I am confused about DENSE_Rank function
so I have a code like this
select ID, date
From TABLE1
order by date
so It executes like this
ID DATE
1 10/25/2016
1 10/23/2015
1 10/22/2014
2 10/11/2015
2 5/24/2014
2 5/21/2014
2 3/23/2013
3 10/21/2016
3 9/20/2015
my code is
select ID, Extract(MONTH FROM DATE), DENSE_RANK () OVER (PARTITION BY ID,Extract(MONTH FROM DATE order by DATE) rank
FROM TABLE
it shows
ID DATE RANK
1 10 1
1 10 2
1 10 3
2 10 1
2 5 1
2 5 2
2 3 1
3 10 1
3 9 2
but I would like to show like below
ID DATE RANK
1 10 1
1 10 1
1 10 1
2 10 1
2 5 2
2 5 2
2 3 3
3 10 1
3 9 2
how can I code to execute above
Thank you so much
You want to order by the month (in descending order) rather than partition by them:
SELECT ID,
Extract(MONTH FROM "DATE"),
DENSE_RANK () OVER ( PARTITION BY ID
ORDER BY Extract(MONTH FROM "DATE") DESC ) rank
FROM your_table
Related
With subquery I need to select after first five rows for each group of id_student and must common values of id_desireCollage between id_student.
More explain : select common collages for each student desires after his five chosen desires
ID
id_desireCollage
id_student
1
1
1
2
2
1
3
3
1
4
4
1
5
5
1
6
8
1
7
9
1
8
7
1
9
2
2
10
12
2
11
1
2
12
3
2
13
6
2
14
5
2
15
8
2
16
9
2
17
7
2
18
4
3
19
3
3
20
2
3
21
1
3
22
8
3
23
9
3
24
7
3
25
5
3
Something like
select id_desireCollage
from
(select *
from desires ds
where ds.id_desireCollage = desires.id_desireCollage)
group by (id_student)
having count(*) > 5
Expected result is:
id_desireCollage
7
9
Try the following:
select id_desireCollage
from
(
select d.*,
row_number() over (partition by id_student order by ID) as rn
from desires d
) T
where rn > 5
group by id_desireCollage
order by count(*) desc
fetch first 1 row with ties
If you don't want to use the row number function (as you commented), you may try the following - supposing there are no gaps in the ID column:
select id_desireCollage
from desires d
where id >=
(
select min(id)+5
from desires t
where t.id_student = d.id_student
)
group by id_desireCollage
order by count(*) desc
fetch first 1 row with ties
See demo
As suggested by #MatBailie, if you meant by common, that all students have selected the id_desireCollage value then you could use the following:
select id_desireCollage
from desires d
where id >=
(
select min(id)+5
from desires t
where t.id_student = d.id_student
)
group by id_desireCollage
having count(*)=
(
select count(distinct id_student)
from desires
)
This is the table t. I want to group it every time the TotalQty >= 5n (let n = group). i.e. once the TotalQty >= 5n I want to sum together the qty from n-1 to n.
ID DateCreated CurrQty
1 01-20-2020 1
2 01-21-2020 4
3 01-22-2020 3
4 01-23-2020 3
5 01-25-2020 1
6 02-13-2020 3
7 02-16-2020 2
With this query I can get pretty close but I doesn't consider the the previous "valid" TotalQty + 5
select DateCreated, CurrQty, TotalQty
, ceiling(TotalQty/5.0) GroupNum
from
(
select DateCreated, CurrQty
, SUM(CurrQty) OVER (ORDER BY DateCreated ROWS BETWEEN UNBOUNDED PRECEDING AND 0 PRECEDING) TotalQty
from t
) t2
ID DateCreated CurrQty TotalQty GroupNum
1 01-20-2020 1 1 1
2 01-21-2020 4 5 1
3 01-22-2020 3 8 2
4 01-23-2020 3 11 3
5 01-25-2020 1 12 3
6 02-13-2020 3 15 3
7 02-16-2020 2 17 4
---
How do I get this result?
