I want to remove only first space in below string.
NSString *str = #"IF_Distance (GET_Mi mi=km*1.4,STRING1,STRING2)";
Note: There is a space after IF_Distance and another space after
GET_Mi. I am unable to remove the space after IF_Distance.
Use rangeOfString: to locate the first space, then use stringByReplacingCharactersInRange:withString: to replace it with the empty string.
Remove space by using below code.
NSString *str = #"IF_Distance (GET_Mi mi=km*1.4,STRING1,STRING2)";
NSString *secondString = [str stringByReplacingOccurrencesOfString:#"IF_Distance " withString:#"IF_Distance"];
Try This:
NSString *str = #"IF_Distance (GET_Mi mi=km*1.4,STRING1,STRING2)";
NSString *firstStringContainingSpace = [[str componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]] firstObject];//firstStringContainingSpace = IF_Distance
str = [str stringByReplacingCharactersInRange:[str rangeOfString:[NSString stringWithFormat:#"%# ",firstStringContainingSpace]] withString:firstStringContainingSpace];
Output:
str = #"IF_Distance(GET_Mi mi=km*1.4,STRING1,STRING2)";
You can remove first space by using following code:
First find space by using rangeOfString: and then remove by using stringByReplacingCharactersInRange:withString: method.
Like,
NSString *str = #"IF_Distance (GET_Mi mi=km*1.4,STRING1,STRING2)";
NSString *strSpace = #" ";
NSRange range = [str rangeOfString:strSpace];
NSString *strFinal;
if (NSNotFound != range.location) {
strFinal = [str stringByReplacingCharactersInRange:range withString:#""];
}
If you are looking for some more universal way - this is the variant of it:
- (NSString *)removeWhitespaces:(NSString *)string {
NSMutableArray * stringComponents = [[string componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]] mutableCopy];
NSString * fStringComponent = [stringComponents firstObject];
[stringComponents removeObject:fStringComponent];
return [fStringComponent stringByAppendingString:[stringComponents componentsJoinedByString:#" "]];
}
Related
I would like to add a spacing between two words if its already not there:
//Sample 1
NSString *word1 = #"First";
NSString *word2 = #"Word";
NSString *output = [NSString stringWithFormat:#"%#%#", word1, word2];
//output = FirstWord --> I want "First Word"
If there is already a space "First " then it should not add another one.
Just trim the first string, and then always put a space.
NSString *word1 = #"First";
NSString *word2 = #"Word";
NSString *word1Trimmed = [string stringByTrimmingCharactersInSet:
[NSCharacterSet whitespaceCharacterSet]];
NSString *output = [NSString stringWithFormat:#"%# %#", word1Trimmed, word2];
I have an array where i am trying to remove the access spaces, brackets and " from the nsarray in order to use componentsSeparatedByString:#";"
NSArray *paths = [dic valueForKey:#"PATH"];
for(NSString *s in paths)
{
NSLog(#"String: %#", s);
}
String: (
"29858,39812;29856,39812;29800,39819;29668,39843;29650,39847;29613,39855;29613,39855;29613,39856;29605,39857;29603,39867;29603,39867;29599,39892;29596,39909;29587,39957;29571,40018;29563,40038;29560,40043"
)
this is the output give as show there are spaces, brackets and " how could i remove them
?
As this line is juz a string inside that array "29858,39812;29856,39812;29800,39819;29668,39843;29650,39847;29613,39855;29613,39855;29613,39856;29605,39857;29603,39867;29603,39867;29599,39892;29596,39909;29587,39957;29571,40018;29563,40038;29560,40043" this line is a string inside the path array and i try using componentsSeparatedByString:#";" it could not be spilt all there are spaces brackets and " inside.
Try stringByTrimmingCharactersInSet:
NSCharacterSet *charsToTrim = [NSCharacterSet characterSetWithCharactersInString:#"() \n\""];
s = [s stringByTrimmingCharactersInSet:charsToTrim];
try to use:
s = [s stringByReplacingOccurrencesOfString:#";"
withString:#""];
it separates the numbers for you and you can work with them as i.e. NSInteger values.
