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I have a a below table where all the columns are same except for group column and I am calculating count(distinct group) and blocks in the same table:
Input:
id
time
CODE
group
value
total_blocks
1
22
32206
mn2
1
200
1
22
32206
mn4
1
200
Output:
id
time
CODE
group
value
count(distinct group)
blocks
1
22
32206
mn2
1
2
100
1
22
32206
mn4
1
2
100
count(distinct group) is just distinct values (mn2 and mn4) and blocks overall wrt to code(32206) is 200, but I am splitting the same over the two rows.
The output should look exactly the same in the final, without removal of any columns.
I tried using count(distinct) but it didn't work
Oracle:
Try it like here:
WITH -- S a m p l e d a t a
tbl (ID, A_TIME, CODE, A_GROUP, A_VALUE, TOTAL_BLOCKS) AS
(
Select 1, 22, 32206, 'mn2', 1, 200 From Dual Union All
Select 1, 22, 32206, 'mn4', 1, 200 From Dual
)
-- S Q L --
Select
ID, A_TIME, CODE, A_GROUP, A_VALUE,
Count(DISTINCT A_GROUP) OVER(Partition By CODE) "COUNT_DIST_GROUP", -- Count distinct groups per CODE
-- Count(DISTINCT A_GROUP) OVER() "COUNT_DIST_GROUP", --Count distinct groups over the whole table
TOTAL_BLOCKS / Count(*) OVER(Partition By CODE) "BLOCKS" -- TOTAL_BLOCKS divided by number of rows per CODDE
-- TOTAL_BLOCKS / Count(*) OVER() "BLOCKS" -- TOTAL_BLOCKS divided by number of rows in the whole table
From
tbl
R e s u l t :
ID A_TIME CODE A_GROUP A_VALUE COUNT_DIST_GROUP BLOCKS
---------- ---------- ---------- ------- ---------- ---------------- ----------
1 22 32206 mn2 1 2 100
1 22 32206 mn4 1 2 100
Comments in code explain the basic use of Count() Over() analytic function. More about analytic functions here.
Using just ROW_NUMBER() analytic function and Max() aggregate function...
-- S Q L --
Select
r.ID, r.A_TIME, r.CODE, t.A_GROUP, r.A_VALUE, MAX_RN "COUNT_DIST_GROUP", (TOTAL_BLOCKS / MAX_RN) "BLOCKS"
From
( SELECT ID, A_TIME, CODE, A_VALUE, Max(RN) "MAX_RN"
FROM (Select ID, A_TIME, CODE, A_VALUE, Row_Number() OVER(Partition By CODE Order By CODE, A_GROUP) "RN"
From tbl )
GROUP BY ID, A_TIME, CODE, A_VALUE ) r
Inner Join tbl t ON(t.CODE = r.CODE)
ID A_TIME CODE A_GROUP A_VALUE COUNT_DIST_GROUP BLOCKS
---------- ---------- ---------- ------- ---------- ---------------- ----------
1 22 32206 mn2 1 2 100
1 22 32206 mn4 1 2 100
... and it works with another group of similar data:
WITH -- S a m p l e d a t a
tbl (ID, A_TIME, CODE, A_GROUP, A_VALUE, TOTAL_BLOCKS) AS
(
Select 1, 22, 32206, 'mn2', 1, 200 From Dual Union All
Select 1, 22, 32206, 'mn4', 1, 200 From Dual Union All
--
Select 1, 22, 32207, 'mn6', 1, 450 From Dual Union All
Select 1, 22, 32207, 'mn7', 1, 450 From Dual Union All
Select 1, 22, 32207, 'mn8', 1, 450 From Dual
)
-- S Q L --
Select
r.ID, r.A_TIME, r.CODE, t.A_GROUP, r.A_VALUE, MAX_RN "COUNT_DIST_GROUP", (TOTAL_BLOCKS / MAX_RN) "BLOCKS"
From
( SELECT ID, A_TIME, CODE, A_VALUE, Max(RN) "MAX_RN"
FROM (Select ID, A_TIME, CODE, A_VALUE, Row_Number() OVER(Partition By CODE Order By CODE, A_GROUP) "RN"
From tbl )
GROUP BY ID, A_TIME, CODE, A_VALUE ) r
Inner Join tbl t ON(t.CODE = r.CODE)
ID A_TIME CODE A_GROUP A_VALUE COUNT_DIST_GROUP BLOCKS
---------- ---------- ---------- ------- ---------- ---------------- ----------
1 22 32206 mn2 1 2 100
1 22 32206 mn4 1 2 100
1 22 32207 mn6 1 3 150
1 22 32207 mn7 1 3 150
1 22 32207 mn8 1 3 150
