca' from dual union all
15 select 'abc2', 'ca' from dual union all
16 select 'abc3', 'ca' from dual union all
17 select 'abc4', 'ca' from dual union all
18 select 'xyz1', 'cb' from dual union all
19 select 'xyz2', 'cb' from dual union all
20 select 'xyz3', 'cb' from dual union all
21 select '9991', 'r3' from dual union all
22 select '9992', 'r4' from dual
23 ),
24 -- count rows per each CKEY (common key)
25 tempa as
26 (select id, ckey, count(*) over (partition by ckey) cnt
27 from a
28 ),
29 tempb as
30 (select id, ckey, count(*) over (partition by ckey) cnt
31 from b
32 )
33 -- final query
34 select distinct
35 case when a.cnt >= b.cnt then a.id
36 else b.id
37 end id,
38 a.ckey
39 from tempa a join tempb b on b.ckey = a.ckey
40 union all
41 select ckey, id from a
42 where not exists (select null from b where a.ckey = b.ckey)
43 union all
44 select ckey, id from b
45 where not exists (select null from a where a.ckey = b.ckey)
46 order by 1, 2;
which results in
ID CKEY
---- -----
r1 551
r2 552
r3 9991
r4 9992
xyz1 cb
xyz2 cb
xyz3 cb
123 ca
124 ca
125 ca
126 ca
11 rows selected.
SQL>
I have a table like this:
ID NAME Dept_ID
1 a 2,3
2 b
3 c 1,2
Department is another table having dept_id and dept_name as columns. i want result like,
ID Name Dept_ID
1 a 2
1 a 3
2 b
3 c 1
3 c 2
any help please?
You can do it as:
--Dataset Preparation
with tab(ID, NAME,Dept_ID) as (Select 1, 'a', '2,3' from dual
UNION ALL
Select 2, 'b','' from dual
UNION ALL
Select 3, 'c' , '1,2' from dual)
--Actual Query
select distinct ID, NAME, regexp_substr(DEPT_ID,'[^,]+', 1, level)
from tab
connect by regexp_substr(DEPT_ID,'[^,]+', 1, level) is not null
order by 1;
Edit:
based on which column i need to join? in one table i have comma
separated ids and in other table i have just ids
with tab(ID, NAME,Dept_ID) as (Select 1, 'a', '2,3' from dual
UNION ALL
Select 2, 'b','' from dual
UNION ALL
Select 3, 'c' , '1,2' from dual) ,
--Table Dept
tbl_dept (dep_id,depname) as ( Select 1,'depa' from dual
UNION ALL
Select 2,'depb' from dual
UNION ALL
Select 3,'depc' from dual
) ,
--Seperating col values for join. Start your query from here using with clause since you already have the two tables.
tab_1 as (select distinct ID, NAME, regexp_substr(DEPT_ID,'[^,]+', 1, level) col3
from tab
connect by regexp_substr(DEPT_ID,'[^,]+', 1, level) is not null
order by 1)
--Joining table.
Select t.id,t.name,t.col3,dt.depname
from tab_1 t
left outer join tbl_dept dt
on t.col3 = dt.dep_id
order by 1
with tmp_tbl as(
select
1 ID,
'a' NAME,
'2,3' DEPT_ID
from dual
union all
select
2 ID,
'b' NAME,
'' DEPT_ID
from dual
union all
select
3 ID,
'c' NAME,
'1,2' DEPT_ID
from dual)
select
tmp_out.ID,
tmp_out.NAME,
trim(tmp_out.DEPT_ID_splited)
from(
select
tmp.ID,
tmp.NAME,
regexp_substr(tmp.DEPT_ID,'[^,]+', 1, level) DEPT_ID_splited
from
tmp_tbl tmp
connect by
regexp_substr(tmp.DEPT_ID,'[^,]+', 1, level) is not null) tmp_out
group by
tmp_out.ID,
tmp_out.NAME,
tmp_out.DEPT_ID_splited
order by
tmp_out.ID,
tmp_out.DEPT_ID_splited
I have to join 2 tables with SQL in a special way:
TABLE1 has the fields GROUP and MEMBER, TABLE2 has the fields GROUP and MASTER.
I have to build a new TABLE3 with the fields GROUP and ID by copying TABLE1 to TABLE3 and search TABLE2 if there is a GROUP from TABLE1 and if, copy GROUP and MASTER to TABLE3.
Example:
table1:
group member
1 a
1 b
1 c
2 x
3 y
table2:
group master
3 n
3 z
1 k
9 v
2 m
7 o
8 p
Expected result, table3:
group id
1 a from table1
1 b from table1
1 c from table1
1 k from table2
2 x from table1
2 m from table2
3 y from table1
3 z from table2
3 n from table2
I hope everything's clear.
So what is the SQL query?
