I need to find the latest 3 records for each user that has a particular status on 'Fail'. At first it seems easy but I just can't seem to get it right.
So in a table of:
ID Date Status
1 2017-01-01 Fail
1 2017-01-02 Fail
1 2017-02-04 Fail
1 2015-03-21 Pass
1 2014-02-19 Fail
1 2016-10-23 Pass
2 2017-01-01 Fail
2 2017-01-02 Pass
2 2017-02-04 Fail
2 2016-10-23 Fail
I would expect ID 1 to be returned as the most recent 3 records are fails, but not ID 2, as they have a pass within their three fails. Each user may have any number of Pass and Fail records. There are thousands of different IDs
So far I've tried a CTE with ROW_NUMBER() to order the attempts but can't think of a way to ensure that the latest three results all have the same status of Fail.
Expected Results
ID Latest Fail Date Count
1 2017-02-04 3
Maybe try something like this:
WITH cte
AS
(
SELECT id,
date,
status,
ROW_NUMBER () OVER (PARTITION BY id ORDER BY date DESC) row
FROM #table
),cte2
AS
(
SELECT id, max(date) as date, count(*) AS count
FROM cte
WHERE status = 'fail'
AND row <= 3
GROUP BY id
)
SELECT id,
date AS latest_fail,
count
FROM cte2
WHERE count = 3
Check This.
Demo : Here
with CTE as
(
select *,ROW_NUMBER () over( partition by id order by date desc) rnk
from temp
where Status ='Fail'
)
select top 1 ID,max(DATE) as Latest_Fail_Date ,COUNT(rnk) as count
from CTE where rnk <=3
group by ID
Ouptut :
I think you can do this using cross apply:
select i.id
from (select distinct id from t) i cross apply
(select sum(case when t.status = 'Fail' then 1 else 0 end) as numFails
from (select top 3 t.*
from t
where t.id = i.id
order by date desc
) ti
) ti
where numFails = 3;
Note: You probably have a table with all the ids. If so, you an use that instead of the select distinct subquery.
Or, similarly:
select i.id
from (select distinct id from t) i cross apply
(select top 3 t.*
from t
where t.id = i.id
order by date desc
) ti
group by i.id
having min(ti.status) = 'Fail' and max(ti.status) = 'Fail' and
count(*) = 3;
Here you go:
declare #numOfTries int = 3;
with fails_nums as
(
select *, row_number() over (partition by ID order by [Date] desc) as rn
from #fails
)
select ID, max([Date]) [Date], count(*) as [count]
from fails_nums fn1
where fn1.rn <= #numOftries
group by ID
having count(case when [Status]='Fail' then [Status] end) = #numOfTries
Example here
Related
I have the following dataset:
id
id_rev
time
1
1
08.01.2022
1
0
31.02.2021
2
2
28.01.2017
2
1
25.07.2021
2
0
25.07.2021
I am looking for a SQL query that can return an entry per id but only the one where the id_rev is maximum. So in this case it should return these two rows:
(id=1, id_rev=1,time)
(id=2, id_rev=2, time)
One canonical approach uses ROW_NUMBER:
WITH cte AS (
SELECT t.*, ROW_NUMBER() OVER (PARTITION BY id ORDER BY id_rev DESC) rn
FROM yourTable t
)
SELECT id, id_rev, time
FROM cte
WHERE rn = 1
ORDER BY id;
Another approach would be to use exists logic:
SELECT id, id_rev, time
FROM yourTable t1
WHERE NOT EXISTS (
SELECT 1
FROM yourTable t2
WHERE t2.id = t1.id AND t2.id_rev > t1.id_rev
);
#result =
SELECT
*,
RANK()
OVER (PARTITION BY id ORDER BY id_rev DESC) AS Rank
FROM dataset ORDER BY Rank;
#result =
SELECT *
FROM #result
WHERE Rank = 1;
I'm struggling with creation of select which shows me penultimate date for each record in my DB.