I'm using SQL Server 2016. I have the below table:
SKU Mkt Week Cost Code
ABC 05 1 10 100
ABC 05 2 12 100
DEF 05 3 20 100
DEF 05 3 25 125
XYZ 08 1 10 100
XYZ 08 2 12 100
XZY 08 2 14 125
This is the desired result:
SKU Mkt Week Cost Code
ABC 05 1 10 100
ABC 05 2 12 100
DEF 05 3 25 125
XYZ 08 1 10 100
XZY 08 2 14 125
So if a SKU\Mkt\Week\Cost exist more than once, I want to keep the record where code = 125 and delete the row where the code is 100.
I'm using the below Cte:
;WITH CTE AS
(
SELECT *,
RN = ROW_NUMBER() OVER( PARTITION BY SKU, Mkt, Week
ORDER BY SKU, Mkt, Week)
FROM [table]
WHERE code = 100
)
DELETE FROM CTE
WHERE RN > 1
However, the Cte doesnot delete anything -what am I missing?
Based on the query and sample data you have provided, You need to note to this section of the cte inner query:
WHERE code = 100
when this filter applied you have the following data:
SKU Mkt Week Cost Code
ABC 05 1 10 100
ABC 05 2 12 100
DEF 05 3 20 100
which will get the 1 as Row_Number()'s output!, so running the following query will not effect any rows:
DELETE FROM CTE
WHERE RN > 1
To achieve the desired result you need to remove the WHERE section in CTE's inner query.
;WITH CTE AS
(
SELECT *,
RN = ROW_NUMBER() OVER( PARTITION BY SKU, Mkt, Week
ORDER BY SKU, Mkt, Week, Cost DESC) --Code/Cost DESC <==== Note this too
FROM [table]
--WHERE code = 100 <========== HERE, I've commented it
)
DELETE FROM CTE
WHERE RN > 1
You need to also add the Cost DESC or Code Desc to Row_Number()'s Order By section.
Ranking function will be evaluated in the select statement , which means the where clause WHERE code = 100 is evaluated before ROW_NUMBER() and so it has already removed the rows with code 125. Use order by Code as well and then apply the code=100 check when deleting from the CTE
;WITH CTE AS
(
SELECT *,
RN = ROW_NUMBER() OVER( PARTITION BY SKU, Mkt, Week
ORDER BY SKU, Mkt, Week,Code DESC)
FROM tt1
)
DELETE FROM CTE
WHERE RN > 1
AND CODE = 100
Try below query to get the desired result -
Sample data and Query
Declare #Table table
(SKU varchar(20), Mkt int, [Week] int, Cost int, Code int)
Insert into #Table
values
( 'ABC', 05 , 1, 10 , 100),
( 'ABC' , 05 , 2 , 12 , 100),
('DEF' ,05 , 3 , 20 , 100),
('DEF' ,05 , 3 ,25 , 125),
('XYZ' , 08 , 1 ,10 , 100),
('XYZ' , 08 , 2 ,12 , 100),
('XYZ' , 08, 2 ,14, 125)
;WITH CTE AS
(
SELECT *,
RN = ROW_NUMBER() OVER( PARTITION BY SKU, Mkt, Week
ORDER BY SKU, Mkt, Week, code desc)
FROM #Table
)
delete from Cte where RN > 1
Along with moving your Where statement, I believe you also want a second cte to work with the records you are identifying... In the following your first cte identifies the duplicate records while the second cte isolates them so you can perform your delete against those SKUs
Table
Create Table #tbl
(
SKU VarChar(10),
Mkt VarChar(10),
Week Int,
Cost Int,
Code Int
)
Insert Into #tbl Values
('ABC','05',1,10,100),
('ABC','05',2,12,100),
('DEF','05',3,20,100),
('DEF','05',3,25,125),
('XYZ','08',1,10,100),
('XYZ','08',2,12,100),
('XYZ','08',2,14,125)
Query
;WITH CTE AS
(
SELECT *,
RN = ROW_NUMBER() OVER( PARTITION BY SKU, Mkt, Week
ORDER BY SKU, Mkt, Week)
FROM #tbl
--WHERE code = 100
)
, cte1 As
(
Select sku from cte where rn > 1
)
DELETE c FROM CTE c inner join cte1 c1 On c.SKU = c1.SKU
WHERE c.Code = 100
Select * From #tbl
Result (Your 'desired result' example removed an XYZ record where the week was not duplicated?)
