Spaces in my phone numbers are causing issues when I am trying to search.
Select * from customers where number LIKE '%02722231%'
This will return records that're LIKE '02722231', but this will not return any records that contain a space e.g. '027 22231'
Can this be done with regular expressions? I need to search 0272542155 and get all records the same including 027 2542155
Try this:
Select * from customers where REPLACE(number, ' ', '') LIKE '%02722231%'
Related
I have a sql server database that has medical descriptions in it. I've created a full text index on it, but I'm still figuring out how this works.
The easiest example to give is if there is a description of Hypertensive heart disease
Now they would like to be able to type hyp hea as a search term and have it return that.
So from what I've read it seems like my query needs to be something like
DECLARE #Term VARCHAR(100)
SET #Term = 'NEAR(''Hyper*'',''hea*'')'
SELECT * FROM Icd10Codes WHERE CONTAINS(Description, #Term)
If I take the wild card out for Hypertensive and heart, and type out the full words it works, but adding the wild card in returns nothing.
If it makes any difference I'm using Sql Server 2017
So it was a weird syntax issue that didn't cause an error, but stopped the search from working.
I changed it to
SELECT * FROM Icd10Codes where CONTAINS(description, '"hyper*" NEAR "hea*"')
The key here being I needed double quotes " and not to single quotes. I assumed it was two single quotes, the first to escape the second, but it was actually double quotes. The above query returns the results exactly as expected.
this will work:
SELECT * FROM Icd10Codes where SOUNDEX(description)=soundex('Hyp');
SELECT * FROM Icd10Codes where DIFFERENCE(description,'hyp hea')>=2;
You could try a like statement. You can find a thorough explanation here.
Like so:
SELECT * FROM Icd10Codes WHERE Icd10Codes LIKE '%hyp hea%';
And then instead of putting the String in there just use a variable.
If you need to search for separated partial words, as in an array of search terms, it gets a bit tricky, since you need to dynamically build the SQL statement.
MSSQL provides a few features for full text search. You can find those here. One of them is the CONTAINS keyword:
SELECT column FROM table WHERE CONTAINS (column , 'string1 string2 string3');
For me - this had more mileage.
create a calculated row with fields as full text search.
fullname / company / lastname all searchable.
ALTER TABLE profiles ADD COLUMN fts tsvector generated always as (to_tsvector('english', coalesce(profiles.company, '') || ' ' || coalesce(profiles.broker, '') || ' ' || coalesce(profiles.firstname, '') || ' ' || coalesce(profiles.lastname, '') || ' ' )) stored;
let { data, error } = await supabase.from('profiles')
.select()
.textSearch('fts',str)
I have a database with table contains information about employees in my company.
I need a SQL statement to show all names whose have 3 parts like "haitham samey hegazy" and who less or more than 3 parts didn't shown in the condition result.
I try to use like operator but it doesn't work and my database is in Arabic language.
Thanks for helping...
Assuming names are separated by a single space, you can get at least three parts using:
where name like '% % %'
You can get exactly three parts using:
where name like '% % %' and name not like '% % % %'
You can use replace to count the number of spaces:
SELECT *
FROM Table
WHERE LEN(LTRIM(RTRIM(varcharColumn))) -
LEN(REPLACE(LTRIM(RTRIM(varcharColumn)), ' ', '')) >= 2
This will return all the rows where there are at least 2 spaces inside the varcharColumn.
I'm wondering if there is a way to query the oracle db against formatted field value.
Example:
I have a table of postcodes stored in the format of "part1 part2". I want to be able to find a postcode either by searching it using the above format or "part1part2" format.
What I was thinking is to format the entered postcode by removing the spaces and then query the database like:
SELECT *
FROM POSTCODES_TBL t
WHERE t.postcode.**Format(remove spaces)** = 'part1part2'
The Format(remove spaces would convert the postcode from "part1 part2" to "part1part".
My question is, is it possible?
You can use regexp_replace
SELECT *
FROM POSTCODES_TBL t
WHERE regexp_replace(t.postcode,'\s', '') = 'part1part2'
This will remove any whitespace (space, tab, newlines etc)
or if you only want to get rid of spaces, replace will work just as well:
SELECT *
FROM POSTCODES_TBL t
WHERE replace(t.postcode,' ', '') = 'part1part2'
More details in the manual:
replace
regexp_replace
You could use like
SELECT *
FROM POSTCODES_TBL t
WHERE t.postcode like 'part1%part2'
I want to write an SQL SERVER statement that searches for the beginning of a word in a string that starts with something.
For example, if I search for 'em' on the Company record, I should get:
Emily, Inc
The Emmmy
NOT
Forget Them
Lemming, LLC
I can do this in PHP by extracting/slicing the string into an array and searching the beginning of each words.
But how I would write this query in SQL server without resorting to Stored procedures/functions?
JW's answer will work for entries where Em is at the very beginning of the field.
If you also need to retrieve values where the word is not the first in the string, try:
SELECT * FROM tableName WHERE CompanyName LIKE 'Em%' or CompanyName LIKE '% Em%'
(This is assuming all word are separated by a space.)
use LIKE
SELECT * FROM tableName WHERE CompanyName LIKE 'Em%'
Another option is CONTAINS, something like:
SELECT ... WHERE CONTAINS(CompanyName, 'Em*');
For MS Access:
SELECT * FROM Table1 WHERE Company_Name LIKE 'Word*'
For more standard DBMSs:
SELECT * FROM Table1 WHERE Company_Name LIKE 'Word%'
I have a MySQL select statement dilemma that has thrown me off course a little. In a certain column I have a category term. This term could look something like 'category' or it could contain multiple CSV's like this: 'category, bank special'.
I need to retrieve all rows containing the term 'bank special' in the comma separated value. Currently I am using the following SQL statement:
SELECT * FROM tblnecklaces WHERE nsubcat REGEXP 'bank special';
Now this works OK, but if I had the category as follows: 'diamond special' for example then the row is still retrieved because the term 'special' in my column seems to be matching up to the term 'bank special' in my REGEXP statement.
How would I go abut checking for the existence of the whole phrase 'bank special' only and not partially matching the words?
Many thanks for your time and help
The simplest solution is to use the LIKE clause (% is wildcard):
SELECT * FROM tblnecklaces WHERE nsubcat LIKE '%bank special%';
Note that LIKE is also a lot faster than REGEXP.
You can prefix the column with comma's, and compare it to the bank special:
SELECT *
FROM tblnecklaces
WHERE ',' + replace(nsubcat,', ','') + ',' LIKE ',bank special,'
I put in a replace to remove optional space after a comma, because your example has one.
Not tested but this RegExp should work (LIKE works too but will match items that starts or ends with the same phrase):
SELECT * FROM tblnecklaces WHERE nsubcat REGEXP '(^|, )bank special($|,)';