Thanks, Hein
The first part (copy members) should be easy:
INSERT INTO table3 (group, id) SELECT group, member FROM table1;
Then You just copy the masters, that are in groups, that are already present in table1:
INSERT INTO table3 (group, id) SELECT group, master FROM table2 WHERE group IN (SELECT DISTINCT group FROM table1);
Try this out. Of course you need to INSERT the whole selection to your new table named Table3.
WITH TABLE1(GRP,MMBR) AS
(SELECT 1, 'a' FROM DUAL UNION ALL
SELECT 1, 'b' FROM DUAL UNION ALL
SELECT 1, 'c' FROM DUAL UNION ALL
SELECT 2, 'x' FROM DUAL UNION ALL
SELECT 3, 'y' FROM DUAL),
TABLE2(GRP,MSTR) AS
(SELECT 3, 'n' FROM DUAL UNION ALL
SELECT 3, 'z' FROM DUAL UNION ALL
SELECT 1, 'k' FROM DUAL UNION ALL
SELECT 9, 'v' FROM DUAL UNION ALL
SELECT 2, 'm' FROM DUAL UNION ALL
SELECT 7, 'o' FROM DUAL UNION ALL
SELECT 8, 'p' FROM DUAL)
SELECT * FROM (
SELECT GRP, MMBR ID FROM TABLE1
UNION --UNION ALL if you need duplicates
SELECT GRP, MSTR ID FROM TABLE2
WHERE TABLE2.GRP IN (SELECT GRP FROM TABLE1)
)
ORDER BY GRP, ID
You can do it using UNION ALL and 2 simple SELECT in an INSERT as follows:
INSERT INTO table3(group,id)
SELECT group,id FROM table1
UNION ALL
SELECT group,id FROM table2
SELECT * FROM table3;
And if you don't want duplicate values,try this using UNION instead of UNION ALL:
INSERT INTO table3(group,id)
SELECT group,id FROM table1
UNION
SELECT group,id FROM table2
SELECT * FROM table3;
I have a table with many of columns, I count the specific names on column and if that name not on list, I want to display it zero, but not get in to list.
SELECT Names, COUNT (*)
FROM NAMESTABLE
WHERE names IN
('Jenny',
'Penny',
'George',
'James',
'Jessica',
'Monica',
'Erica')
AND
adeddate BETWEEN '2014/10/15' AND '2014/10/16'
GROUP BY names
NAMES || COUNT(*)
Jenny || 33
Penny || 4
George || 25
James || 87
so i want to Jessica, Monica, Erica as ZERO even these names are not in COLUMN
Names || Count(*)
Jenny || 33
Penny || 4
George || 25
James || 87
Jessica || 0
Monica || 0
Erica || 0
nvl(count(*),0) does not work
You could group your results by name and then left join the result to a table of your names to fill in the blanks:
SELECT rn.name, NVL(cnt, 0)
FROM (SELECT 'Jenny' AS name FROM dual
UNION ALL
SELECT 'Penny' FROM dual
UNION ALL
SELECT 'George' FROM dual
UNION ALL
SELECT 'James' FROM dual
UNION ALL
SELECT 'Jessica' FROM dual
UNION ALL
SELECT 'Monica' FROM dual
UNION ALL
SELECT 'Erica' FROM dual) rn
LEFT JOIN (SELECT name, COUNT(*) AS cnt
FROM namestable
WHERE adeddate BETWEEN '2014/10/15' AND '2014/10/16'
GROUP BY name) n ON n.name = rn.name
Then you must use other syntax:
SELECT t.Names, COUNT(n.Names)
FROM (
SELECT 'Jenny' AS names FROM DUAL UNION ALL
SELECT 'Penny' FROM DUAL UNION ALL
SELECT 'George' FROM DUAL UNION ALL
SELECT 'James' FROM DUAL UNION ALL
SELECT 'Jessica' FROM DUAL UNION ALL
SELECT 'Monica' FROM DUAL UNION ALL
SELECT 'Erica' FROM DUAL
) t
LEFT OUTER JOIN NAMESTABLE n
ON n.names = t.names AND n.adeddate BETWEEN '2014/10/15' AND '2014/10/16'
GROUP BY t.names
This should work with a CTE..
WITH CTE AS
(SELECT 'Jenny' Names FROM dual UNION ALL
SELECT 'Penny' FROM dual UNION ALL
SELECT 'George' FROM dual UNION ALL
SELECT 'James' FROM dual UNION ALL
SELECT 'Jessica' FROM dual UNION ALL
SELECT 'Monica' FROM dual UNION ALL
SELECT 'Erica' FROM dual)
SELECT CTE.names, coalesce(count(NT.Names),0)
FROM CTE
LEFT JOIN NAMESTABLE NT
on CTE.Names = NT.Names
and adeddate BETWEEN '2014/10/15' AND '2014/10/16'
GROUP BY CTE.Names
You could create an a table containing all valid names, eg valid_names table. Then join to your namestable using an outerjoin. Eg:
select valid_names.name, count(1)
from namestable, valid_names
where valid_names.name=namestable.name (+)
group by valid_names.name
order by valid_names.name;