I am attempting to calculate difference in an entry/exit time by doing something like this:
SELECT entry_time - exit_time AS dwell
However, believe the values are in SimpleDateFormat:
2017-07-15T13:00:37-05:00
and as a result, I have had trouble figuring out what to CAST or CONVERT them to in Postgre Sql
I was able to do this in PySpark, but now I need to do this just using standard SQL. Here is an example of what worked in Spark:
import pyspark.sql.functions as F
timeFmt = "yyyy-MM-dd'T'HH:mm:ss"
timeDiff = (F.unix_timestamp('exit_time', format=timeFmt)
- F.unix_timestamp('entry_time', format=timeFmt))
new_sdf = sdf.withColumn("Dwell", timeDiff)
Any help is greatly appreciated!
You can just cast such a value to get a timestamp in PostgreSQL:
SELECT CAST('2017-07-15T13:00:37-05:00' AS timestamp with time zone);
timestamptz
------------------------
2017-07-15 20:00:37+02
(1 row)
Then use timestamp arithmetic and subtract the two timestamps to get an interval.
Related
I am trying to calculate the average of ride_length (hh:mm:ss format) on Big Query.
1
For example, I am aiming for a result that says 1 instead of 01:00:00.
I tried using the CAST function to convert it into an integer but it didn't work. I also tried following the steps of answers to questions similar to mine but they didn't work as well.
You can use Extract
function which will return the specified part of the time expressions. You can try the below queries.
To extract hour from the TIME expression you can consider the below query.
Query:
SELECT EXTRACT(HOUR FROM TIME "01:00:00") as hour;
Output:
To extract hour from TIMESTAMP expression below query can be considered.
Query:
select EXTRACT(hour from timestamp "2023-01-13 15:30:00" AT TIME ZONE "America/Los_Angeles") as hour
Output:
To extract hour from the TIME column you can consider the below sample query.
Query:
SELECT time,EXTRACT(HOUR FROM (time)) AS hour from `bigquery-public-data.austin_incidents.incidents_2008` limit 10
Output:
I have a table with a text column in the following format:
5/30/2021 9:35:18 AM
I'm trying to convert this to date(yyyy-MM-dd) but I get null values when I use cast, to_date.
Is there any way to get the above data in the yyyy-mm-dd format?
Use Databricks Datetime Patterns. According to SparkSQL documentation on the Databricks website, you can use datetime patterns specific to Databricks to convert to and from date columns. First, you need to convert the text column to a date column like this:
to_date('5/30/2021 9:35:18 AM','M/d/y h:m:s a')
M - month, d - day of month, y - year, h - hour of day (12-hour), m - minute of hour, s - second of minute, a - AM/PM
Once the column is converted to a date, you can easily use the same datetime patterns to convert it back to a specific format. Use the following command to convert it to the required format:
date_format(date to_date('5/30/2021 9:35:18 AM','M/d/y h:m:s a'), 'yyyy/MM/dd')
Note: Depending upon whether you're getting zero left padded days, months, hours, minutes, and seconds, you'll need to tweak the above command.
I would like to extract the date & hour from UTC time from the below table in bigquery. I have used timestamp for getting the date or time using the below code. I would like to apply the code for the entire column. How to apply timestamp for the entire column? Can you please assist with it?
SELECT EXTRACT(HOUR FROM TIMESTAMP "2020-05-03 16:49:47.583494")
My data is like this
I want result like this:
You can do it this way:
SELECT my_column AS original_value,
DATE_FORMAT(STR_TO_DATE(my_column, "%Y-%m-%d %H:%i:%s.%f UTC"), "%e/%m/%Y") AS date,
DATE_FORMAT(STR_TO_DATE(my_column, "%Y-%m-%d %H:%i:%s.%f UTC"), "%l%p") AS hour
FROM my_table;
I am assuming that the column is VARCHAR, that's why I am converting it to DATE.
Output:
Demo:
You can check the demo here.
Edit:
My initial thought was that OP wanted the query for MySQL (probably BigQuery is based on that). But it turns out that BigQuery is not based on MySQL. So you can use FORMAT_TIMESTAMP in BigQuery, this is how the query would look:
SELECT Occurrence AS original_value,
FORMAT_TIMESTAMP("%e/%m/%Y", Occurrence) AS date,
FORMAT_TIMESTAMP("%l%p", Occurrence) AS hour
FROM mytable
is there an alternative to the to_char() function in impala? I want to set a timestamp field where the date and minutes are fixed and only showing the hours, but can't seem to find an alternative.
This is my existing code in postgres which I need to convert to impala.
select to_char(starttime, '1900-01-01 HH24:00:00')::timestamp
Any help is appreciated!
In Impala, you can use
SELECT hours_add('1900-01-01', hour(now()));
to get the same result
function hour extracts the hour part from a timestamp
function hours_add adds hour to a timestamp
i have a requirement in which i have to get time difference of two timestamp in hours and than later find an average of the hours.
i am using below query to find difference of two timestamp but it does not give exact result it gives approx result. do we have any other solution to achieve the same.My two time stamps are as( LAST_MODIFIED_DATETIME - 2016-11-30 15:39:01.131 CREATE_DATETIME - 2016-07-01 17:25:52.375)
select timestampdiff(8, char(LAST_MODIFIED_DATETIME-CREATE_DATETIME)) as total_time from test_table where name='some name';
Use the built-in Db2 function HOURS_BETWEEN()
https://www.ibm.com/support/knowledgecenter/SSEPGG_11.5.0/com.ibm.db2.luw.sql.ref.doc/doc/r0061478.html
It's easy, by converting the timestamp to hours as follows:
(24*DAYS(last_modified_datetime)+MIDNIGHT_SECONDS(last_modified_datetime)/3600)
-
(24*DAYS(create_datetime)+MIDNIGHT_SECONDS(create_datetime)/3600)