I am using following function.
TO_DATE(TO_CHAR (SYSDATE, 'YYYY-MON-DD HH24:MI:SS'),'yyyy/mm/dd hh24:mi:ss')
Its working fine if I am updating data from a simple query like:--
set modified_on= TO_DATE(TO_CHAR (SYSDATE, 'YYYY-MON-DD HH24:MI:SS'),'yyyy/mm/dd hh24:mi:ss')
But not working in case of stored procedure.
Note:- In stored procedure I am using dynamic query. Execute Immediate....
No error but only date getting inserted or updated not time.
Now:-- "31-07-2017"
Need Something like:-- "31-07-2017 hh:mi:ss"
Thanks in Advance for any help.
I might be going mad, but I'm sure this exact question has been posted verbatim before, in all its craziness. Anyway.. You wrote:
TO_DATE(TO_CHAR (SYSDATE, 'YYYY-MON-DD HH24:MI:SS'),'yyyy/mm/dd hh24:mi:ss')
This doesnt make sense. You have a date, you convert it to a string looking like one format and immediately try and convert it back to date, but using a different format. You can't do this: it doesnt make sense to take the date right now, and convert it to a string looking like 2017-JUL-31 18:28:00 and then ask oracle to interpret it using slashes and a numerical month - the string you just had it prepare has dashes, not slashes. It has a text month name not a numerical month identifier.. It won't work. Oracle will hit the first - and expect a \ and it'll choke.
Just use the date you have to start with, as a date:
SYSDATE
i.e:
set modified_on= SYSDATE
In Oracle, Current Date + Time = Sysdate. select sysdate from dual would produce 2017-07-31 23:18:40
Related
Quick help on this line of my code in my oracle database. So, I have a to_char with sysdate. However, I want to change the sysdate to say Jul-2020 but for some reason it tells me invalid number. Can anyone help me solve this small issue? thanks for the help.
here is what I have:
Before:
to_char(sysdate, 'YYYY')
After:
to_char('Jul-2020', 'MM-YYYY'
The problem is first you have let the dB know "Jul-2020" is a date format so the correct line should be to_char(to_date('Jul-2020','Mon-yyyy'), 'MM-YYYY')
Something along these lines should work as long as you provide input dates as below. You just need to be consistent, meaning you can't do 2020-July without changing output format to YYYY-MM
select to_char(to_date('07-2020','MM-YYYY'),'MM-YYYY') from dual;
select to_char(to_date('July-2020','MM-YYYY'),'MM-YYYY') from dual;
If you want to be able to use both sysdate and hardcoded values inter-changeably, you can provide date in a specific format that works for sysdate and hardcoded date
select to_char(to_date(sysdate,'DD-MM-YYYY'),'MM-YYYY') from dual;
select to_char(to_date('01-07-2020','DD-MM-YYYY'),'MM-YYYY') from dual;
select to_char(to_date('01-July-2020','DD-MM-YYYY'),'MM-YYYY') from dual
I am new to SQL and have run into a problem. I want to have the epoch date i.e. 1970-01-01T00:00:00Z in this mentioned format.
I cannot use it as a constant (i.e. '1970-01-01T00:00:00Z') for programming reasons. I need a statement that gives this as an output. I have used this:
select to_char(TRUNC(add_months(sysdate,-555),'MM'), 'YYYY-MM-DD"T"HH24:MI:SS"Z"') from dual;
But the only problem with this statement is it will not give me the date I want next month i.e. it is month specific it will only work for April 2016. But I need a the date to always remain 1970-01-01T00:00:00Z.
Thanks in advance for the help.
PS: I am using Oracle SQL Developer (if that matters).
You can just do:
select '1970-01-01T00:00:00Z' from dual;
Or if you want to have it processed for some reason, which seems like pointless overhead:
select to_char(date '1970-01-01', 'YYYY-MM-DD"T"HH24:MI:SS"Z"') from dual;
Either will give you the string you want. But it is a string, not a date. If you want it as a proper data type (which I don't think you do, but maybe this is for comparison) it needs to be a timestamp with time zone, which you can get with:
select timestamp '1970-01-01 00:00:00 UTC' from dual;
Well this might not be the most elegent way but it is a way that will work:
select regexp_substr('1970-01-01T00:00:00Z','^....................',1,1) from dual;
I am trying to only display the date and time of a table in a certain format. This format is DD-MON-YYYY and the time HH24:MI:SS. I don't understand how to make both formats work together. I can get them to function separately.
select to_char(sysdate, 'DD-MON-YYYY', systimestamp,'HH24:MI:SS') from dual;
My error is 'too many arguments'. I want to understand why it isn't working.
From the documentation TO_CHAR takes three arguments when using dates
a date or date time
a format model
optional NLS parameter for the localization
You can concatenate the two results together with this.
select to_char(sysdate, 'DD-MON-YYYY')||' '|| TO_CHAR(systimestamp,'HH24:MI:SS') from dual;
But why would when you do it one call
SELECT TO_CHAR(systimestamp,'DD-MON-YYYY HH24:MI:SS') from dual;
NB SQL is not case sensitive in regards to keywords. Upper or lower case both work.
Try:
select to_char(sysdate, 'DD-MON-YYYY HH24:MI:SS') from dual;
I have the following statement being run on an oracle database.
SELECT br.Number
FROM Billing_History br
WHERE TRUNC(br.History_Date) BETWEEN to_date('01-Jan-99', 'DD-Mon-YY HH:MI:SS')
AND to_date('11-May-99', 'DD-Mon-YY HH:MI:SS')
There are definitely records in that table that fall between those dates. And they all have a Number that goes with them, but for some reason this isn't returning any Numbers. It's returning nothing at all.