NSString *_inputString = #"29858,39812;29856,39812;29800,39819;29668,39843;29650,39847;29613,39855;29613,39855;29613,39856;29605,39857;29603,39867;29603,39867;29599,39892;29596,39909;29587,39957;29571,40018;29563,40038;29560,40043";
NSString *_setCommonSeparator = [_inputString stringByReplacingOccurrencesOfString:#";" withString:#","];
NSArray *_separetedNumbers = [_setCommonSeparator componentsSeparatedByString:#","];
for (NSString *_currentNumber in _separetedNumbers) {
NSInteger _integer = [_currentNumber integerValue];
NSLog(#"number : %d", _integer);
}
I am adding string into a pickerView like this :
NSString *string = [NSString stringWithFormat:#"%# %#", xxx, xxx];
[pickerViewObjects addObject:string];
what i want to do is to hide the first part of the string, or of there's something to use like charachterAtIndex it will be useful because the first part of my string has a specific number of characters.
Use this method to get "(whitespaces) John"
NSString *string = #"Hello John";
NSUInteger spacePosition = [string rangeOfString:#" "].location;
NSMutableString *newString = [[NSMutableString alloc]init ];
for (int i=0; i<spacePosition; i++)
[newString appendString:#" "];
NSString *otherPartofString = [string substringFromIndex:(spacePosition)];
[newString appendString:otherPartofString];
NSLog(#"new String is '%#'",newString);
[newString release];
You can use [string substringWithRange:NSMakeRange(start, count)], that way you will only get a new string that you can use for displaying.
you can do like this:
find the position of space between two strings like this:
NSUInteger spacePosition = [string rangeOfString:#" "].location
then use:
NSString *otherPartofString = [string substringFromIndex:(spacePosition+1)];
I want to take all values after a new line character \n from my string. How can I get those values?
Try this:
NSString *substring = nil;
NSRange newlineRange = [yourString rangeOfString:#"\n"];
if(newlineRange.location != NSNotFound) {
substring = [yourString substringFromIndex:newlineRange.location];
}
Take a look at method componentsSeparatedByString here.
A quick example taken from reference:
NSString *list = #"Norman, Stanley, Fletcher";
NSArray *listItems = [list componentsSeparatedByString:#", "];
this will produce a NSArray with strings separated: { #"Norman", #"Stanley", #"Fletcher" }
Here is similar function which splits the string by delimeter and return array with two trimmed values.
NSArray* splitStrByDelimAndTrim(NSString *string, NSString *delim)
{
NSRange range = [string rangeOfString: delim];
NSString *first;
NSString *second;
if(range.location == NSNotFound)
{
first = #"";
second = string;
}
else
{
first = [string substringToIndex: range.location];
first = [first stringByTrimmingCharactersInSet: [NSCharacterSet whitespaceCharacterSet]];
second = [string substringFromIndex: range.location + 1];
second = [second stringByTrimmingCharactersInSet: [NSCharacterSet whitespaceCharacterSet]];
}
return [NSArray arrayWithObjects: first, second, nil];
}
NSString *myString = #"A B C D E F G";
I want to remove the spaces, so the new string would be "ABCDEFG".
You could use:
NSString *stringWithoutSpaces = [myString
stringByReplacingOccurrencesOfString:#" " withString:#""];
If you want to support more than one space at a time, or support any whitespace, you can do this:
NSString* noSpaces =
[[myString componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]]
componentsJoinedByString:#""];
Taken from NSString
stringByReplacingOccurrencesOfString:withString:
Returns a new string in which all occurrences of a target string in the receiver are replaced by another given string.
- (NSString *)stringByReplacingOccurrencesOfString:(NSString *)target withString:(NSString *)replacement
Parameters
target
The string to replace.
replacement
The string with which to replace target.
Return Value
A new string in which all occurrences of target in the receiver are replaced by replacement.
All above will works fine. But the right method is this:
yourString = [yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
It will work like a TRIM method. It will remove all front and back spaces.
Thanks
if the string is mutable, then you can transform it in place using this form:
[string replaceOccurrencesOfString:#" "
withString:#""
options:0
range:NSMakeRange(0, string.length)];
this is also useful if you would like the result to be a mutable instance of an input string:
NSMutableString * string = [concreteString mutableCopy];
[string replaceOccurrencesOfString:#" "
withString:#""
options:0
range:NSMakeRange(0, string.length)];
You can try this
- (NSString *)stripRemoveSpaceFrom:(NSString *)str {
while ([str rangeOfString:#" "].location != NSNotFound) {
str = [str stringByReplacingOccurrencesOfString:#" " withString:#""];
}
return str;
}
Hope this will help you out.