SKU Mkt Week Cost Code
ABC 05 1 10 100
ABC 05 2 12 100
DEF 05 3 25 125
XYZ 08 1 10 100
XYZ 08 2 12 100
XZY 08 2 14 125
Your CTE statement is only considering rows with code = 100. If you remove it, then CTE will rank based on all rows from the table. Using this, first find out which combination of have multiple rows. Then, among these combinations, identify rows with code = 100 and delete them.
create table #e1
(
SKU varchar(50)
,Mkt varchar(50)
,_Week int
,Cost int
,_code int
)
insert into #e1(SKU, Mkt, _Week, Cost, _code)
select 'ABC', '05', 1, 10, 100 UNION
SELECT 'ABC', '05', 2, 12, 100 union
SELECT 'DEF', '05', 3, 20, 100 UNION
SELECT 'DEF', '05', 3, 25, 125 UNION
SELECT 'XYZ', '08', 1, 10, 100 UNION
SELECT 'XYZ', '08', 2, 12, 100 UNION
SELECT 'XZY', '08', 2, 14, 125
delete s
from
#e1 s
JOIN
(
SELECT SKU, Mkt, _Week
FROM #e1
group by
SKU, Mkt, _Week
having count(1) > 1
) m
ON
s.SKU = m.sku and s.mkt = m.mkt and s._Week = m._Week
WHERE s._code = 100
Create table #tab1 (SKU varchar(50),Mkt varchar(50),[Week] varchar(50),Cost varchar(50),Code varchar(50))
insert into #tab1
select 'ABC','05','1','10','100'
union
select 'ABC','05','2','12','100'
union
select 'DEF','05','3','20','100'
union
select 'DEF','05','3','25','125'
union
select 'XYZ','08','1','10','100'
union
select 'XYZ','08','2','12','100'
union
select 'XYZ','08','2','14','125'
delete t from #tab1 t
inner join (select t1.SKU,t1.Mkt,t1.[Week],t1.Cost as Cost,t1.Code as Code,ROW_NUMBER()over(partition by t1.SKU,t1.Mkt,t1.[Week] order by t1.Cost desc,t1.Code desc ) as rno
from #tab1 t1
) c on c.SKU = t.SKU and c.Mkt = t.Mkt and c.Cost = t.Cost and c.[Week] = t.[Week] and c.Code = t.Code
where c.rno = 2
select * from #tab1
Output:
SKU Mkt Week Cost Code
ABC 05 1 10 100
ABC 05 2 12 100
DEF 05 3 25 125
XYZ 08 1 10 100
XYZ 08 2 14 125
For example this table, I need to sum this grouped by id and date with distinct
id amt date
1 100 2018/06/01
1 120 2018/06/02
1 100 2018/06/03
1 100 2018/06/03
1 100 2018/06/03
2 100 2018/06/01
2 100 2018/06/01
2 100 2018/06/01
2 130 2018/06/02
2 130 2018/06/02
2 130 2018/06/02
2 130 2018/06/02
2 100 2018/06/03
First i tried
SELECT SUM(DISTINCT amt) GROUP BY id
But the result are wrong, it's removing duplicate for example on id 1, instead of 320 it only results 220 because it remove the duplicated amt 100.