For example:
id date
1 01.01.2018
1 05.01.2018
1 06.02.2018
2 01.06.2018
2 03.06.2018
3 12.12.2017
Out of this record I need to write select, which shows me following:
ID max_date penultimate
1 06.02.2018 05.01.2018
2 03.06.2018 01.06.2018
3 12.12.2017 NULL
Any idea how to do it? many thanks in advance
Use conditional aggregation and the ANSI-standard row_number() or dense_rank() functions:
select id,
max(date) as max_date,
max(case when seqnum = 2 then date end) as penultimate_date
from (select t.*,
dense_rank() over (partition by id order by date desc) as seqnum
from t
) t
where seqnum in (1, 2)
group by id;
Use row_number() if the dates can be the same in the event of ties.
Use GROUP BY to get the MAX and a correlated subquery with another MAX but this time lower than the former.
SELECT
T.id,
MAX(T.date) max_date,
(
SELECT
MAX(N.date)
FROM
YourTable N
WHERE
N.id = T.id AND
N.date < MAX(T.date)
) penultimate
FROM
YourTable T
GROUP BY
T.id
Just an opitimized query:
;WITH cte AS
(
SELECT id AS ID
,[date] AS max_date
,LEAD ([date], 1, 0) OVER (PARTITION BY id ORDER BY [date] DESC) AS penultimate
,ROW_NUMBER() OVER(PARTITION BY id ORDER BY [date] DESC) AS RN
FROM Table3
)
SELECT ID,max_date,penultimate
FROM cte
WHERE RN=1
SQL Fiddle
I wrote in this way,
SELECT ID
,max(StartDate) MaxDate
,(
SELECT StartDate
FROM YourTable t2
WHERE t2.id = t1.id
ORDER BY StartDate DESC OFFSET 1 ROWS FETCH NEXT 1 ROW ONLY
) penultimate
FROM YourTable t1
GROUP BY id
I have a little sql query, like so
SELECT * FROM table
This returns a bunch of results, i output the following fields:
ID
UserID
Amount
Date
What i want to do is get the most recent entry from each UserID ( based on ID ), then if the amount is 0 do not return ANY results from that UserID.
select t1.*
from your_table t1
join
(
select userid, max(date) as mdate
from your_table
group by userid
having sum(case when amount = 0 then 1 else 0 end) = 0
) t2 on t1.userid = t2.userid and t1.date = t2.mdate
In the subquery you group by the user and select only those having no amount of zero. In that select you use max(date) as mdate to get the latest date for each user.
That subquery can be joined to the original table to get the complete record and not just the userid.
try this
WITH cte AS
(
SELECT
MAX(ID) OVER (PARTITION BY UserID) MaxIDForUserID,
ROW_NUMBER() OVER (PARTITION BY UserID ORDER BY ID DESC) rn,
UserID,
Amount,
Date
FROM TableName
)
SELECT * FROM cte WHERE rn = 1 AND Amount != 0
I want to get All records that has duplicate values for SOME of the fields (i.e. Key columns).
My code:
CREATE TABLE #TEMP (ID int, Descp varchar(5), Extra varchar(6))
INSERT INTO #Temp
SELECT 1,'One','Extra1'
UNION ALL
SELECT 2,'Two','Extra2'
UNION ALL
SELECT 3,'Three','Extra3'
UNION ALL
SELECT 1,'One','Extra4'
SELECT ID, Descp, Extra FROM #TEMP
;WITH Temp_CTE AS
(SELECT *
, ROW_NUMBER() OVER (PARTITION BY ID, Descp ORDER BY (SELECT 0))
AS DuplicateRowNumber
FROM #TEMP
)
SELECT * FROM Temp_cte
DROP TABLE #TEMP
The last column tells me how many times each row has appeared based on ID and Descp values.
I want that row but I ALSO need another column* that indicates both rows for ID = 1 and Descp = 'One' has showed up more than once.
So an extra column* (i.e. MultipleOccurances (bool)) which has 1 for two rows with ID = 1 and Descp = 'One' and 0 for other rows as they are only showing up once.
How can I achieve that? (I want to avoid using Count(1)>1 or something if possible.
