SQL Server 2014 Select total for each day - sql

Question

Hello I am working on a dataset for a report in SSRS
and I have a query which gives the total requests in the backlog :
SELECT
COUNT(*) as NB
FROM p_rqt WITH (NOLOCK)
INNER JOIN p_cpy WITH (NOLOCK) ON p_cpy.CpyInCde = p_rqt.OrigCpyInCde
WHERE
CpyTypInCde IN (27, 31)
AND p_rqt.RqtNatInCde IN (74, 75, 76)
AND HeadRqtInCde = 0
AND p_rqt.OrigCpyInCde LIKE CASE WHEN #Client = 0 THEN '%' ELSE #Client END
AND ((RcvDte < DATEADD(day, 1, #DateDeb) AND RqtEndDte IS NULL) OR
(RcvDte < DATEADD(day, 1, #DateDeb) AND RqtEndDte > DATEADD(day, 1, #DateDeb)))
and I want to retrieve the total amount left per day.
I tried lot of things like this :
SELECT CONVERT(date,rcvdte,103), count(*) as nb
FROM p_rqt p WITH (NOLOCK)
INNER JOIN p_cpy WITH (NOLOCK) ON p_cpy.CpyInCde = p.OrigCpyInCde
WHERE
CpyTypInCde IN (27, 31)
AND p.RqtNatInCde IN (74, 75, 76)
AND HeadRqtInCde = 0
AND ((RcvDte < DATEADD(day, 1, '20170901') AND RqtEndDte IS NULL) OR (RcvDte < DATEADD(day, 1, '20170901') AND RqtEndDte > DATEADD(day, 1, '20170901')))
group by CONVERT(date,rcvdte,103)
order by CONVERT(date,rcvdte,103)
I tried inner join subqueries, Sum and other stuff
but all I can manage to do is to have the number of records added per day
and I want something like this :
date: NB:
01/01/2017 1950
02/01/2017 1954 (+4 items)
03/01/2017 1945 (-9 items)
Thank you

Answer 1

Use LAG:
WITH cte AS (
SELECT
CONVERT(date, rcvdte, 103) AS date,
COUNT(*) AS nb
FROM p_rqt p WITH (NOLOCK)
INNER JOIN p_cpy WITH (NOLOCK)
ON p_cpy.CpyInCde = p.OrigCpyInCde
WHERE
CpyTypInCde IN (27, 31) AND
p.RqtNatInCde IN (74, 75, 76) AND
HeadRqtInCde = 0 AND
((RcvDte < DATEADD(day, 1, '20170901') AND RqtEndDte IS NULL) OR (RcvDte < DATEADD(day, 1, '20170901') AND RqtEndDte > DATEADD(day, 1, '20170901')))
GROUP BY CONVERT(date, rcvdte, 103)
ORDER BY CONVERT(date, rcvdte, 103)
)
SELECT
t1.date,
(SELECT SUM(t2.nb) FROM cte t2 WHERE t2.date <= t1.date) AS nb,
CASE WHEN t1.nb - LAG(t1.nb, 1, t1.nb) OVER (ORDER BY t1.date) > 0
THEN '(+' + (t1.nb - LAG(t1.nb, 1, t1.nb) OVER (ORDER BY t1.date)) + ' items)'
ELSE '(' + (t1.nb - LAG(t1.nb, 1, t1.nb) OVER (ORDER BY t1.date)) + ' items)'
END AS difference
FROM cte t1
ORDER BY t1.date;

Answer 2

So i found a solution but it is really slow,
i still post the answer anyway
DECLARE #Tb TABLE ( Colonne1 Datetime, Colonne2 INT )
DECLARE #Debut Datetime = '01/09/2017'
WHILE #Debut < '13/09/2017'
BEGIN
DECLARE #Compteur int = (
SELECT
COUNT(1) NB
FROM p_rqt WITH (NOLOCK)
INNER JOIN p_cpy WITH (NOLOCK) ON p_cpy.CpyInCde = p_rqt.OrigCpyInCde
WHERE
CpyTypInCde IN (27, 31)
AND p_rqt.RqtNatInCde IN (74, 75, 76)
AND HeadRqtInCde = 0
AND p_rqt.OrigCpyInCde LIKE '%'
AND (
(RcvDte < #Debut AND RqtEndDte IS NULL)
OR
(RcvDte < #Debut AND RqtEndDte > #Debut)
)
)
INSERT INTO #Tb (Colonne1, Colonne2) VALUES (#Debut, #Compteur)
SET #Debut = DATEADD(day, 1, #Debut)
IF #Debut > '13/09/2017'
BREAK
ELSE
CONTINUE
END
SELECT * FROM #Tb