The dates in the database are in this format '01-Jan-11'. So it seems like I'm putting the dates in the correct format too. Do you see anything wrong with the SQL I wrote?
The problem is not the time component of the format model, it's the 'YY' component, which would mean in your year is converted to 2099, not 1999. Try this to illustrate:
SQL> SELECT to_char(to_date('01-Apr-99','DD-Mon-YY'),'DD-Mon-YYYY') thedate
FROM dual;
THEDATE
-----------
01-Apr-2099
SQL>
Either use RR or YYYY as a format model component for year when using 20th century dates.
Edit:
You make the statement "The dates in the database are in this format '01-Jan-11'." This is a common, but incorrect, interpretation of dates in Oracle. DATE fields are always stored in the same internal format. It's all about how you use the format model in conversion functions that dictates how the data is converted to/from internal format.
Use RR in your date format instead of YY. It is probably picking up those dates as 2099 instead of 1999.
SELECT br.Number FROM Billing_History br WHERE
TRUNC(br.History_Date) BETWEEN to_date('01-Jan-99', 'DD-Mon-RR HH:MI:SS')
AND to_date('11-May-99', 'DD-Mon-RR HH:MI:SS')
Try removing the time part from the second to_date parameter:
to_date('11-May-99', 'DD-Mon-YY')
Or even better:
to_date('11-05-1999', 'DD-MM-YYYY')
This is more robust as it is language agnostic and doesn't need to guess the century.
I have a table as
create table Dummy (date_created date)
in oracle.I want to store date in 'dd-mon-yyyy' (12-dec-2010) format.
How should i do this.
Please help.
In Oracle a column created with the DATE datatype just stores the date. It doesn't have a particular format, it just stores the day, month, year, hour, minute, and second. You need to convert from whatever format you have using the TO_DATE function. If you have a text string with the date in 'dd-mon-yyyy' format and you want to put this date into your table you'd use something like
INSERT INTO DUMMY (DATE_CREATED)
VALUES (TO_DATE('01-FEB-2011', 'DD-MON-YYYY');
Going the other way (from DATE column value to character string) you'd use the TO_CHAR function. If you were retrieving a value from your table and wanted to convert it to 'DD-MON-YYYY' format you'd use something like
SELECT TO_CHAR(DATE_CREATED, 'DD-MON-YYYY')
FROM DUMMY;
Share and enjoy.
Use to_date() function. In your case, the syntax would be
insert into Dummy values (to_date('08-09-2010', 'dd-mm-yyyy'));
Here is a link to the detailed help.
The DATE datatype will store date and time information (century, year, month, day, hours, minutes, and seconds) in an internal format in the database. When you get it out of the database, you can choose to display it in whatever format you like.
This information is either created using implicit conversion from a string or explicitly using either the TO_DATE function or the ANSI date literal. If you look in the v$nls_parameters view, this will tell you what the NLS_DATE_FORMAT is which is generally used for the implicit conversion. This may often be defined as DD-MON-RR, which might be why the date will come out as 23-DEC-10 when the query select sysdate from dual is run. (Not entirely sure I'm right about the nls stuff. Correct me if I'm wrong.)
However, all the date information is available if you know how to get it. The query select to_char(sysdate, 'dd-mon-yyyy hh24:mi:ss') from dual will return all the date fields.
Likewise, the insert statement shown below will create a row with a date value in it.
insert into dummy (date_created)
values (to_date('12-dec-2010 12:34:56', 'dd-mon-yyyy hh24:mi:ss'))`
This data can then be retrieved.
select date_created from dummy
This will implicitly convert the date to a character string using the NLS_DATE_FORMAT, providing the output below.
DATE_CREA
---------
23-DEC-10
The full date information is available by explicitly converting the date to a character string.
select to_char(date_created, 'DD-MON-YYYY') as date_created from dummy;
select to_char(date_created, 'DD-MON-YYYY HH24:MI:SS') as date_created
from dummy;
This will provide output in the format you require:
DATE_CREATE
-----------
23-DEC-2010
If you always use the TO_DATE and TO_CHAR functions to convert to/from a date datatype, then you will have fewer problems. Implicit conversion is useful but can cause some confusion or problems.
You can keep and eye here
http://www.techonthenet.com/oracle/functions/to_date.php
use to_date function to save a data with the format you need. I suggest to use SYSDATE updating table and when you need to read data from table use something like that:
dbms_output.put_line(TO_CHAR(SYSDATE, 'DD-MON-YYYY HH24:MI:SS'));
to solve your problem use:
to_date('08/JAN/2010', 'DD/MON/YYYY')
Just use TRUNC(YourDate) if date have time part, it will be truncate time part. Oracle have not just 'DATE' type, 'DATE' always have time part.
However if you do not specify time - it will 00:00:00.
SELECT TRUNC(SYSDATE) from dual
Result:
23-12-2010
Oracle does not support DATE without time part.
You can make it always be an integer date by adding a CHECK constraint:
CREATE TABLE dummy (date_created date CHECK (date_created = TRUNC(date_created)))
, insert it in any format you want:
INSERT
INTO dummy (date_created)
VALUES (TO_DATE('23-DEC-2010', 'dd-mon-yyyy'))
and select it in any format you want:
SELECT TO_CHAR(date_created, 'dd-mon-yyyy')
FROM dummy