I am trying to write PHP code that can do the following:
If score is less or equal to 50 then print "take a quiz",
elseif score is between 51 and 80 then print "take a test",
else print "you have passed"
So the main proble is how to get operators for between 50 and 80(to count all the numbers from 51 up to 80). Thank you!
To do this, you will need to combine three operators, the >, <, and &&.
The && operator evaluates its left and right hand side and returns a truthy value if both of them are truthy, and a falsey value if one or both of them are falsey. (The returned value will be one of the arguments).
This is called an and operator because it return a truthy value only if A and B are true.
To combine everything, one would do if($score < 82 && $score > 50).
However, there's actually an easier way in this case.
Assuming that $score is an integer, it's greater than or equal to 51 if it isn't less than 50. And since the else-if won't run unless all previous clauses in the if statement didn't run (i.e. only one of the possible code blocks will run), then you only have to check that $score is less than 80).
So that means, in this case, while the && operator could be used, we could just write
if($score < 50) {
// ...
else if ($score < 80) { // "else if" won't run if ($score < 50) was false.
// ...
} else { // won't run unless ($score < 80) and ($score < 50) were both false
// ...
}
That's why the idea of else is very useful.
I think your looking for this
if($score <= 50)
echo 'take a quiz';
else if($score < 80)
echo 'take a test';
else echo 'you have passed';
Related
I have tried many thing involving this, >=, >==, =>, ==>.i can not find one that works. hey all return either primary expression needed or expected initializer before '>'. I am creating a IR receiver latch switch and thus have to create parameters for the code because the receiver is not constant in all conditions. Full code below. Any suggestions to fix the code please reply and don't DM me. Thank you.
code:
int LEDState = 0;
int LEDPin = 8;
int dt = 100;
int recieverOld ==> 500 and recieverOld ==< 2000;
int recieverNew;
int recieverPin = 12;
void setup() {
// put your setup code here, to run once:
Serial.begin(9600);
pinMode(LEDPin, OUTPUT);
pinMode(recieverPin, INPUT);
}
void loop() {
// put your main code here, to run repeatedly:
recieverNew = digitalRead(recieverPin);
if((recieverOld >== 0 && recieverOld <== 10) && (recieverNew >== 500 && recieverNew <== 2000) {
if(LEDState == 0) {
digitalWrite(LEDPin, HIGH);
LEDState = 1;
}
}
recieverOld = recieverNew;
delay(dt);
}
error:
expected initializer before '==' token
if one = used line 4 and related, return error expected primary-expression before '>' token
if > before = line 4 and related, return error expected initializer before '>=' token
Any solutions or suggestions welcome.
TL;DR
Operators that do no exist, and that you should NOT use:
==>, ==<, >==, <==
Operators that works and you can use them:
>= - MORE THAN OR EQUAL, compare operator, for example X >= 5
<= - LESS THAN OR EQUAL, compare operator, for example X <= 5
> - MORE THAN, compare operator, for example X > 5
< - LESS THAN, compare operator, for example X < 5
== - compare operator, when you want to compare values of the variables if they have the same value, for example X == 5, Y == X, 10 == 7
=== - equality operator, similar to compare operator ==, but aditionally checks the type of a variable. for example X === Y, '10' === 10
= - assign operator, when you want to assign something to the variable, for example X = 5
<> OR != - NOT EQUAL, compare operator, for example X != 5, Y <> 10
!== - similar to != or <>, but also checks the type of a value. For example 10 !== '10', and will return opposite result of the equality operator ===
in my code I have the following if statement:
if (a.count >= 2) {
t2 = array[b % a.count];
array[0] = t2;
}
I have another if statement that goes like the first. What I want it to do is if a <= 0 then goto a certain line, or skip over certain parts of code. How would I do this? I was thinking something along the lines of
if (a.count <= 0) {
goto line 96
}
This wouldn't work, the syntax is wrong, but how would I do this?
Goto statements are generally considered bad programming and excessive utilization of them can lead to code that is hard to maintain and debug.
That said, if/else/else if provide all the functionality you need.
I recommend putting the code you need to run inside that if statement in a separate method and then calling it from the if statement.
if (a.count <= 0) {
nameOfNewMethod();
}
//somewhere else
- (void) nameOfNewMethod {
//code here
}
Put the lines of code you want to "goto" in a function (or if appropriate, a block) and call the function (or block). If there are lines of code you want to skip, you can always return early out of a function, or use an else block?
There is in fact a goto command in Objective-C. To utilize it, you have to create a label, ex:
marker:
and jump to it like so within the same method:
goto marker;
But you can't declare any variables between those two commands. All the variables have to be created before the jump so that they still exist after.
