I'm not sure how to explain what I need but here's the data first:
Table 1
District
-1
3
2
1
3
Table 2
ID ID_Name
1 Main 1
2 Main 2
3 Main 3
How do I join the tables so that it looks like this?
District
-1
Main 3
Main 2
Main 1
Main 3
I'm assuming the second column is named Name for this, but you can do it with a COALESCE and a LEFT JOIN:
Select Coalesce(T2.Name, Str(T1.District)) As District
From Table1 T1
Left Join Table2 T2 On T1.District = T2.Id
assuming table 2 have
Table 2
ID col2
1 Main 1
2 Main 2
3 Main 3
you could use a left join
select table1.Distric, table2.col2
from table1
left join table2 on table1.dictrict = t2.ID
order by table2 col2
You can use left join:
Select coalesce(t2.col, t1.District) from table1 t1
left join table2 t2 on t1.District = t2.Id
Related
I have two tables identical to each other like below
table 1
col1
1
2
3
4
5
table 2
col1
1
2
3
4
5
is there way to write a SQL query to join every row of table 1 to every row of table 2?
Do you want a Cartesian product? If so, use cross join:
select t1.col1, t2.col2
from table1 t1 cross join
table2 t2;
It sounds like an inner join as they are identical tables:
select t1.col, t2.col, ...
from table t1
inner join t2 on t1.col = t2.col
Could anyone help with how to take a single column:
ID
1
2
3
4
and show all possible distinct pairings in 2 columns:
ID ID
1 2
1 3
1 4
2 3
2 4
3 4
You can join the column on itself and arbitrarily decide that the left hand side will always be smaller than the right hand side (as the example shows):
SELECT t1.col, t2.col
FROM mytable t1
JOIN mytable t2 ON t1.col < t2.col
do self join
select t.id,t2.id from t t1 join t t2 on t.id<t1.id
A Simple Cartesian product should do
select distinct a.id as id_a, b.id as id_b
from test a, test b
where a.id<b.id;
Let's say i have:
Table1:
ID Name
1 Ann
2 Mike
3 Stan
4 Kyle
Table2:
Pair ID Person1ID Person2ID
1 1 2
2 3 4
I want to select pairs, but with names instead of IDs, so this would be the output:
1 Ann Mike
2 Stan Kyle
I imagine a simple:
inner join Table1 on Table1.ID=Table2.Person1ID
won't work, because I want both of them, not only one.
I'm pretty new to SQL so i'm sorry if there is a simple answer.
You have to join twice and use alias to diference the tables
SELECT t2.PairID, A.Name, B.Name
FROM Table2 t2
JOIN Table1 A
ON t2.Person1ID = A.ID
JOIN Table1 B
ON t2.Person2ID = B.ID
You can join sub query like below:
Select p.PairID, p.Name, q.Name
from
(Select t2.PairID, t1.Name
from Table1 t1 inner join Table2 t2
on t1.ID = t2.Person1ID) p
inner join
(Select t2.PairID, t1.Name
from Table1 t1 inner join Table2 t2
on t1.ID = t2.Person2ID) q
on p.PairID = q.PairID
See the result here in the demo.
Why does this query produce duplicates in some scenarios?
Table_1
ID
1
2
3
Table_2
ID
1
2
4
Table_3
ID
1
3
4
Query:
SELECT COALESCE(Table_1.ID, Table_2.ID, Table_3.ID)
FROM Table_1
FULL OUTER JOIN TABLE_2
ON Table1.ID=Table_2.ID
FULL OUTER JOIN TABLE_3
ON Table1.ID=Table3.ID;
Result:
1
2
3
4
4
The query duplicates all values where T1 is null and T2/T3 share the same value. Duplicates are removed for any other combination.
This is a little bit hard to explain. If you show the other ids, you will see the full range of what happens:
"coalesce" "id1" "id2" "id3"
1 1 1 1
2 2 2 .
3 3 . 3
4 . 4 .
4 . . 4
You can see the results here.
So, You get one row because t1 & t2 create a row with t2.id = 4 and t1.id = null when they don't match. Then, you get the same thing when t3.id = 4. The comparison is to t1.id -- so you get another row. There is no comparison to t2.id.
I suspect that you intend logic more like this:
select coalesce(t1.id, t2.id, t3.id)
from t1 full join
t2
using (id) full join
t3
using (id);
Here is the SQL Fiddle.
I have two tables. I need to take away from the first table second table. Stim to another table without all the rows of the first table.
Table1
Table2
Result = Table1(value1) – Table2(value1) -----groupe no. 2 or no.1
Result (groupe no. 2)
Result
id value1 groupe
_______________________
1 10 2
2 9 2
3 10 2
5 5 2
6 11 2
7 12 2
I need the result of which I can write the group number and get result for that group.
Try this query:
Select
t1.id,
t1.value1-t2.value1 as value,
t1.groupe from
table1 t1,table2 t2
where t1.id=t2.id and t1.groupe=2;
try this:
SELECT
T1.id, T2.group, T1.valor - T2.valor AS value
FROM
Table1 T1 INNER JOIN
Table2 T2 ON T1.id = T2.id AND T1.group = T2.group
WHERE (T1.group = 2)