ID DateCreated CurrQty TotalQty GroupNum
1 01-20-2020 1 1 1
2 01-21-2020 4 5 1
3 01-22-2020 3 8 2
4 01-23-2020 3 11 2 (from ID2, 11 >= (5+5))
5 01-25-2020 1 12 3
6 02-13-2020 3 15 3
7 02-16-2020 2 17 3 (from ID4, 17 >= (11+5))
And so on, the next group would be until 17+5 = 22
You need to use a recursive CTE for this:
with cte as (
select id, datecreated, currqty, currqty as totalqty, 1 as groupnum
from t
where id = 1
union all
select t.id, t.datecreated, t.currqty,
(case when cte.totalqty >= 5 then t.currqty else t.currqty + cte.totalqty end),
(case when cte.totalqty >= 5 then groupnum + 1 else groupnum end)
from cte join
t
on t.id = cte.id + 1
)
select *
from cte;
EDIT:
Hold on. I think the answer is simpler.
select t.*,
1 + ceil((totalqty - qty + 1) / 5.0)
from (select t.*,
sum(qty) over (order by date) as totalqty
from t
) t;
I want to return each student final semester record from these tables.
Table: dbo.Stdetail
StID YearID TermID
2 1 1
3 1 1
3 2 1
3 2 2
3 3 1
3 3 2
4 1 1
4 1 2
5 1 1
5 1 2
Table: dbo.lastyear
StID YearID TermID
1 5 1
2 5 1
2 6 2
3 5 1
3 6 2
From these two tables I want to return final yearID and term ID.
Desired output:
StID yearID TermID
1 5 1
2 6 2
3 6 2
4 1 2
5 1 2
I think you want to union together dbo.Stdetail and dbo.lastyear and then apply use row_number() to identify the most last record for each student. Like this:
;with cte as (select *
, row_number() over (partition by StID order by YearID desc, TermID desc) rn
from (select StID, YearID, TermID from dbo.Stdetail
union
select StID, YearID, TermID from dbo.lastyear) x
)
select *
from cte
where rn = 1
I have a table like below.
Customer Order Rank
1 12 3
1 14 7
2 15 6
2 16 4
2 17 2
2 21 1
3 24 5
3 25 6
3 27 7
Now, I want to select all rows except for rows with minimum ranks for each customer. It should look like below.
Customer Order Rank
1 14 7
2 15 6
2 16 4
2 17 2
3 25 6
3 27 7
You can use a CTE + ROW_NUMBER:
WITH CTE AS
(
SELECT Customer, [Order], Rank,
RN = ROW_NUMBER() OVER (PARTITION BY Customer ORDER BY Rank)
FROM dbo.Customers
)
SELECT Customer, [Order], Rank
FROM CTE
WHERE RN > 1
ORDER BY Customer, Rank DESC
Demo: http://sqlfiddle.com/#!6/444be/3/0
WITH CTE AS (
SELECT Customer,Order,Rank,
ROW_NUMBER() OVER (PARTITION BY Customer ORDER BY Rank ) as rn FROM t
)
SELECT Customer,Order,Rank FROM CTE
WHERE rn >1
We have a table like below in an sql server 2005 db:
event_id staff_id weeks
1 1 NNNYYYYNNYYY
1 2 YYYNNNYYYNNN
2 1 YYYYYYYYNYYY
This is from a piece of timetabling software and is basically saying which staff members are assigned to an event (register) and the set of weeks they are teaching that register. So staff_id 1 isn't teaching the first 3 weeks of event 1 but is teaching the following 4....
Is there an easy way to convert that to an easier form such as:
event_id staff_id week
1 1 4
1 1 5
1 1 6
1 1 7
1 1 10
1 1 11
1 1 12
1 2 1
1 2 2
1 2 3
1 2 7
1 2 8
1 2 9
2 1 1
2 1 2
2 1 3
2 1 4
2 1 5
2 1 6
2 1 7
2 1 8
2 1 10
2 1 11
2 1 12
WITH cte AS
(
SELECT 1 AS [week]
UNION ALL
SELECT [week] + 1
FROM cte
WHERE [week] < 53
)
SELECT t.event_id, t.staff_id, cte.[week]
FROM your_table AS t
INNER JOIN cte
ON LEN(ISNULL(t.weeks, '')) >= cte.[week]
AND SUBSTRING(t.weeks, cte.[week], 1) = 'Y'
ORDER BY t.event_id, t.staff_id, cte.[week]