Edit:
Desired output:
ID Descp Extra DuplicateRowNumber IsMultiple
1 One Extra1 1 1
1 One Extra4 2 1
2 Two Extra2 1 0
3 Three Extra3 1 0
SQL Fiddle
You say "I want to avoid using Count" but it is probably the best way. It uses the partitioning you already have on the row_number
SELECT *,
ROW_NUMBER() OVER (PARTITION BY ID, Descp
ORDER BY (SELECT 0)) AS DuplicateRowNumber,
CASE
WHEN COUNT(*) OVER (PARTITION BY ID, Descp) > 1 THEN 1
ELSE 0
END AS IsMultiple
FROM #Temp
And the execution plan just shows a single sort
Well, I have this solution, but using a Count...
SELECT T1.*,
ROW_NUMBER() OVER (PARTITION BY T1.ID, T1.Descp ORDER BY (SELECT 0)) AS DuplicateRowNumber,
CASE WHEN T2.C = 1 THEN 0 ELSE 1 END MultipleOcurrences FROM #temp T1
INNER JOIN
(SELECT ID, Descp, COUNT(1) C FROM #TEMP GROUP BY ID, Descp) T2
ON T1.ID = T2.ID AND T1.Descp = T2.Descp
I have the following table structure:
Id, Message
1, John Doe
2, Jane Smith
3, Error
4, Jane Smith
Is there a way to get the error record and the surrounding records? i.e. find all Errors and the record before and after them.
;WITH numberedlogtable AS
(
SELECT Id,Message,
ROW_NUMBER() OVER (ORDER BY ID) AS RN
FROM logtable
)
SELECT Id,Message
FROM numberedlogtable
WHERE RN IN (SELECT RN+i
FROM numberedlogtable
CROSS JOIN (SELECT -1 AS i UNION ALL SELECT 0 UNION ALL SELECT 1) n
WHERE Message='Error')
WITH err AS
(
SELECT TOP 1 *
FROM log
WHERE message = 'Error'
ORDER BY
id
),
p AS
(
SELECT TOP 1 l.*
FROM log
WHERE id <
(
SELECT id
FROM err
)
ORDER BY
id DESC
)
SELECT TOP 3 *
FROM log
WHERE id >
(
SELECT id
FROM p
)
ORDER BY
id
Adapt this routine to pick out your target.
DECLARE #TargetId int
SET #TargetId = 3
select *
from LogTable
where Id in (-- "before"
select max(Id)
from LogTable
where Id < #TargetId
-- target
union all select #TargetId
-- "after"
union all select min(Id)
from LogTable
where Id > #TargetId)
select id,messag from
(Select (Row_Number() over (order by ID)) as RNO, * from #Temp) as A,
(select SubRNO-1 as A,
SubRNO as B,
SubRNO+1 as C
from (Select (Row_Number() over (order by ID)) as SubRNO, * from #Temp) as C
where messag = 'Error') as B
where A.RNO = B.A or A.RNO = B.B or A.RNO = B.C
;WITH Logs AS
(
SELECT ROW_NUMBER() OVER (ORDER BY id), id, message as rownum FROM LogTable lt
)
SELECT curr.id, prev.id, next.id
FROM Logs curr
LEFT OUTER JOIN Logs prev ON curr.rownum+1=prev.rownum
RIGHT OUTER JOIN Logs next ON curr.rownum-1=next.rownum
WHERE curr.message = 'Error'
select id, message from tbl where id in (
select id from tbl where message = "error"
union
select id-1 from tbl where message = "error"
union
select id+1 from tbl where message = "error"
)
Get fixed number of rows before & after target
Using UNION for a simple, high performance query (I found selected answer WITH query above to be extremely slow)
Here is a high performance alternative to the WITH top selected answer, when you know an ID or specific identifier for a given record, and you want to select a fixed number of records BEFORE and AFTER that record. Requires a number field for ID, or something like date that can be sorted ascending / descending.
Example: You want to select the 10 records before and after a specific error was recorded, you know the error ID, and can sort by date or ID.
The following query gets (inclusive) the 1 result above, the identified record itself, and the 1 record below. After the UNION, the results are sorted again in descending order.
SELECT q.*
FROM(
SELECT TOP 2
id, content
FROM
the_table
WHERE
id >= [ID]
ORDER BY id ASC
UNION
SELECT TOP 1
id, content
FROM
the_table
WHERE
id < [ID]
ORDER BY id DESC
) q
ORDER BY q.id DESC