So I tried
SELECT SUM(DISTINCT amt) GROUP BY id, date
But I can't sum it.
Edit: Sorry i forgot to say the result should be
id amt
1 320
2 330
With a long version, but easy to understand query. The below query using CTE should help you
with records as
(select distinct id, date, amt from table_name)
select sum (amt), id
from records
group by
id;
tried with below.
SELECT id,SUM(DISTINCT amt) as amt,date #tmp from [yourTableName] GROUP BY id, date
select id,amt from #tmp
Try this:
select id, SUM(amt) from (
select id, SUM(distinct amt) amt, [date] from #tbl
group by id, [date]
) a group by id
First you need to group distinct amt grouped by id and date. Next, you have to to group the result by id, summing partially summed amt column (in first step we summed only distinct values from particular days).
Try this...
SELECT id,
Sum(amt) AS amt
FROM (SELECT DISTINCT *
FROM mytable) tbl
GROUP BY id
Output
+----+-----+
| id | amt |
+----+-----+
| 1 | 320 |
| 2 | 330 |
+----+-----+
SQL FIDDLE: http://sqlfiddle.com/#!18/2d356/14/0
The below query using CTE and Row_number should help you
with cte
as
(
select 1 id, 100 amt,cast('2018/06/01' as date) date
union all
select 1 id, 120 amt,cast('2018/06/02' as date) date
union all
select 1 id, 100 amt,cast('2018/06/03' as date) date
union all
select 1 id, 100 amt,cast('2018/06/03' as date) date
union all
select 1 id, 100 amt,cast('2018/06/03' as date) date
union all
select 2 id, 100 amt,cast('2018/06/01' as date) date
union all
select 2 id, 100 amt,cast('2018/06/01' as date) date
union all
select 2 id, 100 amt,cast('2018/06/01' as date) date
union all
select 2 id, 130 amt,cast('2018/06/02' as date) date
union all
select 2 id, 130 amt,cast('2018/06/02' as date) date
union all
select 2 id, 130 amt,cast('2018/06/02' as date) date
union all
select 2 id, 130 amt,cast('2018/06/02' as date) date
union all
select 2 id, 100 amt,cast('2018/06/03' as date) date
)
select id,sum(amt) as sum1 from
(
select *,ROW_NUMBER() over(partition by id,date order by id,date) s1 from cte
) b
where s1=1
group by id
I have a table like this:
id name value
1 elec 10
1 water 20
2 elec 15
2 water 45
Now I need to dynamically add some rows to the result of select query:
id name value
1 elec 10
1 water 20
1 ratio 0.5
2 elec 15
2 water 45
2 ratio 0.33
Add two rows dynamically,how can i do?
It would make a lot more sense to "present" the results with ELEC, WATER and RATIO columns - one row per ID. The solution below shows how you can do that efficiently (reading the base table only one time).
with
inputs ( id, name, value ) as (
select 1, 'elec' , 10 from dual union all
select 1, 'water', 20 from dual union all
select 2, 'elec' , 15 from dual union all
select 2, 'water', 45 from dual
)
-- End of simulated inputs (not part of the solution).
-- SQL query begins BELOW THIS LINE. Use your actual table and column names.
select id, elec, water, round(elec/water, 2) as ratio
from inputs
pivot ( min(value) for name in ('elec' as elec, 'water' as water ) )
;
ID ELEC WATER RATIO
---------- ---------- ---------- ----------
1 10 20 .5
2 15 45 .33
If instead you need the results in the format you showed in your original post, you can unpivot like so (still reading the base table only once):
with
inputs ( id, name, value ) as (
select 1, 'elec' , 10 from dual union all
select 1, 'water', 20 from dual union all
select 2, 'elec' , 15 from dual union all
select 2, 'water', 45 from dual
)
-- End of simulated inputs (not part of the solution).