Here's an example of how to use goto:
int x = 0;
if (a.count <= 0) {
goto marker;
}
x = 5;
marker:; // <-- semi-colon indicates the label is followed by an empty statement, thus allowing for immediate variable declaration
int y = x + 7;
In that case, if a.count <= 0, y == 7, else y == 12.
I am developing an app where the user receives an overall score and are judged from that score and given a title. However, with the code I am using, the end result is always the same, no matter what score the subject gets. I dont know if this a math problem or a code problem, as it always comes up with the first option: You have no SWAG whatsoever...
if (totalScore<24) {
describe.text = #"You have no SWAG whatsoever...";
}
else if (25<totalScore<49) {
describe.text = #"You seem to be new to SWAG.";
}
else if (50<totalScore<74) {
describe.text = #"You have a bit of SWAG, not enough though.";
}
else if (75<totalScore<99) {
describe.text = #"You definately have SWAG!";
}
else if (totalScore == 100) {
describe.text = #"You are a GOD of SWAG.";
}
else if (25<totalScore<49) {
should be:
else if (25<totalScore && totalScore<49) {
The way you wrote it is parsed as if you'd written:
else if ((25<totalScore) < 49) {
25<totalScore will be either 1 or 0 depending on whether it's true or false. Either way, it's less than 49.
Also, all your comparisons should be <= rather than <. Otherwise, you're excluding all the boundary values.
building if in this way
if (25<totalScore<49) {...}
is risky.In reality you do something like
25<totalScore -> YES/NO (values will be casted from BOOL to int as 1/0)
and then you will do
0/1 < 49 which will be always true.
so in total your if is wrong.
Your first line of code looks right from what you have displayed so far? You need to output what total score is. You are maybe not setting it before running your code?
Failing that, are you sure its compiling properly? You need to use && in your subsequent if statements.
Also, you need to use <=, because at the moment, if the score is 24 it wont work.
I'm trying to write code that detects if an integer is greater than another integer. Is this possible?
Here is what i've done so far.
if (NumCorrect >> NumWrong) {
btnCool.title = #"Awww";
}
else {
btnCool.title = #"Cool!";
}
All its doing is going to the else
EDIT:
NSString *numCorrect = [NSString stringWithFormat:#"%d",NumCorrect];
NSString *numWrong = [NSString stringWithFormat:#"%d", NumWrong];
lblWrong.text = numWrong;
lblCorrect.text = numCorrect;
if (NumCorrect > NumWrong) {
btnCool.title = #"Awww";
} else {
btnCool.title = #"Cool!";
}
Use single >
if (NumCorrect > NumWrong) {
btnCool.title = #"Awww";
} else {
btnCool.title = #"Cool!";
}
Double >> is a bit shift operation. You shift every bit in the binary representation of your variable NumCorrect NumWrong amount of bytes to the right. In almost all cases this will return in a number other then 0, which will then treated as a false value and thus the else block is executed.
Almost perfect - just take off one of those >'s. >> and << are for "bit-shifting", a weird hold-over from the earliest days of programming. You're not gonna use them much. What you really want is > and <, which is for testing if numbers are greater than each other or less than each other.
In addition, you may remember from math class that ≥ and ≤ (greater-than-or-equal-to and less-than-or-equal-to) are useful operations as well. Because there's no symbols for those on most keyboards, however, C and Xcode use >= and <= instead.
Finally, you may already know this, but to check if two numbers are exactly equal to each other you can use == (because = is used for setting the contents of variables).
Hope that's helpful!
I need to check a variable vi_theIndex for its value. At the given moment it has a value of 65.
I want to check if vi_theIndex is bigger or equal to zero AND smaller than 32.
Right now I do it like this:
long long vi_theIndex = 65;
if ((vi_theIndex >= 0) && (vi_theIndex < 32) )
{
//Case true
}
else
{
//Case false
}
I realized that the results are wrong for 65. The second case should come up but the first case becomes true. Why is this?
I tried this:
long long vi_theIndex = 65;
bool limitFlag1, limitFlag2;
limitFlag1 = (vi_theIndex <= 0);
limitFlag2 = (vi_theIndex = 65);
limitFlag2 becomes true and limitFlag1 becomes undefined, the debugger doesn´t even stop there on my breakpoint. It looks like C doesn´t understand the '<', '<=' or '>' signs. This also happens when I use the '<' or '>' sign alone like here:
limitFlag1 = (vi_theIndex < 0);
limitFlag1 is not defined.
Can somebody please shed some light on this?
You must not be showing your real code for your first example - as you say, "case false" should be executed.
Your second example has a problem - you have vi_theIndex = 65, rather than vi_theIndex == 65, which you probably meant. The statement as you have it is always true. limitFlag1 will be 0 - I'm not sure what you mean by it "becomes undefined" - are you not showing your real code here, too?