How to store result of a function which will return sysrefcursor? - sql

Question

Scenario: there is an procedure inside which we have a cursor.
I need to call a function which will take an input from that cursor value and will return SYS_REFCURSOR.
I need to store that result of function in a different variable/cursor & need to return this value from procedure as out parameter.
I am using Oracle 11g.
How can I proceed?
PFB My Approach:
create or replace procedure prc_test
(p_dept_id in number,
c_detail out sysrefcursor)--need to add extra out parameter
as
var1 varchar2(200) :=null;
begin
open c_detail for
select -1 from dual;
if p_dept_id is not null then
open c_detail for
select emp_no from emp
where dept_id=p_dept_id;
--i need to retrn value of 'get_emp_dtls' function as out parameter.
end if;
end procedure;
/
Function to be called
CREATE OR REPLACE FUNCTION get_emp_dtls
(p_emp_no IN EMP.EMP_NO%TYPE)
RETURN SYS_REFCURSOR
AS
o_cursor SYS_REFCURSOR;
BEGIN
OPEN o_cursor FOR
SELECT
ENAME,
JOB
FROM emp
WHERE EMP_NO = p_emp_no;
RETURN o_cursor;
-- exception part
END;
/

Answer 1

Here is your function that takes a varchar2 variable and returns A refcursor( weakly typed).
CREATE OR replace FUNCTION fn_return_cur(v IN VARCHAR2)
RETURN SYS_REFCURSOR
IS
c1 SYS_REFCURSOR;
BEGIN
OPEN c1 FOR
SELECT 'ABC'
FROM dual
WHERE 'col1' = v;
RETURN c1;
END;
/
Here is the procedure that has a cursor value passed as argument to function and the returned cursor passed as OUT argument.
CREATE OR replace PROCEDURE Pr_pass_out_cur(v_2 OUT SYS_REFCURSOR)
IS
func_arg VARCHAR2(3);
other_arg VARCHAR2(3);
CURSOR c_2 IS
SELECT 'ABC' col1,
'DEF' col2
FROM dual;
BEGIN
LOOP
FETCH c_2 INTO func_arg, other_arg;
EXIT WHEN c_2%NOTFOUND;
v_2 := Fn_return_cur(func_arg);
END LOOP;
EXCEPTION
WHEN OTHERS THEN
NULL;
END;
/
Let me know your feedback.