-- SQL query begins BELOW THIS LINE. Use your actual table and column names.
select id, name, value
from (
select id, elec, water, round(elec/water, 2) as ratio
from inputs
pivot ( min(value) for name in ('elec' as elec, 'water' as water ) )
)
unpivot ( value for name in (elec as 'elec', water as 'water', ratio as 'ratio') )
;
ID NAME VALUE
---------- ----- ----------
1 elec 10
1 water 20
1 ratio .5
2 elec 15
2 water 45
2 ratio .33
Here is one method:
with t as (
<your query here>
)
select id, name, value
from ((select t.*, 1 as ord
from t
) union all
(select id, 'ratio',
max(case when name = 'elec' then value end) / max(case when name = 'water' then value end)
), 2 as ord
from t
group by id
)
) tt
order by id, ord;
If you are fine with slight change in ordering, try this.
SELECT id,name,value FROM yourtable
UNION ALL
SELECT
a.id ,
'ratio' name,
a.value/b.value value
FROM
yourtable a
JOIN yourtable b on a.id = b.id
WHERE a.name = 'elec'
and b.name = 'water'
ORDER BY
id ,
VALUE DESC;
If you need to add the rows to table itself, then use.
INSERT INTO yourtable
SELECT
a.id ,
'ratio' name,
a.value/b.value value
FROM
yourtable a
JOIN yourtable b on a.id = b.id
WHERE a.name ='elec'
and b.name ='water';
I have table like this
OrderNo Item_Description1 Rate1 Quantity1 Item_Description2 Rate2 Quantity2 Item_Description3 Rate3 Quantity3
-------- ------------------ ------ ---------- ------------------ ------ ---------- ------------------ ------ ----------
1001 Laptop 50000 8 Air Conditioner 20000 10 Television 25000 12
1002 Washing Machine 35000 10 Camera 4000 20 Speaker 1500 15
From this I need to create a temp table or table like this:
OrderNo Item_Description Rate Quantity
-------- ------------------ ------ ----------
1001 Laptop 50000 8
Air Conditioner 20000 10
Television 25000 12
1002 Washing Machine 35000 10
Camera 4000 20
Speaker 1500 15
Is there a way I can do this in SQL Server?
You can also use CROSS APPLY to unpivot the data:
select t.order_no,
c.item_description,
c.rate,
c.quantity
from yourtable t
cross apply
(
select item_description1, rate1, quantity1 union all
select item_description2, rate2, quantity2 union all
select item_description3, rate3, quantity3
) c (item_description, rate, quantity)
SELECT * FROM
(select ORDER_NO,ITEM_DESCRIPTION1,RATE1,QUANTITY1FROM TABLE
UNION
select ORDER_NO,ITEM_DESCRIPTION2,RATE2,QUANTITY2 FROM TABLE
UNION
select ORDER_NO,ITEM_DESCRIPTION3,RATE3,QUANTITY3 FROM TABLE)AS A ORDER BY ORDER_NO
Try this
SELECT t.*
FROM Table1
OUTER APPLY
(
VALUES
([OrderNo],item_description1, rate1, quantity1),
(NULL, item_description2, rate2, quantity2),
(NULL, item_description3, rate3, quantity3)
) t([OrdNo],item_description, rate, quantity)
SQL FIDDLE DEMO
Or use #bluefeet answer with NULL
SELECT c.[OrderNo],
c.item_description,
c.rate,
c.quantity
FROM Table1 t
CROSS APPLY
(
SELECT [OrderNo],item_description1, rate1, quantity1 UNION ALL
SELECT NULL, item_description2, rate2, quantity2 UNION ALL
SELECT NULL, item_description3, rate3, quantity3
) c ([OrderNo],item_description, rate, quantity)
SQL FIDDLE DEMO
hope to help you!
select t.* from
(
select order_No, Item_Description1 as Item_Desription, Rate1 as Rate
from Table
union
select order_No, Item_Description2 as Item_Desription, Rate2 as Rate
from Table
union
select order_No, Item_Description3 as Item_Desription, Rate3 as Rate
from Table
) as t
Order by t.order_No asc
this is my test
select t.* from
(select id, apple1 as apple, orange1 as orange
from Test
union all
select id, apple2 as apple, orange2 as orange
from Test
union all
select id, apple3 as apple, orange3 as orange
from Test) as t
order by t.id asc